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`Abstract and Applied AnalysisVolume 2013 (2013), Article ID 181809, 4 pageshttp://dx.doi.org/10.1155/2013/181809`
Research Article

## A Half-Inverse Problem for Impulsive Dirac Operator with Discontinuous Coefficient

Cumhuriyet University, Faculty of Science, Department of Mathematics, 58140 Sivas, Turkey

Received 3 June 2013; Accepted 9 September 2013

Copyright © 2013 Yalçın Güldü. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

#### Abstract

An inverse problem for Dirac differential operators with discontinuity conditions and discontinuous coefficient is studied. It is shown by Hochstadt and Lieberman's method that if the potential function in is prescribed over the interval , then a single spectrum suffices to determine on the interval and it is also shown here that is uniquely determined by a spectrum.

#### 1. Introduction

In this paper, we are concerned with the Dirac operator generated by equation with where ,, subject to the boundary conditions and discontinuity conditions where and are real valued functions in ,   is a spectral parameter, and , .

Inverse problems of spectral analysis implicate the reconstruction of a linear operator from its spectral data (e.g., see [15]). Half inverse problem for a Dirac operator consists in reconstruction of this operator from its spectrum and half of the potential.

The first result on the half-inverse problem is due to Hochstadt and Lieberman [6]. After that, Hald [7] proved that if the potential is known over half of the interval and if one boundary conditions is given, then the potential and the other boundary condition are uniquely determined by the eigenvalues. In [8, 9], Malamud and Gesztesy and Simon obtained some new uniqueness results in inverse spectral analysis with partial information on the potential for scalar and matrix Sturm-Liouville equations, respectively. In 2001, Sakhnovich [10] studied the existence of solution to the half-inverse problem. In [11], necessary and sufficient condition for solvability of the half-inverse spectral problem for Sturm-Liouville operators with singular operator was taken. In [12], by using the Hochstadt and Lieberman's method, half-inverse problem was solved for diffusion operators. In [13], the authors presented half-inverse problem for the Sturm-Liouville equation with eigenparameter-dependent boundary conditions.

On the other hand, the fundamental and detailed results about Dirac operators were given in [14]. Moreover, direct or inverse spectral problems for Dirac operators are largely well studied in [1, 8, 15].

There are also some studies about the interior inverse problems. Arutyunyan [16] proved that the eigenvalues , and normalizing coefficients , uniquely determined the potential . Malamud [8] proved an analog of Borg theorem [17]; he showed that the spectra of two boundary value problems for an operator with different boundary conditions at one end uniquely determined the potential . He also proved an analog of the theorem of Hochstadt and Lieberman [6]; one spectrum and a potential on the interval uniquely determined the potential on the whole interval . On the other hand, in 2001, Del Rio and Grébert [18] proved that in the case where is a priori known on , then only a part (depending on ) of two spectra determined on . Furthermore, inverse problems for interior spectral data of the Sturm-Liouville and Dirac operators were studied in [1922].

The jump conditions like (5) appear in-some important physical problems. The work in [7] is a well-known work about discontinuous inverse eigenvalue problems. Direct and inverse problems for Dirac operators with discontinuities inside the interval were investigated in [23].

In this paper, by using the Hochstadt and Lieberman's method in [6], we discuss the half-inverse problem for Dirac operator with discontinuity conditions and discontinuous coefficients (1)–(5). Furthermore, the potential and discontinuous coefficient are uniquely determined.

#### 2. Statement of Results

Let the function be solution of (1) which satisfies the initial conditions and the jump conditions (5).

It is shown in [14] that, for the solution , the following representation holds: where has the form , , and  are real valued continuous functions for and for each

Next, we define the function

The zeros of which is called the characteristic function of the problem (1)–(5) are the eigenvalues of .

From the equalities (7)–(11), we have where and .

Theorem 1. (i) The problem has denumerable many eigenvalues such that all of them are real and simple.
(ii) The eigenvalues are expressed by the following asymptotic formula: where are the zeros of and ,  .

Proof. (i) Since is entire function, it has denumerable many zeros. Moreover, from [23], zeros of are real and simple.
(ii) It is shown in [24] that . It is obvious that for and .

Therefore, it follows from the Rouche's theorem that the functions and have the same number of zeros inside the contour ; that is, the eigenvalues are given by the following asymptotic formula:

Consider a second operator generated by the differential equation subject to the same boundary conditions (3) and (4) and discontinuity condition (5). Here, with a real valued function .

We denote eigenvalues by and the corresponding eigenfunctions by of the problem and denote eigenvalues by and the corresponding eigenfunctions by of the problem .

Lemma 2. If , then that is, .

Proof. Since , then , = . Letting , then we conclude that . Moreover, since , then . So .

Theorem 3. If , for all and , for , then almost everywhere on .

Proof. Let us write (1) for the solutions and and take into account Lemma 2 as
If we multiply these equalities by and , respectively, and subtract, then we obtain
Integrating the last equality from to with respect to , the equality is obtained where . Applying the initial condition (6) and the assumption ,   in hypothesis, we get
Define where and , depend only on , .
Then we get from the boundary condition (4) that for all .
Now, define is an entire function. Since and for where , then is constant from the Liouville's theorem. Furthermore, from the equalities (7), (9), and (21) and the Riemann-Lebesgue lemma. Thus, on the whole -plane.
It follows from (20) and (21) that for all where . This can be rewritten as
From the completeness of the functions in , we have It follows that ; that is, almost everywhere for .

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