Let
{
π
πΌ
π
}
π
β
β
be the Laguerre functions of Hermite type with index
πΌ
. These are eigenfunctions of the Laguerre differential operator
πΏ
πΌ
=
1
/
2
(
β
π
2
/
π
π¦
2
+
π¦
2
+
ξ·
1
/
π¦
2
ξΈ
(
πΌ
2
β
1
/
4
)
)
. In this paper, we investigate the boundedness of the Hardy-Littlewood maximal function, the heat maximal function, and the Littlewood-Paley
π
-function associated with
πΏ
πΌ
in the localized BMO space
B
M
O
πΏ
πΌ
, which is the dual space of the Hardy space
π»
1
πΏ
πΌ
.
1. Introduction Let
π
β
β
,
πΌ
>
β
1
. The Laguerre function of Hermite type
π
πΌ
on
(
0
,
β
)
is defined as
π
πΌ
π
ξ΅
(
π¦
)
=
Ξ
(
π
+
1
)
ξΆ
Ξ
(
π
+
1
+
πΌ
)
1
/
2
π
β
π¦
2
/
2
π¦
πΌ
πΏ
πΌ
π
ξ·
π¦
2
ξΈ
(
2
π¦
)
1
/
2
,
π¦
β
(
0
,
β
)
,
(
1
.
1
)
where
πΏ
πΌ
π
(
π₯
)
denotes the Laguerre polynomial of degree
π
and order
πΌ
, see [1 ]. It is well known that for every
πΌ
>
β
1
the system
{
π
πΌ
π
}
β
π
=
0
forms an orthonormal basis of
πΏ
2
(
0
,
β
)
. Moreover, these functions are eigenfunctions of the Laguerre differential operator
πΏ
πΌ
=
1
2
ξ΅
β
π
2
π
π¦
2
+
π¦
2
+
1
π¦
2
ξ
πΌ
2
β
1
4
ξ
ξΆ
(
1
.
2
)
satisfying
πΏ
πΌ
π
πΌ
π
=
(
2
π
+
πΌ
+
1
)
π
πΌ
π
. The operator
πΏ
πΌ
can be extended to a positive self-adjoint operator on
πΏ
2
(
0
,
β
)
by giving a suitable domain of definition, see [2 ]; we also denote the extension by
πΏ
πΌ
. Let
{
π
πΌ
π‘
}
π‘
β₯
0
be the heat-diffusion semigroup generated by
β
πΏ
πΌ
. More precisely, for
π
β
πΏ
2
(
0
,
β
)
, we define
π
πΌ
π‘
ξ
π
(
π₯
)
=
β
0
π
πΌ
π‘
(
π₯
,
π¦
)
π
(
π¦
)
π
π¦
,
(
1
.
3
)
where
π
πΌ
π‘
ξ΅
(
π₯
,
π¦
)
=
2
π
β
π‘
1
β
π
β
2
π‘
ξΆ
1
/
2
ξ΅
2
π₯
π¦
π
β
π‘
1
β
π
β
2
π‘
ξΆ
1
/
2
πΌ
πΌ
ξ΅
2
π₯
π¦
π
β
π‘
1
β
π
β
2
π‘
ξΆ
ξ΅
β
1
e
x
p
2
1
+
π
β
2
π‘
1
β
π
β
2
π‘
ξ·
π₯
2
+
π¦
2
ξΈ
ξΆ
.
(
1
.
4
)
πΌ
πΌ
is the modified Bessel function of the first kind and order
πΌ
.
In [3 ], we introduced and developed a localized BMO space
B
M
O
πΏ
πΌ
associated with the operator
πΏ
πΌ
, which is the dual space of the Hardy space
π»
1
πΏ
πΌ
introduced by Dziubański [4 ]. More precisely, let
π
πΏ
πΌ
1
(
π₯
)
=
8
ξ
1
m
i
n
π₯
,
π₯
ξ
,
π₯
>
0
.
(
1
.
5
)
Definition 1.1. Let
πΌ
>
β
1
/
2
,
π΅
π
(
π¦
)
be any ball in
(
0
,
β
)
with the center
π¦
and the radius
π
and
π
a locally integrable function on
(
0
,
β
)
. We say
π
β
B
M
O
πΏ
πΌ
if there exists a constant
πΆ
β₯
0
independent of
π
and
π¦
such that
1
|
|
π΅
π
|
|
ξ
(
π¦
)
π΅
π
(
π¦
)
|
|
π
β
π
π΅
π
(
π¦
)
|
|
β€
πΆ
,
i
f
π
<
π
πΏ
πΌ
(
1
π¦
)
,
|
|
π΅
π
|
|
ξ
(
π¦
)
π΅
π
(
π¦
)
|
|
π
|
|
β€
πΆ
,
i
f
π
β₯
π
πΏ
πΌ
(
π¦
)
.
(
1
.
6
)
Here,
π
π΅
π
(
π¦
)
=
(
1
/
|
π΅
π
β«
(
π¦
)
|
)
π΅
π
(
π¦
)
π
π
π₯
. We let
β
π
β
B
M
O
πΏ
πΌ
denote the smallest
πΆ
in the two inequalities above.
It is readily seen that
B
M
O
πΏ
πΌ
is a Banach space with norm
β
β
β
B
M
O
πΏ
πΌ
.
In this paper, we obtain the boundedness on
B
M
O
πΏ
πΌ
of several operators including the Hardy-Littlewood maximal operator defined on
(
0
,
β
)
, the heat maximal function, and the Littlewood-Paley
π
-function associated with
π
πΌ
π‘
.
These results were investigated by Dziubański et al. in [5 ] for Schrödinger operators on
β
π
with
π
β₯
3
and with potentials satisfying a reverse Hölder's inequality. Recently, a theory of localized BMO spaces on RD-spaces associated with an admissible function
π
was investigated in [6 ]; the authors also established the similar results above for their
B
M
O
spaces. The admissible function
π
in [6 ] is required to satisfy
1
π
(
π₯
)
β€
πΆ
0
1
ξ΅
π
(
π¦
)
1
+
π
(
π₯
,
π¦
)
ξΆ
π
(
π¦
)
π
0
.
(
1
.
7
)
Obviously, our
π
πΏ
πΌ
in (1.5 ) does not satisfy this condition. Indeed, let
π₯
tend to zero and
π¦
=
1
; then the left side becomes greater than the right.
It is notable the generalized square functions associated to Schrödinger operators are studied in [7 ]. The authors of [7 ] gave several of equivalent conditions for BMO-boundedness of square functions.
In this paper, in order to obtain some key estimates, we will employ the differences in integral kernels (the heat kernel, the
π
-function kernel) associated with the Hermite operator and the Laguerre operator, respectively (see [8 , 9 ]).
The paper is organized as follows. In the next section we present some preliminary lemmas and collect some useful estimates of the kernels associated with the heat semigroups and the
π
-functions. In Section 3 , we establish the boundedness of two maximal operators (the Hardy-Littlewood maximal operator and the heat maximal function) from
B
M
O
πΏ
πΌ
to
B
M
O
πΏ
πΌ
. In Section 4 , we obtain the boundedness on
B
M
O
πΏ
πΌ
of the Littlewood-Paley
π
-function associated with the heat semigroup for
πΏ
πΌ
. We make some conventions. Throughout this paper by
πΆ
we always denote a positive constant that may vary at each occurrence;
π΅
π
(
π¦
0
)
stands for
{
π¦
>
0
,
|
π¦
β
π¦
0
|
β€
π
}
;
π΄
βΌ
π΅
means
(
1
/
πΆ
)
π΄
β€
π΅
β€
πΆ
π΄
, and the notation
π
β²
π
is used to indicate that
π
β€
πΆ
π
with an independent positive constant
πΆ
.
2. Preliminaries Now we give the following covering lemma for
(
0
,
β
)
which will be used frequently below. The proof is trivial and left to the reader.
