Figure 10:
Valid LP-solution of
E
C
t
n
with
𝑓
l
p
=
2
+
𝜖
(
𝑙
𝑎
=
1
,
𝑙
𝑏
=
𝜖
,
𝑙
𝑐
=
1
)
that is not valid for
S
C
F
t
n
. It can however be transformed to such, by increasing
𝑥
3
,
4
to 1/5, yielding
𝑓
l
p
=
2
+
1
/
5
. It is easy to see, that this solution is still not valid for
D
C
u
t
t
n
.