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International Journal of Mathematics and Mathematical Sciences

Volume 2011 (2011), Article ID 985323, 21 pages

http://dx.doi.org/10.1155/2011/985323

## Fundamental Domains of Gamma and Zeta Functions

^{1}Simion Stoilow Institute of Mathematics, The Romanian Academy, P.O. Box 1-764, 014700 Bucharest, Romania^{2}Glendon College, York University, 2275 Bayview Avenue, Toronto, ON, Canada M4N 3M6

Received 29 September 2010; Accepted 21 March 2011

Academic Editor: Marianna Shubov

Copyright © 2011 Cabiria Andreian Cazacu and Dorin Ghisa. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

#### Abstract

Branched covering Riemann surfaces are studied, where is the Euler Gamma function and the Riemann Zeta function. For both of them fundamental domains are found and the group of cover transformations is revealed. In order to find fundamental domains, preimages of the real axis are taken and a thorough study of their geometry is performed. The technique of simultaneous continuation, introduced by the authors in previous papers, is used for this purpose. Color visualization of the conformal mapping of the complex plane by these functions is used for a better understanding of the theory. A version of this paper containing colored images can be found in arXiv at Andrian Cazacu and Ghisa.

#### 1. Introduction

Following [1, page 98] we call fundamental region, or fundamental domain of an analytic function , a domain which is mapped conformally by onto the whole plane, except for one or more cuts (or slits). It has been proved in [2] that every neighborhood of an isolated essential singularity of an analytic function contains infinitely many nonoverlapping fundamental domains of . In fact this is true as well for essential singularities which are limits of poles or of isolated essential singularities [2–5]. The Euler Gamma function and the Riemann Zeta function have as their unique essential singularity. For the function Gamma, is a limit of poles, while for the function Zeta it is an isolated essential singularity. It follows that for each one of these functions, the complex plane can be written as a disjoint union of sets whose interiors are fundamental domains, that is, domains which are mapped conformally by the respective function onto the complex plane with a slit. By analogy with the well-known case of elementary functions we use the preimage of the real axis in order to find such a disjoint union of sets. As we will see next, for the function Gamma there is a great similarity with that case, while for the function Zeta a supplementary construction is needed. However, in both cases there is a noticeable difference, namely, while for the elementary functions the slit is the same for every fundamental domain, for the functions Gamma and Zeta it can vary from one fundamental domain to the other. This fact implies some complications when trying to define the cover transformations of the respective branched covering Riemann surfaces. However, the method of fundamental domains allows one to extract a lot of information about the function, in particular about its zeros, as well as the zeros of its derivative and to reveal global mapping properties of the function. Since the fundamental domains are *leafs* of the corresponding *branched* covering Riemann surface, the study of the group of cover transformations of the respective surface must start from them. This has been done in [3–5] for some classes of Blaschke products, in [6] for arbitrary rational functions, and in [2] for functions obtained composing the exponential function with a Möbius transformation and we deal here with this topic in Section 3 for the function Gamma and in Section 7 for the function Zeta. Sometimes we need to use a rather * descriptive* language. This is because we fully adopted Ahlfors opinion [1, page 99]: *whatever the advantage of such a representation may be, the clearest picture of the Riemann surface is obtained by direct consideration of the fundamental regions in the z-plane. *We apply repeatedly the general method of *simultaneous continuations *in order to construct the fundamental domains and then color visualization perfected in the previous papers [2–6] in order to illustrate the facts, *but never as logical proofs*. Expressions indicating motion should be taken only as figures of speech. One can always replace them by* static* pictures.

Before starting the study of the two functions, let us illustrate the method of fundamental domains on the elementary function presented in [1, page 98-99], with the interpretation of the facts proper to this method. The function has the branch points , , where cancels. The points are simple zeros of , and therefore the preimage of a small interval of the real axis centered at produces at every a configuration similar to that of [1, page 133], obtained for . In the following we will call such a configuration* star configuration.* Since for , one of the arcs of this configuration is an interval of the real axis containing and the other one a Jordan arc orthogonal to it at . Since , such an arc is necessarily a vertical segment of line. When performing simultaneous continuations over the real axis of these intervals, we obtain the net of [1, Figures 3–11]. Indeed, the continuation of every vertical interval is unlimited, since there is no critical point of in its way, while the continuation of horizontal intervals join two by two at , as reaches 1 and respectively −1. If we denote by , the vertical strips between and , then by the conformal mapping correspondence theorem, every is mapped conformally by onto the complex plane with a slit alongside the part of the real axis complementary to the interval . The domains are fundamental domains of the function . It is obvious that the functions , , defined by , are such that , that is, they are cover transformations of .