Lemma 2.1. Let
π₯
0
=
1
,
π₯
π
=
π₯
π
β
1
+
π
πΏ
πΌ
(
π₯
π
β
1
)
for
π
β₯
1
, and
π₯
π
=
π₯
π
+
1
β
π
πΏ
πΌ
(
π₯
π
+
1
)
for
π
<
0
. One defines the family of “critical balls” of
β¬
=
{
π΅
π
}
β
π
=
β
β
, where
π΅
π
βΆ
=
{
π₯
β
(
0
,
β
)
βΆ
|
π₯
β
π₯
π
|
<
π
πΏ
πΌ
(
π₯
π
)
}
. Then one has (a)
β
β
π
=
β
β
π΅
π
=
(
0
,
β
)
, (b) for every
π
β
β€
,
π΅
π
β©
π΅
π
=
β
provided that
π
β
{
π
β
1
,
π
,
π
+
1
}
, (c) for any
π¦
0
β
(
0
,
β
)
, at most three balls in
β¬
have nonempty intersection with
π΅
(
π¦
0
,
π
πΏ
πΌ
(
π¦
0
)
)
.
Corollary 2.2. There exists a constant
πΆ
>
0
such that for every
π΅
π
(
π₯
)
β
(
0
,
β
)
with
π
>
π
πΏ
πΌ
(
π₯
)
, one has
|
|
π΅
π
(
|
|
β€
ξ
π₯
)
ξ½
π΅
π
β
β¬
βΆ
π΅
π
β©
π΅
π
ξΎ
(
π₯
)
β
β
|
|
π΅
π
|
|
|
|
π΅
β€
πΆ
π
(
|
|
.
π₯
)
(
2
.
1
)
Corollary 2.3. There exists a constant
πΆ
such that, for
π
β
B
M
O
πΏ
πΌ
, one has
β
π
β
B
M
O
πΏ
πΌ
β€
πΆ
s
u
p
π
ξ
|
|
π
|
|
π΅
π
+
β
π
β
B
M
O
(
π΅
β
π
)
ξ
,
(
2
.
2
)
where, for any ball
π΅
, the norm
β
β
β
B
M
O
(
π΅
)
is given by
β
π
β
B
M
O
(
π΅
)
=
s
u
p
π΅
π
(
π₯
)
β
π΅
1
π΅
π
ξ
(
π₯
)
π΅
π
(
π₯
)
|
|
π
β
π
π΅
π
(
π₯
)
|
|
π
π¦
βΌ
s
u
p
π΅
π
(
π₯
)
β
π΅
i
n
f
π
β
β
1
π΅
π
ξ
(
π₯
)
π΅
π
(
π₯
)
|
|
|
|
π
β
π
π
π¦
.
(
2
.
3
)
Corollary 2.4 (see [3 , Corollary 3]). Let
π΅
=
π΅
π
(
π¦
0
)
β
(
0
,
β
)
. There exists a constant
πΆ
>
0
such that, for all
π
β
B
M
O
πΏ
πΌ
, one has (1) if
π
β₯
π
πΏ
πΌ
(
π¦
0
)
/
2
, then
β«
(
(
1
/
|
π΅
|
)
π΅
|
π
(
π₯
)
|
2
π
π₯
)
1
/
2
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
, (2) if
π
<
π
πΏ
πΌ
(
π¦
0
)
/
2
, then
β«
(
(
1
/
|
π΅
|
)
π΅
|
π
(
π₯
)
β
π
π΅
|
2
π
π₯
)
1
/
2
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
. We give two elementary lemmas, which will be used frequently in next section. The proofs are trivial, and the reader also refer to Lemmas 9 and 2 in [5 ].
Lemma 2.5. Let
β
β
B
M
O
(
π΅
β
π
)
and
π
1
and
π
2
be functions in
πΏ
β
(
0
,
β
)
. If
π
is any measurable function satisfying
β
+
π
1
β€
π
β€
β
+
π
2
,
a
.
e
.
,
(
2
.
4
)
then
π
β
B
M
O
(
π΅
β
π
)
and
β
π
β
B
M
O
(
π΅
β
π
)
β€
β
β
β
B
M
O
(
π΅
β
π
)
+
m
a
x
(
β
π
1
β
β
,
β
π
2
β
β
)
.
Lemma 2.6. For all
π
β
B
M
O
πΏ
πΌ
and
π΅
=
π΅
π
(
π¦
0
)
with
π
<
π
πΏ
πΌ
(
π¦
0
)
. There exists a constant
πΆ
>
0
such that
|
|
π
π΅
β
|
|
ξ©
π
β€
πΆ
1
+
l
o
g
πΏ
πΌ
ξ·
π¦
0
ξΈ
π
ξͺ
β
π
β
B
M
O
πΏ
πΌ
.
(
2
.
5
)
Let
π»
be the Hermite operator
1
π»
=
2
ξ΅
β
π
2
π
π₯
2
+
π₯
2
ξΆ
.
(
2
.
6
)
One considers the heat diffusion semigroup
{
π
π‘
}
π‘
>
0
associated with
π»
and defined by, for every
π
β
πΏ
2
(
β
)
,
π
π‘
ξ
π
(
π₯
)
=
β
π
π‘
(
π₯
,
π¦
)
π
(
π¦
)
π
π¦
,
π₯
β
β
,
(
2
.
7
)
where for each
π₯
,
π¦
β
β
and
π‘
>
0
,
π
π‘
ξ¬
π
(
π₯
,
π¦
)
=
β
π‘
π
ξ·
1
β
π
β
2
π‘
ξΈ
ξ
1
/
2
ξ΅
β
1
e
x
p
2
1
+
π
β
2
π‘
1
β
π
β
2
π‘
ξ·
π₯
2
+
π¦
2
ξΈ
π
+
2
π₯
π¦
β
π‘
1
β
π
β
2
π‘
ξΆ
(
2
.
8
)
(see [10 ]).
Proposition 2.7. Let
πΌ
>
β
1
/
2
,
π
π‘
(
π₯
,
π¦
)
be in (2.8 ). There exists
πΆ
>
0
such that, for
π‘
>
0
, (a)
π
πΌ
π‘
(
π₯
,
π¦
)
β€
πΆ
π¦
πΌ
+
1
/
2
π₯
β
πΌ
β
3
/
2
,
0
<
π¦
<
π₯
/
2
, (b)
π
πΌ
π‘
(
π₯
,
π¦
)
β€
πΆ
π₯
πΌ
+
1
/
2
π¦
β
πΌ
β
3
/
2
,
0
<
2
π₯
<
π¦
, (c)
|
π
πΌ
π‘
(
π₯
,
π¦
)
β
π
π‘
(
π₯
,
π¦
)
|
β€
πΆ
(
1
/
π¦
)
,
π₯
/
2
<
π¦
<
2
π₯
, (d)
|
π
πΌ
π‘
β
(
π₯
,
π¦
)
|
β€
πΆ
(
1
/
π‘
)
π
β
|
π₯
β
π¦
|
2
/
1
0
π‘
.
Parts (a), (b), and (c) are the contents of Lemma 2.11 in [8 ]. Part (d) is from (2.6) in [4 ].
Remark 2.8. The ranges
0
<
π¦
<
π₯
/
2
and
0
<
2
π₯
<
π¦
are not critical; Proposition 2.7 also holds when
0
<
π¦
<
π₯
/
π
and
0
<
π
π₯
<
π¦
, where
π
>
1
.
Now we consider the estimates of the integral kernel for the
π
-function, which will be defined in Section 4 :
π
π‘
(
π₯
,
π¦
)
=
π‘
2
π
π
πΌ
π
(
π₯
,
π¦
)
|
|
|
|
π
π
π
=
π‘
2
,
(
2
.
9
)
π
π‘
(
π₯
,
π¦
)
=
π‘
2
π
π
π
(
π₯
,
π¦
)
|
|
|
|
π
π
π
=
π‘
2
.
(
2
.
1
0
)
Proposition 2.9. One has, (a) for every
π‘
,
π₯
,
π¦
β
(
0
,
β
)
such that
π
β
π‘
2
π₯
π¦
/
(
1
β
π
β
2
π‘
2
)
β€
1
,
|
|
π
π‘
(
|
|
π₯
,
π¦
)
β€
πΆ
π‘
2
(
π₯
π¦
)
(
πΌ
+
1
/
2
)
π
β
(
π₯
2
+
π¦
2
)
/
8
π‘
2
π
β
(
πΌ
+
1
)
π‘
2
ξ·
1
β
π
β
2
π‘
2
ξΈ
πΌ
+
2
,
(
2
.
