Journal of Applied Mathematics
Volume 2008 (2008), Article ID 753518, 29 pages
doi:10.1155/2008/753518
Research Article

Numerical Blow-Up Time for a Semilinear Parabolic Equation with Nonlinear Boundary Conditions

1Institut National Polytechnique Houphouët-Boigny de Yamoussoukro, BP 1093, Yamoussoukro, Cote D'Ivoire
2Département de Mathématiques et Informatiques, Université d'Abobo-Adjamé, UFR-SFA, 16 BP 372 Abidjan 16, Cote D'Ivoire

Received 29 April 2008; Revised 15 December 2008; Accepted 29 December 2008

Academic Editor: Jacek Rokicki

Copyright © 2008 Louis A. Assalé et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

Abstract

We obtain some conditions under which the positive solution for semidiscretizations of the semilinear equation 𝑢 𝑡 = 𝑢 𝑥 𝑥 𝑎 ( 𝑥 , 𝑡 ) 𝑓 ( 𝑢 ) , 0 < 𝑥 < 1 , 𝑡 ( 0 , 𝑇 ) , with boundary conditions 𝑢 𝑥 ( 0 , 𝑡 ) = 0 , 𝑢 𝑥 ( 1 , 𝑡 ) = 𝑏 ( 𝑡 ) 𝑔 ( 𝑢 ( 1 , 𝑡 ) ) , blows up in a finite time and estimate its semidiscrete blow-up time. We also establish the convergence of the semidiscrete blow-up time and obtain some results about numerical blow-up rate and set. Finally, we get an analogous result taking a discrete form of the above problem and give some computational results to illustrate some points of our analysis.

1. Introduction

In this paper, we consider the following boundary value problem: 𝑢 𝑡 𝑢 𝑥 𝑥 𝑢 = 𝑎 ( 𝑥 , 𝑡 ) 𝑓 ( 𝑢 ) , 0 < 𝑥 < 1 , 𝑡 ( 0 , 𝑇 ) , 𝑥 ( 0 , 𝑡 ) = 0 , 𝑢 𝑥 ( 1 , 𝑡 ) = 𝑏 ( 𝑡 ) 𝑔 𝑢 ( 1 , 𝑡 ) , 𝑡 ( 0 , 𝑇 ) , 𝑢 ( 𝑥 , 0 ) = 𝑢 0 ( 𝑥 ) 0 , 0 𝑥 1 , ( 1 . 1 ) where 𝑓 [ 0 , ) [ 0 , ) is a 𝐶 1 function, 𝑓 ( 0 ) = 0 ,   𝑔 [ 0 , ) [ 0 , ) is a 𝐶 1 convex function, 𝑔 ( 0 ) = 0 , 𝑎 𝐶 0 ( [ 0 , 1 ] × + ) , 𝑎 ( 𝑥 , 𝑡 ) 0 in [ 0 , 1 ] × + , 𝑎 𝑡 ( 𝑥 , 𝑡 ) 0 in [ 0 , 1 ] × + , 𝑏 𝐶 1 ( + ) , 𝑏 ( 𝑡 ) > 0 in + , 𝑏 ( 𝑡 ) 0 in + . The initial data 𝑢 0 𝐶 2 ( [ 0 , 1 ] ) , 𝑢 0 ( 0 ) = 0 , 𝑢 0 ( 1 ) = 𝑏 ( 1 ) 𝑔 ( 𝑢 0 ( 1 ) ) .

Here ( 0 , 𝑇 ) is the maximal time interval on which the solution 𝑢 of (1.1) exists. The time 𝑇 may be finite or infinite. Where 𝑇 is infinite, we say that the solution 𝑢 exists globally. When 𝑇 is finite, the solution 𝑢 develops a singularity in a finite time, namely l i m 𝑡 𝑇 𝑢 ( , 𝑡 ) = + , ( 1 . 2 ) where 𝑢 ( , 𝑡 ) = m a x 0 𝑥 1 | 𝑢 ( 𝑥 , 𝑡 ) | .

In this last case, we say that the solution 𝑢 blows up in a finite time and the time 𝑇 is called the blow-up time of the solution 𝑢 .

In good number of physical devices, the boundary conditions play a primordial role in the progress of the studied processes. It is the case of the problem described in (1.1) which can be viewed as a heat conduction problem where 𝑢 stands for the temperature, and the heat sources are prescribed on the boundaries. At the boundary 𝑥 = 0 , the heat source has a constant flux whereas at the boundary 𝑥 = 1 , the heat source has a nonlinear radition haw. Intensification of the heat source at the boundary 𝑥 = 1 is provided by the function 𝑏 . The function 𝑔 also gives a dominant strength of the heat source at the boundary 𝑥 = 1 .

