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ISRN Discrete Mathematics
Volume 2012 (2012), Article ID 956594, 29 pages
doi:10.5402/2012/956594
Research Article

Explicit Evaluations of Cubic and Quartic Theta-Functions

Department of Mathematics, Rajiv Gandhi University, Rono Hills, Doimukh 791112, Arunachal Pradesh, India

Received 24 February 2012; Accepted 8 April 2012

Academic Editors: H.-J. Kreowski and W. Liu

Copyright © 2012 Nipen Saikia. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

Abstract

We find explicit values of cubic and quartic theta-functions and their quotients by parameterizations. In the process, we also find some transformation formulas of these theta-functions.

1. Introduction

For any complex number 𝑎 , define ( 𝑎 ; 𝑞 ) 𝑛 = ( 𝑎 ; 𝑞 ) ( 𝑎 𝑞 𝑛 ; 𝑞 ) , a n d ( 𝑎 ; 𝑞 ) = 𝑘 = 1 1 𝑎 𝑞 𝑘 1 . ( 1 . 1 )

Ramanujan’s general theta-function 𝑓 ( 𝑎 , 𝑏 ) is given by 𝑓 ( 𝑎 , 𝑏 ) = 𝑘 = 𝑎 𝑘 ( 𝑘 + 1 ) / 2 𝑏 𝑘 ( 𝑘 1 ) / 2 , ( 1 . 2 ) where | 𝑎 𝑏 | < 1 . If we set 𝑎 = 𝑞 𝑒 2 𝑖 𝑧 , 𝑏 = 𝑞 𝑒 2 𝑖 𝑧 , and 𝑞 = 𝑒 𝜋 𝑖 𝜏 , where 𝑧 is complex and I m ( 𝜏 ) > 0 , then 𝑓 ( 𝑎 , 𝑏 ) = 𝜗 3 ( 𝑧 , 𝜏 ) , where 𝜗 3 ( 𝑧 , 𝜏 ) [1, page 464] denotes one of the classical theta-functions in its standard notation.

We also define the following three special cases of 𝑓 ( 𝑎 , 𝑏 ) : 𝜙 ( 𝑞 ) = 𝑓 ( 𝑞 , 𝑞 ) = 𝑛 = 𝑞 𝑛 2 = 𝑞 ; 𝑞 2 𝑞 2 ; 𝑞 2 𝑞 ; 𝑞 2 𝑞 2 ; 𝑞 2 , 𝜓 ( 𝑞 ) = 𝑓 𝑞 , 𝑞 3 = 𝑘 = 0 𝑞 𝑘 ( 𝑘 + 1 ) / 2 = 𝑞 2 ; 𝑞 2 𝑞 ; 𝑞 2 , 𝑓 ( 𝑞 ) = 𝑓 𝑞 , 𝑞 2 = 𝑛 = ( 1 ) 𝑛 𝑞 𝑛 ( 3 𝑛 1 ) / 2 = ( 𝑞 ; 𝑞 ) . ( 1 . 3 )

If 𝑞 = 𝑒 2 𝜋 𝑖 𝑧 with I m ( 𝑧 ) > 0 , then 𝑓 ( 𝑞 ) = 𝑞 1 / 2 4 𝜂 ( 𝑧 ) , where 𝜂 ( 𝑧 ) denotes the classical Dedekind eta-function.

In his famous paper [2] and [3, pages 23–39], Ramanujan offered 17 elegant series for 1 / 𝜋 and remarked that 14 of these series belong to the “corresponding theories” in which the base 𝑞 in classical theory of elliptic functions is replaced by one or other of the functions: 𝑞 𝑟 = 𝑞 𝑟 𝜋 ( 𝑥 ) = e x p 𝜋 c s c 𝑟 2 𝐹 1 ( 1 / 𝑟 , ( 𝑟 1 ) / 𝑟 , 1 , 1 𝑥 ) 2 𝐹 1 ( , 1 / 𝑟 , ( 𝑟 1 ) / 𝑟 , 1 , 𝑥 ) ( 1 . 4 ) where 𝑟 = 3, 4, and 6, where 2 𝐹 1 denotes the Gaussian hypergeometric function. In the classical theory, the variable 𝑞 = 𝑞 2 . Ramanujan did not offer any proof of these 14 series for 1 / 𝜋 or any of his theorems in the “corresponding” or “alternative” theories. In 1987, J. M. Borwein and P. B. Borwein [4] proved the formulas for 1 / 𝜋 . However, in his second notebook [5, Vol. II], Ramanujan recorded, without proof, some of his theorems in alternative theories which were first proved by Berndt et al. [6] in 1995. These theories are now known as the theory of signature 𝑟 , where 𝑟 = 3, 4, and 6. In particular, the theories of signature 3 and 4 are called cubic and quartic theories, respectively. An account of this work may also be found in Berndt’s book [7].

In Ramanujan’s cubic theory, the theta-functions 𝑎 ( 𝑞 ) , 𝑏 ( 𝑞 ) , and 𝑐 ( 𝑞 ) are defined by 𝑎 ( 𝑞 ) = 𝑚 , 𝑛 = 𝑞 𝑚 2 + 𝑚 𝑛 + 𝑛 2 , 𝑏 ( 𝑞 ) = 𝑚 , 𝑛 = 𝑤 𝑚 𝑛 𝑞 𝑚 2 + 𝑚 𝑛 + 𝑛 2 , 𝑐 ( 𝑞 ) = 𝑚 , 𝑛 = 𝑞 ( 𝑚 + 1 / 3 ) 2 + ( 𝑚 + 1 / 3 ) ( 𝑛 + 1 / 3 ) + ( 𝑛 + 1 / 3 ) 2 , ( 1 . 5 ) where 𝑤 = e x p ( 2 𝜋 𝑖 / 3 ) . These theta-functions were first introduced by J. M. Borwein and P. B. Borwein [8], who also proved that 𝑎 3 ( 𝑞 ) = 𝑏 3 ( 𝑞 ) + 𝑐 3 ( 𝑞 ) . ( 1 . 6 ) Cubic theta-functions 𝑏 ( 𝑞 ) and 𝑐 ( 𝑞 ) are related with the Dedekind eta-function by [7, page 109, Lemma 5.1]: 𝑓 𝑏 ( 𝑞 ) = 3 ( 𝑞 ) 𝑓 𝑞 3 , 𝑐 ( 𝑞 ) = 3 𝑞 1 / 3 𝑓 3 𝑞 3 𝑓 . ( 𝑞 ) ( 1 . 7 )

The Borwein brothers [8, ( 2 . 2 ) ] also established the following three transformation formulas: 𝑎 𝑒 2 𝜋 𝑡 = 1 𝑡 3 𝑎 𝑒 2 𝜋 / 3 𝑡 , 𝑏 𝑒 ( 1 . 8 ) 2 𝜋 𝑡 = 1 𝑡 3 𝑐 𝑒 2 𝜋 / 3 𝑡 𝑐 𝑒 , ( 1 . 9 ) 2 𝜋 𝑡 = 1 𝑡 3 𝑏 𝑒 2 𝜋 / 3 𝑡 , ( 1 . 1 0 ) where R e ( 𝑡 ) > 0 . Cooper [9] also found alternate proofs of (1.8)–(1.10).

