On a Diophantine Equation That Generates All Integral Apollonian Gaskets

Figure 11

Arrangement (𝑏₀,𝑏₁,𝑏₂,𝑏₃)=(−2,3,6,7) or (𝐵,𝜇,𝑘,𝑛)=(2,4,4,5). Left side shows symbols of the principal and other circles, and right side shows Pythagorean triples.