The definition of homomorphism given in Section 5.2.2 is incorrect. Here is the exact definition. The rest of the discussion is correct.

Let be two LHSs or LBSs. An operator is called a homomorphism if(i)for every , there exists such that both and exist;(ii)for every , there exists such that both and exist.

Equivalently, for every , there exists such that and , and for every , there exists with the same property.

The definition may be rephrased as follows: is a homomorphism if where and , denote the projection on the first, respectively, the second component.

Contrary to what is stated in [1, Definition 3.3.4], the condition (1), which is the correct one, does not imply and .

We denote by the set of all homomorphisms from into . The following property is easy to prove:

Let . Then, implies .