In quartic theory, Berndt et al. [6] (see also [7, page 146, (9.7)]) established a “transfer” principle of Ramanujan by which formulas in this theory can be derived from those of the classical theory. Taking place of 𝑎 ( 𝑞 ) , 𝑏 ( 𝑞 ) , and 𝑐 ( 𝑞 ) in cubic theory is the functions 𝐴 ( 𝑞 ) , 𝐵 ( 𝑞 ) , and 𝐶 ( 𝑞 ) [10], defined by 𝐴 ( 𝑞 ) = 𝜙 4 ( 𝑞 ) + 1 6 𝑞 𝜓 4 𝑞 2 , 𝐵 ( 𝑞 ) = 𝜙 4 ( 𝑞 ) 1 6 𝑞 𝜓 4 𝑞 2 , 𝐶 ( 𝑞 ) = 8 𝑞 𝜙 2 ( 𝑞 ) 𝜓 2 𝑞 2 , ( 1 . 1 1 ) which also satisfy the equality: 𝐴 2 ( 𝑞 ) = 𝐵 2 ( 𝑞 ) + 𝐶 2 ( 𝑞 ) . ( 1 . 1 2 ) Berndt et al. [10] used (1.12) to establish the inversion formula: 𝑧 4 = 2 𝐹 1 1 4 , 3 4 = ; 1 ; 𝑥 𝐴 ( 𝑞 ) , ( 1 . 1 3 ) where 𝑞 = 𝑞 4 is given by (1.4). Therefore, they were able to prove the theorems in the quartic theory directly.

The quartic analogues of (1.7) are given by [10, page 139, Theorem 3.1] 𝑓 𝐵 ( 𝑞 ) = 2 ( 𝑞 ) 𝑓 𝑞 2 4 , 𝐶 ( 𝑞 ) = 8 𝑞 𝑓 2 𝑞 2 𝑓 ( 𝑞 ) 4 . ( 1 . 1 4 )

While proving the explicit values of 𝜙 ( 𝑞 ) and 𝜓 ( 𝑞 ) recorded by Ramanujan in his notebooks, Berndt [7], explicitly determined the value of cubic theta-function 𝑎 ( 𝑒 2 𝜋 ) [7, page 328, Corollary 3], namely, 𝑎 𝑒 2 𝜋 𝜙 2 ( 𝑒 𝜋 ) = 1 ( 1 2 ) 1 / 8 , 3 1 ( 1 . 1 5 ) where 𝜙 ( 𝑒 𝜋 ) = 𝜋 1 / 4 / Γ ( 3 / 4 ) is classical [1]. Certain quotients of 𝐴 ( 𝑞 ) , 𝐵 ( 𝑞 ) , and 𝐶 ( 𝑞 ) were also evaluated by Berndt et al. [10] while deriving the series for 1 / 𝜋 associated with the theory of signature 4.

In this paper, we find several new explicit values of cubic and quartic theta-functions and their quotients by parameterizations. In the process, we also find some transformation formulas of these theta-functions.

We now define some parameters of Dedekind eta-function 𝑓 ( 𝑞 ) and Ramanujan’s theta-functions 𝜙 ( 𝑞 ) and 𝜓 ( 𝑞 ) . For positive real numbers 𝑛 and 𝑘 , define 𝑟 𝑘 , 𝑛 = 𝑓 ( 𝑞 ) 𝑘 1 / 4 𝑞 ( 𝑘 1 ) / 2 4 𝑓 𝑞 𝑘 , 𝑞 = 𝑒 2 𝜋 𝑛 / 𝑘 , 𝑟 ( 1 . 1 6 ) 𝑘 , 𝑛 = 𝑓 ( 𝑞 ) 𝑘 1 / 4 𝑞 ( 𝑘 1 ) / 2 4 𝑓 𝑞 𝑘 , 𝑞 = 𝑒 𝜋 𝑛 / 𝑘 . ( 1 . 1 7 ) The parameters 𝑟 𝑘 , 𝑛 and 𝑟 𝑘 , 𝑛 are defined by Yi [11]. She also evaluated several explicit values of 𝑟 𝑘 , 𝑛 and 𝑟 𝑘 , 𝑛 by using eta-function identities and transformation formulas.

In his lost notebook [12, page 212], Ramanujan defined 𝜆 𝑛 = 1 3 3 𝑓 6 ( 𝑞 ) 𝑞 𝑓 6 𝑞 3 , 𝑞 = 𝑒 𝜋 𝑛 / 3 . ( 1 . 1 8 ) Closely related to 𝜆 𝑛 is the parameter 𝜇 𝑛 defined by Ramanathan [13] as 𝜇 𝑛 = 1 3 3 𝑓 6 ( 𝑞 ) 𝑞 𝑓 6 𝑞 3 , 𝑞 = 𝑒 2 𝜋 𝑛 / 3 . ( 1 . 1 9 )

From the definitions of 𝑟 𝑘 , 𝑛 , 𝜇 𝑛 , 𝑟 𝑘 , 𝑛 , and 𝜇 𝑛 , we note that 𝑟 6 3 , 𝑛 = 𝜆 𝑛 and 𝑟 6 3 , 𝑛 = 𝜇 𝑛 . Ramanujan [12] also provided a list of eleven recorded values of 𝜆 𝑛 and ten unrecorded values of 𝜆 𝑛 . All 21 values of 𝜆 𝑛 and several new were established by Berndt et al. [14]. Yi [11], and Baruah and Saikia [15, 16] also found several new values of parameters 𝜆 𝑛 and 𝜇 𝑛 .

In [11], Yi also introduced the following two parameterizations 𝑘 , 𝑛 and 𝑘 , 𝑛 along with 𝑟 𝑘 , 𝑛 and 𝑟 𝑘 , 𝑛 : 𝑘 , 𝑛 = 𝜙 ( 𝑞 ) 𝑘 1 / 4 𝜙 𝑞 𝑘 , 𝑞 = 𝑒 𝜋 𝑛 / 𝑘 , ( 1 . 2 0 ) 𝑘 , 𝑛 = 𝜙 ( 𝑞 ) 𝑘 1 / 4 𝜙 𝑞 𝑘 , 𝑞 = 𝑒 2 𝜋 𝑛 / 𝑘 , ( 1 . 2 1 ) where 𝑘 and 𝑛 are positive real numbers. Employing modular transformation formulas and theta-function identities, Yi evaluated several many explicit values of 𝑘 , 𝑛 and 𝑘 , 𝑛 to find explicit values of 𝜙 ( 𝑞 ) and their quotients.

