Table 2: Comparison of the first eigenvalue and solutions of Example 3.1 using Taylor’s decomposition method, exact values, and Table 4 from [9], when .

HWSM FDM TDM ExactErrors of TDM Errors of TDMErrors of TDM
( )( )( ) ( ) ( ) ( )( ) ( )( ) ( )

0 0 0 0 0 0 0 0
0.0625 0.27521 0.278599 0.275999 0.275899
0.125 0.54181 0.541196 0.541196 0.541196
0.1875 0.78549 0.785695 0.785695 0.785695
0.25 1.00482 1 1 1
0.3125 1.17851 1.17588 1.17588 1.17588
0.375 1.31285 1.30656 1.30656 1.30656
0.4375 1.38376 1.38704 1.38704 1.38704
0.5 1.41103 1.41421 1.41421 1.41421 0
0.5625 1.38376 1.38704 1.38704 1.38704
0.625 1.31285 1.30656 1.30656 1.30656
0.6875 1.17851 1.17588 1.17588 1.17588
0.75 1.00482 1 1 1 2.06E-11
0.8125 0.78549 0.785695 0.785695 0.785695
0.875 0.54181 0.541196 0.541196 0.541196
0.9375 0.27521 0.275899 0.275999 0.275899
1 0 0 0 0 0 0 0

(HWSM), 10.8379 (FDM), 10.8696 (TDM), 10.8696 (Exact).