The theoretical study of blow-up of solutions for semilinear parabolic equations with nonlinear boundary conditions has been the subject of investigations of many authors (see [17], and the references cited therein).

The authors have proved that under some assumptions, the solution of (1.1) blows up in a finite time and the blow-up time is estimated. It is also proved that under some conditions, the blow-up occurs at the point 1. In this paper, we are interested in the numerical study. We give some assumptions under which the solution of a semidiscrete form of (1.1) blows up in a finite time and estimate its semidiscrete blow-up time. We also show that the semidiscrete blow-up time converges to the theoretical one when the mesh size goes to zero. An analogous study has been also done for a discrete scheme. For the semidiscrete scheme, some results about numerical blow-up rate and set have been also given. A similar study has been undertaken in [8, 9] where the authors have considered semilinear heat equations with Dirichlet boundary conditions. In the same way in [10] the numerical extinction has been studied using some discrete and semidiscrete schemes (a solution 𝑢 extincts in a finite time if it reaches the value zero in a finite time). Concerning the numerical study with nonlinear boundary conditions, some particular cases of the above problem have been treated by several authors (see [1115]). Generally, the authors have considered the problem (1.1) in the case where 𝑎 ( 𝑥 , 𝑡 ) = 0 and 𝑏 ( 𝑡 ) = 1 . For instance in [15], the above problem has been considered in the case where 𝑎 ( 𝑥 , 𝑡 ) = 0 and 𝑏 ( 𝑡 ) = 1 . In [16], the authors have considered the problem (1.1) in the case where 𝑎 ( 𝑥 , 𝑡 ) = 𝜆 > 0 , 𝑏 ( 𝑡 ) = 1 , 𝑓 ( 𝑢 ) = 𝑢 𝑝 , 𝑔 ( 𝑢 ) = 𝑢 𝑞 . They have shown that the solution of a semidiscrete form of (1.1) blows up in a finite time and they have localized the blow-up set. One may also find in [1722] similar studies concerning other parabolic problems.

The paper is organized as follows. In the next section, we present a semidiscrete scheme of (1.1). In Section 3, we give some properties concerning our semidiscrete scheme. In Section 4, under some conditions, we prove that the solution of the semidiscrete form of (1.1) blows up in a finite time and estimate its semidiscrete blow-up time. In Section 5, we study the convergence of the semidiscrete blow-up time. In Section 6, we give some results on the numerical blow-up rate and Section 7 is consecrated to the study of the numerical blow-up set. In Section 8, we study a particular discrete form of (1.1). Finally, in the last section, taking some discrete forms of (1.1), we give some numerical experiments.

2. The Semidiscrete problem

Let 𝐼 be a positive integer and define the grid 𝑥 𝑖 = 𝑖 , 0 𝑖 𝐼 , where = 1 / 𝐼 . We approximate the solution 𝑢 of (1.1) by the solution 𝑈 ( 𝑡 ) = ( 𝑈 0 ( 𝑡 ) , 𝑈 1 ( 𝑡 ) , , 𝑈 𝐼 ( 𝑡 ) ) 𝑇 of the following semidiscrete equations 𝑑 𝑈 𝑖 ( 𝑡 ) 𝑑 𝑡 𝛿 2 𝑈 𝑖 ( 𝑡 ) = 𝑎 𝑖 𝑈 ( 𝑡 ) 𝑓 𝑖 ( 𝑡 ) , 0 𝑖 𝐼 1 , 𝑡 0 , 𝑇 𝑏 , ( 2 . 1 ) 𝑑 𝑈 𝐼 ( 𝑡 ) 𝑑 𝑡 𝛿 2 𝑈 𝐼 2 ( 𝑡 ) = 𝑈 𝑏 ( 𝑡 ) 𝑔 𝐼 ( 𝑡 ) 𝑎 𝐼 𝑈 ( 𝑡 ) 𝑓 𝐼 ( 𝑡 ) , 𝑡 0 , 𝑇 𝑏 𝑈 , ( 2 . 2 ) 𝑖 ( 0 ) = 𝜑 𝑖 0 , 0 𝑖 𝐼 , ( 2 . 3 ) 𝜑 𝑖 + 1 𝜑 𝑖 0 𝑖 𝐼 1 where 𝛿 2 𝑈 0 ( 𝑡 ) = 2 𝑈 1 ( 𝑡 ) 2 𝑈 0 ( 𝑡 ) 2 , 𝛿 2 𝑈 𝐼 ( 𝑡 ) = 2 𝑈 𝐼 1 ( 𝑡 ) 2 𝑈 𝐼 ( 𝑡 ) 2 , 𝛿 2 𝑈 𝑖 𝑈 ( 𝑡 ) = 𝑖 + 1 ( 𝑡 ) 2 𝑈 𝑖 ( 𝑡 ) + 𝑈 𝑖 1 ( 𝑡 ) 2 . ( 2 . 4 ) , ( 0 , 𝑇 𝑏 ) , 𝑈 ( 𝑡 ) Here 𝑈 ( 𝑡 ) = m a x 0 𝑖 𝐼 𝑈 𝑖 ( 𝑡 ) is the maximal time interval on which 𝑇 𝑏 is finite where 𝑈 ( 𝑡 ) . When 𝑇 𝑏 is finite, we say that the solution 𝑈 ( 𝑡 ) blows up in a finite time and the time 𝑎 ( 𝑡 ) 𝐶 0 ( [ 0 , 𝑇 ) , 𝐼 + 1 ) is called the blow-up time of the solution 𝑉 ( 𝑡 ) 𝐶 1 ( [ 0 , 𝑇 ) , 𝐼 + 1 ) .

