Abstract

We will prove the duality and reflexivity of variable exponent Triebel-Lizorkin and Besov spaces. It was shown by many authors that variable exponent Triebel-Lizorkin spaces coincide with variable exponent Bessel potential spaces, Sobolev spaces, and Lebesgue spaces when appropriate indices are chosen. In consequence of the results, these variable exponent function spaces are shown to be reflexive.

1. Introduction

Recently, variable exponent function spaces have been studied by many authors [113], and in particular, the papers about the variable exponent Triebel-Lizorkin and Besov spaces have been published in [1418]. Diening et al. [15] and Almeida and Hästö [14] studied the spaces 𝐹𝛼()𝑝(),𝑞() and 𝐵𝛼()𝑝(),𝑞() and Xu studied [1618] the spaces 𝐹𝑠𝑝(),𝑞(𝑛) and 𝐵𝑠𝑝(),𝑞(𝑛).

In this paper, we will show the duality of variable exponent Triebel-Lizorkin spaces 𝐹𝑠𝑝(),𝑞(𝑛) and Besov spaces 𝐵𝑠𝑝(),𝑞(𝑛) under suitable conditions by using the same arguments in Triebel [19]. The duality follows from the fact that 𝐹𝑠𝑝(),𝑞(𝑛) and 𝐵𝑠𝑝(),𝑞(𝑛) are reflexive under same conditions.

Xu [16] showed that variable exponent Bessel potential space 𝐿𝑠,𝑝()(𝑛) coincides with 𝐹𝑠𝑝(),2(𝑛) if 𝑠0 and 𝑝()(𝑛). Diening et al. [15] showed that the variable exponent Lebesgue space 𝐿𝑝()(𝑛) coincides with 𝐹0𝑝(),2(𝑛) under suitable assumptions on 𝑝(). Gurka et al. [7] showed that 𝐿𝑘,𝑝()(𝑛) coincides with variable exponent Sobolev spaces 𝑊𝑘,𝑝()(𝑛) if 𝑘 and 𝑝()(𝑛). In consequences of these results, we have the duality and reflexivity of 𝐿𝑠,𝑝()(𝑛)(𝑠0), although the duality and reflexivity of 𝐿𝑝()(𝑛) have been obtained in Kováčik and Rákosník [9] under the assumptions on 𝑝() which are weaker than ours.

2. Definitions of Variable Exponent Function Spaces

We first introduce variable exponent Lebesgue spaces. Let 𝑝() be a measurable function on 𝑛 with range in (1,). Let 𝐿𝑝()(𝑛) denote the set of all complex-valued functions 𝑓 on 𝑛 such that, for some 𝜆>0, 𝑛|𝑓(𝑥)|𝜆𝑝(𝑥)d𝑥<.(2.1) The set becomes a Banach function space when it is equipped with the Luxemburg-Nakano norm: 𝑓𝐿𝑝()=inf𝜆>0𝑛|𝑓(𝑥)|𝜆𝑝(𝑥)d𝑥1.(2.2) If 𝑝(𝑥)𝑝 is a constant function, then the above norm coincides with the usual 𝐿𝑝-norm and so the notation is not confusional. In Kováčik and Rákosník [9], variable exponent Lebesgue spaces are defined on arbitrary measurable subset of 𝑛. Denote by 𝒫(𝑛) the set of measurable functions 𝑝() on 𝑛 with range in (1,) such that 1<𝑝=essinf𝑥𝑛𝑝(𝑥),esssup𝑥𝑛𝑝(𝑥)=𝑝+<.(2.3) For a complex-valued locally Lebesgue-integrable function 𝑓() on 𝑛, let (1𝑓)(𝑥)=sup||𝐵||𝐵||||𝑓(𝑦)d𝑦(2.4) denote the Hardy-Littlewood maximal function, where the supremum is taken over all balls 𝐵 centered at 𝑥. There exists 𝑝()𝒫(𝑛) such that the Hardy-Littlewood maximal operator is not bounded on 𝐿𝑝()(𝑛) [11], although the operator is bounded on 𝐿𝑝(𝑛) for 𝑝>1. Some sufficient conditions on 𝑝() for maximal operator to be bounded on 𝐿𝑝()(𝑛) are known. Let (𝑛) be the set of 𝑝()𝒫(𝑛) such that the Hardy-Littlewood maximal operator is bounded on 𝐿𝑝()(𝑛).

Let 𝒮(𝑛) be the Schwartz space of all complex-valued rapidly decreasing and infinitely differentiable functions on 𝑛. Let 𝒮(𝑛) be the set of all the tempered distribution on 𝑛. For 𝜑𝒮(𝑛), let 𝜑 denote the Fourier transform of 𝜑 and 1𝜑 the inverse Fourier transform of 𝜑. We write 1𝑚𝑓=1[𝑚𝑓] for the sake of simplicity.

Let 𝑠0 and 𝑝()𝒫(𝑛). The variable exponent Bessel potential space 𝐿𝑠,𝑝()(𝑛) is the collection of 𝑓𝐿𝑝()(𝑛) such that the norm: 𝑓𝐿𝑠,𝑝()=11+||2𝑠/2𝑓()𝐿𝑝()<.(2.5)

Let 𝑘 and 𝑝𝒫(𝑛). The variable exponent Sobolev space 𝑊𝑘,𝑝()(𝑛) is the collection of 𝑓𝐿𝑝()(𝑛) such that the derivatives (in the sense of distribution) up to the order 𝑘 belong to 𝐿𝑝()(𝑛) and the norm: 𝑓𝑊𝑘,𝑝()=|𝛼|𝑘𝐷𝛼𝑓𝐿𝑝()<,(2.6) where 𝛼 is a multi-index and |𝛼|=𝛼1++𝛼𝑛.

Let Φ𝒮(𝑛) be a function such that suppΦ𝐵(0,1) and Φ=1 on 𝐵(0,1/2), where 𝐵(0,𝜆) is an open ball centered at 0 with radius 𝜆. Set Φ𝑗(𝑥)=2𝑛𝑗Φ(2𝑗𝑥) for 𝑥𝑛 and 𝑗. We also set 𝜃𝑗(𝑥)=Φ𝑗(𝑥)Φ𝑗1(𝑥).(2.7) It follows that 𝑗=0𝜃𝑗(𝜉)1,(2.8) where 𝜃0=Φ0.