We can obtain by the method we used in [2–6], which will be used also for the functions Gamma and Zeta in Section 3, respectively, Section 7. Let us denote for every and notice that , . Since for , , we have that , that is, the functions and coincide on , . Being analytic functions, they must coincide on . We can extend by continuity to every the functions so defined and they become the analytic functions with the domain . They form an infinite cyclic group . Every couple of fundamental domains and determines a unique cover transformation which maps conformally onto . Indeed, suppose that is an arbitrary cover transformation of , that is, is analytic in , for every and suppose as well that maps conformally onto . Then . The involution is also a cover transformation of due to the fact that . We have that and then , thus the cover transformation which maps conformally onto with arbitrary , is if and , where if . The involution does not belong to . It is an elementary exercise to show that the group generated by and is the group of cover transformations of .

#### 2. Global Mapping Properties of the Euler Gamma Function

We use the explicit representation of the Euler Gamma function as a canonical product [1]: where is the Euler constant

It is obvious from this representation that has the set of simple poles and has no zero. The product converges uniformly on compact subsets of and therefore is a meromorphic function in the complex plane .

Theorem 2.1. *The preimage by of the real axis is formed with infinitely many unbounded curves (components). The components corresponding to the positive and to the negative real half axis alternate and do not cross each other. Some of them start however from the same poles of .*

*Proof. *The number is real for every real and the graph of the function has the lines , , as vertical asymptotes [7].

Figure 1 can be found in most of the books of complex analysis serving as texts for graduate studies. We used the online document [7]. It shows the graph of the real function , which can be used to draw some information about the complex function .

The respective graph has local minima and maxima, which correspond to the points where . All these points are on the real axis, namely, , and for every positive integer , there is a unique such that . Indeed, let us denote

The sequence converges uniformly on compact sets of to . It can be easily checked that for every , the equation is equivalent to an algebraic equation of degree and has exactly real solutions situated one in every interval , and one in the interval . Therefore cannot have nonreal solutions. Since converges in turn uniformly on compact subsets of to , we infer that every interval , , contains exactly one solution of the equation , and there is one more solution . There are no other solutions of this equation. It is also obvious that

Based on this information, we can reveal the preimage by of the real axis, denoted . Since all , are simple roots of , in a neighborhood of every , has the form [1, page 133]
where is analytic and where .

By the Big Picard Theorem, the preimage by of is for every a countable set of points. The formula (2.1) shows that , thus this set is of the form , having the unique accumulation point . Suppose that is . Then by (2.5), the preimage of a small interval of the real axis centered at is the union of an interval of the real axis and another Jordan arc orthogonal to the real axis at (let in [1, Figure 4.8]) and symmetric with respect to the real axis, as well as infinitely many other Jordan arcs passing each one through a , respectively, , . Simultaneous continuations [6] over the real axis of these preimages have as result the interval for . Indeed, and being poles for , we have that for , and if and only if . The continuations have as result an unbounded curve crossing the real axis at for and infinitely many other unbounded curves passing each one through , or through for . The unboundedness is guaranteed by the fact that the continuation is unlimited, since there are no poles of off the real axis. We use the same notation for the curves passing through and , respectively, for the others. We notice that these curves cannot intersect each other, since in such a point of intersection we would have , which is excluded. Also, the curves , and , cannot intersect the real axis, for a similar reason. We call these curves* components* of .

Since 0 is a lacunary value for , there can be no continuity (except at the poles) between the preimage of the real positive half axis and negative half axis, which means that each one of these components is unbounded. Moreover, if we use two different colors, say black and red for the preimage of the negative, respectively, positive real half axis, then these colors must alternate, since minima and maxima for the real function are alternating. Hence the intervals have alternating colors, which imply alternating colors for . Indeed, due to the continuity of , except at the poles, change of color can happen only there, which means that the color of and that of must agree. Thus, the colors of are alternating. On the other hand, if a point travels on a small circle centered at origin in the -plane (), it will meet alternatively the positive and the negative half axis, which implies alternation into the colors of . If were multiple zeros of then more than one curve of the same color would start from violating this rule of color alternation. Thus, as previously stated, has only simple zeros.

We notice that, by Formula (2.1), if , or then and . Therefore, when describes any or its image describes the positive or the negative real half axis, the correspondence being bijective there. Also, if , then .

The preimage of the real axis seen in the computer generated picture in Figure 2 illustrates these affirmations. These limits will help next to prove the following theorem.