1
1
)
(b) for every
π‘
,
π₯
,
π¦
β
(
0
,
β
)
such that
π
β
π‘
2
π₯
π¦
/
(
1
β
π
β
2
π‘
2
)
>
1
,
|
|
π
π‘
(
π₯
,
π¦
)
β
π
π‘
(
|
|
π₯
,
π¦
)
β€
πΆ
π‘
2
π
β
(
π₯
β
π¦
)
2
/
2
π‘
2
π
π‘
2
/
2
ξ·
π₯
π¦
1
β
π
β
π‘
2
ξΈ
1
/
2
.
(
2
.
1
2
)
Parts (a) and (b) are contained in [9 , (3.4) and (3.6)].
Proposition 2.10. For every
π
β₯
1
, there is a constant
πΆ
π
such that (a) if
π‘
>
0
,
|
π
π‘
(
π₯
,
π¦
)
|
β€
πΆ
π
π
β
π‘
2
/
8
(
1
/
π‘
)
π
β
|
π₯
β
π¦
|
2
/
1
0
π‘
2
(
1
+
π‘
|
π₯
|
)
β
π
; (b) for
|
β
|
β€
π‘
,
|
π
π‘
(
π₯
+
β
,
π¦
)
β
π
π‘
(
π₯
,
π¦
)
|
β€
πΆ
(
|
β
|
/
π‘
)
(
1
/
π‘
)
π
β
|
π₯
β
π¦
|
2
/
2
0
π‘
2
,
πΆ
is independent of
π₯
,
π¦
,
π‘
; (c)
|
β«
β
β
β
π
π‘
(
π₯
,
π¦
)
π
π¦
|
β€
πΆ
(
π‘
/
π
πΏ
πΌ
(
π₯
)
)
2
,
πΆ
is independent of
π₯
and
π‘
.
Proof. By using (2.8 ) we can write, for every
π₯
,
π¦
β
β
and
π
>
0
,
π
π
π
π
π
1
(
π₯
,
π¦
)
=
β
2
β
π
π
β
(
(
π₯
β
π
β
π
π¦
)
2
+
(
π¦
β
π
β
π
π₯
)
2
)
/
2
(
1
β
π
β
2
π
)
π
β
π
/
2
ξ·
1
β
π
β
2
π
ξΈ
3
/
2
Γ
ξ»
1
+
π
β
2
π
+
2
π
β
π
(
π¦
(
π₯
β
π
β
π
π¦
)
+
π₯
(
π¦
β
π
β
π
π₯
)
)
β
2
π
β
2
π
(
π₯
β
π
β
π
π¦
)
2
+
(
π¦
β
π
β
π
π₯
)
2
1
β
π
β
2
π
ξΌ
.
(
2
.
1
3
)
By the simple fact
(
π₯
β
π
β
π
π¦
)
2
+
(
π¦
β
π
β
π
π₯
)
2
=
2
(
π₯
β
π¦
)
2
π
β
π
+
ξ·
π₯
2
+
π¦
2
ξΈ
(
1
β
π
β
π
)
2
,
(
2
.
1
4
)
a straightforward manipulation leads to
|
|
|
π
π
π
π
π
|
|
|
(
π₯
,
π¦
)
β€
πΆ
π
β
(
(
π₯
β
π¦
)
2
+
(
π₯
2
+
π¦
2
)
(
1
β
π
β
π
)
2
)
/
8
(
1
β
π
β
2
π
)
π
β
π
/
2
ξ·
1
β
π
β
2
π
ξΈ
3
/
2
β€
πΆ
π
π
β
π
/
8
ξ·
1
β
π
β
2
π
ξΈ
3
/
2
π
β
π
(
|
π₯
β
π¦
|
2
/
1
0
π
)
ξ
β
1
+
ξ
π
|
π₯
|
β
π
,
(
2
.
1
5
)
which implies (a). To prove (b), we also directly compute the
π₯
partial derivative:
π
π
π
π₯
π
π
π
1
(
π₯
,
π¦
)
=
β
2
β
π
π
β
(
(
π₯
β
π
β
π
π¦
)
2
+
(
π¦
β
π
β
π
π₯
)
2
)
/
2
(
1
β
π
β
2
π
)
π
β
π
/
2
ξ·
1
β
π
β
2
π
ξΈ
3
/
2
Γ
ξ»
4
π
β
π
(
π¦
β
π
β
π
π₯
)
β
4
π
β
2
π
(
π₯
β
π¦
)
1
+
π
β
π
ξΌ
+
1
2
β
π
π
β
(
(
π₯
β
π
β
π
π¦
)
2
+
(
π¦
β
π
β
π
π₯
)
2
)
/
2
(
1
β
π
β
2
π
)
π
β
π
/
2
ξ·
1
β
π
β
2
π
ξΈ
5
/
2
(
(
π₯
β
π
β
π
π¦
)
β
π
β
π
(
π¦
β
π
β
π
π₯
Γ
ξ»
)
)
1
+
π
β
2
π
+
2
π
β
π
(
π¦
(
π₯
β
π
β
π
π¦
)
+
π₯
(
π¦
β
π
β
π
π₯
)
)
β
2
π
β
2
π
(
π₯
β
π
β
π
π¦
)
2
+
(
π¦
β
π
β
π
π₯
)
2
1
β
π
β
2
π
ξΌ
.
(
2
.
1
6
)
By an elementary manipulation and (2.14 ), we have
|
|
|
π
π
π
π₯
π
π
π
|
|
|
1
(
π₯
,
π¦
)
β€
πΆ
π
2
π
β
(
π₯
β
π¦
)
2
/
1
6
π
.
(
2
.
1
7
)
This together with the mean value theorem and the condition
|
β
|
β€
π‘
leads to (b). Let
π
π
(
π¦
)
=
π
(
π¦
/
π
)
;
π
(
π¦
)
is a smooth function satisfying
π
(
π¦
)
=
1
for
|
π¦
|
β€
1
,
π
(
π¦
)
=
0
for
|
π¦
|
β₯
2
and
Ξ
π
(
π¦
)
β€
1
for
π¦
β
β
. From the above, for fixed
π
and
π₯
, a straightforward manipulation shows that
ξ
+
β
β
β
|
|
|
|
π
π
π
(
π₯
,
π¦
)
|
|
|
|
π
π
π
π¦
<
β
.
(
2
.
1
8
)
Hence, we have
|
|
|
|
ξ
β
β
β
π
π
π
(
π₯
,
π¦
)
|
|
|
|
=
|
|
|
|
π
π
π
π¦
l
i
m
π
β
β
ξ
β
β
β
π
π
π
(
π₯
,
π¦
)
π
π
π
π
|
|
|
|
=
|
|
|
|
(
π¦
)
π
π¦
l
i
m
π
β
β
ξ
β
β
β
π
π
(
π₯
,
π¦
)
π»
π
π
(
|
|
|
|
ξ
π¦
)
π
π¦
β€
πΆ
β
β
β
π
π
(
π₯
,
π¦
)
π¦
2
π
π¦
.
(
2
.
1
9
)
Using (2.8 ) again,
|
|
|
|
ξ
πΌ
=
β
β
β
π
π
π
(
π₯
,
π¦
)
|
|
|
|
ξ
π
π
π
π¦
β€
πΆ
β
β
β
π
β
π
/
4
β
π
ξ©
β
e
x
p
(
π₯
β
π¦
)
2
π
β
π
+
ξ·
π₯
2
+
π¦
2
ξΈ
(
1
β
π
β
π
)
2
2
ξ·
1
β
π
β
2
π
ξΈ
ξͺ
ξ·
(
π¦
β
π₯
)
2
+
π₯
2
ξΈ
π
π¦
,
(
2
.
2
0
)
which implies (c).
Lemma 2.11 (see [3 , Theorem 2]). For all
π
β
B
M
O
πΏ
πΌ
and
π΅
=
π΅
π
(
π¦
0
)
β
(
0
,
β
)
, there exists a constant
πΆ
>
0
such that
1
|
|
π΅
|
|
ξ
π
0
ξ
π΅
π
2
π‘
π
(
π₯
)
π
π₯
π
π‘
π‘
β€
πΆ
β
π
β
2
B
M
O
πΏ
πΌ
.