3. Properties of the Semidiscrete Scheme

In this section, we give some lemmas which will be used later.

The following lemma is a semidiscrete form of the maximum principle.Lemma 3.1. Let 𝑑 𝑉 𝑖 ( 𝑡 ) 𝑑 𝑡 𝛿 2 𝑉 𝑖 ( 𝑡 ) + 𝑎 𝑖 ( 𝑡 ) 𝑉 𝑖 𝑉 ( 𝑡 ) 0 , 0 𝑖 𝐼 , 𝑡 ( 0 , 𝑇 ) , 𝑖 ( 0 ) 0 , 0 𝑖 𝐼 . ( 3 . 1 ) and let 𝑉 𝑖 ( 𝑡 ) 0 such that 0 𝑖 𝐼 Then we have 𝑡 ( 0 , 𝑇 ) , 𝑇 0 < 𝑇 , 𝑍 ( 𝑡 ) = 𝑒 𝜆 𝑡 𝑉 ( 𝑡 ) .

Proof. Let 𝜆 and define the vector 𝑎 𝑖 ( 𝑡 ) 𝜆 > 0 where 𝑡 [ 0 , 𝑇 0 ] is large enough that 0 𝑖 𝐼 for 𝑚 = m i n 0 𝑖 𝐼 , 0 𝑡 𝑇 0 𝑍 𝑖 ( 𝑡 ) , 𝑖 { 0 , , 𝐼 } . Let 𝑍 𝑖 ( 𝑡 ) . Since for 𝑡 0 [ 0 , 𝑇 0 ] , 𝑚 = 𝑍 𝑖 0 ( 𝑡 0 ) is a continuous function, there exists 𝑖 0 { 0 , , 𝐼 } such that 𝑑 𝑍 𝑖 0 𝑡 0 𝑑 𝑡 = l i m 𝑘 0 𝑍 𝑖 0 𝑡 0 𝑍 𝑖 0 𝑡 0 𝑘 𝑘 𝛿 0 , 2 𝑍 𝑖 0 𝑡 0 = 𝑍 𝑖 0 + 1 𝑡 0 2 𝑍 𝑖 0 𝑡 0 + 𝑍 𝑖 0 1 𝑡 0 2 0 i f 1 𝑖 0 𝛿 𝐼 1 , 2 𝑍 𝑖 0 𝑡 0 = 2 𝑍 1 𝑡 0 2 𝑍 0 𝑡 0 2 0 i f 𝑖 0 𝛿 = 0 , 2 𝑍 𝑖 0 𝑡 0 = 2 𝑍 𝐼 1 𝑡 0 2 𝑍 𝐼 𝑡 0 2 0 i f 𝑖 0 = 𝐼 . ( 3 . 2 ) for a certain 𝑑 𝑍 𝑖 0 𝑡 0 𝑑 𝑡 𝛿 2 𝑍 𝑖 0 𝑡 0 + 𝑎 𝑖 0 𝑡 0 𝑍 𝜆 𝑖 0 𝑡 0 0 . ( 3 . 3 ) . It is not hard to see that ( 𝑎 𝑖 0 ( 𝑡 0 ) 𝜆 ) 𝑍 𝑖 0 ( 𝑡 0 ) 0 A straightforward computation reveals that 𝑍 𝑖 0 ( 𝑡 0 ) 0 We observe from (3.2) that 𝑎 𝑖 0 ( 𝑡 0 ) 𝜆 > 0 which implies that 𝑉 ( 𝑡 ) 0 because 𝑡 [ 0 , 𝑇 0 ] . We deduce that 𝑉 ( 𝑡 ) for 𝑈 ( 𝑡 ) 𝐶 1 ( [ 0 , 𝑇 ) , 𝐼 + 1 ) and the proof is complete.

