Table 3: Comparison of the numerical solution and error obtained by present method with series solution [25].

𝑥 Present method Series method [25]
𝑚 = 3 2 𝑚 = 1 2 8 𝑚 = 2 5 6

0.0 0 . 0 0 𝐸 + 0 0 0 . 0 0 𝐸 + 0 0 0 . 0 0 𝐸 + 0 0 0 . 0 0 𝐸 + 0 0
0.1 4 . 6 6 𝐸 0 4 2 . 9 1 𝐸 0 5 7 . 2 8 𝐸 0 6 3 . 9 4 𝐸 0 6
0.5 1 . 4 6 𝐸 0 4 9 . 1 6 𝐸 0 6 2 . 2 9 𝐸 0 7 3 . 0 2 𝐸 0 6
1.0 8 . 6 0 𝐸 0 5 3 . 6 8 𝐸 0 6 1 . 2 8 𝐸 0 8 9 . 3 1 𝐸 0 7