Table 2: Example 4.1: The maximum absolute errors ( π‘˜ / β„Ž 2 = 6 4 ) .

β„Ž Proposed 𝑂 ( π‘˜ 2 + β„Ž 4 ) method 𝑂 ( π‘˜ 4 + β„Ž 4 ) method discussed in [8]
𝛽 = 5 𝛽 = 1 0 𝛽 = 1 5 𝛽 = 5 𝛽 = 1 0 𝛽 = 1 5

1 1 6 0 . 1 8 0 8 𝐸 0 1 0 . 1 6 3 6 𝐸 0 1 0 . 1 4 9 4 𝐸 0 1 0 . 4 4 0 8 𝐸 −01 0 . 4 2 1 2 𝐸 −01 0 . 4 0 1 8 𝐸 −01
1 3 2 0 . 1 1 2 9 𝐸 0 2 0 . 1 0 2 6 𝐸 0 2 0 . 9 3 9 6 𝐸 0 3 0 . 2 6 9 2 𝐸 −02 0 . 2 5 5 4 𝐸 0 2 0 . 2 4 8 2 𝐸 −02
1 6 4 0 . 7 0 5 4 𝐸 0 4 0 . 6 4 1 9 𝐸 0 4 0 . 5 8 8 1 𝐸 0 4 0 . 1 6 4 5 𝐸 −03 0 . 1 5 6 6 𝐸 −03 0 . 1 5 1 2 𝐸 −03