Figure 2 shows the computer generated preimage by of the real axis. Since zero is a lacunary value, red curves meet black curves only at the poles.

Theorem 2.2. *The complex plane can be written as a disjoint union of sets bounded by the components of such that the interior of each one of them is a fundamental domain of . These domains accumulate to infinity and only there. The function extended to the boundary of each one of them maps them surjectively onto .*

*Proof. *Let us introduce first some notations. We denote by the domain bounded by and , . Let be the domain from the upper half plane bounded by , the interval and the second component of situated in the upper half plane and which does not intersect the real axis, be the domain bounded by this component and the fourth one and so forth. We denote by , the domain symmetric to with respect to the real axis. Obviously, for , we have .

Let us notice that, by the conformal correspondence theorem, the image by of every , is the complex plane with a slit alongside the real axis, from to , while the image of every and of every , is the complex plane with a slit (the same for every . It is obvious that the union of the closures of the domains and , , is the complex plane and if the common boundary of every adjacent couple of them is counted just once, we obtain a disjoint union. As proven in [2], for an arbitrary analytic function having the unique essential singularity at , these domains accumulate to and only there in the sense that every neighborhood of contains infinitely many domains and and any compact set in intersects only a finite number of these domains. Finally, since for every and every there is such that ( if is not on the corresponding slit and if is on the slit) we have that is surjective. The same is true for every .

Figure 3 represents a visualization of the way the fundamental domains are mapped conformally by onto the complex plane with a slit. Figure 3(a) is obtained by taking preimages of colored annuli centered at the origin of the -plane Figures 3(b)–3(d) and imposing the same color, saturation, and brightness on the preimage of every point. The very big annuli Figure 3(d) have preimages around the poles, and this is obvious when looking at the colored pictures on the web project. However, the same colors appear for with big positive values of characterizing the fact that . Coupled with the preimage of orthogonal rays to these annuli, the picture in Figure 3(a) gives a pretty accurate *graphic* of the function.

#### 3. The Group of Cover Transformations of

The results from the previous section allow one to treat as a branched covering Riemann surface of whose leafs are the fundamental domains . We call *cover transformation* of an analytic function such that, where is a countable set of slits. The cover transformations of form a group.

The covering Riemann surfaces we are dealing with here are not smooth, and it is expected that some of the familiar properties of smooth covering surfaces be invalid for them. For example, while the cover transformations of smooth covering Riemann surfaces have no fixed point, the origin is a fixed point for the transformation we defined in the first section. Next, as long as the slits are not the same for all the fundamental domains, as it happens in the case of the functions and , we are forced to introduce a set of slits in when defining the cover transformations in order to avoid working with multivalued functions. For the case of this can be done as follows. Let us denote and . Since, for we can have , in order to be able to use, for example, the formula we have to take this time instead of . The functions can be extended by continuity to every , yet they can take different values on different borders of the slits . Since for the extended must fulfil the equalities , for and for . Next, we extend to the lower half plane by symmetry:

Theorem 3.1. *The group of cover transformations of has two generators: an involution and a transformation generating an infinite cyclic subgroup of .*

*Proof. *We notice that are conformal mappings in since the branch points belong to . For every we have , . Moreover, , .

Finally we define , by

It can be easily seen that is an involution and , , , , and so forth. We notice also that

This shows in particular that generates an infinite cyclic subgroup. It is an elementary exercise to show that the group generated by and is the group of covering transformations of .

#### 4. The Riemann Zeta Function

The Riemann Zeta function is one of the most studied transcendental functions, in view of its many applications in number theory, algebra, complex analysis, and statistics as well as in physics. Another reason why this function has drawn so much attention is the celebrated Riemann conjecture regarding its nontrivial zeros, which resisted proof or disproof until now.

We are mainly concerned with the global mapping properties of Zeta function. The Riemann conjecture prompted the study of at least local mapping properties in the neighborhood of nontrivial zeros. There are known color visualizations of the module, the real part and the imaginary part of Zeta function at some of those points, however they do not offer an easy way to visualize the global behavior of this function.

The Riemann Zeta function has been obtained by analytic continuation [1, page 178] of the series
which converges uniformly on the half plane , where is arbitrarily chosen. It is known [1, page 215] that Riemann function is a meromorphic function in the complex plane having a single simple pole at with the residue 1. Since it is a transcendental function, must be an essential isolated singularity. Consequently, the branched covering Riemann surface of has infinitely many fundamental domains accumulating at infinity and only there. The representation formula
where is the Euler function and is an infinite curve turning around the origin, which does not enclose any multiple of , allows one to see that for every positive integer and there are no other zeros of on the real axis. However, the function has infinitely many other zeros (so called,* nontrivial* ones), which are all situated in the* (critical) strip *. The famous Riemann hypothesis says that these zeros are actually on the* (critical) line *. Our study brings some new insight into this theory.