Motivated by Yi’s work, for any positive real numbers 𝑘 and 𝑛 , Baruah and Saikia [17] defined the parameters 𝑔 𝑘 , 𝑛 and 𝑔 𝑘 , 𝑛 by 𝑔 𝑘 , 𝑛 = 𝜓 ( 𝑞 ) 𝑘 1 / 4 𝑞 ( 𝑘 1 ) / 8 𝜓 𝑞 𝑘 , 𝑞 = 𝑒 𝜋 𝑛 / 𝑘 , 𝑔 ( 1 . 2 2 ) 𝑘 , 𝑛 = 𝜓 ( 𝑞 ) 𝑘 1 / 4 𝑞 ( 𝑘 1 ) / 8 𝜓 𝑞 𝑘 , 𝑞 = 𝑒 𝜋 𝑛 / 𝑘 . ( 1 . 2 3 ) In [17], they proved many properties of the parameterizations 𝑔 𝑘 , 𝑛 and 𝑔 𝑘 , 𝑛 and established their relationship with Yi’s parameters 𝑟 𝑘 , 𝑛 , 𝑟 𝑘 , 𝑛 , 𝑘 , 𝑛 , 𝑘 , 𝑛 , and Weber-Ramanujan class-invariants 𝐺 𝑛 and 𝑔 𝑛 , where 𝐺 𝑛 and 𝑔 𝑛 defined by 𝐺 𝑛 = 2 1 / 4 𝑞 1 / 2 4 𝑞 ; 𝑞 2 , 𝑔 𝑛 = 2 1 / 4 𝑞 1 / 2 4 𝑞 ; 𝑞 2 ; 𝑞 = 𝑒 𝜋 𝑛 . ( 1 . 2 4 ) They also found several values of the parameters 𝑔 𝑘 , 𝑛 and 𝑔 𝑘 , 𝑛 .

In Section 2, we record some known values of above parameters, which will be used in this paper.

In Sections 3 and 4, we deal with explicit evaluations of cubic theta-functions and their quotients. In Sections 5 and 6, we find explicit values of the quartic theta-functions and their quotients.

2. Explicit Values of Parameters

Lemma 2.1. If 𝑟 𝑘 , 𝑛 is as defined in (1.16), then 𝑟 1 , 1 = 1 , 𝑟 2 , 1 = 1 , 𝑟 2 , 2 = 2 1 / 8 , 𝑟 2 , 3 = 1 + 2 1 / 6 , 𝑟 2 , 4 = 2 1 / 8 1 + 2 1 / 8 , 𝑟 2 , 5 = 1 + 5 2 , 𝑟 2 , 6 = 2 1 / 2 4 3 + 1 1 / 4 , 𝑟 2 , 7 = 2 + 1 + 2 2 1 2 1 / 2 , 𝑟 2 , 8 = 2 3 / 1 6 1 + 2 1 / 4 , 𝑟 2 , 9 = 2 + 3 1 / 3 , 𝑟 2 , 1 0 = 1 2 1 + 5 5 + 1 + 2 1 / 4 , 𝑟 2 , 1 2 = 1 + 2 5 / 2 4 2 1 + 2 + 6 1 / 8 , 𝑟 2 , 1 6 = 2 1 / 8 1 + 2 1 / 4 4 + 2 + 1 0 2 1 / 8 , 𝑟 2 , 1 8 = 1 + 3 1 / 3 1 + 3 + 2 3 3 / 4 1 / 3 2 1 1 / 2 4 , 𝑟 2 , 2 0 = 1 + 5 5 / 8 2 + 3 2 + 5 1 / 8 2 , 𝑟 2 , 2 7 = 1 + 2 5 / 1 8 2 + 2 1 + 2 1 / 3 + 1 + 2 2 / 3 1 / 3 , 𝑟 2 , 3 2 = 2 3 / 1 6 1 + 2 1 / 4 1 6 + 1 5 2 1 / 4 + 1 2 2 + 9 2 3 / 4 1 / 8 , 𝑟 2 , 3 6 = 2 1 + 3 5 2 2 8 3 1 / 8 3 2 2 / 3 , 𝑟 2 , 4 9 = 1 + 7 + 2 1 4 2 2 + 1 4 + 7 + 2 1 4 2 , 𝑟 2 , 5 0 = 2 5 / 8 5 1 / 4 , 𝑟 1 2 , 7 2 = 2 + 3 1 / 3 2 + 4 + 2 3 + 3 3 / 4 3 + 1 1 / 3 2 1 3 / 4 8 2 1 5 / 1 2 , 𝑟 2 , 3 / 2 = 1 + 3 1 / 4 2 7 / 2 4 , 𝑟 2 , 5 / 2 = 5 + 1 + 2 1 / 4 2 1 / 4 , 𝑟 2 , 7 / 2 = 3 + 7 1 / 4 2 3 / 8 , 𝑟 2 , 9 / 2 = 1 + 3 + 2 3 3 / 4 1 / 3 2 1 3 / 2 4 , 𝑟 2 , 2 5 / 2 = 5 1 / 4 + 1 2 5 / 8 , 𝑟 2 , 2 7 / 2 = 1 + 3 1 / 1 2 1 3 + 2 2 / 3 3 1 / 3 2 3 / 8 2 1 / 3 1 1 / 3 , 𝑟 2 , 6 3 / 2 = 7 2 3 + 2 1 + 3 + 3 3 + 1 6 2 1 2 7 7 1 / 3 2 1 3 / 2 4 3 1 2 / 3 3 7 1 / 1 2 , 𝑟 2 , 9 / 4 = 1 + 3 5 2 + 2 8 3 1 / 8 2 1 / 8 2 + 3 1 / 3 , 𝑟 2 , 9 / 8 = 2 5 / 4 8 2 1 5 / 1 2 3 1 1 / 3 3 2 1 / 3 1 2 + 3 + 3 3 / 4 2 6 1 / 3 , 𝑟 3 , 3 = 3 1 / 1 2 3 + 2 3 1 / 1 2 = 3 1 / 8 1 + 3 1 / 6 2 1 / 1 2 , 𝑟 3 , 4 = 3 + 1 2 , 𝑟 3 , 5 = 5 + 1 2 5 / 6 = 1 1 + 5 5 2 1 / 6 , 𝑟 3 , 7 = 3 + 7 2 2 3 1 / 4 , 𝑟 3 , 8 = 2 + 1 1 / 3 2 + 3 1 / 4 , 𝑟 3 , 9 = 3 1 / 6 1 + 2 1 / 3 + 2 2 / 3 1 / 3 = 3 1 / 6 2 1 / 3 1 1 / 3 , 𝑟 3 , 1 8 = 3 1 / 6 1 + 2 5 / 1 8 2 + 2 1 + 2 1 / 3 + 1 + 2 2 / 3 1 / 3 , 𝑟 3 , 2 5 = 1 2 1 + 3 1 0 + 5 + 2 3 1 0 + 3 1 0 2 , 𝑟 3 , 4 9 = 3 + 3 2 2 3 7 + 3 2 3 7 2 + 4 9 + 1 3 3 2 2 3 7 + 8 3 2 3 7 2 2 3 , 𝑟 4 , 4 = 2 5 / 1 6 1 + 2 1 / 4 , 𝑟 4 , 5 = 1 + 5 + 2 + 1 + 5 2 1 / 2 , 𝑟 4 , 8 = 2 1 / 4 1 + 2 3 / 8 4 + 2 + 1 0 2 1 / 8 , 𝑟 4 , 9 = 1 2 1 + 2 4 3 + 3 , 𝑟 4 , 7 = 8 + 3 7 1 / 4 , 𝑟 4 , 9 = 1 2 + 3 1 / 4 2 + 3 2 , 𝑟 4 , 2 5 = 1 2 3 + 4 5 + 5 + 4 5 3 = 4 5 + 1 4 , 𝑟 5 1 4 , 4 9 = 1 4 4 + 7 + 2 1 + 8 7 + 7 + 2 1 + 8 7 2 , 𝑟 5 , 5 = 2 5 + 1 0 5 1 / 6 = 5 + 5 2 , 𝑟 6 , 6 = 3 1 / 8 3 + 1 1 + 3 + 2 3 3 / 4 1 / 3 2 1 3 / 2 4 . ( 2 . 1 ) For values of 𝑟 4 , 7 , 𝑟 4 , 9 , and 𝑟 4 , 4 9 see [18]. For remaining values we refer to [11] or [17].
We also note that 𝑟 𝑘 , 1 = 1 , 𝑟 𝑘 , 1 / 𝑛 = 1 𝑟 𝑘 , 𝑛 , 𝑟 𝑘 , 𝑛 = 𝑟 𝑛 , 𝑘 . ( 2 . 2 )