Another form of the maximum principle for semidiscrete equations is the following comparison lemma.Lemma 3.2. Let 𝑓 𝐶 0 ( × , ) , 𝑡 ( 0 , 𝑇 ) and 𝑑 𝑉 𝑖 ( 𝑡 ) 𝑑 𝑡 𝛿 2 𝑉 𝑖 𝑉 ( 𝑡 ) + 𝑓 𝑖 < ( 𝑡 ) , 𝑡 𝑑 𝑈 𝑖 ( 𝑡 ) 𝑑 𝑡 𝛿 2 𝑈 𝑖 𝑈 ( 𝑡 ) + 𝑓 𝑖 𝑉 ( 𝑡 ) , 𝑡 , 0 𝑖 𝐼 , ( 3 . 4 ) 𝑖 ( 0 ) < 𝑈 𝑖 ( 0 ) , 0 𝑖 𝐼 . ( 3 . 5 ) such that for 𝑉 𝑖 ( 𝑡 ) < 𝑈 𝑖 ( 𝑡 ) 0 𝑖 𝐼 𝑡 ( 0 , 𝑇 ) . Then we have 𝑍 ( 𝑡 ) = 𝑈 ( 𝑡 ) 𝑉 ( 𝑡 ) , 𝑡 0 , 𝑡 ( 0 , 𝑇 )

Proof. Define the vector 𝑍 𝑖 ( 𝑡 ) > 0 . Let 𝑡 [ 0 , 𝑡 0 ) be the first 0 𝑖 𝐼 such that 𝑍 𝑖 0 ( 𝑡 0 ) = 0 for 𝑖 0 { 0 , , 𝐼 } , 𝑑 𝑍 𝑖 0 𝑡 0 𝑑 𝑡 = l i m 𝑘 0 𝑍 𝑖 0 𝑡 0 𝑍 𝑖 0 𝑡 0 𝑘 𝑘 𝛿 0 , 2 𝑍 𝑖 0 𝑡 0 = 𝑍 𝑖 0 + 1 𝑡 0 2 𝑍 𝑖 0 𝑡 0 + 𝑍 𝑖 0 1 𝑡 0 2 0 i f 1 𝑖 0 𝛿 𝐼 1 , 2 𝑍 𝑖 0 𝑡 0 = 2 𝑍 1 𝑡 0 2 𝑍 0 𝑡 0 2 0 i f 𝑖 0 𝛿 = 0 , 2 𝑍 𝑖 0 𝑡 0 = 2 𝑍 𝐼 1 𝑡 0 2 𝑍 𝐼 𝑡 0 2 0 i f 𝑖 0 = 𝐼 , ( 3 . 6 ) , but 𝑑 𝑍 𝑖 0 𝑡 0 𝑑 𝑡 𝛿 2 𝑍 𝑖 0 𝑡 0 𝑈 + 𝑓 𝑖 0 𝑡 0 , 𝑡 0 𝑉 𝑓 𝑖 0 𝑡 0 , 𝑡 0 0 . ( 3 . 7 ) for a certain 𝑈 . We observe that 𝛿 2 which implies that 𝑈 𝐼 + 1 But this inequality contradicts (3.4) and the proof is complete.

4. Semidiscrete Blow-Up Solutions

In this section under some assumptions, we show that the solution 𝑈 0 of (2.1)–(2.3) blows up in a finite time and estimate its semidiscrete blow-up time.

Before starting, we need the following two lemmas. The first lemma gives a property of the operator 𝛿 2 𝑔 𝑈 𝑖 𝑔 𝑈 𝑖 𝛿 2 𝑈 𝑖 f o r 0 𝑖 𝐼 . ( 4 . 1 ) and the second one reveals a property of the semidiscrete solution.Lemma 4.1. Let 𝑔 𝑈 1 𝑈 = 𝑔 0 + 𝑈 1 𝑈 0 𝑔 𝑈 0 + 𝑈 1 𝑈 0 2 2 𝑔 𝜂 0 , 𝑔 𝑈 𝑖 + 1 𝑈 = 𝑔 𝑖 + 𝑈 𝑖 + 1 𝑈 𝑖 𝑔 𝑈 𝑖 + 𝑈 𝑖 + 1 𝑈 𝑖 2 2 𝑔 𝜃 𝑖 𝑔 𝑈 , 1 𝑖 𝐼 1 , 𝑖 1 𝑈 = 𝑔 𝑖 + 𝑈 𝑖 1 𝑈 𝑖 𝑔 𝑈 𝑖 + 𝑈 𝑖 1 𝑈 𝑖 2 2 𝑔 𝜂 𝑖 𝑔 𝑈 , 1 𝑖 𝐼 1 , 𝐼 1 𝑈 = 𝑔 𝐼 + 𝑈 𝐼 1 𝑈 𝐼 𝑔 𝑈 𝐼 + 𝑈 𝐼 1 𝑈 𝐼 2 2 𝑔 𝜂 𝐼 , ( 4 . 2 ) be such that 𝜃 𝑖 . Then we have 𝑈 𝑖