Definition 2.1. Let 𝑠, 0<𝑞<, and 𝑝()𝒫(𝑛). Let 𝜃𝑗, 𝑗0={0} as above. The variable exponent Triebel-Lizorkin space 𝐹𝑠𝑝(),𝑞(𝑛) is the collection of 𝑓𝒮(𝑛) such that 𝑓𝐹𝑠𝑝(),𝑞=2𝑠𝑗𝜃𝑗𝑓0𝐿𝑝()(𝑞)<.(2.9) Let 𝑠, 0<𝑞, and 𝑝()𝒫(𝑛). The variable exponent Besov space 𝐵𝑠𝑝(),𝑞(𝑛) is the collection of 𝑓𝒮(𝑛) such that 𝑓𝐵𝑠𝑝(),𝑞=2𝑠𝑗𝜃𝑗𝑓0𝑞(𝐿𝑝())<.(2.10)

Here, 𝐿𝑝()(𝑞) and 𝑞(𝐿𝑝()) are the spaces of all sequences {𝑔𝑗} of measurable functions on 𝑛 such that quasi-norms: 𝑔𝑗0𝐿𝑝()(𝑞)={𝑔𝑗}0𝑞𝐿𝑝()=𝑗=0||𝑔𝑗||()𝑞1/𝑞𝐿𝑝(),𝑔𝑗0𝑞(𝐿𝑝())=𝑔𝑗𝐿𝑝()0𝑞=𝑗=0𝑔𝑗()𝑞𝐿𝑝()1/𝑞(2.11) are finite, respectively.

Definition 2.2. Let 𝑝()𝒫(𝑛) and 0<𝑞. For a sequence of compact subsets Ω={Ω𝑘}𝑘=0 of 𝑛, 𝐿Ω𝑝()(𝑞) denotes the space of all sequences {𝑓𝑘}𝑘=0 of 𝒮(𝑛) such that supp𝑓𝑘Ω𝑘for𝑘=0,1,2,,(2.12) and 𝑓𝑘𝐿𝑝()(𝑞)<. For a compact subset Γ of 𝑛, 𝐿Γ𝑝()(𝑛) denotes the space of all elements 𝑓𝒮(𝑛) such that supp𝑓Γ,(2.13) and 𝑓𝐿𝑝()<.

3. Preliminaries

We need the following fundamental properties of 𝐿𝑝()(𝑛).

Theorem 3.1 (see [5, Theorem 8.1]). Let 𝑝()𝒫(𝑛). Then, the following conditions are equivalent:
(a)𝑝()(𝑛),
(b)𝑝()/𝑡(𝑛) for some 1<𝑡<𝑝,
(c)𝑝()(𝑛), where 𝑝()=𝑝().𝑝()1(3.1)

In [1, 5], some other conditions equivalent to the above are given. Let 𝑝()(𝑛) and 0<𝑞<. Then we write 𝑟𝑝,𝑞𝑝=sup𝑟0<𝑟<min,,𝑞𝑝()𝑟(𝑛).(3.2) If 𝑞=𝑝, then, we write 𝑟𝑝,𝑝=𝑟𝑝.

Remark 3.2. Let 𝑝()(𝑛) and 𝑡 as in Theorem 3.1. Then, for any 𝑤(1,𝑡], we have 𝑝()/𝑤(𝑛). Furthermore, for any 𝑤(0,1], we have also 𝑝()/𝑤(𝑛) by Jensen inequality. The proofs are found in [5]. Consequently, if 𝑝()(𝑛), then, 𝑝()/𝑟(𝑛) for any 𝑟(0,𝑟𝑝). For any 𝑟(0,𝑟𝑝,𝑞), we have also 𝑝()/𝑟(𝑛).

The next theorem gives a generalized Hölder inequality, which is shown in [9, 13].

Theorem 3.3 (see [9, 13]). Let 𝑝𝒫(𝑛). Then, 𝑛||||1𝑓(𝑥)𝑔(𝑥)d𝑥1+𝑝1𝑝+𝑓𝐿𝑝()𝑔𝐿𝑝(),(3.3) for every 𝑓𝐿𝑝()(𝑛) and 𝑔𝐿𝑝()(𝑛).

The next theorem is shown in [6].

Theorem 3.4. Let 𝑝()𝒫(𝑛) and 𝑓𝐿𝑝()(𝑛). Then, min𝑛|𝑓(𝑥)|𝑝(𝑥)d𝑥1/𝑝,𝑛||||𝑓(𝑥)𝑝(𝑥)d𝑥1/𝑝+𝑓𝐿𝑝()max𝑛||||𝑓(𝑥)𝑝(𝑥)d𝑥1/𝑝,𝑛||||𝑓(𝑥)𝑝(𝑥)d𝑥1/𝑝+.(3.4)

The next theorem is shown in [9].

Theorem 3.5. (i) Let 𝑝()𝒫(𝑛). Then, 𝐿𝑝()(𝑛) is a Banach space.
(ii) If 𝑝()(𝑛), then 𝐶0(𝑛) is dense in 𝐿𝑝()(𝑛).

Let 𝑝()𝒫(𝑛) such that 𝑝() is not a constant function. Then, according to [9, Example 2.9, Theorem 2.10], for every 𝐿𝑝(), there exists a function 𝑓()𝐿𝑝()(𝑛) such that its translation 𝑓(𝛽+)𝐿𝑝()(𝑛) if 𝛽𝑛{(0,0,,0)}. However, we can prove that all elements of 𝒮(𝑛) belong to 𝐿𝑝()(𝑛) for every 𝑝()𝒫(𝑛). Let 𝑓()𝒮(𝑛). Then, we have sup𝛽𝑛𝑓(𝛽+𝛼)𝐿𝑝()|𝛼|𝑛/𝑝+𝜋𝑛/𝑝sup𝑥𝑛1+|𝑥|2𝑛||||𝑓(𝑥)if|𝛼|1,|𝛼|𝑛/𝑝𝜋𝑛/𝑝sup𝑥𝑛1+|𝑥|2𝑛||||𝑓(𝑥)if|𝛼|<1,(3.5) where 𝛼{0}.

Hence, by the same arguments of Triebel [20], we have the following two theorems.

Theorem 3.6. Let Ω be a compact subset of 𝑛 and 𝛼 an arbitrary multi-index. Let 𝑝(), 𝑞()(𝑛) such that 1<𝑝(𝑥)𝑞(𝑥)<. Then, there exists a positive constant 𝑐 such that 𝐷𝛼𝑓𝐿𝑞()𝑐𝑓𝐿𝑝(),𝐷(3.6)𝛼𝑓𝐿𝑐𝑓𝐿𝑝(),(3.7) for all 𝑓𝐿Ω𝑝()(𝑛).

Let 𝑓()𝐿Ω𝑝()(𝑛) and 1𝑀𝐿1(𝑛). Then, 1(𝑀𝑓𝑥)=𝑐𝑛1𝑀(𝑥𝑦)𝑓(𝑦)d𝑦(3.8) makes sense for any 𝑥𝑛 by the classical Hölder inequality and (3.7).

Let 𝑠 be a real number and 𝐻𝑠2(𝑛) the spaces of 𝑓𝒮(𝑛) such that 𝑓𝐻𝑠2=1+||2𝑠/2(𝑓)()𝐿2<.(3.9)

Theorem 3.7. Let 𝑝()(𝑛) and 0<𝑞<. Let Ω={Ω𝑘}𝑘=0 be a sequence of compact subsets of 𝑛. Let 𝑑𝑘>0 be the diameter of Ω𝑘. If 𝑣>𝑛/2+𝑛/𝑟𝑝,𝑞, then there exists a number 𝑐 such that 1𝑀𝑘𝑓𝑘𝐿𝑝()(𝑞)𝑐sup𝑙𝑀𝑙𝑑𝑙𝐻𝑣2𝑓𝑘𝐿𝑝()(𝑞)(3.10) for {𝑓𝑘(𝑥)}𝑘=0𝐿Ω𝑝()(𝑞) and {𝑀𝑘(𝑥)}𝑘=0𝐻𝑣2(𝑛).

