Solving a Class of Singular Fifth-Order Boundary Value Problems Using Reproducing Kernel Hilbert Space Method

Table 2

Comparison of the absolute error of Example 13.

𝑥	Solution			Absolute error
	𝑢𝑇(𝑡,𝑥)	Reference [9]	𝑢100(𝑥)	|𝑢50(𝑥)−𝑢𝑇(𝑥)|	Reference [9]	|𝑢100(𝑥)−𝑢𝑇(𝑥)|
0.0	0.0	0.0	0.0	0.0	0.0	0.0
0.1249	0.0000752	0.0000754	0.0000754	8.11621×10^−7	2×10^−7	2.74983×10^−7
0.2431	0.0013039	0.0013043	0.0013037	3.70493×10^−6	4×10^−7	1.13843×10^−7
0.3806	0.0080242	0.0080249	0.0080244	7.8819×10^−6	7×10^−7	2.32339×10^−7
0.4195	0.0116531	0.0116538	0.0116533	8.85202×10^−6	7×10^−7	2.59035×10^−7
0.5	0.0220970	0.0220978	0.0220972	1.01895×10^−5	8×10^−7	2.94629×10^−7
0.6923	0.0588207	0.0588201	0.0588209	8.5994×10^−6	6×10^−7	2.44068×10^−7
0.7854	0.0723723	0.0723726	0.0723724	5.68292×10^−6	4×10^−7	1.60302×10^−7
0.8917	0.0646361	0.0646363	0.0646366	1.96562×10^−6	2×10^−7	5.51306×10^−7
1.0	0.0	0.0	0.0	0.0	0.0	0.0