143732.fig.0010
Figure 10: Valid LP-solution of E C t n with 𝑓 l p = 2 + 𝜖 ( 𝑙 𝑎 = 1 , 𝑙 𝑏 = 𝜖 , 𝑙 𝑐 = 1 ) that is not valid for S C F t n . It can however be transformed to such, by increasing 𝑥 3 , 4 to 1/5, yielding 𝑓 l p = 2 + 1 / 5 . It is easy to see, that this solution is still not valid for D C u t t n .