4. Basic Properties of Variable Exponent Triebel-Lizorkin and Besov Spaces

We will first consider the quasi-norms on 𝐹𝑠𝑝(),𝑞(𝑛) and 𝐵𝑠𝑝(),𝑞(𝑛).

Definition 4.1. (i) The set Ψ(𝑛) is the collection of all systems 𝜑={𝜑𝑗}𝑗=0𝒮(𝑛) with 𝜑𝑘(𝜉)=𝜑(2𝑘𝜉) for 𝑘=1,2,, such that supp𝜑0{𝑥|𝑥|2},supp𝜑𝑗𝑥2𝑗1|𝑥|2𝑗+1for𝑗=1,2,,(4.1) for every multi-index 𝛼, there exists a positive number 𝑐𝛼 such that 2𝑗|𝛼|||𝐷𝛼𝜑𝑗||(𝑥)𝑐𝛼,(4.2) for 𝑗=0,1,, and 𝑥𝑛 and there exists a positive number 𝑐 such that 𝑐𝑗=0𝜑𝑗(𝑥),(4.3) for 𝑥𝑛.
(ii) The set Φ(𝑛) is the collection of all systems 𝜑={𝜑𝑗}𝑗=0𝒮(𝑛) such that supp𝜑0{𝑥|𝑥|2},supp𝜑𝑗𝑥2𝑗1|𝑥|2𝑗+1for𝑗=1,2,,(4.4) for every multi-index 𝛼, there exists a positive number 𝑐𝛼 such that 2𝑗|𝛼|||𝐷𝛼𝜑𝑗||(𝑥)𝑐𝛼,(4.5) for 𝑗=0,1,, and 𝑥𝑛, and 𝑗=0𝜑𝑗(𝑥)=1,(4.6) for 𝑥𝑛.

Theorem 4.2. (i) Let 𝑝()𝒫(𝑛), 0<𝑞, and 𝑠. Let 𝜃𝑗 be as in Definition 2.1 and 𝜑𝑗=𝜃𝑗. Then, the norm 𝑓𝐹𝑠𝑝(),𝑞 coincides with 2𝑗𝑠1𝜑𝑗𝑓𝐿𝑝()(𝑞) and the norm 𝑓𝐵𝑠𝑝(),𝑞 with 2𝑗𝑠1𝜑𝑗𝑓𝑞(𝐿𝑝()).
(ii) Let 𝑝()(𝑛), 0<𝑞, and 𝑠. Let 𝜑, 𝜓Φ(𝑛). Then, 2𝑗𝑠1𝜑𝑗𝑓𝐿𝑝()(𝑞) and 2𝑗𝑠1𝜓𝑗𝑓𝐿𝑝()(𝑞) are equivalent quasi-norms on 𝐹𝑠𝑝(),𝑞(𝑛). Similarly, 2𝑗𝑠1𝜑𝑗𝑓𝑞(𝐿𝑝()) and 2𝑗𝑠1𝜓𝑗𝑓𝑞(𝐿𝑝()) are equivalent quasi-norms on 𝐵𝑠𝑝(),𝑞(n).
(iii) Let 𝑝()(𝑛), 0<𝑞, and 𝑠. Let 𝜑Φ(𝑛) and 𝜓Ψ(𝑛). Then, 2𝑗𝑠1𝜑𝑗𝑓𝐿𝑝()(𝑞) and 2𝑗𝑠𝜓𝑗𝑓𝐿𝑝()(𝑞) are equivalent quasi-norms on 𝐹𝑠𝑝(),𝑞(𝑛). Similarly, 2𝑗𝑠1𝜑𝑗𝑓𝑞(𝐿𝑝()) and 2𝑗𝑠𝜓𝑗𝑓𝑞(L𝑝()) are equivalent quasi norms on 𝐵𝑠𝑝(),𝑞(𝑛).

Proof. Let 𝜃𝑗 be as in Definition 2.1. It is obvious that 𝜃𝑗𝑓=𝑑1(𝜃𝑗𝑓) for some positive number 𝑑, which depends only on the definition of Fourier transform . Let 𝜑𝑗=𝜃𝑗. Then {𝜑𝑗}𝑗=0Φ(𝑛). Hence, the norm 𝑓𝐹𝑠𝑝(),𝑞 coincides with 2𝑗𝑠1𝜑𝑗𝑓𝐿𝑝()(𝑞). Similarly, the variable exponent Besov norm 𝑓𝐵𝑠𝑝(),𝑞 coincides with 2𝑗𝑠1𝜑𝑗𝑓𝑞(𝐿𝑝()). This proves (i). The proof of (ii) is done as in the proof of [20, page 46, Proposition 1] with using Theorem 3.7, the scalar case of Theorem 3.7, and Definition 4.1.
We will prove (iii). Let 𝑓𝐹𝑠𝑝(),𝑞(𝑛), 𝑔𝑗=1(𝜑𝑗𝑓), and 𝜓Ψ(𝑛). Let 𝜓𝑘𝑔𝑘0 for 𝑘<0. Then, 𝑓𝜓𝑘(𝑥)=𝒮𝑗=0𝑔𝑗𝜓𝑘(𝑥)=𝑘+2𝑗=𝑘2𝑔𝑗𝜓𝑘(𝑥),(4.7) because 𝑔𝑗𝜓𝑘=1𝑔𝑗𝜓𝑘=𝑑1𝜓𝑘𝑔𝑗=0,(4.8) for 𝑗<𝑘2 and 𝑗>𝑘+2. Here, 𝑓=𝒮0𝑎𝑗 means 𝑁0𝑎𝑗 converges to 𝑓 in 𝒮(𝑛). It follows that 2𝑠𝑘𝑓𝜓𝑘0𝐿𝑝()(𝑞)2𝑟=22𝑠𝑘𝑔𝑘+𝑟𝜓𝑘0𝐿𝑝()(𝑞)2𝑟=22𝜓𝑟+1𝐻𝜘22𝑠𝑘𝑔𝑘+𝑟0𝐿𝑝()(𝑞),(4.9) where we use Theorem 3.7 with 𝑓𝑘=𝑔𝑘+𝑟, 𝑀𝑘=𝜓𝑘, and 𝑑𝑘=2𝑘+1+𝑟. Hence, we have 2𝑠𝑘𝑓𝜓𝑘0𝐿𝑝()(𝑞)2𝑟=22𝜓𝑟+1𝐻𝜘2𝑓𝐹𝑠𝑝(),𝑞.(4.10) We will prove the opposite inequality. Let 𝜌(𝑥) be a real function with 𝜌(𝑥)=1 for 21|𝑥|2 and 𝜌()𝐶0𝜉22||𝜉||22.(4.11) We set 𝜌𝑘(𝑥)=𝜌(2𝑘𝑥), for 𝑘=1,2,. Furthermore, let 𝜌0(𝑥) be a real function such that 𝜌0(𝑥)=1 for |𝑥|2 and 𝜌0()𝐶0||𝜉||𝜉22.(4.12) We define 𝑘(𝑥) by 𝑘(𝜉)=𝑙=0𝜓𝑙(𝜉)1𝜌𝑘(𝜉),(4.13) for 𝑘=0,1,2, (𝑘=0 for 𝑘<0). Then, 𝑘()𝐶0(𝑛) and 𝑘()𝒮(𝑛). Let 𝛾𝑘=𝜓𝑘𝑘. It is obvious that {𝛾𝑘/𝑑}Φ(𝑛) and {2𝑠𝑘𝜓𝑘𝑓}0𝐿Ω𝑝()(𝑞) by Theorem 4.8 and (4.10), where Ω is some sequence of compact subsets of 𝑛. Then, 2𝑘𝑠𝑓𝛾𝑘0𝐿𝑝()(𝑞)=2𝑘𝑠𝑓𝜓𝑘𝑘0𝐿𝑝()(𝑞)sup𝑘𝑘2𝑘+1𝐻𝜘22𝑘𝑠𝑓𝜓𝑘0𝐿𝑝()(𝑞),𝑘2𝑘+1𝑥=𝜌𝑘2𝑘+1𝑥𝑙=0𝜓𝑙2𝑘+1𝑥=𝜌𝑘2𝑘+1𝑥𝑘+3𝑙=𝑘3𝜓𝑙2𝑘+1𝑥=𝜌(2𝑥)4𝑟=4𝜓(2𝑟,𝑥)(4.14) for any 𝑘=1,2,. This means that 𝑘(2𝑘+1𝑥) is independent of 𝑘 and in 𝐶0(𝑛). Hence, we have sup𝑘𝑘(2𝑘+1)𝐻𝜘2<. This implies that 𝑓𝐹𝑠𝑝(),𝑞sup𝑘𝑘2𝑘+1𝐻𝜘22𝑘𝑠𝑓𝜓𝑘0𝐿𝑝()(𝑞).(4.15) This proves the 𝐹𝑠𝑝(),𝑞 case of (iii). The proof of the 𝐵𝑠𝑝(),𝑞 case of (iii) is essentially the same as one of the 𝐹𝑠𝑝(),𝑞 case.