Lemma 2.2. One has ( i ) 1 , 1 = 1 , ( i i ) 2 , 2 = 2 2 2 , ( i i i ) 3 , 3 = 2 3 3 1 / 4 = 3 1 / 8 3 1 2 1 / 4 , ( i v ) 4 , 4 = 2 3 / 4 4 , 2 + 1 ( v ) 5 , 5 = 5 2 ( 5 , v i ) 6 , 6 = 2 3 / 4 3 1 / 8 2 1 3 1 1 / 6 4 + 3 2 + 3 5 / 4 + 2 3 3 3 / 4 + 2 2 3 3 / 4 1 / 3 . ( 2 . 3 )

We refer to [19, page 19, Theorem 5.4] or [11, page 150, Theorem 9.2.4] for proofs of the above assertions.

Lemma 2.3. One has ( i ) 1 , 1 = 1 , ( i i ) 2 , 2 = 2 1 / 1 6 2 1 1 / 4 , ( i i i ) 3 , 3 = 2 1 / 3 3 1 / 8 3 1 1 / 6 1 + 3 + 2 4 3 3 1 / 3 , ( i v ) 4 , 4 = 2 1 / 4 1 6 + 1 5 4 2 + 1 2 2 + 9 4 2 3 1 / 8 , ( v ) 5 , 5 = 1 2 4 5 1 5 + 5 , ( v i ) 6 , 6 = 2 1 / 4 3 1 / 8 2 1 1 / 1 2 3 + 1 1 / 6 1 3 + 2 3 3 / 4 1 / 3 2 3 2 + 3 5 / 4 + 3 3 / 4 1 / 3 , ( v i i ) 3 , 1 = 2 1 / 4 3 1 . ( 2 . 4 )

For proofs (i)–(vi), see [19, page 21, Theorem 5.6] or [11, page 152, Theorem 9.2.6]. For proof of (vii), see [19, page 15, Theorem 4.11] or [11, page 145, Theorems 9.1.10].

Lemma 2.4. One has ( i ) 𝑔 1 , 1 = 1 , ( i i ) 𝑔 2 , 2 = 2 3 / 8 , ( i i i ) 𝑔 3 , 3 = 3 1 / 3 1 + 3 + 2 3 3 / 4 1 / 3 1 + 3 1 / 6 2 , ( i v ) 𝑔 4 , 4 = 2 3 / 8 1 + 2 1 / 2 , ( v ) 𝑔 5 , 5 = 5 + 5 1 / 2 5 1 / 4 + 1 2 , ( v i ) 𝑔 6 , 6 = 3 1 / 8 1 + 3 5 / 6 1 + 3 + 2 3 3 / 4 2 / 3 2 2 9 / 2 4 , ( v i i ) 𝑔 9 , 9 = 𝑎 + ( 2 ( 𝑏 2 𝑐 ) ) 1 / 3 + ( 2 ( 𝑏 + 2 𝑐 ) ) 1 / 3 2 , ( 2 . 5 ) where 𝑎 = 2 + 2 3 1 / 4 + 2 3 + 2 3 3 / 4 , 𝑏 = 8 2 + 4 5 2 + 4 8 3 + 2 5 2 3 3 / 4 , 𝑐 = 3 8 8 + 4 7 2 3 1 / 4 + 5 0 3 + 2 7 2 3 3 / 4 . ( 2 . 6 )

For proofs we refer to [17, page 1781, Theorem 6.7].

3. Theorems on Explicit Evaluation of 𝑎 ( 𝑞 ) , 𝑏 ( 𝑞 ) , and 𝑐 ( 𝑞 )

In this section, we present some general formulas for the explicit evaluations of cubic theta-functions and their quotients by parameterizations given in Section 1. In the process, we also establish some transformation formulas of quotients of cubic theta-functions.

Theorem 3.1. For any positive real number 𝑛 , one has 𝑏 𝑒 2 𝜋 𝑛 / 3 𝑐 𝑒 2 𝜋 𝑛 / 3 = 𝑟 4 3 , 𝑛 = 𝜇 𝑛 2 / 3 , ( 3 . 1 ) where 𝑟 𝑘 , 𝑛 and 𝜇 𝑛 are as defined in (1.16) and (1.19), respectively.

Proof. Using the definitions of 𝑏 ( 𝑞 ) and 𝑐 ( 𝑞 ) from (1.7), one has 3 𝑏 ( 𝑞 ) 𝑐 = ( 𝑞 ) 𝑓 ( 𝑞 ) 𝑞 1 / 1 2 𝑓 𝑞 3 4 . ( 3 . 2 ) Setting 𝑞 = 𝑒 2 𝜋 𝑛 / 3 and then employing the definitions of 𝑟 𝑘 , 𝑛 and 𝜇 𝑛 , we finish the proof.

Remark 3.2. Replacing 𝑛 by 1 / 𝑛 in Theorem 3.1 and noting that 𝑟 3 , 1 / 𝑛 = 1 / 𝑟 3 , 𝑛 from (2.2), we also have 𝑏 𝑒 2 𝜋 𝑛 / 3 𝑐 𝑒 2 𝜋 𝑛 / 3 = 𝑐 𝑒 2 𝜋 / 3 𝑛 𝑏 𝑒 2 𝜋 / 3 𝑛 . ( 3 . 3 ) Thus, if we know the value of one quotient of (3.3), then the other quotient follows readily.

From Theorem 3.1 and (1.6), the following theorem is apparent.

