Department of Mathematics, Wilfrid Laurier University, 75 University Ave West, Waterloo, ON, N2L 3C5, Canada
Abstract
A new approach for demonstrating the global stability of ordinary differential equations is given. It is shown that if the curvature of solutions is bounded on some set, then any nonconstant orbits that remain in the set, must contain points that lie some minimum distance apart from each other. This is used to establish a negative-criterion for periodic orbits. This is extended to give a method of proving an equilibrium to be globally stable. The approach can also be used to rule out the sudden appearance of large-amplitude periodic orbits.
1. Introduction
A key issue in the analysis of a system of ordinary
differential equations is to determine the long-term dynamics. Generally, it is
desirable, if possible, to know whether a system settles down to an
equilibrium, approaches a limit cycle, or exhibits some other long-term
behavior. In this paper, we give a method that uses the curvature of solutions
to help show that a system approaches an equilibrium.
A nice feature of considering the curvature is that
the calculation only involves local information. Furthermore, it is not
necessary to calculate solutions to the differential
equations since the curvature calculation uses the
derivative of a solution, and this is given by the vector field that defines
the flow.
On any set for which the curvature is bounded, there
is a minimum length of a closed orbit (not including equilibria). Also, in such
a set, any closed orbit must contain points that are a certain distance away
from each other. The smaller the curvature, the farther apart certain points on
the orbit must be from each other. This idea is used to formulate a negative
criterion for periodic orbits. The method is then extended to give a criterion
that shows that all forward trajectories leave the set.
Unfortunately, if the eigenvalues of the Jacobian at
an equilibrium are not all equal, then the curvature near the equilibrium is
unbounded. This makes it necessary to deal with the behavior near an
equilibrium separately. For instance, one may use a Lyapunov function near an
equilibrium to show that a certain neighborhood is contained in the
equilibrium's basin of attraction. Then, analysis of the curvature can be used
to show that all other solutions enter this set (by showing that they leave the
complement), making the stability global.
This approach can also be useful in ruling out
nonlocal bifurcations as parameters are varied. It is often possible to show
that an equilibrium is locally asymptotically stable for all parameter values,
and that it is globally stable for a particular set of parameter values. As
parameters are varied, the continued local stability precludes the possibility
of local bifurcations such as Hopf. Nonlocal bifurcations, however, may still
occur. The method presented here can be used to preclude the existence (and
sudden appearance) of large-amplitude periodic orbits and, therefore, help rule
out nonlocal bifurcations.
We now give a brief outline of the paper. In Section
2, the curvature of parametric curves is discussed. This is
applied to periodic solutions of differential equations in Section 3. In Section 4, results are given for
omega limit points. Section 5 stability gives stability theorems. A discussion of how to apply the results is included in Section 6.
2. Curvature Calculations
Consider a curve
given by the function
,
where
is
and
is nonzero for all
.
In this paper, we use the convention that
represents differentiation with respect to
time.
Let
be the arclength along
from some reference point, that is,
.
We use the convention that when the arguement of a function is changed to
,
the function is considered to be reparameterized in terms of arc length. Note
that
,
and so
.
For each
,
the unit tangent at the point
is
(2.1)and so
(2.2)The curvature [1] of
is defined to be
and is given by
(2.3)Using (2.2) gives
(2.4)
Let
be a unit vector in
.
Let
be the angle between
and
:
Proposition 2.1.
(2.5)Proof. Noting that
,
we have
.
Letting
be the angle between
and
,
then,
.
Thus,
(2.6)We now show that
is at most one. Since
is a unit vector for all
,
it follows that
is orthogonal to
.
Since
is a unit vector separated from
by angle
,
the component of
normal to
has magnitude
.
Thus, the component of
in the direction of
has magnitude less than or equal to
.
On the other hand, this magnitude is given by
,
showing that
.
Combining with (2.6) yields the proposition.
Now, suppose
is a simple closed curve given by the 
-periodic function
,
where
is nonvanishing. Let
.
Choose
such that
,
and let
,
that is,
is the unit tangent to
at
.
Since
is
-periodic, it follows that
for all
.
Hence,
.
Combining this with the fact that
is
-periodic, continuous and positive at
,
we see that
oscillates in sign and, therefore, must have
at least two zeros in every interval of length
.
Let
be the maximal interval containing
such that
is positive. Note that
.
Let
be the Euclidean distance between points
.
We now work toward finding a lower bound on the distance between the points
and
:
(2.7)Let
be the least upper bound of
on
.
Then, recalling that
gives
(2.8)where the inequality follows
from Proposition 2.1. Similarly,
.
Since
and
are orthogonal, it follows that
.
Similarly,
and
.
This leads to the following result.
Theorem 2.2.
Let
be a simple closed curve and let
be an upper bound for the curvature on
.
Then, given a point
,
there exist points
such that
and
.
Furthermore, the tangents to
at
and
are orthogonal to the tangent at
.
By not requiring that the curve
be closed, we obtain the following result,
which will be useful in Section 4.
Theorem 2.3.
Let
be an upper bound for the curvature on a curve
which is given by
,
with
nonvanishing. Suppose further that there exist
,
with
such that the tangent at
is orthogonal to the tangents at
and
,
and
for all
.
Then,
and
.
3. Periodic Solutions of Differential Equations
Consider the differential equation
(3.1)where
is
.
We denote by
the solution to (3.1) which passes through
at time
.
Suppose
is a nonconstant solution to (3.1). Noting that
,
it follows from (2.4) that the curvature at
is
(3.2)Thus, as long as the point
is not an equilibrium of (3.1), the curvature at
of the solution through
can be precisely calculated without any
explicit knowledge of the solution.
