Research Article
Solving a Class of Singular Fifth-Order Boundary Value Problems Using Reproducing Kernel Hilbert Space Method
Table 2
Comparison of the absolute error of Example
13.
| | Solution | Absolute error | | Reference [9] | | | Reference [9] | |
| 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.1249 | 0.0000752 | 0.0000754 | 0.0000754 | | | | 0.2431 | 0.0013039 | 0.0013043 | 0.0013037 | | | | 0.3806 | 0.0080242 | 0.0080249 | 0.0080244 | | | | 0.4195 | 0.0116531 | 0.0116538 | 0.0116533 | | | | 0.5 | 0.0220970 | 0.0220978 | 0.0220972 | | | | 0.6923 | 0.0588207 | 0.0588201 | 0.0588209 | | | | 0.7854 | 0.0723723 | 0.0723726 | 0.0723724 | | | | 0.8917 | 0.0646361 | 0.0646363 | 0.0646366 | | | | 1.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 | 0.0 |
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