We will make reference to the Laurent expansion of for : where are the Stieltjes constants: as well as to the functional equation [1, page 216]:

#### 5. The Preimage by of the Real Axis

We will make use of the preimage by of the real axis in order to find fundamental domains for the branched covering Riemann surface of . By the Big Picard Theorem, every value from the -plane , if it is not a lacunary value, is taken by the function in infinitely many points accumulating to and only there. This is true, in particular, for .

A small interval of the real axis containing 0 will have as preimage by the union of infinitely many Jordan arcs passing each one through a zero of , and vice versa, every zero belongs to some arcs . Since , for , and by the formula (4.5), the *trivial zeros* of are simple zeros and the arcs corresponding to these zeros are intervals of the real axis, if is small enough. For such an arc the subscript is superfluous. Due to the fact that is analytic (except at ), between two consecutive trivial zeros of , there is at least one zero of the derivative , that is, at least one branch point of . Since we have also for , if we perform simultaneous continuations over the real axis of the components included in of the preimage of , we encounter at some moments these branch points and, as in the case of , the continuations follow on unbounded curves crossing the real axis at these points.

The argument for the unboundedness of these curves and of the fact that they have no common points is the same as in the case of . Only the continuation of the interval containing the zero stops at the unique pole , since . Similarly, if instead of we take another real greater than 1 and perform the same operations, since , the continuation over the interval stops again at . In particular, the preimage by of this interval can contain no zero of the Zeta function. Thus, if we color red the preimage by of the negative real half axis and let black the preimage of the positive real half axis, then all the components of the preimage of the interval will be black, while those of the interval will have a part red and another black, the junction of the two colors corresponding to a zero (trivial or not) of the function Zeta.

Figure 4 represents the preimage of the real axis in which the components previously described are visible. We notice the existence of branch points on the negative real half axis and their color alternation, as well as the trivial zeros between them. Since these zeros are those of , they are simple zeros and consequently there is no branching at them. Some nontrivial zeros are also visible.

The red and the black unbounded curves passing through the branch points on the real axis cannot meet elsewhere (except at ). Indeed, such an intersection point would be a zero of and the two curves would bound a domain which is mapped conformally by onto the complex plane with a slit alongside the real axis from the image of one branch point to the image of the next one. Yet such a domain should contain a pole of the function, which is impossible.

The components of the preimage of the real axis passing through nontrivial zeros form a more complex configuration. This configuration has something to do with the special status of the value . Let us introduce notations which will help making some order here and justifying the configurations shown on the computer generated picture, Figure 4. Due to the symmetry with respect to the real axis, it is enough to deal only with the upper half plane. Let and let . Continuation over from is either an unbounded curve such that , by (4.2), and , where , or there are points such that , thus the continuation can take place over the whole real axis. We notice that it is legitimate to let tend to on , since if supremum of were reached for a finite , then that would be a pole of , which is impossible.

The existence of and that of with is attested by computation. The graphs just illustrate this computational fact. However, they hint to something more, namely, that the number of these entities is infinite. This can be proved rigorously. Indeed, suppose that for a no other unbounded curve situated above it is mapped by onto the interval . For a point above let and let be arbitrary. We can connect and by a Jordan arc not intersecting the interval . If we perform continuation by over starting from we arrive at a point above such that . Then the closed domain above would be mapped by onto the whole complex plane, which is absurd.

Theorem 5.1. *Consecutive curves and form strips which are infinite in both directions. The function maps these strips (not necessarily bijectively) onto the complex plane with a slit alongside the interval of the real axis.*

*Proof. *Indeed, if two such curves met at a point , one of the domains bounded by them would be mapped by onto the complex plane with a slit alongside the real axis from 1 to . Such a domain must contain a pole of , which cannot happen.When a point travels on and leaving the strip at left, moves on the real axis from 1 to and back.

When the continuation can take place over the whole real axis, we obtain unbounded curves each one containing a nontrivial zero of and a point with . Such a point is necessarily interior to a strip since the borders of every and are disjoint.