(
2
.
2
1
)
3. Maximal Operators First of all, we define the following notions:
π
+
π
(
π₯
)
=
s
u
p
π₯
β
π΅
β
(
0
,
β
)
1
|
|
π΅
|
|
ξ
π΅
|
|
|
|
β
π
(
π¦
)
π
π¦
,
(
3
.
1
)
β
πΌ
π
(
π₯
)
=
s
u
p
π‘
>
0
|
|
π
πΌ
π‘
|
|
.
π
(
π₯
)
(
3
.
2
)
In this section, we will show
β
β
πΌ
and
π
+
are bounded on
B
M
O
πΏ
πΌ
.
Theorem 3.1. There exists a constant
πΆ
>
0
such that, for all
π
β
B
M
O
πΏ
πΌ
,
π
+
π
<
β
, for a.e.
π₯
β
(
0
,
β
)
, and
β
β
π
+
π
β
β
B
M
O
πΏ
πΌ
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
3
)
Proof. First of all, we show that for a.e.
π₯
β
(
0
,
β
)
,
π
+
π
<
β
. To do this, we only need to show that for, at almost
π₯
β
π΅
π
β
β¬
in Lemma 2.1 ,
π
+
π
(
π₯
)
<
β
. Let us split
π
=
π
1
+
π
2
with
π
1
=
π
π
π΅
β
π
. Obviously, since
π
is locally integrable, we have
π
+
π
1
<
β
for a.e.
π₯
β
(
0
,
β
)
. For
π
2
, if
π₯
β
π΅
and
π΅
β©
π΅
β
π
=
β
, since supp
π
2
is in the complement of
π΅
β
π
, we have
β«
(
1
/
|
π΅
|
)
π΅
|
π
(
π¦
)
|
π
π¦
=
0
. Otherwise, by the definition of
B
M
O
πΏ
πΌ
,
β«
(
1
/
|
π΅
|
)
π΅
|
π
(
π¦
)
|
π
π¦
β€
(
4
/
|
π΅
4
π
(
π₯
π
β«
)
|
)
π΅
4
π
(
π₯
π
)
|
π
(
π¦
)
|
π
π¦
β€
π
β
π
β
B
M
O
πΏ
πΌ
. We turn to the boundedness in
B
M
O
πΏ
πΌ
. Let
π
denote the Hardy-Littlewood function on
β
; it is well known in [11 ] that
π
is bounded on
B
M
O
(
β
)
. Let
π
0
be a function defined on
β
which is
π
on
(
0
,
β
)
and
0
on
(
β
β
,
0
]
. Notice that
π
+
π
=
π
π
0
, for
π₯
β
(
0
,
β
)
, so
β
β
π
+
π
β
β
B
M
O
(
π΅
β
π
)
=
β
β
π
π
0
β
β
B
M
O
(
π΅
β
π
)
β
β
π
β€
πΆ
0
β
β
B
M
O
.
(
3
.
4
)
Now, we need to show that
β
π
0
β
B
M
O
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
. Indeed, if
π΅
β
(
0
,
β
)
, it is obvious that
β«
(
1
/
|
π΅
|
)
π΅
|
π
0
β
(
π
0
)
π΅
|
π
π¦
β€
β
π
β
B
M
O
πΏ
πΌ
. If
π΅
β©
(
0
,
β
)
=
β
, then
β«
(
1
/
|
π΅
|
)
π΅
|
π
0
β
(
π
0
)
π΅
|
π
π¦
=
0
. If
π΅
β©
(
0
,
β
)
β
β
and
π΅
β©
(
β
β
,
0
)
β
β
, let
π΅
=
π΅
1
βͺ
π΅
2
, here
π΅
1
=
π΅
β©
(
β
β
,
0
)
and
π΅
2
=
π΅
β©
(
0
,
β
)
, then
1
|
|
π΅
|
|
ξ
π΅
|
|
π
0
β
ξ·
π
0
ξΈ
π΅
|
|
1
π
π¦
β€
2
|
|
π΅
|
|
ξ
π΅
2
|
|
π
0
|
|
π
π¦
β€
2
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
5
)
On the other hand, we again split
π
=
π
1
+
π
2
with
π
1
=
π
π
π΅
β
π
, from the argument above,
π
+
π
2
(
π₯
)
β€
π
β
π
β
B
M
O
πΏ
πΌ
, for a.e
π₯
β
π΅
π
. So
1
|
|
π΅
π
|
|
ξ
π΅
π
|
|
π
+
π
|
|
1
π
π¦
β€
|
|
π΅
π
|
|
ξ
π΅
π
|
|
π
+
π
1
|
|
1
π
π¦
+
|
|
π΅
π
|
|
ξ
π΅
π
|
|
π
+
π
2
|
|
β²
ξ΅
1
π
π¦
|
|
π΅
π
|
|
ξ
π΅
π
|
|
π
+
π
1
|
|
2
ξΆ
π
π¦
1
/
2
+
β
π
β
B
M
O
πΏ
πΌ
β²
β
π
β
B
M
O
πΏ
πΌ
,
(
3
.
6
)
where in the last inequality we have used Corollary 2.4 .
Theorem 3.2. Let
πΌ
>
β
1
/
2
. There exists a constant
πΆ
>
0
such that
β
β
β
β
πΌ
π
β
β
B
M
O
πΏ
πΌ
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
7
)
Proof. By the definition of
B
M
O
πΏ
πΌ
and Corollary 2.3 , it suffices to prove the following: for every fixed “critical ball”
π΅
π
β
β¬
(see Lemma 2.1 ) we have (1)
β«
(
1
/
|
π΅
_
π
|
)
π΅
π
|
β
β
πΌ
π
|
π
π₯
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
, (2)
β
β
β
πΌ
π
β
B
M
O
(
π΅
β
π
)
β€
πΆ
β
π
β
B
M
O
L
πΌ
. Let us start to prove (1). It is immediate from Theorem 3.1 and (d) of Proposition 2.7 ; since
β
β
πΌ
π
(
π₯
)
β€
π
+
π
(
π₯
)
, for
π₯
>
0
, therefore,
1
|
|
π΅
π
|
|
ξ
π΅
π
|
|
π
+
π
|
|
π
π¦
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
8
)
It remains to show (2). By Lemma 2.5 , we split
β
β
πΌ
π
(
π₯
)
into several parts. First, we shall show
β
β
β
β
β
s
u
p
π‘
>
π
2
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
π
πΌ
π‘
|
|
β
β
β
β
β
π
(
π₯
)
πΏ
β
(
π΅
β
π
)
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
9
)
From (d) of Proposition 2.7 , we have
|
|
π
πΌ
π‘
|
|
β²
ξ
π
(
π₯
)
β
0
|
|
|
|
1
π
(
π¦
)
π‘
1
/
2
ξ©
|
|
|
|
1
+
π₯
β
π¦
β
π‘
ξͺ
β
π
β²
π
π¦
β
ξ
π
=
0
1
2
π
π
1
π‘
1
/
2
ξ
{
π¦
>
0
,
|
π¦
β
π₯
|
<
2
π
β
π‘
}
|
|
|
|
π
(
π¦
)
π
π¦
.
(
3
.
1
0
)
Notice that, for
π
β₯
0
and
π‘
>
π
2
πΏ
πΌ
(
π₯
π
)
, we have
2
π
β
π‘
β₯
π
πΏ
πΌ
(
π₯
)
βΌ
π
πΏ
πΌ
(
π₯
π
)
, for
π₯
β
π΅
β
π
. Thus
1
β
π‘
ξ
{
π¦
>
0
,
|
π¦
β
π₯
|
<
2
π
β
π‘
}
|
|
|
|
π
(
π¦
)
π
π¦
β€
πΆ
2
π
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
1
1
)
Therefore,
s
u
p
π‘
>
π
2
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
π
πΌ
π‘
|
|
β²
π
(
π₯
)
β
ξ
π
=
0
1
2
π
β
1
β
π
β
B
M
O
πΏ
πΌ
β²
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
1
2
)
By Lemma 2.5 , it suffices to show that
s
u
p
0
<
π‘
β€
π
2
πΏ
πΌ
π
)
(
π₯
|
π
πΌ
π‘
π
(
π₯
)
|
satisfies (2). Write
π
=
π
π
{
π₯
π
/
2
β€
π¦
β€
2
π₯
π
}
+
π
π
{
π¦
<
π₯
π
/
2
}
+
π
π
{
π¦
>
2
π₯
π
}
=
π
1
+
π
2
+
π
3
.
