Table 1:
Comparison of the numerical solution and error obtained by present method for
𝑛
=
3
in (
36
) with series solution [
25
].
𝑥
Our method
Series method [
25
]
𝑚
=
3
2
𝑚
=
1
2
8
𝑚
=
2
5
6
0.0
0
.
0
0
𝐸
+
0
0
0
.
0
0
𝐸
+
0
0
0
.
0
0
𝐸
+
0
0
0
.
0
0
𝐸
+
0
0
0.1
4
.
0
2
𝐸
−
0
5
2
.
5
1
𝐸
−
0
6
6
.
2
8
𝐸
−
0
7
1
.
4
0
𝐸
−
0
6
0.5
2
.
8
9
𝐸
−
0
5
1
.
8
5
𝐸
−
0
6
4
.
9
6
𝐸
−
0
7
2
.
9
9
𝐸
−
0
6
1.0
4
.
3
9
𝐸
−
0
5
3
.
7
9
𝐸
−
0
5
3
.
7
6
𝐸
−
0
5
1
.
9
9
𝐸
−
0
6