Table 3:
Example
4.2
: The maximum absolute errors.
(
h, k
)
Proposed
π
(
π
2
+
β
4
)
method
π
(
π
2
+
β
2
)
method
ξ
1
,
1
2
0
ξ
1
0
0
.
3
9
8
6
πΈ
−03
0
.
1
1
3
3
πΈ
−02
ξ
1
,
1
4
0
ξ
2
0
0
.
1
0
8
9
πΈ
−03
0
.
3
0
0
3
πΈ
−03
ξ
1
,
1
2
0
ξ
4
0
0
.
4
1
1
7
πΈ
−03
0
.
1
1
3
2
πΈ
−02
ξ
1
,
1
8
0
ξ
4
0
0
.
2
8
9
3
πΈ
−04
0
.
7
8
3
6
πΈ
−04
ξ
1
,
1
4
0
ξ
8
0
0
.
1
1
1
6
πΈ
−03
0
.
2
9
8
4
πΈ
−03