This paper studies the eigenvalue interval for the singular boundary value problem , where may be singular at , , and may change sign and be superlinear at . The approach is based on an approximation method together with the theory of upper
and lower solutions.
1. Introduction
The singular boundary value problems of the form
occurs in several problems in applied mathematics, see [1–6] and their references. In many papers, a critical condition is that
or there exists a constant such that for any compact set there is such that
We refer the reader to [1–4]. In the case, when may change sign in a neighborhood of and for , very few existence results are available in literature [1].
In this paper we study positive solutions of the second boundary value problem
here and are continuous, so as a result, our nonlinearity may be singular at and Also our nonlinearity may change sign and be superlinear at . Our main existence results (Theorems 1.1, 1.2 and 1.4) are new (see Remark 1.5, Examples 3.1 and 3.2).
A function is a solution of the boundary value problem (1.4) if satisfies the differential equation (1.4) on and the stated boundary data.
Let denote the class of maps continuous on , with norm We put ; Given , let
Let
In this paper, we suppose the following conditions hold:
() suppose there exist continuous functions such that
where is defined in Lemma 2.1;
there exist continuous functions such that
there exists such that for The main results of the paper are the following.
Theorem 1.1. Suppose , and the following conditions hold: for all there exists such that is increasing in there exists a sequence such that and
where
Then there exists such that for every (1.4) has at least one positive solution and for
Theorem 1.2. Suppose and the following conditions hold: for all there exists such that is increasing in there exists such that
there exists , such that for all
where
and for
Then there exists such that
(i)if (1.4) has at least one solution and for ;(ii)if (1.4) has no solutions.Remark 1.3. Notice that satisfies and for fixed
Theorem 1.4. Suppose , , and the following conditions hold: there exists such that
where is defined in Lemma 2.1 and for all there exists such that is increasing in
Then there exists such that
(i)if (1.4) has at least one solution and for ;(ii)if (1.4) has no solutions.Remark 1.5. In [5, 6], the authors consider the boundary value problem (1.4) under the conditions
In Section 3, we give two examples (see Examples 3.1 and 3.2) which satisfy the conditions in Theorem 1.1 or Theorem 1.2 but they do not satisfy the conditions in [1–5].
2. Proof of Main Results
2.1. Some Lemmas
Lemma 2.1. Consider the following eigenvalue problem
Then the eigenvalues are
and the corresponding eigenfunctions are
Let be the Green's function for the BVP:
Then
Also for all , define
It follows easily that
Define the operator by
The following four results can be found in [5] (notice is not needed in the proofs there).
Lemma 2.2. Suppose and hold. Let Assume that for every there exist , , such that
and there exist , , , such that
and . If
where and , then (1.4) has a solution such that for
Lemma 2.3. Let be a continuous function with
Then the problem
has a solution such that
If we let for then
Next we consider the boundary value problem
where , for
Lemma 2.4. The following statements hold: (i)for any (2.16) is uniquely solvable and
(ii)if for then the solution of (2.16) is nonnegative.
Corollary 2.5. Let be the operator such that is the solution of (2.16). Then we have (i)if for then for (ii)let and If , for all then is relatively compact with respect to the topology of
Lemma 2.6 (see [2]). Let , , , satisfy
Then there exist , such that
2.2. The Proof of Theorem 1.1
Claim 1 (see [5]). There exists , independent of such that for all there exist , with and
with
Let , and be defined in Claim 1. Define
From notice that satisfies the assumptions of Lemma 2.3, so there exist , , for such that
where
Let , be fixed. We consider the following boundary value problem:
By there exist such that and
so
There exists such that
If and for then
and so
Let be the operator defined by
It is easy to see that is a continuous and completely continuous operator. Also if for then for , so Schauder's fixed point theorem guarantees that there exists such that that is,
Let
Then , and
Let
so
From Claim 1, we obtain
that is,
A standard argument yields
From there exists such that is increasing on . Let From (2.35) and (2.38) we have
Also for we have