We now relate Theorem 2.2 to periodic
solutions of ordinary differential equations.
Theorem 3.1.
Let
be the simple closed curve traced out by a
nontrivial periodic solution of (3.1) and suppose
that
lies entirely in a region, where the curvature
of solutions is bounded above by
.
Then, the conclusions of Theorem 2.2 hold.
Let
.
Define
(3.3)Then, any periodic solution
to (3.1) which lies
entirely in
has maximum curvature less than or equal to
.Corollary 3.2. If
contains no simple closed curve for which the
maximum curvature is less than or equal to
,
then there are no nontrivial periodic orbits of
(3.1) which lie entirely in
.
Property (The Negative Property).
Let
be the maximum curvature of
on a set which contains no equilibria. The set
is said to have the negative property if it does not contain a point
such that there are two corresponding points
and
satisfying
and
,
with
and
orthogonal to
.
Corollary 3.3.
If
has the negative property, then there are no
periodic solutions to (3.1) contained entirely in
.
4. Omega Limit Points
Theorem 4.1.
Suppose
has the negative property, and that
is a forward trajectory of (3.1) which is
contained entirely in
.
Then, the omega limit set of
consists entirely of equilibria which lie in
the closure of
,
but not in
.
Proof.
Suppose
is an omega limit point of
,
where
for all
,
and that
.
Then, there is an increasing sequence of times
which limits to
such that
.
Then,
(4.1)Fix
such that
if
,
the open ball centred at
with radius
.
Choose
so that
if
and
.
Taking the dot product of each side of (4.1) with a vector
gives
(4.2)For sufficiently large
,
we have
and, therefore,
for
.
Thus,
(4.3)Hence, the integrand must
oscillate between positive and negative for large enough
,
in order that (4.2) be satisfied. Thus, for large enough
,
there exist
and
with
,
such that
and
are orthogonal to
.
Furthermore,
and
can be chosen so that
is positive on the interval with these
endpoints.
The only restriction on
,
thus far, is that
.
In order for
to be sufficiently large for
and
to be defined, it is only necessary that
.
(For large
,
a change in the choice of
will change the values of
and
but will not change the fact that they exist.)
Now, fix
to be sufficiently large that
,
and choose
.
Applying
Theorem 2.3, with
,
yields
and
.
This contradicts the negative property, and so if
is an omega limit point, then we must have
.
Since
satisfies the negative property, there are no
equilibria in
and, therefore,
is not an element of
.
However, since
is an omega limit point of
,
it must be an element of the closure of
,
completing the proof.
Corollary 4.2.
If
is a compact set which has the negative
property, then there are no forward trajectories contained entirely in
.
Proof.
Since
is compact, any forward trajectory contained
entirely in
has a nonempty omega limit set
.
By Theorem 4.1,
consists entirely of equilibria, but by the
negative property
contains no equilibria, so
cannot contain an entire forward trajectory.
Corollary 4.3.
Let
be the diameter of a compact set
which contains no equilibria. If
,
then any orbit starting in
leaves
.
5. Stability Theorems
Suppose
is positively invariant under (3.1). If
is compact and has the negative property, then
by Corollary 4.2 there are no forward trajectories
contained entirely in
.
If it is known that all solutions intersecting
limit to an equilibrium, then we can conclude
that all solutions in
limit to an equilibrium giving the following
result.
Theorem 5.1.
Suppose
is positively invariant, and
is a compact set which has the negative
property. If all solutions in
limit to an equilibrium, then all solutions in
limit to an equilibrium.
Corollary 5.2.
Suppose
is positively invariant and contains a unique
equilibrium
.
Suppose
is a compact set which has the negative
property. If all solutions in
limit
,
then
is globally stable in
.
We now consider the effect of making a change of
variables. Suppose
(5.1)where
is a diffeomorphism. Then,
,
and so
(5.2)If the set
is compact and has the negative property
for (5.2), then Corollary 4.2 implies solutions of (5.2) leave
,
which then implies solutions of (3.1) leave
.
This allow Theorem 5.1 to be generalized as
follows.
Theorem 5.3. Suppose
is positively invariant under (3.1),
is compact and that all solutions in
limit to an equilibrium. If there exists a
diffeomorphism
such that
has the negative property for (5.2), then all
solutions in
limit to an equilibrium.
6. Discussion
If it is known that the curvature of a vector field is
bounded on a set, then it follows that the rate at which trajectories turn is
bounded. A consequence of this is that a closed orbit has a minimum size. In
particular, there exist points on the orbit which are separated by a distance
at least twice as large as the reciprocal of the
bound on the curvature.
This approach can be used to rule out periodic
trajectories of a differential equation and to show that solutions which remain
in a given set must limit to sets consisting of equilibria.
It may appear that this alone could be used to show
global stability of an equilibrium in an invariant compact set, but there is a
problem. Near an equilibrium the curvature is usually unbounded. This is true
whenever the linearization at the equilibrium has at least two distinct
eigenvalues.
Thus, in determining the global stability of an
equilibrium, it would be necessary to deal with the behavior near the
equilibrium in some other manner. For instance, one could use the linearization
to obtain a quadratic form that could be used to show that a given neighborhood
limits to the equilibrium. Then, by showing that the remainder of the compact
set has the negative property, it would follow that the equilibrium is globally
stable.
References
- J. Stewart, Multivariable Calculus: Early Transcendentals, Thomson Brooks/Cole, Belmont, Calif, USA, 2008.