Department of Mathematics, Chungnam National University, Daejeon 305-764, South Korea
Department of Mathematics Education, Gongju National University of Education, Gongju 314-711, South Korea
Abstract
We establish the generalized Hyers-Ulam stability of a Pexider-type functonal equation f1(x+y+z)+f2(x−y)+f3(x−z)−f4(x−y−z)−f5(x+y)−f6(x+z)=0, which is mixed of a quadratic and an additive functional equations. Also, we obtain its general solution from the stability results.
1. Introduction
In 1940, Ulam [1] raised the following question. Under what conditions does
there exist an additive mapping near an approximately additive mapping?
In 1941, Hyers [2] proved that if
is a mapping satisfying
(1.1)for all
,
where
and
are Banach spaces and
is a given positive number, then there exists
a unique additive mapping
such that
(1.2)for all
.
In 1978, Rassias [3] gave a significant generalization of Hyers' result.
Rassias [4] during the 27th International Symposium on Functional Equations,
that took place in Bielsko-Biala,
Poland, in
1990, asked the question whether such a theorem can also be proved for a more
general setting. Gadja [5] following Rassias's approach [3] gave an
affirmative solution to the question. Recently, Găvruţa [6] obtained a further generalization of Rassias' theorem, the
so-called generalized Hyers-Ulam-Rassias stability (see also [4, 7–10]). Jun et al. [11–13] also obtained the Hyers-Ulam-Rassias stability of the Pexider
equation of
. Quadratic functional equation was used to
characterize inner product spaces [14]. Several other functional equations were
also to characterize inner product spaces. A square norm on an inner product
space satisfies the important parallelogram equality
(1.3)The functional equation
(1.4)is related to a symmetric
biadditive function [14]. It is natural that each equation is called a quadratic
functional equation. A stability problem for the quadratic functional equation
was proved by Skof [15] for a function
,
where
is a normed space and
a Banach space. Cholewa [16] noticed that the
theorem of Skof is still true if the relevant domain
is replaced by an Abelian group. Czerwik [17]
proved the Hyers-Ulam-Rassias stability of the quadratic functional equation.
Jun and Lee [13, 18–22] proved the Hyers-Ulam-Rassias stability of the Pexiderized
quadratic equation
(1.5)Now, we introduce the following
new Pexider type functional equation:
(1.6)which is mixed of a quadratic and
an additive functional equations. In this paper, we establish the generalized
Hyers-Ulam-Rassias stability for (1.6) on the punctured domain
and obtain its general solution from the
stability results. Throughout this paper, let
and
be a normed space and a Banach space,
respectively. For convenience, we employ the operators as follows: for a given
function
,
let
,
be functions defined by
(1.7)for all
.
2. Generalized Hyers-Ulam-Rassias Stability
We need the following lemma to prove our main results.
Lemma 2.1.1.
Let
be a positive real number. Let
be a map such that
(2.1)
or
(2.2)
Suppose that the function
satisfies the inequality
(2.3)
for all
and
.
Then, there exists exactly one function
satisfying
(2.4)
Proof.
First we assume that
satisfies
(2.5)for all
.
Replacing
by
and dividing it by
in (2.3), we have
(2.6)for all
and
.
Induction argument implies that
(2.7)for all
and
.
Hence
(2.8)for all positive integers
and
.
This shows that
is a Cauchy sequence for
and thus converges. Therefore, we can define
such that
(2.9)for all
.
From (2.7) and the definition of
,
we obtain
(2.10)for all
.
Now, let
be another mapping satisfying the above
inequality and equality. Then, it follows that
(2.11)which tends to zero by the
definition of
as
for all
.
So we can conclude that
for all
.
This proves the uniqueness of
.
Next we assume that
satisfies
(2.12)for all
.
Replacing
by
and multiplying it by
in (2.3), we have
(2.13)for all
and
.
Induction argument implies that
(2.14)for all
and
.
Hence
(2.15)for all positive integers
and
.
This shows that
is a Cauchy sequence for
and thus converges. Therefore we can define
such that
(2.16)for all
.
From (2.14) and the definition of
,
we obtain
(2.17)for all
.
The uniqueness of
is proved similarly as the first case. This
completes the proof.
We establish the
stability results for the even functions in Theorems 2.2 and
2.3.
Theorem 2.2.
Let
be a function such that
(a)
holds for all
.
If the even functions
satisfy the inequality
(2.18)
for all
,
then there exists exactly one quadratic function
satisfying the inequalities
(2.19)
(2.20)
for all
,
where
(2.21)
for all
.
Moreover, the function
is given by
(2.22)
for all
and for
.
Proof.
Replace
by
in (2.18) to obtain
(2.23)for all
.
From (2.18) and (2.23), we get
(2.24)for all
.
Let the functions
be defined by
(2.25)for all
.
Then, it follows from (2.24) that
(2.26)for all
,
where
.
Replace
and
by
and
in (2.26) to get
(2.27)for all
.
Replacing
,
by
in (2.26) and using (2.27), we get
(2.28)for all
.
Replacing
,
,
by
,
,
in (2.26) and using (2.27), one obtains
(2.29)for all
.