Proof. Apply Taylor's expansion to obtain 𝑈 𝑖 + 1 where 𝜂 𝑖 is an intermediate between 𝑈 𝑖 1 and 𝑈 𝑖 and 𝛿 2 𝑔 𝑈 0 = 𝑔 𝑈 0 𝛿 2 𝑈 0 + 𝑈 1 𝑈 0 2 2 𝑔 𝜂 0 , 𝛿 2 𝑔 𝑈 𝐼 = 𝑔 𝑈 𝐼 𝛿 2 𝑈 𝐼 + 𝑈 𝐼 1 𝑈 𝐼 2 2 𝑔 𝜂 𝐼 . ( 4 . 3 ) the one between 𝛿 2 𝑔 𝑈 𝑖 = 𝑔 𝑈 𝑖 𝛿 2 𝑈 𝑖 + 𝑈 𝑖 + 1 𝑈 𝑖 2 2 2 𝑔 𝜃 𝑖 + 𝑈 𝑖 1 𝑈 𝑖 2 2 2 𝑔 𝜂 𝑖 , 1 𝑖 𝐼 1 . ( 4 . 4 ) and 𝑔 ( 𝑠 ) 0 . The first and last equalities imply that 𝑠 0 Combining the second and third equalities, we see that 𝑈 0 Use the fact that 𝑈 for 𝑈 𝑖 + 1 ( 𝑡 ) > 𝑈 𝑖 ( 𝑡 ) , 0 𝑖 𝐼 1 , 𝑡 0 , 𝑇 𝑏 . ( 4 . 5 ) and 𝑡 0 to complete the rest of the proof.

Lemma 4.2. Let 𝑡 > 0 be the solution of (2.1)–(2.3). Then we have 𝑈 𝑖 + 1 ( 𝑡 ) > 𝑈 𝑖 ( 𝑡 )

Proof. Let 0 𝑖 𝐼 1 be the first 𝑈 𝑖 0 + 1 ( 𝑡 0 ) = 𝑈 𝑖 0 ( 𝑡 0 ) such that 𝑖 0 { 0 , , 𝐼 1 } for 𝑖 0 but 𝑍 𝑖 ( 𝑡 ) = 𝑈 𝑖 + 1 ( 𝑡 ) 𝑈 𝑖 ( 𝑡 ) for a certain 0 𝑖 𝐼 1 . Without loss of generality, we may suppose that 𝑑 𝑍 𝑖 0 𝑡 0 𝑑 𝑡 = l i m 𝑘 0 𝑍 𝑖 0 𝑡 0 𝑍 𝑖 0 𝑡 0 𝑘 𝑘 𝛿 0 , 2 𝑍 𝑖 0 𝑡 0 = 𝑍 𝑖 0 + 1 𝑡 0 2 𝑍 𝑖 0 𝑡 0 + 𝑍 𝑖 0 1 𝑡 0 2 > 0 i f 1 𝑖 0 𝛿 𝐼 2 , 2 𝑍 𝑖 0 𝑡 0 = 𝛿 2 𝑍 0 𝑡 0 = 𝑍 1 𝑡 0 3 𝑍 0 𝑡 0 2 > 0 i f 𝑖 0 𝛿 = 0 , 2 𝑍 𝑖 0 𝑡 0 = 𝛿 2 𝑍 𝐼 1 𝑡 0 = 𝑍 𝐼 2 𝑡 0 3 𝑍 𝐼 1 𝑡 0 2 > 0 i f 𝑖 0 = 𝐼 1 , ( 4 . 6 ) is the smallest integer which satisfies the equality. Introduce the functions 𝑑 𝑍 𝑖 0 𝑡 0 𝑑 𝑡 𝛿 2 𝑍 𝑖 0 𝑡 0 𝑎 𝑖 0 + 1 𝑡 0 𝑓 𝑈 𝑖 0 + 1 ( 𝑡 0 + 𝑎 𝑖 0 𝑡 0 𝑓 𝑈 𝑖 0 𝑡 0 < 0 i f 0 𝑖 0 𝐼 2 , 𝑑 𝑍 𝑖 0 𝑡 0 𝑑 𝑡 𝛿 2 𝑍 𝑖 0 𝑡 0 + 2 𝑏 𝑡 0 𝑔 𝑖 0 + 1 𝑡 0 𝑎 𝑖 0 + 1 𝑡 0 𝑓 𝑈 𝑖 0 + 1 ( 𝑡 0 + 𝑎 𝑖 0 𝑡 0 𝑓 𝑈 𝑖 0 𝑡 0 < 0 i f 𝑖 0 = 𝐼 1 . ( 4 . 7 ) for 𝑥 𝐼 . We get 𝑈 which implies that 𝛿 2 𝜑 𝑖 𝑎 𝑖 𝜑 ( 0 ) 𝑓 𝑖 𝛿 0 , 1 𝑖 𝐼 1 , 2 𝜑 𝐼 𝑎 𝐼 𝜑 ( 0 ) 𝑓 𝐼 + 𝑏 ( 0 ) 𝑔 𝐼 𝜑 𝐼 𝜑 𝐴 𝑔 𝐼 . ( 4 . 8 ) But this contradicts (2.1)-(2.2) and we have the desired result.