Theorem 3.3. One has 𝑎 𝑒 2 𝜋 𝑛 / 3 𝑐 𝑒 2 𝜋 𝑛 / 3 = 𝑟 1 2 3 , 𝑛 + 1 1 / 3 . ( 3 . 4 )

Theorem 3.4. For any positive real number 𝑛 , one has 𝑏 𝑒 2 𝜋 𝑛 𝑐 𝑒 2 𝜋 𝑛 / 3 = 𝑟 9 , 𝑛 3 . ( 3 . 5 )

Proof. From the definitions 𝑏 ( 𝑞 ) and 𝑐 ( 𝑞 ) in (1.7), we observe that 𝑏 𝑞 3 = 𝑐 ( 𝑞 ) 𝑓 ( 𝑞 ) 3 𝑞 1 / 3 𝑓 𝑞 9 . ( 3 . 6 ) Setting 𝑞 = 𝑒 2 𝜋 𝑛 / 3 in (3.6) and then employing the definition of 𝑟 𝑘 , 𝑛 , we arrive at the desired result.

Remark 3.5. Noting that 𝑟 9 , 1 / 𝑛 = 1 / 𝑟 9 , 𝑛 from (2.2) and using Theorem 3.4, we find that 𝑒 3 𝑏 2 𝜋 𝑛 𝑐 𝑒 2 𝜋 𝑛 / 3 = 𝑐 𝑒 2 𝜋 / 3 𝑛 𝑏 𝑒 2 𝜋 / 𝑛 . ( 3 . 7 ) Now, from (3.7), it is obvious that if we know the value of one quotient then the other quotient can easily be evaluated.

In the next theorem, we give a relation between 𝑐 ( 𝑞 ) and the parameter 𝑘 , 𝑛 as defined in (1.21).

Theorem 3.6. For any positive real number 𝑛 , one has 𝑐 𝑒 8 𝜋 𝑛 / 3 𝑐 𝑒 2 𝜋 𝑛 / 3 = 1 4 1 3 3 , 𝑛 2 . ( 3 . 8 )

Proof. From [10, page 111, Lemma 5.5], we note that 𝑐 𝑞 1 4 4 𝑐 = ( 𝑞 ) 𝜙 ( 𝑞 ) 𝜙 𝑞 3 2 . ( 3 . 9 ) Now applying the definition of 𝑘 , 𝑛 , with 𝑘 = 3 , in (3.9), we complete the proof.

The next theorem connects 𝑎 ( 𝑞 ) with the parameter 𝑟 𝑘 , 𝑛 defined in (1.16).

Theorem 3.7. For any positive real number 𝑛 , one has 𝑎 1 2 𝑒 2 𝜋 𝑛 / 3 = 𝑟 2 7 1 2 3 , 𝑛 + 1 4 𝑒 2 𝜋 𝑛 / 3 𝑓 2 4 𝑒 2 𝜋 𝑛 / 3 𝑟 3 6 3 , 𝑛 . ( 3 . 1 0 )

Proof. From [20, page 196, ( 2 . 9 ) ], we note that 2 7 𝑞 𝑓 2 4 ( 𝑞 ) = 𝑎 1 2 ( 𝑞 ) ( 1 𝛼 ( 𝑞 ) ) 3 𝛼 ( 𝑞 ) , ( 3 . 1 1 ) where 𝛼 ( 𝑞 ) = 𝑐 3 ( 𝑞 ) / 𝑎 3 ( 𝑞 ) .
Setting 𝑞 = 𝑒 2 𝜋 𝑛 / 3 and then applying (3.3) in (3.11), we obtain 2 7 𝑒 2 𝜋 𝑛 / 3 𝑓 2 4 𝑒 2 𝜋 𝑛 / 3 = 𝑎 1 2 𝑒 2 𝜋 𝑛 / 3 1 1 𝑟 1 2 3 , 𝑛 + 1 3 1 𝑟 1 2 3 , 𝑛 , + 1 ( 3 . 1 2 ) which on simplification gives the required result.

Theorem 3.8. One has 𝑎 𝑒 3 𝑛 𝜋 = 1 3 { 𝑎 ( 𝑒 𝑛 𝜋 ) + 2 𝑏 ( 𝑒 𝑛 𝜋 ) } . ( 3 . 1 3 )

Proof. From [7, page 93, (2.8)], one has 1 𝑏 ( 𝑞 ) = 2 𝑞 3 𝑎 3 . 𝑎 ( 𝑞 ) ( 3 . 1 4 ) Setting 𝑞 = 𝑒 𝑛 𝜋 in (3.14), we readily complete the proof.

Theorem 3.9. For any positive real number 𝑛 , one has ( i ) 𝑏 ( 𝑒 𝑛 𝜋 𝑓 ) = 3 ( 𝑒 𝑛 𝜋 ) 𝑓 𝑒 3 𝑛 𝜋 , ( i i ) 𝑏 ( 𝑒 𝑛 𝜋 𝑓 ) = 3 ( 𝑒 𝑛 𝜋 ) 𝑓 𝑒 3 𝑛 𝜋 . ( 3 . 1 5 )

Proof. Setting 𝑞 = 𝑒 𝑛 𝜋 and 𝑞 = 𝑒 𝑛 𝜋 in (1.7), we readily arrive at (i) and (ii), respectively.

Theorem 3.10. For all positive real numbers 𝑛 , one has 𝑒 ( i ) 𝑏 2 𝜋 𝑛 / 3 = 3 1 / 4 𝑒 𝜋 𝑛 / 6 3 𝑓 2 𝑒 2 𝜋 𝑛 / 3 𝑟 3 , 𝑛 , ( i i ) 𝑏 𝑒 𝜋 𝑛 / 3 = 3 1 / 4 𝑒 𝜋 𝑛 / 1 2 3 𝑓 2 𝑒 𝜋 𝑛 / 3 𝑟 3 , 𝑛 , ( 3 . 1 6 ) where the parameters 𝑟 3 , 𝑛 and 𝑟 3 , 𝑛 are defined in (1.16) and (1.17), respectively.

Proof. We rewrite 𝑏 ( 𝑞 ) in (1.7) as 𝑏 ( 𝑞 ) = 𝑓 2 ( 𝑞 ) 𝑞 1 / 1 2 𝑓 ( 𝑞 ) 𝑞 1 / 1 2 𝑓 𝑞 3 . ( 3 . 1 7 ) Setting 𝑞 = 𝑒 2 𝜋 𝑛 / 3 and employing the definition of 𝑟 3 , 𝑛 , we arrive at (i). To prove (ii), we replace 𝑞 by 𝑞 in (3.17) and then use the definition of 𝑟 3 , 𝑛 .

Theorem 3.11. For all positive real number 𝑛 , we have ( i ) 𝑐 ( 𝑒 𝑛 𝜋 ) = 3 𝑒 𝑛 𝜋 / 3 𝑓 3 𝑒 3 𝑛 𝜋 𝑓 ( 𝑒 𝑛 𝜋 ) , ( i i ) 𝑐 ( 𝑒 𝑛 𝜋 ) = 3 𝑒 𝑛 𝜋 / 3 𝑓 3 𝑒 3 𝑛 𝜋 𝑓 ( 𝑒 𝑛 𝜋 ) . ( 3 . 1 8 )

Proof. It follows readily from (1.7) with 𝑞 = 𝑒 𝑛 𝜋 and 𝑞 = 𝑒 𝑛 𝜋 .

