Table 2: The solution when the number of chains increases.

Number of chainsCalculated eignvalues
𝑁 Exact 𝜆 1 ( 1 ) = . 7 4 5 2 9 3 9 5 Exact 𝜆 1 ( 2 ) = . 8 5 5 3 7 1 3 1 Exact 𝜆 1 ( 3 ) = . 9 1 0 3 2 7 4 0

20.74737713.85513704.91008238
40.74529979.85537157.91034304
80.74529407.85537175.9102873