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Journal of Applied Mathematics
Volume 2013 (2013), Article ID 853476, 10 pages
A Generalized Nonlinear Gronwall-Bellman Inequality with Maxima in Two Variables
Department of Mathematics, Sichuan University for Nationalities, Kangding, Sichuan 626001, China
Received 15 November 2012; Accepted 20 January 2013
Academic Editor: Jitao Sun
Copyright © 2013 Yong Yan. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
This paper deals with a generalized form of nonlinear retarded Gronwall-Bellman type integral inequality in which the maximum of the unknown function of two variables is involved. This form includes both a nonconstant term outside the integrals and more than one distinct nonlinear integrals. Requiring neither monotonicity nor separability of given functions, we apply a technique of monotonization to estimate the unknown function. Our result can be used to weaken conditions for some known results. We apply our result to a boundary value problem of a partial differential equation with maxima for uniqueness.
The Gronwall-Bellman inequality [1, 2] plays an important role in the study of existence, uniqueness, boundedness, stability, invariant manifolds, and other qualitative properties of solutions of differential equations and integral equations. There can be found a lot of its generalizations in various cases from literatures (see, e.g., [3–18]). In 1956, Bihari  discussed the integral inequality where is a constant, is a continuous and nonnegative function, and is a continuous and nondecreasing positive function. Replacing by a function in (1), Lipovan  investigated the retarded integral inequality Their results were further generalized by Agarwal et al.  to the inequality where the constant is replaced with a function , ’s are continuously differentiable and nondecreasing functions, and ’s are continuous and nondecreasing positive functions such that that is, each ratio is also nondecreasing on , called in  that is stronger nondecreasing than . On the basis of this work, Wang  considered the inequality of two variables where the functions , , and are not required to be monotone, and those ’s are not required to be stronger monotone than the one after the next as shown in (4). This inequality belongs to both the case of multivariables, to which great attentions [7–11] have been paid, and to the case that the left-hand side is a composition of the unknown function with a known function, in which Ou-Iang's idea  was applied [11–14]. He applied a technique of monotonization to construct a sequence of functions, made each function possess stronger monotonization than the previous one, and gave an estimate for the unknown function .
On the other aspect, many problems in the control theory can be modeled in the form of differential equations with the maxima of the unknown function [20–22]. In connection with the development of the theory of differential equations with maxima (see, e.g., [20, 21, 23]) and partial differential equations with maxima [24, 25], a new type of integral inequalities with maxima is required, respectively. There have been given some results for integral inequalities containing the maxima of the unknown function [23, 26–28]. Concretely, in 2012, Bohner et al.  discussed the following system of integral inequalities: where , ’s, ’s, , and are nonnegative continuous functions and ’s are nonnegative continuously differentiable and nondecreasing functions. They required that , is on and increasing such that for , and satisfies the following: (i) is an increasing function, and (ii) for all and . Bainov and Hristova  considered the following system: where is nonnegative and nondecreasing in both of its arguments, , , and are continuous and nonnegative functions, and .
In this paper, we consider the system of integral inequalities as follows: where , ’s, ’s, and are continuous and nonnegative functions, ’s and ’s are nonnegative continuously differentiable and nondecreasing functions, and . As required in previous works [27–29], we suppose that , , is constant. In this paper, we require neither monotonicity of , 's, 's, and nor . We monotonize those ’s to make a sequence of functions in which each one possesses stronger monotonicity than the previous one so as to give an estimation for the unknown function. We can use our result to discuss inequalities (6) and (7), giving the stronger results under weaker conditions. We finally apply the obtained result to a boundary value problem of a partial differential equation with maxima for uniqueness.
2. Main Result
Consider system (8) of integral inequalities with and in . Let , . Suppose that(H1) and , , are nondecreasing such that on , on and ; (H2) all ’s are continuous and nonnegative functions on ;(H3) and are continuous, and is strictly increasing such that ; (H4) all ’s () are continuous on and positive on ; (H5) is a continuous and nonnegative function on .
For those ’s given in (), define , , inductively by for and for , where for , if or if for , and be a given very small constant.
Theorem 1. Suppose that hold, for all and satisfies the system (8) of integral inequalities. Then, for all , where is the inverse of the function is a given constant, is defined just before the theorem, and is defined recursively by for , and are chosen such that for .