Theorem 5.2. *There are infinitely many points with .*

*Proof. *Let us denote by the points of for which , by the components of containing and by the nontrivial zero of situated on . When , , we assign (by abuse!) the value to the respective . We will see later that every contains a unique with this property. The monodromy theorem assures that there is a one to one correspondence between (counted with multiplicities if they exist), , and . If is a zero of order , then curves cross at that zero making a star configuration. The color alternation rule is still respected. Since there are infinitely many nontrivial zeros of , it follows that there are infinitely many points .

Let us notice that every strip can contain only a finite number of nontrivial zeros, since they belong also to the critical strip and then infinitely many of them would have an accumulation point in , which is not allowed (see [1, page 127]).

Consequently, the given contains also exactly points with (including ) and exactly components . This analysis suggests that the value behaves simultaneously like a lacunary value since , and like an ordinary value, since . We can call it* quasilacunary. *

Theorem 5.3. *When the continuation takes place over the whole real axis, the components are such that the branches corresponding to both the positive and the negative real half axis contain only points with for big enough.*

*Proof. *Indeed, a point traveling in the same direction on a circle centered at the origin of the -plane meets consecutively the positive and the negative real half axis. Thus the preimage of should meet consecutively the branches corresponding to the preimage of the positive and the negative real half axis. It can be easily seen that two components can meet only at multiple nontrivial zeros of (if they exist) and no can intersect any . Thus, those components of preimages of circles centered at the origin which cross a , will continue to cross alternatively red and black components of the preimage of the real axis. These last components are mapped by either on the interval , or on the whole real axis.

On the other hand, due to the continuity of on , if a component of meets a , it should cross it and all , meeting consecutively the branches corresponding to the preimage of the positive and of the negative real half axis. Such an alternation is possible only if the previously stated condition on is fulfilled.

Theorem 5.4. *For every there is a unique component of situated in the strip , say , which is mapped bijectively by onto , that is, such that , and , .*

*Proof. *The strip is mapped by onto the complex plane with a slit alongside the real axis from 1 to . The mapping is not necessarily bijective. For every , there is and such that . Let us connect and by a Jordan arc interior to (except for its ends). Then is a closed curve bounding a domain or a Jordan arc travelled twice in opposite directions, in which case . We need to show that intersects again the real axis, in other words intersects the preimage of . Indeed, otherwise would be contained either in the upper or in the lower half plane. Then would map half of the strip bounded by and the branches of and corresponding to onto with a slit alongside the real axis from to 1. We can take big enough such that this half strip contains no zero of , which makes impossible such a mapping.

Let us show that cannot contain more than one component of the preimage of . Indeed, if there were more, we could repeat the previous construction with two consecutive such components, taking and with and arrive again to a contradiction.

Figure 5 represents dynamically the *birth* of a strip. We picked up the strip with in the range of 45 to 55 on the imaginary axis. It shows consecutively domains which are mapped conformally by onto the sectors centered at the origin with angles from to , where takes, respectively, the values of , , and . It is visible how the border of such a domain * splits* into , and previously defined as . Between them can be seen the curves and .

Theorem 5.5. *Every strip contains a unique unbounded component of the preimage of the unit disc.*

*Proof. *Indeed, to see this it is enough to take the preimage of a ray making an angle with the real half axis and let . A point with , , tends to as if and only if the corresponding component of the preimage of that ray tends to as , which happens if and only if the component of the preimage of the closed unit disc containing the point is unbounded. The uniqueness of implies the uniqueness of such a component. Obviously, the respective unbounded component can contain besides some other nontrivial zeros of , as it appears on the pictures in Figures 6 and 7. We notice that some of contain bounded components of the preimage of the unit disc and some others do not contain such components, and this is another experimental fact. For example ,, do contain one bounded component, while the others in this range do not. However, it looks like the existence of bounded components becomes a rule for big enough, when there can be several bounded components of the preimage of the unit disc in every strip (see Figure 7). We have found (see [8]) that the strip corresponding to has three bounded components of the preimage of the unit circle, one of which contains two nontrivial zeros and the strip corresponding to has six of them, one containing three nontrivial zeros.

We do not try to answer the question “why is it so?". On the other hand it is obvious that, as increases past 1, all the unbounded components of the preimage of fuse into a unique one intersecting every . Since as , the points of intersection of this component with every move to the left as increases, such that the bounded components of the preimage of will touch the unbounded one for some values of fusing with it. It might be interesting to know what is the greatest value of (if any) for which such a fusion takes place.

