Table 1: Example 4.1: The maximum absolute errors.

( β„Ž , π‘˜ ) Proposed 𝑂 ( π‘˜ 2 + β„Ž 4 ) method 𝑂 ( π‘˜ 2 + β„Ž 2 ) method
𝛽 = 1 0 𝛽 = 5 0 𝛽 = 1 0 𝛽 = 5 0

ξ‚€ 1 , 1 2 0  1 0 0 . 2 6 4 5 𝐸 −02 0 . 1 9 8 2 𝐸 −01 0 . 9 2 1 2 𝐸 −02 0 . 2 2 4 0 𝐸 +00
ξ‚€ 1 , 1 4 0  2 0 0 . 6 5 6 0 𝐸 −03 0 . 1 8 2 3 𝐸 −02 0 . 2 2 7 9 𝐸 −02 0 . 6 5 1 1 𝐸 −01
ξ‚€ 1 , 1 2 0  4 0 0 . 2 1 6 7 𝐸 −03 0 . 1 8 7 5 𝐸 −01 0 . 1 1 2 5 𝐸 −01 0 . 2 2 5 3 𝐸 +00
ξ‚€ 1 , 1 8 0  4 0 0 . 1 6 3 5 𝐸 −03 0 . 1 5 1 1 𝐸 −03 0 . 5 6 8 2 𝐸 −03 0 . 1 4 1 6 𝐸 −01
ξ‚€ 1 , 1 4 0  8 0 0 . 4 3 5 2 𝐸 −04 0 . 1 6 0 4 𝐸 −02 0 . 2 7 5 5 𝐸 −02 0 . 6 5 3 4 𝐸 0 1