(
3
.
1
3
)
By Proposition 2.7 , it easily follows that
β
β
β
β
β
s
u
p
0
<
π‘
β€
π
2
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
π
πΌ
π‘
π
2
|
|
β
β
β
β
β
(
π₯
)
πΏ
β
(
π΅
β
π
)
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
,
β
β
β
β
β
s
u
p
0
<
π‘
β€
π
2
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
π
πΌ
π‘
π
3
|
|
β
β
β
β
β
(
π₯
)
πΏ
β
(
π΅
β
π
)
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
1
4
)
Indeed, since
π₯
βΌ
π₯
π
, for
π₯
β
π΅
β
π
, by (a) of Proposition 2.7 and Remark 2.8 , we have
|
|
π
πΌ
π‘
π
2
|
|
β²
ξ
(
π₯
)
π₯
π
0
/
2
π¦
πΌ
+
1
/
2
π₯
π
β
πΌ
β
3
/
2
|
|
|
|
β²
1
π
(
π¦
)
π
π¦
π₯
π
ξ
π₯
π
0
/
2
|
|
π
|
|
(
π¦
)
π
π¦
β²
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
1
5
)
Similarly,
|
|
π
πΌ
π‘
π
3
(
|
|
β²
π₯
)
β
ξ
π
=
1
ξ·
2
π
π₯
π
ξΈ
β
πΌ
β
3
/
2
ξ·
π₯
π
ξΈ
πΌ
+
1
/
2
ξ
2
π
+
1
π₯
π
2
π
π₯
π
|
|
|
|
β²
π
(
π¦
)
π
π¦
β
ξ
π
=
1
(
2
π
)
β
πΌ
β
1
/
2
β
π
β
B
M
O
πΏ
πΌ
β²
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
1
6
)
Now, we come to treat
π
1
. We make further decompositions. Split
π
πΌ
π‘
π
1
=
ξ·
π
πΌ
π‘
π
1
β
π
π‘
π
1
ξΈ
+
ξ·
π
π‘
π
1
β
π»
π‘
π
1
ξΈ
+
π»
π‘
π
1
,
(
3
.
1
7
)
where
π»
π‘
ξ
π
(
π₯
)
=
β
0
ξ¬
π
β
π‘
π
ξ·
1
β
π
β
2
π‘
ξΈ
ξ
1
/
2
ξ΅
β
1
e
x
p
2
1
+
π
β
2
π‘
1
β
π
β
2
π‘
(
π₯
β
π¦
)
2
ξΆ
π
(
π¦
)
π
π¦
.
(
3
.
1
8
)
For the first term, by (c) of Proposition 2.7 , we have
|
|
π
πΌ
π‘
π
1
β
π
π‘
π
1
|
|
1
β€
πΆ
π₯
π
ξ
2
π₯
π
π₯
2
/
2
|
|
|
|
π
(
π¦
)
π
π¦
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
1
9
)
By (2.8 ),
π
π‘
π
1
(
π₯
)
β
π»
π‘
π
1
=
ξ
(
π₯
)
β
0
ξ¬
π
β
π‘
π
ξ·
1
β
π
β
2
π‘
ξΈ
ξ
1
/
2
ξ΅
β
1
e
x
p
2
1
+
π
β
2
π‘
1
β
π
β
2
π‘
(
π₯
β
π¦
)
2
ξΆ
ξ
π
β
2
π₯
π¦
(
1
β
π
β
π‘
)
2
/
1
β
π
β
2
π‘
ξ
π
β
1
1
(
π¦
)
π
π¦
.
(
3
.
2
0
)
Notice that
|
π
β
2
π₯
π¦
(
1
β
π
β
π‘
)
2
/
(
1
β
π
β
2
π‘
)
β
1
|
β€
π
π‘
π₯
2
π
, when
π‘
β€
π
πΏ
πΌ
(
π₯
π
)
2
,
π₯
π
/
2
β€
π¦
β€
2
π₯
π
and
π₯
β
π΅
β
π
. Therefore, for
π₯
β
π΅
β
π
and
π‘
β€
π
πΏ
πΌ
(
π₯
π
)
2
, we obtain
|
|
π
π‘
π
1
(
π₯
)
β
π»
π‘
π
1
|
|
(
π₯
)
β²
π‘
π₯
2
π
ξ
β
0
1
β
π‘
π
β
π
0
|
π₯
β
π¦
|
2
/
π‘
|
|
π
1
|
|
(
π¦
)
π
π¦
β²
π‘
π₯
2
π
ξ
1
β€
2
π
β€
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
/
β
π‘
2
β
π
(
π
β
1
)
1
2
π
β
π‘
ξ
{
π¦
>
0
,
|
π¦
β
π₯
|
<
2
π
β
π‘
}
|
|
|
|
π
(
π¦
)
π
π¦
+
π‘
π₯
2
π
ξ
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
/
β
π‘
<
2
π
2
β
π
(
π
β
1
)
1
2
π
β
π‘
ξ
{
π¦
>
0
,
|
π¦
β
π₯
|
<
2
π
β
π‘
}
|
|
|
|
β²
ξ
π
(
π¦
)
π
π¦
1
β€
2
π
β€
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
/
β
π‘
2
β
π
(
π
β
1
)
π‘
π₯
2
π
ξ©
ξ©
π
1
+
l
o
g
πΏ
πΌ
ξ·
π₯
π
ξΈ
2
π
β
π‘
ξͺ
ξͺ
β
π
β
B
M
O
πΏ
πΌ
+
β
ξ
π
=
0
2
β
π
(
π
β
1
)
β
π
β
B
M
O
πΏ
πΌ
β²
β
ξ
π
=
0
2
β
π
(
π
β
1
)
β
π
β
B
M
O
πΏ
πΌ
β²
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
2
1
)
Finally, by Lemma 2.5 again, we need to show that
s
u
p
0
<
π‘
β€
π
2
πΏ
πΌ
π
)
(
π₯
|
π»
π‘
π
1
(
π₯
)
|
satisfies (2). Consider
π΅
=
π΅
π
(
π₯
0
)
β
π΅
β
π
and write
π
1
=
ξ·
π
1
β
π
π΅
β
ξΈ
π
π΅
β
+
π
ξΊ
ξ·
1
β
π
π΅
β
ξΈ
π
(
π΅
β
)
π
β©
(
0
,
β
)
+
π
π΅
β
π
(
0
,
β
)
ξ»
=
π
1
1
+
π
1
2
.
(
3
.
2
2
)
By Corollary 2.3 , we choose a constant
πΆ
π΅
=
s
u
p
0
<
π‘
β€
π
πΏ
πΌ
(
π₯
π
)
2
|
π»
π‘
π
1
2
(
π₯
0
)
|
,
1
|
|
π΅
|
|
ξ
π΅
|
|
|
|
|
s
u
p
0
<
π‘
β€
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
2
|
|
π»
π‘
π
1
|
|
(
π₯
)
β
πΆ
π΅
|
|
|
|
|
1
π
π₯
β€
|
|
π΅
|
|
ξ
π΅
s
u
p
0
<
π‘
β€
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
2
|
|
π»
π‘
π
1
(
π₯
)
β
π»
π‘
π
1
2
ξ·
π₯
0
ξΈ
|
|
β€
1
π
π₯
|
|
π΅
|
|
ξ
π΅
s
u
p
0
<
π‘
β€
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
2
|
|
π»
π‘
π
1
1
|
|
1
(
π₯
)
π
π₯
+
|
|
π΅
|
|
ξ
π΅
s
u
p
0
<
π‘
β€
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
2
|
|
π»
π‘
π
1
2
(
π₯
)
β
π»
π‘
π
1
2
ξ·
π₯
0
ξΈ
|
|
π
π₯
.