The above lemma says that the semidiscrete solution is increasing in space. This property will be used later to show that the semidiscrete solution attains its minimum at the last node 𝑓 ( 𝑠 ) 𝑔 ( 𝑠 ) 𝑓 ( 𝑠 ) 𝑔 ( 𝑠 ) 0 f o r 𝑠 0 . ( 4 . 9 ) .

Now, we are in a position to state the main result of this section.Theorem 4.3. Let 𝑈 be the solution of (2.1)–(2.3). Suppose that there exists a positive integer A such that 𝑇 𝑏 Assume that 𝑇 𝑏 1 𝐴 + 𝜑 𝑑 𝑠 𝑔 ( 𝑠 ) . ( 4 . 1 0 ) Then the solution ( 0 , 𝑇 𝑏 ) blows up in a finite time 𝑈 ( 𝑡 ) < and we have the following estimate 𝑇 𝑏

Proof. Since 𝐽 is the maximal time interval on which 𝐽 𝑖 ( 𝑡 ) = 𝑑 𝑈 𝑖 ( 𝑡 ) 𝑑 𝑡 , 0 𝑖 𝐼 1 , 𝐽 𝐼 ( 𝑡 ) = 𝑑 𝑈 𝐼 ( 𝑡 ) 𝑈 𝑑 𝑡 𝐴 𝑔 𝐼 ( 𝑡 ) . ( 4 . 1 1 ) , our aim is to show that 𝑑 𝐽 𝑖 𝑑 𝑡 𝛿 2 𝐽 𝑖 = 𝑑 𝑑 𝑡 𝑑 𝑈 𝑖 𝑑 𝑡 𝛿 2 𝑈 𝑖 , 0 𝑖 𝐼 1 , 𝑑 𝐽 𝐼 𝑑 𝑡 𝛿 2 𝐽 𝐼 = 𝑑 𝑑 𝑡 𝑑 𝑈 𝐼 𝑑 𝑡 𝛿 2 𝑈 𝐼 𝐴 𝑔 𝑈 𝐼 𝑑 𝑈 𝐼 𝑑 𝑡 + 𝐴 𝛿 2 𝑔 𝑈 𝐼 . ( 4 . 1 2 ) is finite and satisfies the above inequality. Introduce the vector 𝛿 2 𝑔 ( 𝑈 𝐼 ) 𝑔 ( 𝑈 𝐼 ) 𝛿 2 𝑈 𝐼 such that 𝑑 𝐽 𝐼 𝑑 𝑡 𝛿 2 𝐽 𝐼 𝑑 𝑑 𝑡 𝑑 𝑈 𝐼 𝑑 𝑡 𝛿 2 𝑈 𝐼 𝐴 𝑔 𝑈 𝐼 𝑑 𝑈 𝐼 𝑑 𝑡 𝛿 2 𝑈 𝐼 . ( 4 . 1 3 ) A straightforward calculation gives 𝑑 𝐽 𝑖 𝑑 𝑡 𝛿 2 𝐽 𝑖 𝑎 𝑖 𝑈 ( 𝑡 ) 𝑓 𝑖 𝑎 𝑖 ( 𝑡 ) 𝑓 𝑈 𝑖 𝑑 𝑈 𝑖 𝑑 𝑡 , 0 𝑖 𝐼 1 , 𝑑 𝐽 𝐼 𝑑 𝑡 𝛿 2 𝐽 𝐼 𝑎 𝐼 𝑈 ( 𝑡 ) 𝑓 𝐼 𝑎 𝐼 ( 𝑡 ) 𝑓 𝑈 𝐼 𝑑 𝑈 𝐼 + 2 𝑑 𝑡 𝑏 𝑈 ( 𝑡 ) 𝑔 𝐼 + 2 𝑏 ( 𝑡 ) 𝑔 𝑈 𝐼 𝑑 𝑈 𝐼 𝑑 𝑡 𝐴 𝑔 𝑈 𝐼 𝑎 𝐼 𝑈 ( 𝑡 ) 𝑓 𝐼 + 2 𝑈 𝑏 ( 𝑡 ) 𝑔 𝐼 . ( 4 . 