Corollary 4.3. Let 𝑝()(𝑛), 𝑠, and 1<𝑞<.
(i)𝑓𝐹𝑠𝑝(),𝑞(𝑛) if and only if there exist continuous functions {𝑎𝑗}𝑗0 such that 𝑓=𝒮𝑗=0𝑎𝑗, {2𝑗𝑠𝑎𝑗}0𝐿𝑝()(𝑞)<, supp𝑎0||𝜉||𝜉2,supp𝑎𝑗𝜉2𝑗1||𝜉||2𝑗+1,for𝑗0.(4.16) In particular, 𝑓𝐹𝑠𝑝(),𝑞 coincides with inf𝑎𝑓=j{2𝑗𝑠𝑎𝑗}0𝐿𝑝()(𝑞), where the infimum is taken over all representation 𝑎𝑓=𝑗.
(ii)𝑓𝐵𝑠𝑝(),𝑞(𝑛) if and only if, there exist continuous functions {𝑎𝑗}𝑗0 such that 𝑓=𝒮𝑗=0𝑎𝑗, {2𝑗𝑠𝑎𝑗}0𝑞(𝐿𝑝())<, supp𝑎0{𝜉|𝜉|2}, and supp𝑎𝑗{𝜉2𝑗1|𝜉|2𝑗+1} for 𝑗0. In particular, the norm 𝑓𝐵𝑠𝑝(),𝑞 coincides with inf𝑎𝑓=𝑗{2𝑗𝑠𝑎𝑗}0𝑞(𝐿𝑝()).

Proposition 4.4. (i) Let 𝑝()𝒫(𝑛), 𝑠, and 0<𝑞1𝑞2. Then, 𝐵𝑠𝑝(),𝑞1(𝑛)𝐵𝑠𝑝(),𝑞2(𝑛),𝐹𝑠𝑝(),𝑞1(𝑛)𝐹𝑠𝑝(),𝑞2(𝑛).(4.17)
(ii) Let 𝑝()𝒫(𝑛), 𝑠, 0<𝑞1, 0<𝑞2, and 𝜖>0. Then 𝐵𝑠+𝜖𝑝(),𝑞1(𝑛)𝐵𝑠𝑝(),𝑞2(𝑛𝐹),𝑠+𝜖𝑝(),𝑞1(𝑛)𝐹𝑠𝑝(),𝑞2(𝑛).(4.18)
(iii) Let 𝑝()𝒫(𝑛) and 𝑠. If 0<𝑞, then 𝐵𝑠𝑝(),min{𝑝,𝑞}(𝑛)𝐹𝑠𝑝(),𝑞(𝑛)𝐵𝑠𝑝(),max{𝑝+,𝑞}(𝑛).(4.19)

The proof is almost same as in [20]. Furthermore, Almeida and Hästö [14] proved the above inclusion for 𝐹𝛼()𝑝(),𝑞()(𝑛) and 𝐵𝛼()𝑝(),𝑞()(𝑛).

Theorem 4.5. Let 0<𝑞<, 𝑠, and 𝑝()(𝑛). Let 𝐴𝑠𝑝(),𝑞 be either 𝐵𝑠𝑝(),𝑞(𝑛) or 𝐹𝑠𝑝(),𝑞(𝑛). Then, 𝒮(𝑛)𝐴𝑠𝑝(),𝑞𝒮(𝑛). Furthermore, 𝑆(𝑛) is dense in 𝐴𝑠𝑝(),𝑞(𝑛) and 𝐴𝑠𝑝(),𝑞(𝑛) is a quasi Banach space (a Banach space if 1𝑞).