(
3
.
2
3
)
For the first integral, by Corollary 2.4 it easily follows that
1
|
|
π΅
|
|
ξ
π΅
s
u
p
0
<
π‘
β€
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
2
|
|
π»
π‘
π
1
1
|
|
ξ΅
1
(
π₯
)
π
π₯
β€
|
|
π΅
|
|
ξ
π΅
|
|
π
1
1
|
|
2
ξΆ
π
π₯
1
/
2
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
2
4
)
For the second integral,
|
|
π»
π‘
π
1
(
π₯
)
β
π»
π‘
π
1
2
ξ·
π₯
0
ξΈ
|
|
β€
|
|
|
|
ξ
(
π΅
β
)
π
β©
(
0
,
β
)
ξ·
π»
π‘
(
π₯
,
π¦
)
β
π»
π‘
ξ·
π₯
0
π
,
π¦
ξΈ
ξΈ
ξ·
1
(
π¦
)
β
π
π΅
ξΈ
|
|
|
|
+
|
|
|
|
ξ
π
π¦
β
0
ξ·
π»
π‘
(
π₯
,
π¦
)
β
π»
π‘
ξ·
π₯
0
π
,
π¦
ξΈ
ξΈ
π΅
|
|
|
|
π
π¦
=
πΌ
π‘
1
(
π₯
)
+
πΌ
π‘
2
(
π₯
)
.
(
3
.
2
5
)
By the mean value theorem and the elementary inequality
1
2
π
π
ξ
{
π¦
>
0
,
|
π¦
β
π₯
0
|
<
2
π
π
}
|
|
π
(
π¦
)
β
π
π΅
|
|
π
π¦
β€
π
π
β
π
β
B
M
O
πΏ
πΌ
,
(
3
.
2
6
)
we have
πΌ
π‘
1
ξ
(
π₯
)
β²
(
π΅
β
)
π
β©
(
0
,
β
)
1
β
π‘
π
β
|
π¦
β
π₯
0
|
2
/
1
0
π‘
|
|
π₯
β
π₯
0
|
|
β
π‘
|
|
π
1
(
π¦
)
β
π
π΅
|
|
β²
ξ
π
π¦
(
π΅
β
)
π
β©
(
0
,
β
)
|
|
π₯
β
π₯
0
|
|
|
|
π¦
β
π₯
0
|
|
2
|
|
π
1
(
π¦
)
β
π
π΅
|
|
π
π¦
β²
π
β
ξ
π
=
0
1
(
2
π
π
)
2
ξ
{
π¦
>
0
,
|
π¦
β
π₯
0
|
<
2
π
π
}
ξ·
|
|
π
(
π¦
)
β
π
π΅
|
|
+
|
|
π
(
π¦
)
β
π
1
|
|
ξΈ
β²
(
π¦
)
π
π¦
β
ξ
π
=
0
2
β
π
(
π
+
1
)
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
2
7
)
On the other hand, by the fact
|
π
π΅
|
β€
πΆ
(
1
+
l
o
g
(
π
πΏ
πΌ
(
π₯
0
)
/
π
)
)
β
π
β
B
M
O
πΏ
πΌ
in Lemma 2.6 , we obtain
πΌ
π‘
2
|
|
|
|
ξ
(
π₯
)
β²
0
β
β
ξ·
π»
π‘
(
π₯
,
π¦
)
β
π»
π‘
ξ·
π₯
0
π
,
π¦
ξΈ
ξΈ
π΅
|
|
|
|
β²
ξ
π
π¦
{
π¦
<
0
}
|
|
π₯
β
π₯
0
|
|
|
|
π¦
β
π₯
0
|
|
2
|
|
π
π΅
|
|
β²
π
π
π¦
π
πΏ
πΌ
ξ·
π₯
0
ξΈ
ξ©
π
1
+
l
o
g
πΏ
πΌ
ξ·
π₯
0
ξΈ
π
ξͺ
β
π
β
B
M
O
πΏ
πΌ
β²
β
π
β
B
M
O
πΏ
πΌ
.
(
3
.
2
8
)
Therefore, we obtain
1
|
|
π΅
|
|
ξ
π΅
s
u
p
0
<
π‘
β€
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
2
|
|
π»
π‘
π
1
2
(
π₯
)
β
π»
π‘
π
1
2
ξ·
π₯
0
ξΈ
|
|
π
π₯
β²
β
π
β
B
M
O
πΏ
πΌ
,
(
3
.
2
9
)
which establishes the proof.
4.
π
-Function For all
π
β
πΏ
1
l
o
c
(
0
,
β
)
and
π₯
β
(
0
,
β
)
, define the Littlewood-Paley
π
-function by
ξ΅
ξ
π
(
π
)
(
π₯
)
β‘
β
0
|
|
π
π‘
|
|
π
(
π₯
)
2
π
π‘
π‘
ξΆ
1
/
2
,
(
4
.
1
)
where,
{
π
π‘
}
π‘
>
0
is a family of operators with the integral kernels
π
π‘
(
π₯
,
π¦
)
=
π‘
2
π
π
πΌ
π
(
π₯
,
π¦
)
|
|
|
|
π
π
π
=
π‘
2
.
(
4
.
2
)
Theorem 4.1. Let
πΌ
>
β
1
/
2
. There exists a constant
πΆ
>
0
such that, for all
π
β
B
M
O
πΏ
πΌ
,
π
(
π
)
β
B
M
O
πΏ
πΌ
and
β
π
(
π
)
β
B
M
O
πΏ
πΌ
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
Proof. By Proposition 2.9 and (a) of Proposition 2.10 , we have
π
π‘
1
(
π₯
,
π¦
)
β€
π
π‘
π
β
π
1
|
π₯
β
π¦
|
2
/
π‘
2
.
(
4
.
3
)
For
π
β
B
M
O
πΏ
πΌ
, because of this and the integrability of
(
1
+
|
π₯
|
)
β
2
π
(
π₯
)
(see [12 , page 141]),
π
π‘
ξ
π
(
π₯
)
=
β
0
π
π‘
(
π₯
,
π¦
)
π
(
π¦
)
π
π¦
(
4
.
4
)
is well defined absolutely convergent integral for all
(
π₯
,
π‘
)
β
(
0
,
β
)
Γ
(
0
,
β
)
. Similar to the proof of Theorem 3.2 , we will try to show that, for
π΅
π
β
β¬
in Lemma 2.1 , (1)
(
1
/
|
π΅
π
β«
|
)
π΅
π
|
π
(
π
)
(
π₯
)
|
π
π₯
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
, (2)
β
π
(
π
)
(
π₯
)
β
B
M
O
(
π΅
β
π
)
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
. We split
[
]
π
(
π
)
(
π₯
)
2
=
ξΊ
π
1
ξ»
(
π
)
(
π₯
)
2
+
ξΊ
π
2
ξ»
(
π
)
(
π₯
)
2
=
ξ
2
0
π
πΏ
πΌ
(
π₯
π
)
0
|
|
π
π‘
|
|
π
(
π₯
)
2
π
π‘
π‘
+
ξ
β
2
0
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
π
π‘
|
|
π
(
π₯
)
2
π
π‘
π‘
.
(
4
.
5
)
By Lemma 2.11 and Hölder inequality, assertion (1) holds for
π
1
(
π
)
(
π₯
)
. To finish the proof of (1), it suffices to show that
β
β
π
2
β
β
(
π
)
πΏ
β
(
π΅
β
π
)
β€
π
β
π
β
B
M
O
πΏ
πΌ
.
(
4
.
6
)
In the next proof, for the sake of brevity we introduce the additional notations:
π
π‘
1
ξ―
π
(
π₯
)
=
π¦
β
(
0
,
β
)
βΆ
β
π‘
2
π₯
π¦
1
β
π
β
2
π‘
2
ξ°
π
β€
1
,
(
4
.
7
)
π‘
2
ξ―
π
(
π₯
)
=
&
π¦
β
(
0
,
β
)
βΆ
β
π‘
2
π₯
π¦
1
β
π
β
2
π‘
2
ξ°
>
1
.
(
4
.