Theorem 3.12. For all positive real number 𝑛 , one has 𝑐 𝑒 2 𝜋 𝑛 / 3 = 3 3 / 4 𝑒 𝜋 𝑛 / 2 3 𝑓 2 𝑒 2 𝜋 3 𝑛 𝑟 3 , 𝑛 . ( 3 . 1 9 )

Proof. We set 𝑞 = 𝑒 2 𝜋 𝑛 / 3 in (1.7) and then employ the definition of the parameter 𝑟 𝑘 , 𝑛 to finish the proof.

4. Explicit Values of 𝑎 ( 𝑞 ) , 𝑏 ( 𝑞 ) , and 𝑐 ( 𝑞 )

In this section, we find explicit values of cubic theta-functions and their quotients by using the results established in the previous section.

Theorem 4.1. One has 𝑏 𝑒 ( i ) 2 𝜋 / 3 𝑐 𝑒 2 𝜋 / 3 𝑏 𝑒 = 1 , ( i i ) 2 𝜋 2 / 3 𝑐 𝑒 2 𝜋 2 / 3 = 1 + 2 2 / 3 , 𝑏 𝑒 ( i i i ) 2 𝜋 𝑐 𝑒 2 𝜋 = 3 1 / 2 1 + 3 2 / 3 2 1 / 3 , 𝑏 𝑒 ( i v ) 4 𝜋 / 3 𝑐 𝑒 4 𝜋 / 3 = 1 + 3 2 2 , 𝑏 𝑒 ( v ) 2 𝜋 5 / 3 𝑐 𝑒 2 𝜋 5 / 3 = 1 + 5 2 1 0 / 3 , 𝑏 𝑒 ( v i ) 2 𝜋 7 / 3 𝑐 𝑒 2 𝜋 7 / 3 = 3 + 7 2 2 3 , 𝑏 𝑒 ( v i i ) 4 𝜋 2 / 3 𝑐 𝑒 4 𝜋 2 / 3 = 1 + 2 4 / 3 2 + 3 , 𝑏 𝑒 ( v i i i ) 2 𝜋 3 𝑐 𝑒 2 𝜋 3 = 3 2 / 3 2 1 / 3 1 4 / 3 , ( 𝑏 𝑒 i x ) 6 𝜋 2 / 3 𝑐 𝑒 6 𝜋 2 / 3 = 3 2 / 3 1 + 2 1 0 / 9 2 + 2 1 + 2 1 / 3 + 1 + 2 2 / 3 4 / 3 , 𝑏 𝑒 ( x ) 2 𝜋 1 3 / 3 𝑐 𝑒 2 𝜋 1 3 / 3 = 1 1 + 1 3 + 3 + 1 3 2 2 4 , 𝑏 𝑒 ( x i ) 1 0 𝜋 / 3 𝑐 𝑒 1 0 𝜋 / 3 = 1 1 6 1 + 3 1 0 + 5 + 2 3 1 0 + 3 1 0 2 4 , 𝑏 𝑒 ( x i ) 1 4 𝜋 / 3 𝑐 𝑒 1 4 𝜋 / 3 = 3 + 3 2 2 3 7 + 3 2 3 7 2 + 4 9 + 1 3 3 2 2 3 7 + 8 3 2 3 7 2 2 3 4 . ( 4 . 1 )

Proof. It follows directly from Theorem 3.1 and the corresponding values of 𝑟 3 , 𝑛 listed in Lemma 2.1.

More values can be calculated by employing Theorem 3.1 and the corresponding values of 𝜇 𝑛 evaluated in [15, 16].

Theorem 4.2. One has 𝑎 𝑒 ( i ) 2 𝜋 / 3 𝑐 𝑒 2 𝜋 / 3 = 3 𝑎 𝑒 2 , ( i i ) 2 𝜋 2 / 3 𝑐 𝑒 2 𝜋 2 / 3 = 2 1 / 3 2 + 2 1 / 3 , 𝑎 𝑒 ( i i i ) 2 𝜋 𝑐 𝑒 2 𝜋 = 3 3 / 2 1 + 3 2 2 + 1 1 / 3 , 𝑎 𝑒 ( i v ) 4 𝜋 / 3 𝑐 𝑒 4 𝜋 / 3 = 1 + 3 2 6 + 1 1 / 3 , 𝑎 𝑒 ( v ) 2 𝜋 5 / 3 𝑐 𝑒 2 𝜋 5 / 3 = 1 + 5 2 1 0 + 1 1 / 3 , 𝑎 𝑒 ( v i ) 2 𝜋 7 / 3 𝑐 𝑒 2 𝜋 7 / 3 = 3 + 7 2 2 3 3 + 1 1 / 3 , 𝑎 𝑒 ( v i i ) 4 𝜋 2 / 3 𝑐 𝑒 4 𝜋 2 / 3 = 1 + 2 4 2 + 3 4 + 1 1 / 3 , 𝑎 𝑒 ( v i i i ) 1 0 𝜋 / 3 𝑐 𝑒 1 0 𝜋 / 3 = 1 + 3 1 6 + 5 + 2 3 1 0 + 3 1 0 2 2 1 2 + 1 1 / 3 , 𝑎 𝑒 ( i x ) 6 𝜋 / 3 𝑐 𝑒 6 𝜋 / 3 = 9 2 1 / 4 1 4 + 1 1 / 3 , 𝑎 𝑒 ( x ) 1 4 𝜋 / 3 𝑐 𝑒 1 4 𝜋 / 3 = 3 + 3 2 3 7 + 3 2 3 7 2 + 4 9 + 1 3 3 2 3 7 + 8 3 2 3 7 2 2 3 + 1 1 / 3 , 𝑎 𝑒 ( x i ) 6 𝜋 𝑐 𝑒 6 𝜋 = 3 4 1 + 2 1 0 / 3 2 + 2 1 + 2 4 + 1 + 2 8 + 1 1 / 3 . ( 4 . 2 )

Proof. It follows easily from (3.3) and the corresponding values of 𝑟 3 , 𝑛 listed in Lemma 2.1.

Theorem 4.3. One has 𝑏 𝑒 ( i ) 2 𝜋 𝑐 𝑒 2 𝜋 / 3 = 1 3 , 𝑏 𝑒 ( i i ) 2 𝜋 2 𝑐 𝑒 2 𝜋 2 / 3 = 3 + 2 1 / 3 3 , 𝑏 𝑒 ( i i i ) 2 𝜋 3 𝑐 𝑒 2 𝜋 / 3 = 1 3 3 2 1 1 / 3 , 𝑏 𝑒 ( i v ) 4 𝜋 𝑐 𝑒 4 𝜋 / 3 = 1 2 3 1 + 2 3 1 / 4 + 3 , 𝑏 𝑒 ( v ) 2 5 𝜋 𝑐 𝑒 2 5 𝜋 / 3 = 1 3 1 0 4 + 6 0 3 + 4 5 5 + 2 6 1 5 1 / 6 . ( 4 . 3 )

Proof. It follows from Theorem 3.4 and the corresponding values of 𝑟 9 , 𝑛 in listed in Lemma 2.1.

