Table 1:
Error analysis of first and second order of accuracy difference schemes for Example
3.1
.
Method
𝑁
=
𝑀
=
2
5
𝑁
=
𝑀
=
5
0
𝑁
=
𝑀
=
1
0
0
1st order of accuracy
0.2553
0.1256
0.0622
2nd order of accuracy
0.0062
9
.
7
7
1
×
1
0
−
4
1
.
9
6
3
×
1
0
−
4