Table 2:
The comparison of the results of the HAM (
ℎ
=
−
1
) and exact solution for the
𝑢
(
𝑥
,
𝑡
)
,
𝛼
=
𝛽
=
1
.
x
t
|
∑
5
𝑖
=
0
𝑢
(
𝑖
)
−
E
x
a
c
t
|
|
∑
5
𝑖
=
0
𝑣
(
𝑖
)
−
E
x
a
c
t
|
−15
0.002
8
.
0
6
7
2
×
1
0
−
8
2
.
4
4
2
6
×
1
0
−
8
−12
0.002
5
.
9
5
3
9
×
1
0
−
7
1
.
8
0
3
8
×
1
0
−
7
−6
0.002
3
.
0
2
5
7
×
1
0
−
6
1
.
3
2
7
0
×
1
0
−
6
6
0.002
3
.
0
2
6
3
×
1
0
−
6
1
.
3
4
8
1
×
1
0
−
6
12
0.002
5
.
9
5
5
0
×
1
0
−
7
1
.
7
7
2
2
×
1
0
−
7
15
0.002
8
.
0
6
8
6
×
1
0
−
8
2
.
3
9
9
8
×
1
0
−
8