Theorem 5.4 does not exclude the possibility of containing several other components , , which are mapped bijectively by onto the whole real axis. Every one of the components , contains a nontrivial zero of and, for , intersects the preimage of the unit circle in two points corresponding to 1 and . There is no point corresponding to on . Using the approximation of by the partial sums from (4.3), it can be easily shown that for , , we have as . If contains components we will call it *-strip*. Every -strip contains nontrivial zeros of (counted with multiplicities, if they exist). Let us denote them by . The computer generated data suggest that the height of every strip is approximately 10. A rigorous proof of this fact and an estimation of could bring us to an alternative formula for the estimate of the number of nontrivial zeros of for .

#### 6. Fundamental Domains of the Riemann Zeta Function

The preimage of circles centered at the origin of the -plane are useful in the study of the configuration of the components . A circle with radius less than 1 has bounded components of its preimage containing one or several zeros. All the components of the preimage of the respective circle must meet alternatively components of the preimage of the positive and negative real half axis. Indeed, a point moving in the same direction on a circle centered at the origin will cross alternatively the positive and the negative real half axis. A corollary of this fact is as follows

Theorem 6.1. *All the real zeros of are simple zeros and they alternate with the trivial zeros of .*

*Proof. *Indeed, since the color change can happen only at a zero of (and at ) and the trivial zeros of are simple, if several branches of the preimage of the positive or of the negative half axis crossed the real axis at the same point or in different points between consecutive trivial zeros of , the color alternation for those branches would be violated.

A way to envision this violation is to keep in mind that the function is locally conformal, except at the branch points, hence the orthogonal net formed with the real axis and a family of circles centered at the origin of the -plane is the image by of an orthogonal net in which the components of the preimages of the negative and of the positive half axis must alternate when travelling in the same direction on each one of the components of the preimage of those circles.

The preimages of circles centered at the origin of radius less than or equal to 1 cannot meet the curves (which belong to the preimage of ). We will see later that there are bounded components of the preimage of circles of radius greater than 1, but close to 1 with the same property. However, the unbounded components of the preimages of these circles must intersect every , which are then counted in the alternation of the branches of the preimage of the positive and negative half axis.

The mesh they give rise of is formed with quadrilaterals of different conformal modules, which are the images by of quadrilaterals from the -plane having the same conformal modules and colors with the same saturation and brightness for the corresponding points. The preimage of the unit disc in the next pictures is formed with domains colored red and white (which is in fact degraded red). Several unbounded components of it are visible in Figures 6 and 7, one containing trivial zeros and the others containing nontrivial zeros. For the fundamental domains containing nontrivial zeros, the parts mapped onto the unit disc and onto different annuli interior or exterior to the unit disc are obvious. The same is true for the fundamental domains containing nontrivial zeros, except for those unbounded parts which are mapped onto a small quadrilateral around the point . More exactly, in the respective pictures, this quadrilateral is that bounded by rays of angle and by the circles of radius 0.8 and, respectively, 2.5 in *Mathematica*'s grid. We will make next more precise statements about this mapping.

Figure 6 shows the preimages by of the colored annuli from Figure 3 intersecting the preimage of the real axis in the box in Figure 6(a) with a zoom on the origin in Figure 6(b). The curves on the left side in Figure 6(a) crossing alternatively components of the preimage of the negative and positive real half axis are preimages of circles centered at the origin with radius greater than 1. The preimage of annuli coupled with the preimage of some orthogonal rays give a pretty accurate description of the mapping.

Figure 7 displays a 7-strip situated in the area corresponding to . There are clearly visible two components of the preimage of the unit circle: one bounded situated in the upper part of the strip containing a unique nontrivial zero, and one unbounded containing the other 6 nontrivial zeros. We notice in the strip above this 7-strip two bounded components of the preimage of the unit circle. It appears that the number of these bounded components in consecutive strips also increases (on the average) with .

Theorem 6.2. *If is a -strip with , then it contains at least one and at most zeros (counted with multiplicities, if any) of the derivative .*

