Abstract

Common coupled fixed point theorems are examined in this paper for comparable mappings ensuring nonlinear contraction in ordered partial metric spaces. Given theorems enlarge and universalize some conclusions of Gnana Bhaskar and Lakshmikantham (2006).

1. Introduction

The contraction method presented the fixed point theory on partially metric spaces. It is enlarged to nonlinear contraction mapping, which is attributed by many authors. (cf. [125]). Particularly a partial metric space is a universalized metric space. Some further generalizations of the conclusions in [16] are demonstrated by Valero [25], Oltra and Valero [18], Shatanawi et al. [23], and Altun and Erduran [5]. Additionally, Caristi type fixed point theorem on a partial metric space was introduced by Romaguera [21].

Existence of fixed points was introduced in ordered metric spaces by Ran and Reurings [19]. Some applications of fixed points are also shown for linear and nonlinear equations. Fixed and common fixed point theorems are searched recently by many authors on this topic. Moreover coupled coincidence and coupled fixed point theorems for two mappings and such that has to be mixed g-monotone property are stated by Lakshmikantham and Ćirić [15].

The authors propose to give more information about couple fixed point theory exists in the theory [125] for the reader.

Let us give some necessarily definitions related to mixed monotone maps and common coupled fixed point of a mapping.

Definition 1. Suppose that () is a partially ordered set and also . Assume that is monotone nondecreasing pursuant and also is monotone nonincreasing according to , for any , at the time the map is named to have mixed monotone property:

Definition 2. If and , then is defined as an a coupled fixed point of a mapping [15].

Definition 3. Suppose that is a nonempty set. A partial metric on is a real function of of ordered pairs of elements of which satisfies the following four conditions: ,,, [16]. A metric space consists of two objects: a set and partial metric on , and also the elements of are called the point of the metric space () (see [16]).

Notice that the span of any point to itself need not be null; so universalizing metrics, namely, a metric on a set , are named to be a partial metric on providing for any . We refer the reader to check some results and related examples on partial metric spaces in the theory [125].

Each partial metric on generates a topology on , which has a base of the family of open p-balls , where

If is a partial metric on , then the function given by is a metric on .

Definition 4. Assume that is a partial metric space and also is a sequence in .

At the time,(i) converges to a point ,(ii)if there exists , then is a Cauchy sequence [5].

Definition 5. A partial metric space is named to be complete if every Cauchy sequence in converges,

in accordance with , to a point , with [5].

Lemma 6. Suppose that is a partial metric space. At the time (i)the sequence is Cauchy sequence in it is a Cauchy sequence in the metric space ,(ii) is complete the metric space is complete. Besides, [16].

Theorem 7. Assume that is a complete partial metric space and also suppose that is a mapping to itself. Then there exists a constant providing for all . So has an individual fixed point [16].

Recently, Gnana Bhaskar and Lakshmikantham [8] obtained the following nice result for possessing the mixed monotone property mapping, which universalizes Theorem 7 of Matthews [16].

Theorem 8. Suppose that is a continuous mapping possessing the mixed monotone property on . There exists a such that If there exist   with then, there exist with

The goal of the paper is to build coupled and common fixed point theorems in partially ordered partial metric spaces with a function providing conditions , nonincreasing, and for each . Offered theorems universalize and enlarge to a pair of mappings which are conclusions of Gnana Bhaskar and Lakshmikantham [8] and some other theorems related to them.

2. Main Result

Definition 9. Assume that () is a partially ordered set and . and mappings have the following properties: if is even, then and ;if is odd, then and .

Theorem 10. Suppose that () is a partially ordered set and is a partial metric on with being a complete partial metric space. Assume that are satisfied by Definition 2 and also are continuous mappings possessing the mixed monotone property on . Let there be a non-increasing function such that , and for all and also having and , with for . If there exists with and , at the time with and .

Proof. Suppose with and . Define sequences and in in the following way: We are to prove that sequence is nondecreasing and sequence is nonincreasing. That is, for all For this, mathematical induction method is used.
Firstly suppose . Having and , because and and as and , so (10) is verified for .
Assume that (10) is satisfied for a constant ; then, because and , from Definition 9 we have Thus we get and .
Hereby, by the induction method we conclude that (10) hold for all . Thereof,
Denote showing sequence is nonincreasing. From (10) and (8) we have Similarly, we can obtain Thus, using properties of function we get Similarly one can show that Then, we obtain
Thus a sequence is nonincreasing. Thence, there is a is obtained with
Now, we claim that we substitute in (14). Then we can get Letting in (22), we get Hence . That is
Now we show that Suppose the contrary. At the time there exists when obtaining two subsequences and of with is the smallest index where This means that By in Definition 3 and (27), we have Similarly, we can obtain that Adding (28) and (29) and also from (27) and (26) we get Taking the limit as in (30) and by (26) we get Employing the triangle inequality, Similarly, we get As in (33) and (32) and from (31) and (26) we can obtain
Since from (12) we have and and also by (8) and (10), Similarly, we get Thus As in (37) we get , which is a contrast. Whence (25) is verified, possessing By (3), we have and are Cauchy sequences in the metric space . Because is complete, it is also the case for , then there exist with On the other hand, we have Getting the limit as in the upward equation and utilizing (40) and (38), we attain in other words, possessing for all . On letting , we achieve Using (42) and (43), we get that Analogously, one can show that exposing , , , and . To do that we prove the following steps.

Step 1. Demonstrate that and .
Since and , we have Letting in (46) we get . The same one can demonstrate that .

Step 2. We show that and .
We have . Since and as in and is continuous as in , then we get That is, Similarly one can show that .

Step 3. Indicating and , we have While in (49) and employing (46) and Steps 1 and 2, we obtain . By in Definition 3, we have . Similarly one can show that , , and .

Theorem 11. Intercalarily to the supposition of Theorem 10 assume that there exist , such that is compared with . Then for is couple common fixed point. To wit, and possess a couple common fixed point and .

Proof. If is comparable to , at the time is comparable to . So if we substitute , , , and in (8), then we obtain Therefore .

Conflict of Interests

The authors declare that there is no conflict of interests regarding the publication of this paper.