Research Article

Advanced Iterative Procedures for Solving the Implicit Colebrook Equation for Fluid Flow Friction

Table 4

Newton–Raphson procedure. Option 4: starting point x0 depends on input parameters: Equation (2), indirect calculation of λ through the transmission factor x: Equation (12), and the symbolic derivative f′(x): Equation (11).

Re = 5·106, ε/D = 2.5·10−5f(x), Equation (8)f′(x), Equation (11)x0 = 10.34052343λ0 = 0.009352225155363

Iteration 10.4950920141.0364950319.8628636258180000.010280019623455
Iteration 2−0.0001773051.0372424719.8630345644333100.010279663295576
Iteration 30.0000000001.037242198x = 9.863034564455800λ = 0.010279663295529
Control step0.0000000001.0372421989.8630345644558000.010279663295529

Re = 3·104, ε/D = 9·10−3f(x), Equation (8)f′(x), Equation (11)x0 = 5.227918429λ0 = 0.036588313752304

Iteration 10.1436322671.0253226915.0878334897504300.038630846139210
Iteration 2−0.0000072631.0254265335.0878405730924000.038630738574793
Iteration 30.0000000001.025426528x = 5.087840573092420λ = 0.038630738574792
Control step0.0000000001.0254265285.0878405730924200.038630738574792