8
)
By
π
π‘
1
(
π₯
)
and
π
π‘
1
(
π₯
)
, we split
π
π‘
π
(
π₯
)
as
|
|
π
π‘
|
|
β€
ξ
π
(
π₯
)
π
π‘
1
(
π₯
)
|
|
|
|
|
|
π
π
(
π¦
)
π‘
(
|
|
ξ
π₯
,
π¦
)
π
π¦
+
π
π‘
2
(
π₯
)
|
|
|
|
|
|
π
π
(
π¦
)
π‘
(
π₯
,
π¦
)
β
π
π‘
(
|
|
+
ξ
π₯
,
π¦
)
π
π¦
π
π‘
2
(
π₯
)
|
|
π
|
|
|
|
π
(
π¦
)
π‘
|
|
(
π₯
,
π¦
)
π
π¦
=
πΌ
π‘
1
(
π₯
)
+
πΌ
π‘
2
(
π₯
)
+
πΌ
π‘
3
(
π₯
)
.
(
4
.
9
)
For
πΌ
π‘
1
(
π₯
)
and
π₯
β
π΅
β
π
, we shall first show the inequality
π½
1
ξ
(
π₯
)
=
β
2
0
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
πΌ
π‘
1
|
|
π
(
π₯
)
2
π
π‘
π‘
β€
π
β
π
β
2
B
M
O
πΏ
πΌ
.
(
4
.
1
0
)
Using (a) of Proposition 2.9 , if
π₯
π
β€
1
,
π
πΏ
πΌ
(
π₯
π
)
βΌ
π₯
π
, we get
|
|
π
π‘
(
|
|
π₯
,
π¦
)
β€
πΆ
π‘
2
πΌ
+
3
ξ
π₯
π¦
π‘
2
ξ
πΌ
+
1
/
2
π
β
(
π₯
2
+
π¦
2
)
/
8
π‘
2
π
β
(
πΌ
+
1
)
π‘
2
ξ·
1
β
π
β
2
π‘
2
ξΈ
πΌ
+
2
ξ
π₯
β€
πΆ
π
π‘
ξ
πΌ
+
1
/
2
1
π‘
π
β
|
π₯
β
π¦
|
2
/
1
6
π‘
2
.
(
4
.
1
1
)
If
π₯
π
β₯
1
,
π
πΏ
πΌ
(
π₯
π
)
βΌ
1
/
π₯
π
, we have
|
|
π
π‘
|
|
1
(
π₯
,
π¦
)
β€
πΆ
π‘
π
β
(
π₯
2
+
π¦
2
)
/
8
π‘
2
π
β
(
(
πΌ
+
1
)
/
2
)
π‘
2
1
β€
πΆ
π‘
π₯
π
1
π‘
π
β
|
π₯
β
π¦
|
2
/
1
6
π‘
2
.
(
4
.
1
2
)
The previous two inequalities above imply
π½
1
ξ
(
π₯
)
β²
β
2
0
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
|
|
|
ξ
β
0
ξ©
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
π‘
ξͺ
π
1
π‘
π
β
|
π₯
β
π¦
|
2
/
1
6
π‘
2
|
|
|
|
|
|
|
|
|
π
(
π¦
)
π
π¦
2
π
π‘
π‘
β²
ξ
β
2
0
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
ξ©
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
π‘
ξͺ
2
π
|
|
|
|
|
β
ξ
π
=
0
2
β
π
(
π
β
1
)
1
2
π
π‘
ξ
{
π¦
>
0
,
|
π¦
β
π₯
|
<
2
π
π‘
}
|
|
|
|
|
|
|
|
|
π
(
π¦
)
π
π¦
2
π
π‘
π‘
β²
β
π
β
2
B
M
O
πΏ
πΌ
.
(
4
.
1
3
)
For
πΌ
π‘
2
(
π₯
)
and
π₯
β
π΅
β
π
, we shall also prove the inequality
π½
2
ξ
(
π₯
)
=
β
2
0
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
πΌ
π‘
2
|
|
π
(
π₯
)
2
π
π‘
π‘
β€
π
β
π
β
2
B
M
O
πΏ
πΌ
.
(
4
.
1
4
)
We split this integral as
π½
2
ξ
(
π₯
)
=
1
2
0
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
πΌ
π‘
2
|
|
π
(
π₯
)
2
π
π‘
π‘
+
ξ
β
1
|
|
πΌ
π‘
2
|
|
π
(
π₯
)
2
π
π‘
π‘
=
π½
3
(
π₯
)
+
π½
4
(
π₯
)
.
(
4
.
1
5
)
To deal with
π½
3
(
π₯
)
, we discuss two cases. In the first case of
π₯
π
β€
1
, notice that
π¦
>
π₯
, when
π₯
β
π΅
β
π
,
π¦
β
π
π‘
2
(
π₯
π
)
and
π‘
β₯
2
0
π
πΏ
πΌ
(
π₯
π
)
. According to (b) of Proposition 2.9 ,
π½
3
ξ
(
π₯
)
β²
1
2
0
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
|
|
|
ξ
β
ξ
1
β
π
2
β
2
π‘
ξ
π
π‘
2
/
π₯
1
π‘
π
β
|
π₯
β
π¦
|
2
/
4
π‘
2
π₯
π‘
ξ·
1
β
π
β
2
π‘
2
ξΈ
π
π‘
2
β
π₯
2
|
|
|
|
|
|
|
|
|
π
(
π¦
)
π
π¦
2
π
π‘
π‘
β²
ξ
β
2
0
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
π₯
2
π
π‘
2
|
|
|
|
ξ
β
0
1
π‘
π
β
|
π₯
β
π¦
|
2
/
4
π‘
2
|
|
|
|
|
|
|
|
π
(
π¦
)
π
π¦
2
π
π‘
π‘
β²
β
π
β
2
B
M
O
πΏ
πΌ
.
(
4
.
1
6
)
The last inequality is from the same proof of
π½
1
(
π₯
)
. In the second case of
π₯
π
>
1
, using (b) of Proposition 2.9 again, for
π‘
>
2
0
π
πΏ
πΌ
(
π₯
π
)
we obtain
|
|
πΌ
π‘
2
|
|
β²
1
(
π₯
)
π₯
π
ξ
2
π₯
π
π₯
π
/
2
π‘
π₯
π
|
|
|
|
ξ
π
(
π¦
)
π
π¦
+
(
0
,
β
)
β©
(
π₯
π
/
2
,
2
π₯
π
)
π
1
π‘
π
β
|
π₯
β
π¦
|
2
/
2
π‘
2
|
|
|
|
β²
π‘
π
(
π¦
)
π
π¦
π₯
π
β
π
β
B
M
O
πΏ
πΌ
+
π‘
π₯
π
ξ
β
0
1
π‘
π
β
|
π₯
β
π¦
|
2
/
4
π‘
2
|
|
|
|
β²
π‘
π
(
π¦
)
π
π¦
π₯
π
β
π
β
B
M
O
πΏ
πΌ
.
(
4
.
1
7
)
The last inequality is also from the same proof of
π½
1
(
π₯
)
. Inserting this into
π½
3
(
π₯
)
leads to
π½
3
(
π₯
)
β€
πΆ
β
π
β
2
B
M
O
πΏ
πΌ
. Now, it remains to show
π½
4
(
π₯
)
β€
π
β
π
β
2
B
M
O
πΏ
πΌ
. Using (b) of Proposition 2.9 , by the standard argument it easily follows that
π½
4
ξ
(
π₯
)
β²
β
1
π
β
π‘
/
1
0
π‘
|
|
|
|
ξ
β
0
1
π‘
π
β
|
π₯
β
π¦
|
2
/
2
π‘
2
|
|
|
|
|
|
|
|
π
(
π¦
)
π
π¦
2
π
π‘
β²
β
π
β
2
B
M
O
πΏ
πΌ
.
(
4
.
1
8
)
To complete the proof of (4.6 ), we need to show that
π½
5
ξ
(
π₯
)
=
β
2
0
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
|
|
πΌ
π‘
3
|
|
π
(
π₯
)
2
π
π‘
π‘
β€
π
β
π
β
2
B
M
O
πΏ
πΌ
.
(
4
.