*Proof. *Let us notice first that is a 1 strip, thus the derivative cannot have any zero in . This is attested by the fact that maps conformally onto the complex plane with a slit alongside the interval of the real axis; therefore there cannot be branch points of in . The strips and are 2 strips, , , and are 3 strips, and so forth. Let be a circle for a small enough value of , such that the preimage of consists of disjoint closed curves. If such a curve is in the critical strip, then we can suppose that it contains a unique nontrivial zero of . Suppose first that belongs to the unbounded component of the preimage of the unit disc. As increases the corresponding curves expand such that for some value of , will meet another curve of the same type at point . Indeed, starting with there are at least two such curves and each one will cover, as varies from 0 to 1, the whole component of the preimage of the unit disc. It is obvious that must be a branch point of , due to the fact that takes the same value in points situated on different curves in every neighborhood of . Since cannot be a multiple pole, we have necessarily that . All the zeros of we could visit were simple zeros. However, up to now, nothing allows us to say that this should always be the case. If more than two curves touch at the same point for a , then that point must be a multiple zero of . Let us see what global mapping properties of can be described in such a case. At a multiple zero of order of the preimage of the segment of line from 1 to produces a star configuration with arcs converging to . The simultaneous continuation of those arcs over must end up in points with , or at , as . The theorem of domain preservation (which says that an analytic function in an open and connected set maps that set onto another one of the same type) assures that the respective are different. Thus, if , at least two of these arcs must turn to different points with . It is obvious that those are consecutive on the preimage of the unit circle. Then the domains bounded by those arcs and the preimage of the unit circle is mapped conformally by onto the unit disc with a slit alongside . Consequently, the domains bounded by the preimage of the interval and those arcs are mapped conformally by onto the complex plane with a slit alongside this interval followed by a slit alongside .

When increases past the respective *fuse* into a unique closed curve. This last curve can meet for a another or another curve obtained by fusion and so on until we obtain a curve turning around all the zeros of contained in the respective unbounded component of the preimage of the unit disc. The fact that these curves must fuse and not simply intersect each other is obvious. Indeed, due to the continuity of if crossed each other, this would have happen at points as close as we wanted of , which is impossible, since the zeros of are isolated points. Finally, since for a in the preimage of the unit disc with , the preimage of passing through must contain at least two different components , we conclude that the points are the only zeros of having images by situated in the unit disc.

The preimage of any circle with contains a unique unbounded component obtained by the fusion of all unbounded components when increasing past 1. This component intersects every since intersects the interval . As increases, the respective component moves to the left covering unbounded domains in every which are mapped by onto a small quadrilateral situated in the neighborhood of the point and exterior to the unit circle. The real axis divides this quadrilateral into two quadrilaterals, the preimages of which have unbounded components. The respective components are curvilinear *-gones *with two *unbounded sides, *one corresponding to a segment of the real axis and the other one to an arc of the unit circle having both one end in . For bigger values of ( is big enough) these domains are the quadrilaterals which can be seen in Figures 6 and 7 on the left of the critical strip. The unbounded component of the preimage of touches bounded components of the preimage of for some values of in zeros of which project by outside the unit disc. Figures 6 and 7 do not give us an accurate description of the intermediate positions of this component at the right of critical strip, since the increment of is too rough and the range of is too small. Such a position can be seen in the supplementary pictures of [8] for . There the preimage of has a bounded component for and the unbounded component of is on its right side.

A zero of in some strip with image by outside the unit disc cannot belong to components of preimages of with different values of , due to the fact that is a single valued function. The only way for a branch point of to have the image on a with is for it to be the touching point of two bounded components of the preimage of or of a bounded and unbounded component of the preimage of . When increasing past the two components fuse into a unique one, which is unbounded if the two components were not both bounded. To facilitate the counting of the zeros of in , we form a *full binary tree *in which the leafs are the zeros of and the internal vertices are the zeros of ,corresponding to the points where the curves come into contact. If a zero of is multiple of order , we can build the tree such that it generates internal vertices. It follows easily by recursion that if the number of leafs is , then the number of internal vertices is and the conclusion of the theorem is obvious.

Figure 8 illustrates the situation where a component of the preimage of has a self-intersection point. In the box , Figure 8(a), two components of the preimage of the circle with are visible: a bounded one on the upper part of the box, containing a unique nontrivial zero of and an unbounded one covering the right lower corner of the box and containing two nontrivial zeros. As the radius takes values greater than 1, the two components expand, Figures 8(b), 8(c), touching each other for in Figure 8(b). We can interpret the preimage of as having a unique unbounded component with a self-intersection point . It borders three domains, one bounded and two unbounded. As takes values greater than , the bounded component *opens*, Figure 8(c), and we get a unique unbounded component separating the plane into two unbounded domains. It is obvious that is a branch point of . Indeed, the arcs of the preimage of situated in a small neighborhood of are mapped by onto an arc of containing . Thus and is a simple zero of . Figure 8(e) is a superposition of Figures 5 and 8(a)–8(c) showing the domains mapped by outside the circles and the sectors in Figure 5. It helps to locate on Figure 8(d).