Theorem 4.4. One has 𝑐 𝑒 ( i ) 8 𝜋 / 3 𝑐 𝑒 2 𝜋 / 3 = 1 4 2 + 3 3 2 , 𝑐 𝑒 ( i i ) 8 𝜋 𝑐 𝑒 2 𝜋 = 1 4 1 3 2 2 / 3 3 1 / 4 3 1 1 / 3 1 + 3 + 2 4 3 3 2 / 3 . ( 4 . 4 )

Proof. We set 𝑛 = 1 and 3 in Theorem 3.6 and then employ the values of 3 , 1 and 3 , 3 from Lemma 2.3(vii) and (iii), respectively, to finish the proof.

For the remaining part of this paper, we set 𝑎 = 𝜙 ( 𝑒 𝜋 ) = 𝜋 1 / 4 / Γ ( 3 / 4 ) .

Lemma 4.5. One has ( i ) 𝑓 ( 𝑒 𝜋 ) = 𝑎 2 3 / 8 𝑒 𝜋 / 2 4 , ( i i ) 𝑓 ( 𝑒 𝜋 ) = 𝑎 2 1 / 4 𝑒 𝜋 / 2 4 , ( i i i ) 𝑓 𝑒 2 𝜋 = 𝑎 2 1 / 2 𝑒 𝜋 / 1 2 , ( i v ) 𝑓 𝑒 3 𝜋 = 𝑎 𝑒 𝜋 / 4 1 + 3 + 2 3 3 / 4 1 / 3 3 3 / 8 2 1 7 / 2 4 1 + 3 1 / 6 , ( v ) 𝑓 𝑒 4 𝜋 = 𝑎 2 7 / 8 𝑒 𝜋 / 6 , ( v i ) 𝑓 𝑒 6 𝜋 = 𝑎 2 7 / 1 2 3 3 / 8 𝑒 𝜋 / 4 3 1 1 / 4 , ( v i i ) 𝑓 𝑒 1 2 𝜋 = 𝑎 𝑒 𝜋 / 2 2 5 / 2 4 3 3 / 8 1 + 3 1 + 3 + 2 3 3 / 4 1 / 3 , ( v i i i ) 𝑓 𝑒 𝜋 / 3 = 𝑎 2 7 / 2 4 3 1 / 8 𝑒 𝜋 / 7 2 1 + 3 1 + 3 + 2 3 3 / 4 1 / 3 , ( i x ) 𝑓 𝑒 2 𝜋 / 3 = 𝑎 2 7 / 1 2 3 1 / 8 𝑒 𝜋 / 3 6 3 1 1 / 6 , 𝑒 ( x ) 𝑓 2 𝜋 = 𝑎 2 1 3 / 1 6 𝑒 𝜋 / 1 2 2 + 1 1 / 4 , 𝑒 ( x i ) 𝑓 3 𝜋 = 𝑎 2 1 / 3 3 3 / 8 𝑒 𝜋 / 8 3 + 1 1 / 6 , 𝑒 ( x i i ) 𝑓 6 𝜋 = 𝑎 𝑒 𝜋 / 4 2 3 2 + 3 5 / 4 + 3 3 / 4 1 / 3 2 1 5 / 1 6 3 3 / 8 2 1 1 / 1 2 3 + 1 1 / 6 . ( 4 . 5 )

For a proof of the lemma, we refer to [7, page 326, Entry 6] and [11, page 125–129].

Theorem 4.6. One has ( i ) 𝑏 ( 𝑒 𝜋 𝑎 ) = 2 3 3 / 8 1 + 3 1 / 6 2 5 / 1 2 1 + 3 + 2 3 3 / 4 1 / 3 , 𝑒 ( i i ) 𝑏 2 𝜋 = 𝑎 2 3 3 / 8 2 1 1 / 1 2 3 1 1 / 6 , 𝑒 ( i i i ) 𝑏 4 𝜋 = 𝑎 2 2 2 9 / 1 2 3 3 / 8 1 + 3 1 / 2 1 + 3 + 2 3 3 / 4 1 / 3 , 𝑒 ( i v ) 𝑏 𝜋 / 3 = 𝑎 2 2 5 / 4 3 3 / 8 1 + 3 3 / 2 1 + 3 + 2 3 3 / 4 , 𝑒 ( v ) 𝑏 2 𝜋 / 3 = 𝑎 2 3 1 / 8 3 1 1 / 3 2 1 3 / 1 2 3 + 1 1 / 6 , ( v i ) 𝑏 ( 𝑒 𝜋 𝑎 ) = 2 3 3 / 8 2 5 / 1 2 3 + 1 1 / 6 , ( v i i ) 𝑏 𝑒 2 𝜋 = 𝑎 2 3 3 / 8 2 + 1 3 / 4 2 1 1 / 1 2 3 + 1 1 / 6 2 3 / 2 2 3 2 + 3 5 / 4 + 3 3 / 4 1 / 3 . ( 4 . 6 )

Proof. To prove (i)–(v), we set 𝑛 = 1 , 2, 4, 1/3, and 2/3, respectively, in Theorem 3.9(i) and use the corresponding values of 𝑓 ( ± 𝑒 𝜋 𝑛 ) from Lemma 4.5.
To prove (vi) and (vii), we set 𝑛 = 1 and 2, respectively, in Theorem 3.9(ii) and then use the corresponding values 𝑓 ( ± 𝑒 𝜋 𝑛 ) from Lemma 4.5.

Theorem 4.7. One has 𝑒 ( i ) 𝑐 4 𝜋 / 3 = 𝑎 2 3 7 / 8 1 + 3 1 / 6 2 1 7 / 1 2 1 + 3 + 2 3 3 / 4 1 / 3 , 𝑒 ( i i ) 𝑐 2 𝜋 / 3 = 𝑎 2 2 1 3 / 1 2 3 7 / 8 3 + 1 1 / 6 , ( 𝑒 i i i ) 𝑐 𝜋 / 3 = 2 1 7 / 1 2 3 7 / 8 𝑎 2 1 + 3 1 / 2 1 + 3 + 2 3 3 / 4 1 / 3 , 𝑒 ( i v ) 𝑐 4 𝜋 = 𝑎 2 3 3 / 8 2 1 / 4 1 + 3 3 / 2 1 + 3 + 2 3 3 / 4 , 𝑒 ( v ) 𝑐 2 𝜋 = 𝑎 2 3 1 1 / 3 3 3 / 8 2 1 3 / 1 2 3 + 1 1 / 6 , ( v i ) 𝑐 ( 𝑒 𝜋 𝑎 ) = 2 1 + 3 + 2 3 3 / 4 3 1 / 8 2 7 / 4 1 + 3 1 / 2 , 𝑒 ( v i i ) 𝑐 8 𝜋 = 1 4 1 3 2 2 / 3 3 1 / 4 3 1 1 / 3 1 + 3 + 2 + 4 3 2 2 / 3 × 𝑎 2 3 1 1 / 3 3 3 / 8 2 1 3 / 1 2 3 + 1 1 / 6 . ( 4 . 7 )

Proof. To prove (i)–(v), we set 𝑡 = 1 / 2 , 1 , 2 , 1 / 6 , and 1/3, respectively, in (1.9) and then apply the corresponding values of 𝑏 ( 𝑒 𝑛 𝜋 ) from Theorem 4.6.
To prove (vi), we set 𝑛 = 1 in Theorem 3.11 and use the corresponding values of 𝑓 ( 𝑒 𝑛 𝜋 ) from Lemma 4.5. At last, (vii) follows from Theorems 4.7(v) and 4.4(ii).