1 4 ) From Lemma 4.1, we have 𝑎 𝑖 ( 𝑡 ) 0 which implies that 𝑏 ( 𝑡 ) 0 Using (2.1), we get 𝑑 𝑈 𝑖 / 𝑑 𝑡 = 𝐽 𝑖 + 𝐴 𝑔 ( 𝑈 𝑖 ) It follows from the fact that 𝑑 𝐽 𝐼 𝑑 𝑡 𝛿 2 𝐽 𝐼 𝑎 𝐼 ( 𝑡 ) 𝑓 𝑈 𝐼 + 2 𝑏 ( 𝑡 ) 𝑔 𝑈 𝐼 𝐽 𝐼 + 𝐴 𝑎 𝐼 𝑔 ( 𝑡 ) 𝑈 𝐼 𝑓 𝑈 𝐼 𝑓 𝑈 𝐼 𝑔 𝑈 𝐼 . ( 4 . 1 5 ) , 𝑑 𝐽 𝑖 𝑑 𝑡 𝛿 2 𝐽 𝑖 𝑎 𝑖 ( 𝑡 ) 𝑓 𝑈 𝑖 𝐽 𝑖 , 0 𝑖 𝐼 1 , 𝑑 𝐽 𝐼 𝑑 𝑡 𝛿 2 𝐽 𝐼 𝑎 𝐼 ( 𝑡 ) 𝑓 𝑈 𝐼 + 2 𝑏 ( 𝑡 ) 𝑔 𝑈 𝐼 𝐽 𝐼 . ( 4 . 1 6 ) and 𝐽 𝑖 ( 0 ) = 𝛿 2 𝜑 𝑖 𝑎 𝑖 𝜑 ( 0 ) 𝑓 𝑖 𝐽 0 , 0 𝑖 𝐼 1 , 𝐼 ( 0 ) = 𝛿 2 𝜑 𝐼 𝑎 𝐼 𝜑 ( 0 ) 𝑓 𝐼 + 𝑏 ( 0 ) 𝑔 𝐼 𝜑 𝐼 𝜑 𝐴 𝑔 𝐼 0 . ( 4 . 1 7 ) that 𝐽 𝑖 ( 𝑡 ) 0 We deduce from (4.9) that 0 𝑖 𝐼 From (4.8), we observe that 𝑑 𝑈 𝐼 / 𝑑 𝑡 𝑔 ( 𝑈 𝐼 ) We deduce from Lemma 3.1 that 0 𝑖 𝐼 , 𝑑 𝑈 𝐼 𝑔 𝑈 𝐼 𝐴 𝑑 𝑡 . ( 4 . 1 8 ) , which implies that ( 𝑡 , 𝑇 𝑏 ) , 𝑇 𝑏 1 𝑡 𝐴 𝑈 + 𝐼 ( 𝑡 ) 𝑑 𝑠 𝑔 ( 𝑠 ) , ( 4 . 1 9 ) . Obviously we have 𝑇 𝑏 1 𝐴 + 𝑈 ( 0 ) 𝑑 𝑠 𝑔 ( 𝑠 ) . ( 4 . 2 0 ) Integrating this inequality over 𝑈 , we arrive at 𝑈 ( 0 ) = 𝜑 which implies that 𝑇 𝑏 𝑡 0 1 𝐴 + 𝑈 ( 𝑡 0 ) 𝑑 𝑠 𝑔 ( 𝑠 ) i f 0 < 𝑡 0 < 𝑇 𝑏 , 𝑈 𝑖 𝐴 𝑇 ( 𝑡 ) 𝐻 𝑏 𝑡 , 0 𝑖 𝐼 , ( 4 . 2 1 ) Since the quantity on the right hand side of the above inequality is finite, we deduce that the solution 𝐻 ( 𝑠 ) blows up in a finite time. Use the fact that 𝐺 ( 𝑠 ) = 𝑠 + ( 𝑑 𝑧 / 𝑔 ( 𝑧 ) ) to complete the rest of the proof.