Proof. To prove the inclusion, we may restrict ourselves to 𝐵𝑠𝑝(),𝑞(𝑛) with 𝑞= by Proposition 4.4. Let 𝑓𝒮(𝑛) and 𝜑={𝜑𝑘(𝑥)}𝑘=0Φ(𝑛). We recall that the topology of the complete locally convex space 𝒮(𝑛) is generated by seminorms: 𝑝𝑁(𝑓)=sup𝑥𝑛|𝛼|+𝑘𝑁1+|𝑥|2𝑘||𝐷𝛼||𝑓(𝑥),𝑁,(4.20) yields a one-to-one mapping from 𝒮(𝑛) onto itself, and, in particular, 𝑝𝑁(𝜑) with 𝑁=1,2, generates the topology of 𝒮(𝑛). If 𝑁 is a sufficiently large natural number, then 𝑓𝐵𝑠𝑝(),𝑞=sup𝑘2𝑘𝑠1𝜑𝑘𝑓𝐿𝑝()𝑐𝑝𝑁(𝑓),(4.21) where 𝑐 is a positive number. This proves the left-hand side of the inclusion with 𝑞=. We prove the right-hand side of the inclusion with 𝑞=. Let 𝜑Φ(𝑛) be the above system. It is well known that 𝑓(𝜓)=𝑘=01𝜑𝑘𝑓(𝜓)(4.22) in 𝒮(𝑛) for all 𝑓𝒮(𝑛) and 𝜓𝒮(𝑛). By the Paley-Wiener-Schwartz Theorem, the definition of 𝜑𝑘 implies that 1𝜑𝑘𝑓 are analytic functions, and that these functions are regular distributions. We put 𝜒𝑘(𝑥)=𝜑𝑘1(𝑥)+𝜑𝑘(𝑥)+𝜑𝑘+1(𝑥) if 𝑘=0,1,, with 𝜑1=0. If 𝑓𝐵𝑠𝑝(),(𝑛) and 𝜓𝒮(𝑛), then 𝑓(𝜓) denotes the value of the functional 𝑓 of 𝒮(𝑛) of the test function 𝜓. We obtain |||||||||𝑓(𝜓)𝑘=01𝜑𝑘𝑓𝜒𝑘1𝜓|||||𝑘=01𝜑𝑘𝑓𝐿𝜒𝑘1𝜓𝐿1(4.23) by the classical Hölder inequality. Because both 1𝜑𝑘𝑓 and 𝜒𝑘1𝜓 are analytic functions, the last estimate makes sense. By applying (3.7) with 𝛼=(0,0,,0) to 1𝜑𝑘𝑓, we have ||||𝑓(𝜓)𝑐𝑓𝐵𝑠𝑝(),𝑘=02𝑠𝑘𝜒𝑘1𝜓𝐿1𝑐𝑓𝐵𝑠𝑝(),𝜓𝐵𝑠1,1.(4.24) If 𝑁 is a sufficiently large natural number, then, for any 𝜓𝒮(𝑛), we have ||||𝑓(𝜓)𝑐𝑓𝐵𝑠𝑝(),𝑝𝑁(𝜓)(4.25) by the left-hand side of the inclusion for 𝐵𝑠1,1(𝑛). Hence, we have the inclusion for 𝐴𝑠𝑝(),𝑞.
The proof of the completeness and the density of 𝒮(𝑛) is given by the same arguments of step 4 and step 5 of the proof of [20, page 48, Theorem] with 𝑝 replaced by 𝑝().

As we mentioned in Section 1, the next theorem is found in [15, 16].

Theorem 4.6. Let 𝑠0 and 𝑝()(𝑛). Then, 𝐹𝑠𝑝(),2(𝑛) coincides with 𝐿𝑠,𝑝()(𝑛). Let 𝑘 and 𝑝()(𝑛). Then, 𝐹𝑘𝑝(),2(𝑛) coincides with 𝑊𝑘,𝑝()(𝑛).

Definition 4.7. Let 𝜑𝒮(𝑛) such that (𝜑)(𝜉)=1 for 1/2|𝜉|2 and 0𝜑𝐶0𝜉𝑛12||𝜉||<𝜖<2+𝜖,(4.26) and let 𝜌𝒮(𝑛) such that 0𝜌𝐶0𝜉𝑛12||𝜉||<+𝛿<2𝛿,(4.27) where 𝜖 and 𝛿 are positive numbers. We construct {𝜑𝑘}𝑘=0 and {𝜌𝑘}𝑘=0 by 𝜑𝑘2(𝜉)=(𝜑)𝑘𝜉,𝜌𝑘2(𝜉)=(𝜌)𝑘𝜉.(4.28) We choose 𝜖 and 𝛿 sufficiently small so that 𝜑𝑘𝜌𝑗0(4.29) for 𝑘𝑗.

Diening [3] shows that Young inequality 𝑓𝑔𝐿𝑝()𝑓𝐿𝑝()𝑔𝐿1 holds if and only if 𝑝() is a constant function. However, the next theorem, which is a part of Corollary 3.6 of [3], holds.

Theorem 4.8. Let 𝑝()(𝑛). Let 𝜙 be an integrable function on 𝑛 with range in and set 𝜙𝜖(𝑥)=𝜖𝑛𝜙(𝑥/𝜖) for all 𝜖>0. Assume that the least decreasing radial majorant of 𝜙 is integrable, that is, 𝐴=𝑛sup|𝑦||𝑥||𝜙(𝑦)|d𝑥<. Then, for any 𝑓𝐿𝑝()(𝑛), one has sup𝜖>0||𝑓𝜙𝜖||(𝑥)2𝐴𝑓(𝑥).(4.30) Hence, there exist a positive number 𝐶(𝐴,𝑝) such that 𝑓𝜙𝜖𝐿𝑝()𝐶(𝐴,𝑝)𝑓𝐿𝑝(),(4.31) where 𝐶(𝐴,𝑝) only depends on 𝐴 and 𝑝().

The duality pair of 𝑔(𝐹𝑠𝑝(),𝑞(𝑛)) and 𝑓𝐹𝑠𝑝(),𝑞(𝑛) is denoted by 𝑔,𝑓, although, for 𝜑𝒮(𝑛)𝐹𝑠𝑝(),𝑞(𝑛), we also write 𝑔(𝜑) as 𝑔,𝜑. In order to prove the duality of 𝐹𝑠𝑝(),𝑞(𝑛) and 𝐵𝑠𝑝(),𝑞(𝑛) (Theorem 5.1), we will first prove the following two lemmas which correspond to [19, Lemmas  7.1.3, and 7.1.5].

Lemma 4.9. Let 𝑔(𝐹𝑠𝑝(),𝑞), {𝜌𝑘} as in Definition 4.7 and ̃𝑔=𝑘=01𝜌𝑘𝑔(4.32) in 𝒮(𝑛). Then, ̃𝑔(𝐹𝑠𝑝(),𝑞) and ̃𝑔(𝐹𝑠𝑝(),𝑞)𝑐𝑔(𝐹𝑠𝑝(),𝑞),(4.33) where 𝑐 does not depend on 𝑔.