For the special choice that , , , , , , , , and , where is a nonnegative continuously differentiable and nondecreasing function, Theorem 1 gives an estimate for the unknown in the system (7). we require neither the monotonicity of nor the monotonicity of . Obviously, Lemma 2 and Theorem 1 are applicable to more general forms than Corollary 2.3.4 in . Even if is enlarged to such that (8) is changed into the form of in , where , our theorem gives a better estimate. For example, the system of inequalities implies that by enlarging to . Applying Theorem 1, we obtain On the other hand, Theorem 2.2 of  gives from (17) that Clearly, (18) is sharper than (19) for large and .
In order to prove Theorem 1, we need the following lemma.
Lemma 2. Suppose that (C1) and are nondecreasing such that on and on and ;(C2), for ; (C3) all ’s are continuous and nondecreasing on and positive on such that ; (C4) is continuously differentiable in and , nonnegative on , and for all .
If satisfies the system of inequalities as follows: then for all , where is the inverse of the function is a given constant, and is defined recursively by for , and are chosen such that for .
Proof. From (23), we see that is nondecreasing on , , and for . It implies from (20) that for all . LetClearly, is nondecreasing in . Then, we have From (25), (27), and (28) and the definition of on , we get Applying Theorem 1 of  to the case that , , , and , , we obtain (21) from (28). This completes the proof.
Proof of Theorem 1. First of all, we monotonize some given functions , , , and in the system (8) of integral inequalities. Let
From (13), we see that the function is strictly increasing, and therefore its inverse is well defined, continuous, and increasing in its domain. The sequence , defined by , consists of nondecreasing nonnegative functions on and satisfies
because the ratios , , are all nondecreasing. Furthermore, let
which is nondecreasing in and for each fixed and and satisfies for all . The monotonicity of implies that
for . From (8) and the definition of , we obtain
Concerning (34), we consider the auxiliary system of inequalities
where and are chosen arbitrarily, and claim
for all , , where
, is defined inductively by
for , and are chosen such that
Notice that we may take and . In fact, the monotonicity that and are both nondecreasing in and for fixed , . Furthermore, it is easy to check that , for . If , are replaced with , , respectively, on the left side of (39), we get from (15) that Thus, it means that we can take , .
Now, we prove (36) by induction. From (33), (35), and the definitions of , , and , we obtain for all , where and are chosen arbitrarily. Since and , we have . Define a function byClearly, is nondecreasing in . By (41) and the definition of , we have Then noting that is nondecreasing and is strictly increasing, from (43), we obtain It follows from (43), (44), and the definition of that In order to demonstrate the basic condition of monotonicity, let , which is clearly a continuous and nondecreasing function on . Thus, each is continuous and nondecreasing on and satisfies for . Moreover, since , is also continuous and nondecreasing on and positive on , implying that , for . By Lemma 2 and (45), for and . It follows from (43) and (46) that for and . This proves the claimed (36).
Taking , , and in (36), we have for all , . It is easy to verify . Thus, (48) can be written as Since are arbitrary, replacing and with and , respectively, we get for all . This completes the proof.
In this section, we apply our result to prove the boundedness of solutions for a differential equation with the maxima.
Consider a system of partial differential equations with maxima where , , are nondecreasing such that , , and ( is a positive constant) for , , and , satisfy that and , for all .
Corollary 3. Suppose that functions and in (51) satisfy where and , . Then, any solution of (51) has the estimate for all , where and , are given as in Theorem 1, and constants , are given arbitrarily.
Next, we discuss the uniqueness of solutions for system (51).
Corollary 4. Suppose that and for all and all , where and are both nondecreasing such that , for , is also nondecreasing, and , . Then, system (51) has at most one solution on .
Proof. . From (51), we get Assume that (59) has two different solutions and . From the equivalent integral equation system (55), we have for all . The continuity of the function implies that for any fixed points and there exists a point such that the inequality holds, and therefore Hence, Let Because , from (62), we obtain Applying Theorem 1 to specified , , , , , , , , and , from (64), we obtain for all , where By the definition of and properties of , noting that , we obtain Since is finite on a finite interval, and , by (67), we obtain Thus, we obtain from (68), (69), and (70) immediately. Similarly, noting that is finite on finite interval,