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Journal of Applied Mathematics
Volume 2014 (2014), Article ID 780486, 7 pages
The Existence and Application of Unbounded Connected Components
1School of Mathematics and Quantitative Economics, Dongbei University of Finance and Economics, Dalian 116025, China
2Department of Mathematics, Northwest Normal University, Lanzhou 730070, China
Received 25 December 2013; Accepted 5 March 2014; Published 6 April 2014
Academic Editor: Bo-Qing Dong
Copyright © 2014 Hua Luo and Ruyun Ma. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
Let X be a Banach space and a family of connected subsets of . We prove the existence of unbounded components in superior limit of , denoted by , which have prescribed shapes. As applications, we investigate the global behavior of the set of positive periodic solutions to nonlinear first-order differential equations with delay, which can be used for modeling physiological processes.
1. Introduction and the Main Results
The connectivity result on the fixed set of a -parameter family of maps, which goes back to Leray and Schauder  and was proved in its full generality by Browder , is a useful tool in the study of global continua of solutions on nonlinear differential equations. Costa and Gonçalves  stated and proved a suitable version for the study of nonlinear boundary value problems at resonance. Massabò and Pejsachowicz  generalized the main results of [1, 2] to the -parameter family of compact vector fields. The above results were established when the parameter(s) changes in a bounded set. Sun and Song  proved the existence of unbounded connected component of -parameter family of compact vector fields, where the parameter varies on whole real line. All of these results play important roles in the study of nonlinear functional analysis and nonlinear differential equations.
For clearly reading, we firstly recall Kuratowski's definitions and notations in .
Let be a metric space. Let be a family of subsets of . Then the superior limit of is defined by
A component of a set means a maximal connected subset of .
Definition 1. Let be a Banach space with the norm . Let be a component of solutions in . meets and infinity means that there existed a sequence such that as .
For , let us denote
Let be a family of connected subsets of . The purpose of this paper is to study the existence of unbounded components in which have prescribed shapes.
More precisely, we will prove the following theorems.
Theorem 2. Let be a Banach space and let be a family of connected subsets of . Assume that(A1)there exist and , such that (A2) and meets and infinity;(A3)for every , is a relatively compact set of , where Then there exists a component in satisfying(a) meets and infinity;(b).
Theorem 3. Let be a constant. Let be a Banach space, and let be a family of connected subsets of . Assume that(H1); (H2)there exist and , such that (H3) for all , and meets and infinity in ;(H4)for every , is a relatively compact set of . Then there exists a component in such that(a)both and are unbounded;(b).
2. Proofs of the Main Results
Lemma 4 (see [7, Lemma 2.2]). Let be a Banach space with the norm . Let be a family of connected subsets of . Assume that(i)there exist , , and , such that ;(ii), where ;(iii)for every , is a relatively compact set of , where Then there exists an unbounded component in and .
Proof of Theorem 2. (a) It is a direct consequence of Lemma 4.
(b) Assume, on the contrary, that the conclusion is not true. Then there exists with and . Hence, there exists , such that Thus, there exists , such that, for , However, this contradicts (3).
Proof of Theorem 3. (a) Since , we may assume that
So, it follows from conditions (ii) and (iii) that meets and infinity in .
For each , let be a component containing . Let
Set Then since From Lemma 4, it follows that is closed in , and, furthermore, is compact in .
Let By Lemma 4, contains a component which meets and infinity in . Obviously
If for some , then Theorem 3 holds.
Assume, on the contrary, that for all .
For every , let be the component in which contains . Using the standard method, we can find a bounded open set in , such that and for every , where and are the boundary and closure of in , respectively.
Evidently, the following family of the open sets of is an open covering of . Since is compact set in , there exist such that , and the family of open sets in is a finite open covering of . This implies that
Let Then is a bounded open set in , and by (16), we have where and are the boundary and closure of in , respectively.
Now, (22) together with (19) and (21) implied that However, this contradicts .
Therefore, there exists such that which is unbounded in both and .
(b) By a fully analogous argument as in the proof of Theorem 2(b) (with minor modifications), one can immediately obtain the desired results.
3. Application to Functional Differential Equations
In recent years, there has been considerable interest in the existence of -periodic solutions of the equation where are -periodic functions and is a continuous -periodic function. Equation (24) has been proposed as a model for a variety of physiological processes and conditions including production of blood cells, respiration, and cardiac arrhythmias. See, for example, [8–20] and the references therein.
Recently, Wang  used the fixed point index [20, 21] to study the existence, multiplicity, and nonexistence of positive solutions of (24) under the following assumptions.(C1) are -periodic functions, , on ; is -periodic functions.(C2) are continuous. for , are given positive constants. for .
Let and denote His results provide no any information about the global behavior of the set of positive solutions of (24).