Proof. We use the same argument of the proof of [19, Lemma 7.1.3]. Let 𝑓𝒮(𝑛). Then, it holds that ̃𝑔(𝑓)=(̃𝑔)1𝑓=𝑘=0𝑔𝜌𝑘1𝑓=𝑐𝑘=0𝑔𝜌𝑘𝑓=𝑐𝑔𝑘=0𝜌𝑘,𝑓(4.34) where 𝜌𝑘(𝑥)=𝜌𝑘(𝑥). Using 𝑔(𝐹𝑠𝑝(),𝑞) and Theorem 3.7 with 𝑀𝑘=(𝜌𝑘) and 𝑑𝑘=2𝑘+1, we find that ||||̃𝑔(𝑓)𝑔(𝐹𝑠𝑝(),𝑞)2𝑘𝑠𝜌𝑘𝜑𝑘𝑓0𝐿𝑝()(𝑞)𝑐𝑔(𝐹𝑠𝑝(),𝑞)2𝑘𝑠𝜑𝑘𝑓0𝐿𝑝()(𝑞),(4.35) where {𝜑𝑘}𝑘=0 is a system of Definition 4.7. Thus, we get ||||̃𝑔(𝑓)𝑐𝑔(𝐹𝑠𝑝(),𝑞)𝑓𝐹𝑠𝑝(),𝑞,(4.36) from Definition 2.1 and Theorem 4.2.

Lemma 4.10. Let {𝜌𝑘} and {𝜑𝑘} be ones as in Definition 4.7, 𝑔(𝐹𝑠𝑝(),𝑞), and ̃𝑔 the functional in Lemma 4.9. Let {𝑏𝑘}𝑁𝑘=0 be a system of functions such that 𝑏𝑘𝐿𝑝()(𝑛). Set 𝑎𝑘=1𝜌𝑘,𝑐𝑔(4.37)𝑘=𝑏𝑘𝜑𝑘,(4.38) for 𝑘=0,1,2,,𝑁, and 𝑓=𝑁𝑘=0𝑐𝑘.(4.39) Then, ̃𝑔,𝑓=𝑐𝑛𝑁𝑘=0𝑎𝑘𝑏𝑘d𝑥,(4.40) where 𝑐 depends only on the definition of Fourier transform.

Proof. We use the same argument of the proof of [19, Lemma 7.1.5]. We first prove that 𝑎𝑘𝐿𝑝(), where 𝑝() is defined by (3.1). The consideration of the proof of Lemma 4.9 implies that for 𝑓𝒮(𝑛), ||𝑎𝑘||(𝑓)𝑐𝑔(𝐹𝑠𝑝(),𝑞)2𝑠𝑗𝛿𝑗,𝑘𝜑𝑘𝑓𝑗𝐿𝑝()(𝑞)𝑐𝑓𝐿𝑝(),(4.41) where 𝛿𝑘,𝑘=1 and 𝛿𝑗,𝑘=0 if 𝑗𝑘. This implies 𝑎𝑘𝐿𝑝() and the right-hand side of (4.40) has a sense. We assume 𝑏𝑘𝒮(𝑛). Then, 𝑐𝑘𝒮(𝑛) and 𝑓𝒮(𝑛). By (4.32), we have ̃𝑔,𝑓=̃𝑔(𝑓)=𝑘=0𝑎𝑘(𝑓)(4.42) in 𝒮(𝑛) and 𝑎𝑘(𝑓)=𝑁𝑙=0𝑎𝑘𝑐𝑙=𝑁𝑙=0𝑎𝑘1𝑐𝑙=𝑐𝑁𝑙=0𝑎𝑘1𝜑𝑙1𝑏𝑙.(4.43) Since (1)(𝜉)=()(𝜉), (4.29), (4.37), and (4.38) imply that 𝑎𝑘(𝑓)=𝑐𝑎𝑘1𝑏𝑘=𝑐𝑛𝑎𝑘𝑏𝑘d𝑥.(4.44) From this, (4.40) follows for 𝑏𝑘𝒮(𝑛). Let 𝑏𝑘𝐿𝑝()(𝑛), 𝑏𝑘,𝑗𝒮(𝑛) such that 𝑏𝑘,𝑗𝑏𝑘(4.45) in 𝐿𝑝()(𝑛) as 𝑗 and 𝑐𝑘,𝑗=𝑏𝑘,𝑗𝜑𝑘,𝑓𝑗=𝑁𝑘=0𝑐𝑘,𝑗.(4.46) Thus, (4.40) holds for 𝑓𝑗 and 𝑏𝑘,𝑗. For any 𝒮(𝑛), the least decreasing radial majorant of is integrable. By the definition of 𝜑𝑘(𝑥), 𝜑𝑘(𝑥)=2𝑘𝑛𝜑2𝑘𝑥.(4.47) Hence, 𝑐𝑘,𝑗 converges to 𝑐𝑘 in 𝐿𝑝()(𝑛) as 𝑗 by Theorem 4.8 and 𝑓𝑗 converges to 𝑓 in 𝐹𝑠𝑝(),𝑞(𝑛) as 𝑗. Equation (4.40) follows from the last relation.

5. Duality and Reflexivity of Variable Exponent Function Spaces

Theorem 5.1. Let 1<𝑞<, 𝑠, and 𝑝()(𝑛). Let 𝐴𝑠𝑝(),𝑞 be either 𝐵𝑠𝑝(),𝑞(𝑛) or 𝐹𝑠𝑝(),𝑞(𝑛). Then, 𝐴𝑠𝑝(),𝑞(𝑛)=𝐴𝑝𝑠(),𝑞(𝑛),(5.1) where 𝑝()=𝑝()𝑝()1,(5.2) and 1/𝑞+1/𝑞=1. The spaces 𝐹𝑠𝑝(),𝑞(𝑛) and 𝐵𝑠𝑝(),𝑞(𝑛) are reflexive.

