Criteria are established for existence of least one or three positive solutions for boundary value problems of second-order functional dynamic equations on time scales. By this purpose, we use a fixed-point index theorem in cones and Leggett-Williams fixed-point theorem.
1. Introduction
In a recent
paper [1], by applying a fixed-point index theorem in cones,
Jiang and Weng studied the existence of positive solutions for the boundary
value problems described by second-order functional differential equations of
the form Aykut [2] applied a cone fixed-point index theorem in cones
and obtained sufficient conditions for the existence of positive solutions of
the boundary value problems of functional difference equations of the form
In this
article, we are interested in proving the existence and multiplicity of
positive solutions for the boundary value problems of a second-order functional
dynamic equation of the form Throughout this
paper we let be any time
scale (nonempty closed subset of ) and be a subset of such that and for is not right
scattered and left dense at the same time.
Some
preliminary definitions and theorems on time scales can be found in books [3, 4] which are
excellent references for calculus of time scales.
We will assume
that the following conditions are satisfied.
(H1)
(H2)
is continuous
with respect to and for , where denotes the set of nonnegative real numbers.
(H3)
defined on satisfies Let be nonempty
subset of
(H4)
if then ; for , where denotes the
set of all positively regressive and rd-continuous functions.
(H5)
and are defined on and , respectively,
where ; furthermore, ;
There have been
a number of works concerning of at least one and multiple positive solutions
for boundary value problems recent years. Some authors have studied the problem
for ordinary differential equations, while others have studied the problem for
difference equations, while still others have considered the problem for
dynamic equations on a time scale [5–10]. However there are fewer research for the existence
of positive solutions of the boundary value problems of functional differential,
difference, and dynamic equations [1, 2, 11–13].
Our problem is
a dynamic analog of the BVPs (1.1) and (1.2). But it is more general than them. Moreover,
conditions for the existence of at least one positive solution were studied for
the BVPs (1.1) and (1.2). In this paper, we investigate the conditions for the
existence of at least one or three positive solutions for the BVP (1.3). The key tools in our approach are the following
fixed-point index theorem [14], and Leggett-Williams fixed-point theorem [15].
Theorem 1.1 (see [14]). Let be Banach space
and be a cone in . Let , and define . Assume is a completely
continuous operator such that for
(i)
If for , then
(ii)
If for , then
Theorem 1.2 (see [15]). Let be a cone in the real Banach
space . Set Suppose that is a completely continuous
operator and is a
nonnegative continuous concave functional on with for all . If there exists such that the
following conditions hold:
(i)
and for all
(ii)
for
(iii)
for with
Then has at
least three fixed points in satisfying
2. Preliminaries
First, we give
the following definitions of solution and positive solution of BVP (1.3).
Definition 2.1. We say a
function is a solution
of BVP (1.3) if it satisfies
the following.
(1)
is nonnegative
on .
(2)
as , where is defined as
(3)
as , where is defined as
(4)
is -differentiable, is -differentiable
on and is continuous.
(5)
for
Furthermore, a
solution of (1.3) is called a
positive solution if for
Denote by and the solutions of the corresponding homogeneous
equation under the
initial conditions Set Since the
Wronskian of any two solutions of (2.3) is independent
of , evaluating at and using the
initial conditions (2.4) yield Using the
initial conditions (2.4), we can deduce from (2.3) for and , the following equations: (See
[8].)
Lemma 2.2 (see [8]). Under the conditions (H1) and the first
part of (H4) the solutions and possess the
following properties:
Let be the Green
function for the boundary value problem: given by where and are given in (2.7) and (2.8), respectively.
It is obvious from (2.6), (H1) and (H4), that holds.
Lemma 2.3. Assume the
conditions (H1) and (H4) are satisfied.
Then
(i)
for
(ii)
for and
where in which
Proof. for , and , for . Besides, is
nondecreasing and is
nonincreasing, for . Therefore, we have So statement (i) of the lemma is
proved. If for a given then statement (ii) of the lemma is
obvious for such values. Now, and . Consequently, , for all such Let us take any . Then we have for , and we have for ,
Let be endowed with
maximum norm for , and let be a cone
defined by where is as in (2.12).
Suppose that is a solution
of (1.3), then it can be written as where
Throughout this
paper we assume that is the solution
of (1.3) with . Clearly, can be
expressed as follows: where
Let be a solution
of (1.3) and . Noting that for , we have where
Define an
operator as follows: where
It is easy to
derive that is a positive
solution of BVP (1.3) if and only if is a nontrivial
fixed point of , where be defined as
before.
Lemma 2.4.
Proof. For , we have . Moreover, we have from definition of that and , for and , respectively. Thus, where . It follows from the definition and Lemma 2.3 that Thus, .
Lemma 2.5. is completely
continuous.
Lemma 2.6. If for all , then there exist such that , for and , for .
Proof. Choose such that By using the
first equality of (2.27), we can choose such that If , then for , we have Therefore we
get Thus, we have
from Theorem 1.1, , for . On the other hand, the second equality of (2.27) implies for
every , there is an , such that Here we choose satisfying (2.28). For , we have definition of that It follows from (2.32) that This shows that Thus, by
Theorem 1.1, we conclude that for . The proof is therefore complete.
3. Existence of One Positive Solution
In this
section, we investigate the conditions for the existence of at least one
positive solution of the BVP (1.3).
In the next
theorem, we will also assume that the following condition on .
(H6): where is large
enough such that and is small
enough such that where is the
eigenfunction related to the smallest eigenvalue of the
eigenvalue problem:
Theorem 3.1. If (H1)–(H6) are satisfied,
then the BVP (1.3) has at least
one positive solution.
Proof. Fix and let for . Then, satisfies (2.27). Define by
where Then is a completely
continuous operator. One has from Lemma 2.6 that there exist such that Define by then is a completely
continuous operator. By the first equality in (H6) and the
definition of , there are and such that We now prove
that for all and . In fact, if there exists and such that , then satisfies the
equation and the
boundary conditions Multiplying
both sides of (3.10) by , then integrating from to , and using integration by parts in the left-hand side
two times, we obtain Combining (3.9) and (3.12), we get We also have
Equations (3.13) and (3.14) lead to This is
impossible. Thus for and . By (3.7) and the
homotopy invariance of the fixed-point index (see [11]), we get that On the other
hand, according to the second inequality of (H6), there exist and such that We define then it follows
that Define by , then is a completely
continuous operator. We claim that there exists such that In fact, if for some and , then where Combining (3.21) with (3.22), we have Let Then we get Consequently,
by the homotopy invariance of the fixed-point index, we have where is zero
operator. Use (3.16) and (3.25) to conclude
that Hence, has a
fixed point in .
Let . Since for and .
(H7)
Theorem 3.2. If (H1)–(H5) and (H7) are satisfied,
then the BVP (1.3) has at least
one positive solution.
Proof. Define by , then is a completely
continuous operator. By the first inequality in (H7), there exist and such that We claim that for and . In fact, if there exist and such that , then satisfies the
boundary condition (3.11). Since , we have . Then we have Multiplying the
last equation by integrating
from to , by (3.28),
we obtain then we have
Equations (3.30) and (3.31) lead to This is
impossible. By homotopy invariance of the fixed-point index, we get that Define by , then is a completely
continuous operator. By the second inequality in (H7), and definition of , there exist