Table 1: Comparison of the numerical solution and error obtained by present method for 𝑛 = 3 in (36) with series solution [25].

𝑥 Our method Series method [25]
𝑚 = 3 2 𝑚 = 1 2 8 𝑚 = 2 5 6

0.0 0 . 0 0 𝐸 + 0 0 0 . 0 0 𝐸 + 0 0 0 . 0 0 𝐸 + 0 0 0 . 0 0 𝐸 + 0 0
0.1 4 . 0 2 𝐸 0 5 2 . 5 1 𝐸 0 6 6 . 2 8 𝐸 0 7 1 . 4 0 𝐸 0 6
0.5 2 . 8 9 𝐸 0 5 1 . 8 5 𝐸 0 6 4 . 9 6 𝐸 0 7 2 . 9 9 𝐸 0 6
1.0 4 . 3 9 𝐸 0 5 3 . 7 9 𝐸 0 5 3 . 7 6 𝐸 0 5 1 . 9 9 𝐸 0 6