Remark 4.4. The inequality (4.19) implies that 𝑔 ( 𝑠 ) = 𝑠 𝑞 where 𝐺 ( 𝑠 ) = 𝑠 1 𝑞 / ( 𝑞 1 ) is the inverse of 𝐻 ( 𝑠 ) = ( ( 𝑞 1 ) 𝑠 ) 1 / ( 1 𝑞 ) .

Remark 4.5. If [ 0 , 𝑇 ] , then 𝑢 and 𝑈 ( 𝑡 ) .

5. Convergence of the Semidiscrete Blow-Up Time

In this section, we show the convergence of the semidiscrete blow-up time. Now we will show that for each fixed time interval 𝑢 where is defined, the solution 𝑢 𝐶 4 , 1 ( [ 0 , 1 ] × [ 0 , 𝑇 ] ) of (2.1)–(2.3) approximates 𝜑 𝑢 ( 0 ) = 𝑜 ( 1 ) a s 0 , ( 5 . 1 ) , when the mesh parameter 𝑢 ( 𝑡 ) = ( 𝑢 ( 𝑥 0 , 𝑡 ) , , 𝑢 ( 𝑥 𝐼 , 𝑡 ) ) 𝑇 goes to zero.Theorem 5.1. Assume that (1.1) has a solution 𝑈 𝐶 1 ( [ 0 , 𝑇 ] , 𝐼 + 1 ) and the initial condition at (2.3) satisfies m a x 0 𝑡 𝑇 𝑈 ( 𝑡 ) 𝑢 ( 𝑡 ) 𝜑 = 𝑂 𝑢 ( 0 ) + 2 a s 0 . ( 5 . 2 ) where 𝛼 > 0 . Then, for h sufficiently small, the problem (2.1)–(2.3) has a unique solution 𝑢 ( , 𝑡 ) 𝛼 f o r 𝑡 [ 0 , 𝑇 ] . ( 5 . 3 ) such that

Proof. Let 𝑈 𝐶 1 ( [ 0 , 𝑇 𝑏 ) , 𝐼 + 1 ) be such that 𝑡 ( ) m i n { 𝑇 , 𝑇 𝑏 } The problem (2.1)–(2.3) has for each 𝑡 > 0 , a unique solution 𝑈 ( 𝑡 ) 𝑢 ( 𝑡 ) < 1 f o r 𝑡 0 , 𝑡 ( ) . ( 5 . 4 ) . Let 𝑡 ( ) > 0 the greatest value of such that 𝑈 ( 𝑡 ) 𝑢 ( , 𝑡 ) + 𝑈 ( 𝑡 ) 𝑢 ( 𝑡 ) f o r 𝑡 0 , 𝑡 ( ) , ( 5 . 5 ) The relation (5.1) implies that 𝑈 ( 𝑡 ) 1 + 𝛼 f o r 𝑡 0 , 𝑡 ( ) . ( 5 . 6 ) for 𝑒 ( 𝑡 ) = 𝑈 ( 𝑡 ) 𝑢 ( 𝑡 ) sufficiently small. By the triangle inequality, we obtain 𝑡 ( 0 , 𝑡 ( ) ) which implies that 𝑑 𝑒 𝑖 ( 𝑡 ) 𝑑 𝑡 𝛿 2 𝑒 𝑖 ( 𝑡 ) = 𝑎 𝑖 ( 𝑡 ) 𝑓 𝜉 𝑖 𝑒 ( 𝑡 ) 𝑖 ( 𝑡 ) + 𝑜 2 , 0 𝑖 𝐼 1 , 𝑑 𝑒 𝐼 ( 𝑡 ) 𝑑 𝑡 𝛿 2 𝑒 𝐼 ( 𝑡 ) = 𝑎 𝐼 ( 𝑡 ) 𝑓 𝜉 𝐼 𝑒 ( 𝑡 ) 𝐼 2 ( 𝑡 ) + 𝑏 ( 𝑡 ) 𝑔 𝑈 𝐼 𝑒 ( 𝑡 ) 𝐼 ( 𝑡 ) + 𝑜 2 , ( 5 . 7 ) Let 𝜃 𝐼 ( 𝑡 ) be the error of discretization. Using Taylor's expansion, we have for 𝑈 𝐼 ( 𝑡 ) , 𝑢 ( 𝑥 𝐼 , 𝑡 ) where 𝜉 𝑖 ( 𝑡 ) is an intermediate value between 𝑈 𝑖 ( 𝑡 ) and 𝑢 ( 𝑥 𝑖 , 𝑡 ) and 𝐾 the one between 𝐿 and 𝑑 𝑒 𝑖 ( 𝑡 ) 𝑑 𝑡 𝛿 2 𝑒 𝑖 | | | 𝑒 ( 𝑡 ) 𝐿 𝑖 | | | ( 𝑡 ) + 𝐾 2 , 0