Proof. We will only prove (5.1) because the reflexivity of 𝐴𝑠()𝑝(),𝑞() follows from Theorem 3.1.
Step 1. We will first prove the 𝐹𝑠𝑝(),𝑞 case. We use the arguments of the proof of [19, Theorems  7.1.7, and 7.2.2]. Let 𝑓𝒮(𝑛), 𝑔𝐹𝑝𝑠(),𝑞(𝑛), and {𝜓𝑘}𝑘=0 replaced by {𝜃𝑘}𝑘=0 as in Definition 2.1. Then, 𝑓=𝑘=0𝑓𝜓𝑘 in 𝒮(𝑛), 𝑓𝜓𝑘𝒮(𝑛), and 𝑔=𝑘=0𝑔𝜓𝑘 in 𝒮(𝑛). It follows from Definition 2.1 that 𝑔(𝑓)=𝑘=0𝑔𝜓𝑘(𝑓)=𝑘=0𝑙=0𝑔𝜓𝑘𝑓𝜓𝑙=𝑘=02𝑁𝑟=2𝑁𝑔𝜓𝑘𝑓𝜓𝑘+𝑟(5.3) in 𝒮(𝑛). Here, 𝜓𝑗=0 for 𝑗<0. Using Hölder inequality, we get ||||𝑔(𝑓)𝑐𝑛2𝑘𝑠𝑔𝜓𝑘𝑞2𝑘𝑠𝑓𝜓𝑘𝑞2d𝑥𝑐𝑘𝑠𝑔𝜓𝑘𝐿𝑝()(𝑞)2𝑘𝑠𝑓𝜓𝑘𝐿𝑝()(𝑞)𝑐𝑔𝐹𝑝𝑠(),𝑞𝑓𝐹𝑠𝑝(),𝑞,(5.4) where 𝑐 does not depend on 𝑔, 𝑓 and 𝜓. Hence, we see 𝑔(𝐹𝑠𝑝(),𝑞) and 𝑔(𝐹𝑠𝑝(),𝑞)𝑐𝑔𝐹𝑠𝑝(),𝑞 since 𝒮(𝑛) is dense in 𝐹𝑠𝑝(),𝑞(𝑛).Step 2. Let 𝑔(𝐹𝑠𝑝(),𝑞). We assume that ̃𝑔 and the functions 𝜑𝑘 and 𝜌𝑘 have the same sense as in Definition 4.7, Lemmas 4.9, and 4.10. We show that ̃𝑔𝐹𝑠𝑝(),𝑞(𝑛). For this purpose, we construct functions 𝑎𝑘 as (4.37) and set 𝑏𝑘(𝑥)=sgn𝑎𝑘||𝑎𝑘||(𝑥)𝑞12𝑠𝑘𝑞2𝑗𝑠𝑎𝑗𝑁𝑗=0𝑝(𝑥)𝑞𝑞,(5.5) for 𝑘=0,1,,𝑁. If 𝑎𝑘=0, we set 𝑏𝑘=0. We have 2𝑘𝑠𝑏𝑘(𝑥)𝑁𝑘=0𝑞=𝑁𝑘=0||𝑎𝑘||𝑞12𝑘𝑠(1𝑞)2𝑗𝑠𝑎𝑗𝑁𝑗=0𝑝(𝑥)𝑞𝑞𝑞1/𝑞=2𝑗𝑠𝑎𝑗𝑁𝑗=0𝑝(𝑥)𝑞𝑞𝑁𝑘=0||𝑎𝑘||𝑞2𝑘𝑠𝑞1/𝑞=2𝑗𝑠𝑎𝑗𝑁𝑗=0𝑞/𝑞+𝑝(𝑥)𝑞𝑞,(5.6) where we used (𝑞1)𝑞=𝑞. We set 𝛼=essinf𝑥𝑛𝑝(𝑥)2𝑝(𝑥),if𝑘𝑠𝑎𝑘𝑁𝑘=0𝐿𝑝()(𝑞)1,esssup𝑥𝑛𝑝(𝑥)2𝑝(𝑥),if𝑘𝑠𝑎𝑘𝑁𝑘=0𝐿𝑝()(𝑞)>1,(5.7) and 𝜆={2𝑘𝑠𝑎𝑘}𝑁𝑘=0𝐿𝑝()(𝑞). Then, 𝑛2𝑘𝑠𝑏𝑘𝑁𝑘=0𝑞𝜆𝛼𝑝(𝑥)d𝑥=𝑛2𝑗𝑠𝑎𝑗𝑁𝑗=0𝑞/𝑞+𝑝(𝑥)𝑞𝑞𝜆𝛼𝑝(𝑥)=d𝑥𝑛2𝑗𝑠𝑎𝑗𝑁𝑗=0(𝑞/𝑞+𝑝(𝑥)𝑞)𝑝(𝑥)𝑞𝜆𝛼𝑝(𝑥)=d𝑥𝑛{2𝑗𝑠𝑎j}𝑁𝑗=0𝑞𝜆𝛼(𝑝(𝑥)/𝑝(𝑥))𝑝(𝑥)d𝑥𝑛2𝑗𝑠𝑎𝑗𝑁𝑗=0𝑞𝜆𝑝(𝑥)d𝑥1,(5.8) where we used 𝑞𝑞𝑝𝑝(𝑥)+𝑝(𝑥)(𝑥)𝑞=𝑝(𝑥),esssup𝑥𝑛𝑝(𝑥)𝑝=(𝑥)essinf𝑥𝑛𝑝(𝑥)𝑝(𝑥)1,essinf𝑥𝑛𝑝(𝑥)=𝑝(𝑥)esssup𝑥𝑛𝑝(𝑥)𝑝(𝑥)1.(5.9) Hence, we have 2𝑘𝑠𝑏𝑘𝑁𝑘=0𝐿𝑝()(𝑞)2𝑘𝑠𝑎𝑘𝑁𝑘=0𝛼𝐿𝑝()𝑞.(5.10) In particular, 𝑏𝑘𝐿𝑝()(𝑛). Now, we construct the same function 𝑓 by (4.39). Using Lemma 4.10, (4.37) and Theorem 4.8, we have 𝑛2𝑘𝑠𝑎𝑘𝑁0𝑝(𝑥)𝑞d𝑥=𝑛𝑁𝑘=02𝑠𝑘𝑞||𝑎𝑘||𝑞2𝑗𝑠𝑎𝑗𝑁𝑗=0𝑝(𝑥)𝑞𝑞=d𝑥𝑛𝑁𝑘=0𝑎𝑘𝑏𝑘d𝑥=̃𝑔,𝑓𝑐𝑔(𝐹𝑠𝑝(),𝑞)2𝑘𝑠𝑏𝑘𝜑𝑘𝑁0𝐿𝑝()(𝑞)𝑐𝑔(𝐹𝑠𝑝(),𝑞)2𝑘𝑠𝑏𝑘𝑁𝑘=0𝐿𝑝()(𝑞).(5.11) We set 𝛽=esssup𝑥𝑛𝑝2(𝑥),if𝑘𝑠𝑎𝑘𝑁𝑘=0𝐿𝑝()(𝑞)1,essinf𝑥𝑛𝑝(𝑥),if{2𝑘𝑠𝑎𝑘}𝑁𝑘=0𝐿𝑝()(𝑞)>1.(5.12) Then, it follows from Theorem 3.4, (5.11), and (5.10) that 2𝑘𝑠𝑎𝑘𝑁𝑘=0𝐿𝛽𝛼𝑝()(𝑞)𝑐𝑔(𝐹𝑠𝑝(),𝑞).(5.13) If 𝑝(𝑥) is not a constant function, then 𝛽𝛼1. So, we normalize the 𝑎𝑘. We put 𝑎𝑘=𝑎𝑘/𝜆 and 𝑏𝑘=sgn𝑎𝑘||𝑎𝑘||𝑞12𝑠𝑘𝑞2𝑗𝑠𝑎𝑗𝑁𝑗=0𝑝()𝑞𝑞.(5.14) Then, we have 2𝑘𝑠𝑏𝑘𝑁𝑘=0𝐿𝑝()(𝑞)21,𝑘𝑠𝑎𝑘𝑁𝑘=0𝐿𝛽𝛼𝑝()(𝑞)𝑔𝑐𝜆(𝐹𝑠𝑝(),𝑞).(5.15) Hence we have 2𝑘𝑠𝑎𝑘𝑁𝑘=0𝐿𝑝()(𝑞)𝑐𝑔(𝐹𝑠𝑝(),𝑞).(5.16) The last estimate, (4.32), (4.37), and Corollary 4.3 lead us to ̃𝑔𝐹𝑝𝑠(),𝑞,̃𝑔𝐹𝑝𝑠(),𝑞𝑐𝑔(𝐹𝑠𝑝(),𝑞).(5.17) We specialize the function 𝜌(𝑥) in Definition 4.7 by setting (𝜌)(𝜉)=1 for 12||𝜉||+2𝛿22𝛿,(5.18) where 𝑓 is a sufficiently small positive number. Then, we find a function ̃𝜌(𝑥)𝒮(𝑛) such that 0̃𝜌𝐶0𝜉𝑛||𝜉||<22𝛿<2+5𝛿,(5.19)(𝜌+̃𝜌+𝜌1)=1 for 1/2+2𝛿<|𝜉|2(22𝛿). As in (4.28), we construct ̃𝜌𝑘(𝑥), and, as in (4.32), we put ̃̃𝑔=𝑘=01̃𝜌𝑘𝑔(5.20) in 𝒮(𝑛). The function ̃̃𝑔 has properties similar to ̃𝑔, notably, (5.17) holds. Changing the function ̃𝜌0=̃𝜌, we obtain 𝑔=̃𝑔+̃̃𝑔. Then, (5.17) implies 𝑔𝐹𝑝𝑠(),𝑞(𝑛)𝑔𝐹𝑠𝑝(),𝑞𝑐𝑔(𝐹𝑠𝑝(),𝑞).(5.21) This completes Theorem 5.1 for the 𝐹𝑠𝑝(),𝑞(𝑛). Step 3. Finally, we will prove the 𝐵𝑠𝑝(),𝑞 case. Let 𝑓𝒮(𝑛) and 𝑔𝐵𝑠𝑝(),𝑞(𝑛). Then, we have 𝑔(𝐵𝑠𝑝(),𝑞(𝑛)) and see that there exists a positive number 𝑐 such that 𝑔(𝐵𝑠𝑝(),𝑞)𝑐𝑔𝐵𝑝𝑠(),𝑞,(5.22) by the same manner as in the Step 1. Step 4. Let 𝑔(𝐵𝑠𝑝(),𝑞) and ̃𝑔 as in (4.32). Then, we have ̃𝑔(𝐵𝑠𝑝(),𝑞) and ̃𝑔(𝐵𝑠𝑝(),𝑞)𝑐𝑔(𝐵𝑠𝑝(),𝑞)(5.23) by the same argument in the proof of Lemma 4.9. Furthermore, Lemma 4.10 also holds for 𝑔(𝐵𝑠𝑝(),𝑞) by the same argument in the proof of Lemma 4.10. Let 𝑎𝑘 as in (4.37). Then, 𝑎𝑘𝐿𝑝()(𝑛). We set 𝑏𝑘(𝑥)=sgn𝑎𝑘||𝑎𝑘||(𝑥)𝑝(𝑥)12𝑠𝑘𝑞𝑎𝑘𝑞𝑝𝑝(𝑥)(),(5.24) for 𝑘=0,1,2,. Then, we have 𝑏𝑘𝐿𝑝()2𝑠𝑘𝑞𝑎𝑘𝑞𝐿/𝑞𝑝() by the following calculating: 𝑛||𝑏𝑘(||𝑥)2𝑘𝑠𝑞𝑎𝑘𝑞𝐿/𝑞𝑝()𝑝(𝑥)d𝑥=𝑛||𝑎𝑘||(𝑥)𝑝(𝑥)1𝑎𝑘𝑞𝑝𝐿(𝑥)𝑝()𝑎𝑘𝐿𝑞/𝑞𝑝()𝑝(𝑥)=d𝑥𝑛||𝑎𝑘||(𝑥)𝑝(𝑥)𝑎𝑘(𝑞/𝑞)𝑝(𝑥)𝑝𝐿(𝑥)𝑝()𝑎𝑘(𝑞𝐿/𝑞)𝑝(𝑥)𝑝()=d𝑥𝑛||𝑎𝑘(||𝑥)𝑎𝑘𝐿𝑝()𝑝(𝑥)d𝑥=1.(5.25) Hence, we have 2𝑘𝑠𝑏𝑘𝑁0𝑞(𝐿𝑝())𝑁𝑘=02𝑠𝑘𝑞(1𝑞)𝑎𝑘𝑞𝐿𝑝()1/𝑞=𝑁𝑘=02𝑠𝑘𝑞𝑎𝑘𝑞𝐿𝑝()𝑞/(𝑞𝑞)=2𝑘𝑠𝑎𝑘𝑁0𝑞/𝑞𝑞(𝐿𝑝()).(5.26) We have 𝑛𝑁𝑘=0𝑎𝑘𝑏𝑘d𝑥=𝑁𝑘=02𝑠𝑘𝑞𝑛||𝑎𝑘||(𝑥)𝑝(𝑥)𝑎𝑘𝑞𝑝𝐿(𝑥)𝑝()=d𝑥𝑁𝑘=02𝑠𝑘𝑞𝑎𝑘𝑞𝐿𝑝()=2𝑘𝑠𝑎𝑘𝑁0𝑞𝑞(𝐿𝑝()).(5.27) Hence, we have 2𝑘𝑠𝑎𝑘𝑁0𝑞𝑞𝐿𝑝()𝑔(𝐵𝑠𝑝(),𝑞)2𝑘𝑠𝑎𝑘𝑁0𝑞/𝑞𝑞𝐿𝑝()(5.28) by the same manner as in Step 2. It follows from this, as in Step 2, that 𝑔𝐵𝑝𝑠(),𝑞(𝑛),𝑔𝐵𝑝𝑠(),𝑞𝑐𝑔(𝐵𝑠𝑝(),𝑞).(5.29) This complete the proof.