Remark 4.8. Setting 𝑡 = 1 / 2 in (1.10) and then employing the value of 𝑐 ( 𝑒 𝜋 ) from Theorem 4.7(vi), we can also evaluate 𝑏 ( 𝑒 4 𝜋 / 3 ) .

Theorem 4.9. One has 𝑒 ( i ) 𝑎 2 𝜋 = 𝑎 2 1 0 + 6 3 1 / 3 2 3 + 2 3 1 / 4 , 𝑒 ( i i ) 𝑎 2 𝜋 / 3 = 𝑎 2 3 1 0 + 6 3 1 / 3 2 3 + 2 3 1 / 4 , 𝑒 ( i i i ) 𝑎 6 𝜋 = 𝑎 2 3 3 1 / 4 1 + 2 1 / 6 + 1 0 + 6 3 1 / 3 2 3 + 2 3 1 / 4 , ( 𝑒 i v ) 𝑎 2 𝜋 / 9 = 3 𝑎 2 3 1 / 4 1 + 2 1 / 6 + 1 0 + 6 3 1 / 3 2 3 + 2 3 1 / 4 . ( 4 . 8 )

Proof. To prove (i), we set 𝑛 = 3 in Theorem 3.7 and use 𝑓 ( 𝑒 2 𝜋 ) from Lemma 4.5 and the values of 𝑟 3 , 3 from Lemma 2.1.
To prove (ii), we set 𝑡 = 1 in (1.8) and then employ Theorem 4.9(i).
To prove (iii), we set 𝑛 = 2 in Theorem 3.8 and then employ the values of 𝑎 ( 𝑒 2 𝜋 ) and 𝑏 ( 𝑒 2 𝜋 ) from Theorems 4.9(i) and 4.6(ii), respectively.
To prove (iv), we set 𝑡 = 3 in (1.8) and use the value of 𝑎 ( 𝑒 6 𝜋 ) .

5. Theorems on Explicit Evaluations of 𝐴 ( 𝑞 ) , 𝐵 ( 𝑞 ) , and 𝐶 ( 𝑞 )

In this section, we use the parameters 𝑟 𝑘 , 𝑛 , 𝑘 , 𝑛 , and 𝑔 𝑘 , 𝑛 defined in (1.16), (1.20), and (1.23), respectively, to establish some formulas for the explicit evaluations of quartic theta-functions and their quotients.

Theorem 5.1. For any positive real number 𝑛 , one has 𝐵 𝑒 𝜋 2 𝑛 𝐶 𝑒 𝜋 2 𝑛 = 𝑟 1 2 2 , 𝑛 = 𝑔 1 2 2 𝑛 . ( 5 . 1 )

Proof. Employing the definition of 𝐵 ( 𝑞 ) and 𝐶 ( 𝑞 ) given in (1.14), we find that 𝐵 ( 𝑞 ) 𝐶 = ( 𝑞 ) 𝑓 ( 𝑞 ) 2 1 / 4 𝑞 1 / 2 4 𝑓 𝑞 2 1 2 . ( 5 . 2 ) Setting 𝑞 = 𝑒 2 𝜋 𝑛 / 2 in (5.2) and then using the definition of 𝑟 𝑘 , 𝑛 , we arrive at the first equality. Second equality readily follows from (1.24) and (5.2).

Remark 5.2. From Theorem 5.1 and (2.2), we have the following transformation formula: 𝐵 𝑒 𝜋 2 / 𝑛 𝐶 𝑒 𝜋 2 / 𝑛 = 𝐶 𝑒 𝜋 2 𝑛 𝐵 𝑒 𝜋 2 𝑛 . ( 5 . 3 ) Thus, if we know the value of one of the quotient of (5.3), then the other one follows immediately.

Theorem 5.3. One has 𝐵 𝑒 2 𝜋 𝑛 𝐶 𝑒 𝜋 𝑛 = 𝑟 4 4 , 𝑛 2 . ( 5 . 4 )

Proof. Theorem follows easily from (1.14) and the definition of 𝑟 𝑘 , 𝑛 with 𝑘 = 4 .

Remark 5.4. Using the fact that 𝑟 4 , 1 / 𝑛 = 1 / 𝑟 4 , 𝑛 in Theorem 5.3, we have the following transformation formula 𝑒 4 𝐵 2 𝜋 / 𝑛 𝐶 𝑒 𝜋 / 𝑛 = 𝐶 𝑒 𝜋 𝑛 𝐵 𝑒 2 𝜋 𝑛 . ( 5 . 5 ) Hence, if we know one quotient of (5.5) then the other quotient follows immediately.

Lemma 5.5. One has ( i ) 𝜙 𝑒 2 𝑛 𝜋 = 𝑎 2 1 / 8 𝑛 1 / 4 𝑛 , 𝑛 = 𝑎 𝑟 2 , 2 𝑛 2 𝑛 1 / 4 2 1 / 4 𝑟 𝑛 , 𝑛 , ( i i ) 𝜙 ( 𝑒 𝑛 𝜋 𝑎 ) = 𝑛 1 / 4 𝑛 , 𝑛 = 𝑎 𝐺 2 𝑛 2 𝑛 1 / 4 𝑟 𝑛 , 𝑛 , ( i i i ) 𝜓 ( 𝑒 𝑛 𝜋 ) = 𝑎 2 5 / 8 𝑒 𝑛 𝜋 / 8 𝑛 1 / 4 𝑔 𝑛 , 𝑛 = 𝑎 2 3 / 4 𝑒 𝑛 𝜋 / 8 𝑛 1 / 4 𝑟 2 , 𝑛 2 / 2 𝑟 𝑛 , 𝑛 , 𝑒 ( i v ) 𝜓 𝜋 / 𝑛 = 𝑎 𝑛 1 / 4 2 3 / 4 𝑟 2 , 2 𝑛 2 𝑒 𝑛 𝜋 / 8 𝑟 𝑛 , 𝑛 , ( 5 . 6 ) where the parameters 𝑟 𝑘 , 𝑛