1
9
)
We also consider two cases of
π₯
π
β€
1
and
π₯
π
>
1
. When
π₯
π
β€
1
, repeating the above argument for
π½
3
(
π₯
)
and using (a) of Proposition 2.10 , we have
π½
5
β€
π
β
π
β
2
B
M
O
πΏ
πΌ
. When
π₯
π
>
1
, using (a) of Proposition 2.10 again, for
π‘
β₯
2
0
π
πΏ
πΌ
(
π₯
π
)
, we obtain
|
|
πΌ
π‘
3
|
|
β²
1
(
π₯
)
π₯
π
π‘
ξ
β
0
1
π‘
π
β
π
|
π¦
β
π₯
|
2
/
π‘
2
|
|
|
|
β²
1
π
(
π¦
)
π
π¦
π‘
π₯
π
β
ξ
π
=
0
2
β
π
(
π
β
1
)
1
2
π
π‘
ξ
{
π¦
>
0
,
|
π¦
β
π₯
|
<
2
π
π‘
}
|
|
|
|
β²
π
π
(
π¦
)
π
π¦
πΏ
πΌ
ξ·
π₯
π
ξΈ
π‘
β
π
β
B
M
O
πΏ
πΌ
,
(
4
.
2
0
)
which shows that (4.19 ) holds. Next, we come to prove assertion (2). By (4.6 ) and Lemma 2.5 , we only need to show
β
β
β
β
ξ΅
ξ
2
0
π
πΏ
πΌ
(
π₯
π
)
0
|
|
π
π‘
|
|
π
(
π₯
)
2
π
π‘
π‘
ξΆ
1
/
2
β
β
β
β
B
M
O
(
π΅
β
π
)
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
4
.
2
1
)
Consider any ball
π΅
=
π΅
π
(
π₯
0
)
β
π΅
β
π
. By Lemma 2.11 , we have
1
|
|
π΅
|
|
ξ
π΅
ξ΅
ξ
π
0
|
|
π
π‘
|
|
π
(
π₯
)
2
π
π‘
π‘
ξΆ
1
/
2
ξ΅
1
π
π₯
β€
|
|
π΅
|
|
ξ
π΅
ξ
π
0
|
|
π
π‘
|
|
π
(
π₯
)
2
π
π‘
π‘
ξΆ
π
π₯
1
/
2
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
4
.
2
2
)
Therefore, by Lemma 2.5 and Corollary 2.3 , it suffices to prove
1
|
|
π΅
|
|
ξ
π΅
|
|
|
|
|
ξ΅
ξ
2
0
π
πΏ
πΌ
(
π₯
π
)
π
|
|
π
π‘
|
|
π
(
π₯
)
2
π
π‘
π‘
ξΆ
1
/
2
β
ξ΅
ξ
2
0
π
πΏ
πΌ
(
π₯
π
)
π
|
|
π
π‘
π
ξ·
π₯
0
ξΈ
|
|
2
π
π‘
π‘
ξΆ
1
/
2
|
|
|
|
|
π
π₯
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
4
.
2
3
)
To prove (4.23 ), we first claim that, for all
π
β
B
M
O
πΏ
πΌ
,
π₯
β
π΅
β
π
, and
π‘
β€
2
0
π
πΏ
πΌ
(
π₯
π
)
,
|
|
π
π‘
|
|
π
(
π₯
)
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
4
.
2
4
)
We shall split into three different estimates:
ξ
π
π‘
1
(
π₯
)
|
|
|
|
|
|
π
π
(
π¦
)
π‘
(
|
|
π₯
,
π¦
)
π
π¦
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
,
ξ
(
4
.
2
5
)
π
π‘
2
(
π₯
)
|
|
π
|
|
|
|
π
(
π¦
)
π‘
(
π₯
,
π¦
)
β
π
π‘
|
|
(
π₯
,
π¦
)
π
π¦
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
,
|
|
|
|
ξ
(
4
.
2
6
)
π
π‘
2
(
π₯
)
π
(
π¦
)
π
π‘
|
|
|
|
(
π₯
,
π¦
)
π
π¦
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
4
.
2
7
)
Let us first treat (4.25 ). Since
π¦
β€
π
(
π
πΏ
πΌ
(
π₯
π
)
2
/
π₯
π
)
, when
π¦
β
π
π‘
1
(
π₯
)
, notice that
π₯
βΌ
π₯
π
when
π₯
β
π΅
β
π
, using (a) of Proposition 2.9 , and recalling the definition of
π
πΏ
πΌ
(
π₯
)
, we have
ξ
π
π‘
1
(
π₯
)
|
|
|
|
|
|
π
π
(
π¦
)
π‘
|
|
ξ
(
π₯
,
π¦
)
π
π¦
β€
πΆ
π
π
πΏ
πΌ
(
π₯
π
)
2
/
π₯
π
0
π‘
π₯
2
π
|
|
|
|
π‘
π
(
π¦
)
π
π¦
β€
πΆ
π₯
π
β
π
β
B
M
O
πΏ
πΌ
β€
πΆ
β
π
β
B
M
O
πΏ
πΌ
.
(
4
.
2
8
)
For (4.26 ), using (b) of Proposition 2.9 , for
π₯
β
π΅
β
π
, the left side of (4.26 ) is controlled by
1
π₯
π
ξ
2
π₯
π
π₯
π
/
2
π‘
π₯
π
|
|
|
|
ξ
π
(
π¦
)
π
π¦
+
(
0
,
β
)
β©
(
π₯
π
/
2
,
2
π₯
π
)
π
1
π‘
π
β
|
π₯
β
π¦
|
2
/
2
π‘
2
|
|
|
|
β²
π‘
π
(
π¦
)
π
π¦
π₯
π
β
π
β
B
M
O
πΏ
πΌ
+
π‘
π₯
π
ξ
β
0
1
π‘
π
β
|
π₯
β
π¦
|
2
/
4
π‘
2
|
|
|
|
β²
π‘
π
(
π¦
)
π
π¦
π₯
π
β
π
β
B
M
O
πΏ
πΌ
+
ξ΅
π‘
π₯
π
ξΆ
1
2
β
π
β
B
M
O
πΏ
πΌ
.
(
4
.
2
9
)
The third inequality is from the same argument for dealing with (3.21 ) in the proof of Theorem 3.2 . For (4.27 ), we write
|
|
|
|
ξ
π
π‘
2
(
π₯
)
π
(
π¦
)
π
π‘
|
|
|
|
β€
|
|
|
|
ξ
(
π₯
,
π¦
)
π
π¦
π
π‘
2
(
π₯
)
|
|
π
(
π¦
)
β
π
π΅
π‘
(
π₯
)
|
|
|
|
π
π‘
|
|
|
|
|
|
+
|
|
|
|
ξ
(
π₯
,
π¦
)
π
π¦
π
π‘
2
(
π₯
)
π
π΅
π‘
(
π₯
)
π
π‘
|
|
|
|
.
(
π₯
,
π¦
)
π
π¦
(
4
.
3
0
)
By (a), (c) of Proposition 2.10 and the fact that
|
π
π΅
π‘
(
π₯
)
|
β²
(
1
+
l
o
g
2
0
π
πΏ
πΌ
(
π₯
π
)
/
π‘
)
β
π
β
B
M
O
πΏ
πΌ
, we have
|
|
|
|
ξ
π
π‘
2
(
π₯
)
π
π΅
π‘
(
π₯
)
π
π‘
|
|
|
|
β€
|
|
|
|
ξ
(
π₯
,
π¦
)
π
π¦
β
β
β
π
π΅
π‘
(
π₯
)
π
π‘
|
|
|
|
+
|
|
|
|
|
ξ
(
π₯
,
π¦
)
π
π¦
π
π‘
2
(
1
β
π
2
β
2
π‘
)
/
π₯
β
β
π
π΅
π‘
(
π₯
)
π
π‘
|
|
|
|
|
β²
π‘
(
π₯
,
π¦
)
π
π¦
2
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
2
ξ©
1
+
l
o
g
2
0
π
πΏ
πΌ
ξ·
π₯
π
ξΈ
π‘
ξͺ
β
π
β
B
M
O
πΏ
πΌ
+
ξ
(
1
β
π
2
β
2
π‘
)
π
π‘
2