The next corollary is an immediate consequence of Theorems 4.6 and 5.1.

Corollary 5.2. Let 𝑠0 and p()(𝑛). Then, 𝐿𝑠,𝑝()(𝑛)=𝐹𝑝𝑠(),2(𝑛).(5.30) In addition, for 𝑘0, one has 𝑊𝑘,𝑝()(𝑛)=𝐹𝑝𝑘(),2(𝑛).(5.31) Hence, 𝐿𝑠,𝑝()(𝑛) and 𝑊𝑘,𝑝()(𝑛) are reflexive.

Remark 5.3. Let Ω be 𝑛 or any measurable subset of 𝑛. As we mentioned in Section 1, Kováčik and Rákosník [9] showed that the dual of 𝐿𝑝()(Ω) is 𝐿𝑝()(Ω) if 𝑝() is a measurable function on Ω with a range in [1,] and 𝑝()𝐿(Ω). Furthermore, 𝐿𝑝()(Ω) is reflexive if 1<𝑝𝑝+<. There is no assumption of boundedness of Hardy-Littlewood maximal operator on 𝐿𝑝()(Ω).

Acknowledgments

The authors would like to express his gratitude to Professor Y. Kobayashi for the great support in any manner and for his valuable suggestions in many discussions. He is also thankful to the anonymous referees for their reading carefully and their advices in an appropriate manner.