In this section, we will use Theorems 2 and 3 to establish several results on the global behavior of the set of positive solutions of (24), and, accordingly, we get some existence and multiplicity results of positive solutions of (24).
We will work essentially in the Banach space - with sup norm .
Let be the closure of the set of positive solutions of (24).
We extend the function to a continuous function defined on in such a way that for all . For , we then look at arbitrary solutions of the eigenvalue problem It was shown in  that (26) is equivalent to where By the positivity of Green's function , , and , such solutions are positive. Therefore, the closure of the set of nontrivial solutions of (24) in is exactly .
Next, we consider the spectrum of the linear eigenvalue problem
Lemma 5. Let be a positive constant. Then the linear problem (29) has a unique eigenvalue , which is positive and simple, and the corresponding eigenfunction is of one sign.
Proof. Define an operator by Let be the cone Then it follows from [18, Lemma 2.2] that is strongly positive and completely continuous. Thus, the desired result is a direct consequence of Krein-Rutman Theorem, cf. [22, Theorem 19.3].
Theorem 6. Let (C1)-(C2) hold. Assume that(C3). Then contains a component satisfying(1) meets and ;(2)for every , there exists , such that
Corollary 7. Let (C1)–(C3) hold. Then there is a constant such that (24) has at least two positive solutions as .
Denote the cone in by and for , let
Define an operator by
Lemma 8 (see ). Assume that (C1)-(C2) hold. Then is completely continuous.
Lemma 9. Let (C1)-(C2) hold. If , then where .
Proof. It is well known from Wang  that This together with the fact that is -periodic and on implies that
To prove above Theorem 6, we define by Then with By (C3), it follows that
Now let us consider the auxiliary family of the equations Let be such that Note that Define a linear operator with From , it follows that is compact and continuous.
Since , the results of Nonlinear Krein-Rutman Theorem (see Dancer  and Zeidler [23, Corollary 15.12]) for (48) can be stated as follows: there exists a continuum of positive solutions of (48) joining to infinity in . Moreover, and is the only bifurcation point of (48) lying on trivial solutions line .
Proof of Theorem 6. Let us verify that satisfies all of the conditions of Theorem 2.
It follows from (42) that as . Therefore, (A2) holds.
Let be fixed. Then there exists , such that Thus From this and Lemma 9, it follows that there exists with , such that (48) has no solution with Since is arbitrary, we see that (A1) is satisfied.(A3)can be deduced directly from the Arzela-Ascoli Theorem and the definition of .
Therefore, the superior limit of contains an unbounded component with .
Finally, we show that meets and .
Let with We claim that .
Assume on the contrary that . Let Then So on as . This contradicts (58). Thus (55) implies that
Assume on the contrary that ( after taking a subsequence and relabeling if necessary).
Since on , it follows from (59) that uniformly on . This together with implies on as . This contradicts (58) again.
Theorem 10. Let (C1)-(C2) hold. Assume that(C4). Then contains a component satisfying the following.(1)For given , (2)For every , there exists , such that
Corollary 11. Let (C1)-(C2) and (C4) hold. Then there is a constant such that (24) has at least two positive solutions as .
By similar method to deal with (48) in which , we have from and [23, Corollary 15.12]) that there exists a continuum of positive solutions of (63) joining to infinity in . Moreover, and is the only bifurcation point of (48) lying on trivial solutions line .
Lemma 12. Assume that (C1)-(C2) hold. If , then where
Proof. Since and for , it follows that
Lemma 13. Assume that (C1)-(C2) and (C4) hold, and let be a compact subinterval of . Then for some positive constant , independent of , and .
Proof. Assume on the contrary that there exists a sequence such that Set . Then By (72), is bounded in . This together with the fact that implies that there exists with such that (after choosing a subsequence and relabeling if necessary). Since is bounded in , is bounded in , and subsequently, for some . By the standard method, we can prove that Moreover, combining (75) and (76) with the assumption and the corresponding integral equations of (72) and (73) and using Lebesgue dominated convergence theorem, we conclude that Note that and on . This means that . However, this contradicts (78).
Now, we are in the position to prove Theorem 10.
Proof of Theorem 10 (sketched). fixed . From Lemma 12, it follows that (63) has no solution if
Applying Lemma 13, it is easy to verify that satisfies all of the conditions of Theorem 3. So, there exists a component in such that(a)both and are unbounded;(b). Lemma 13 guarantees that satisfies
Conflict of Interests
The authors declare that there is no conflict of interests regarding the publication of this paper.
The authors are very grateful to the anonymous referees for their valuable suggestions. The research was supported by the NSFC (nos. 11301059 and 11361054) and HSSF of Ministry of Education of China (no. 13YJA790078).
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