It is obvious that the scenario described in Figure 8 repeats itself in every strip which contains bounded components of the preimage of with . Some of the can be obtained as the touching points of these components as increases. In other words, to every , except for , corresponds a branch point of situated in the strip . We notice that components of the preimage of with different values of cannot intersect, since this would contradict the single value nature of . Thus, cannot have branch points other than . The way have been obtained suggests that they are all situated in the right half plane. We have no knowledge of a proof of this affirmation, nor could we provide a proof of it, hence we make the following.

Conjecture 6. *All the nonreal zeros of are situated in the right half plane.*

In order to build fundamental domains for it is enough to deal with an arbitrary strip . Since every simple nontrivial zero of from belongs to one and only one fundamental domain, and every multiple zero of order , if it exists, must be a common boundary point of exactly fundamental domains, it is important to know as much as possible about the branch points of and the existence of multiple zeros. In our knowledge, there are just statistical estimations of the proportion of such zeros [9], and this happens only if the Riemann hypothesis were true. This topic transcends the scope of the present paper and a separate study will be devoted to it.

Theorem 6.3. *If is a -strip, then is the disjoint union of exactly substrips, whose interiors are fundamental domains of .*

*Proof. *The only 1 strip in the upper half plane is and it has no branch point of . It is by itself a fundamental domain of and it is mapped conformally by onto the complex plane with a slit alongside . As we have seen in Theorem 5.2, a -strip contains exactly components of and exactly points with , and one of these points being considered (by abuse!) as (which is the only one for . For , there is a number , of branch points of in . If we connect all the points to the point by a segment of line (which is the interval when is a multiple zero of ) and follow the protocol of Theorem 6.2, we obtain arcs or unbounded curves belonging to which are projected by onto different . The arcs connect consecutive points via a point , while the unbounded curves go from to via a point . For every at most one of the arcs containing can be unbounded. There cannot be unbounded containing a when this point is between two *embraced* curves , as in the case where appearing in supplementary pictures of [8]. By the conformal correspondence theorem, the sub-strips formed by consecutive arcs or unbounded curves and consecutive components of are mapped conformally by onto the complex plane with a slit alongside followed by at most three slits alongside intervals starting at and ending in some . Every such sub-strip contains a unique , if it is a simple zero of , and if is a multiple zero of order then exactly sub-strips meet at . Thus the number of sub-strips of is exactly . If the joint boundary of every couple of adjacent sub-strips is counted just once, is the disjoint union of these sub-strips, which proves completely the theorem.

Figure 9 describes the conformal mapping by in the strip . Figure 9(a) shows the way in which is obtained as the point where the components of the preimage of the circle meet each other for . In Figure 9(b) a curve is shown such that obtained by adding to the part of corresponding to divides the strip into two fundamental domains. Details of the conformal mapping by of these domains onto the complex plane with a slit are visible when one compares Figures 9(b) and 9(c).

#### 7. The Group of Cover Transformations of

Theorem 7.1. *The group of cover transformations of has two generators: an involution and a transformation generating an infinite cyclic subgroup of .*

*Proof. *In order to find the group of cover transformations of we need to rename the fundamental domains. We proceed in a way similar to what we did in the case of the function Gamma. Let us denote by the branch points of situated on the negative real half axis counted in an increasing order of their module. Let be the domain bounded by the branches of the components of the preimage of the positive real half axis crossing the real axis at (see Figure 4). It is mapped conformally by onto the complex plane with a slit alongside the real axis from to 1. Let be the domain bounded by the component of the preimage of the negative real half axis crossing the real axis in the -plane at , by the boundary of , by and its symmetric with respect to the real axis. We notice that is mapped conformally by onto the complex plane with a slit alongside the real axis complementary to the interval , The domains , are those bounded by the branches of the preimage of the real axis crossing the real axis at , respectively . They are mapped conformally by onto the complex plane with a slit alongside the complementary with respect to the real axis of the interval between and . Finally the domains , are the former domains counted starting from the positive real half axis and going up. In order to have consecutive subscripts for all adjacent domains, we take . All the domains , are fundamental domains of . So are the domains symmetric to them with respect to the real axis. For , we have .

We define, as in the case of the function Gamma mappings and by the formulas similar to (3.1) and (3.3), where is replaced by . As in that case we need to perform slits into every such that for every and , , and are mapped by onto the same slits into the -plane in order for these formulas to be applicable. We notice that the group generated by and is the group of covering transformations of . The group generated by is an infinite cyclic subgroup of .

#### Acknowledgment

The authors are grateful to Cristina Ballantine for providing computer generated graphics.

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