Table 2: Result of the Van der Pol problem (2).

𝜇 = 1 0 4 𝜇 = 1 0 6 𝜇 = 1 0 8
Explicit Implicit Explicit Implicit Explicit Implicit
max. errormax. errormax. errormax. errormax. errormax. error

0.01 1.15 𝐸 0 5 1.10 𝐸 0 5 6.22 𝐸 0 7 1.10 𝐸 0 7 5.13 𝐸 0 7 1.10 𝐸 0 9
0.005 1.10 𝐸 0 5 1.10 𝐸 0 5 1.72 𝐸 0 7 1.10 𝐸 0 7 6.48 𝐸 0 8 1.10 𝐸 0 9
0.0025 1.10 𝐸 0 5 1.10 𝐸 0 5 1.17 𝐸 0 7 1.10 𝐸 0 7 8.90 𝐸 0 9 1.10 𝐸 0 9
0.001 1.10 𝐸 0 5 1.10 𝐸 0 5 1.10 𝐸 0 7 1.10 𝐸 0 7 1.59 𝐸 0 9 1.10 𝐸 0 9
0.0005 1.10 𝐸 0 5 1.10 𝐸 0 5 1.10 𝐸 0 7 1.10 𝐸 0 7 1.16 𝐸 0 9 1.10 𝐸 0 9
0.00025 1.10 𝐸 0 5 1.10 𝐸 0 5 1.10 𝐸 0 7 1.10 𝐸 0 7 1.07 𝐸 0 9 1.10 𝐸 0 9