From (2.28) and the above inequality, we have
(2.30)for all
.
Replacing
by
and dividing it by
in the above inequality, we get
(2.31)for all
.
By Lemma 2.1, there exists
for all
satisfying
(2.32)for all
,
where
(2.33)By the similar method in
obtaining inequality (2.32), we get
(2.34)for all
,
where
(2.35)From (2.27), we have
(2.36)for all
.
From (2.36), we can define a map
by
(2.37)for all
.
It follows from (2.26), (2.32), and (2.37) that
(2.38)for all
.
Replacing
by
,
dividing it by
in the above inequality and taking the limit
in the resulted inequality as
,
we have
(2.39)for all
.
Using (2.26), (2.36), (2.37), and (2.39), we obtain
(2.40)for all
.
Replacing
and
by
in (2.40) and using the fact
,
we have
(2.41)for all
.
Replace
and
by
and
in (2.40) to have
(2.42)for all
.
Subtracting (2.41) from (2.42) and using the evenness of
,
we lead to
(2.43)for all
.
On the other hand, it follows from (2.18) and (2.23)
that
(2.44)for all
.
Let the functions
be defined by
(2.45)for all
.
From (2.44), we have
(2.46)for all
.
Replace
,
by
in (2.46) to get
(2.47)for all
.
Replace
,
,
by
,
,
in (2.46) to get
(2.48)for all
.
From (2.47) and the above inequality, we have
(2.49)for all
.
Replace
,
,
by
,
,
in (2.46) to get
(2.50)for all
.
From (2.47) and the above inequality, we get
(2.51)for all
.
It follows from (2.46) that
(2.52)for all
.
By the definitions of
,
we have
(2.53)for all
.
Hence by using (2.32), (2.34), (2.36), (2.37), (2.38), (2.49), (2.51), and (2.52),
the inequalities in (2.19) can be shown. The uniqueness of
follows from Lemma 2.1.
Theorem 2.3.
Let
be a function such that
(a')
holds for all
.
If the even functions
satisfy inequality (2.18) for all
,
then there exists exactly one quadratic function
satisfying inequalities (2.19) for all
,
where
(2.54)
Moreover, the function
is given by
(2.55)
for all
and for
.
Proof.
The proof is similar to that of Theorem 2.2.
Applying Theorems 2.2 and 2.3, we get the
following corollary in the sense of Rassias inequality.
Corollary 2.4.1.
Let
and
.
If the even functions
,
,
satisfy
(2.56)
for all
.
Then there exist exactly one
quadratic function
satisfying
(2.57)
for all
and
.
Moreover, the function
is given by
(2.58)
for all
and
Proof.
Apply Theorem 2.2 for
and Theorem 2.3 for
.
We establish Theorems 2.5 and 2.6
for the odd functions.
Theorem 2.5.
Let
be a function such that
(b)
holds for all
.
If the odd functions
satisfy
(2.59)
for all
,
then there exist exactly three additive functions
satisfying
(2.60)
(2.61)
for all
,
where
(2.62)
Moreover, the functions
are given by
(2.63)
for all
.
Proof.
Replace
by
in (2.59) to obtain
(2.64)for all
.
Let the functions
be defined by
(2.65)for all
.
From (2.59) and (2.64), we get
(2.66)for all
.
From (2.66), we have
(2.67)for all
.
It follows from (2.66) and (2.67) that
(2.68)for all
.
Replacing
by
and dividing it by
in the above inequality, we obtain
(2.69)for all
.
Applying Lemma 2.1, we obtain
(2.70)for all
.
Similarly we have
(2.71)for all
.
From (2.67), we get
(2.72)for all
and we can define a function
by
(2.73)for all
.
It follows from (2.66) and (2.70) that
(2.74)for all
.
Replacing
by
,
dividing it by
in the above inequality and taking the limit
in the resulted inequality as
,
we obtain
(2.75)for all
.
From (2.73) and (2.75), we have
(2.76)for all
.
Replace
and
by
and
in (2.76) to obtain
(2.77)for all
.
Replace
and
by
and
in (2.76) to get
(2.78)for all
.
Since
and
,
using the above two equalities, we have
(2.79)for all
.
Hence,
is an additive function.
Let the functions
be defined by
(2.80)for all
.
From (2.59) and (2.64), we have
(2.81)for all
.
It follows from (2.81) that
(2.82)for all
.
Applying Lemma 2.1, we obtain an odd function
defined by
(2.83)and the inequality
(2.84)holds for all
.
Similarly we have an odd function
defined by
(2.85)for all
and the inequality
(2.86)for all
.
Replace
,
,
by
,
,
in (2.81) to get
(2.87)for all
.
Replacing
by
and dividing it by
in the above inequality, we obtain
(2.88)for all
.
Taking the limit in the above inequality as
,
we have
(2.89)for all
.
It follows from (2.81) that
(2.90)for all
.
Applying Lemma 2.1 and (2.89), we have
(2.91)for all
.
From (2.81), (2.83), (2.85), and (2.89), we have
(2.92)for all
.
Replace
and
by
and
in (2.92) to get
(2.93)for all
.
Replace
and
by
and
in (2.92) to get
(2.94)for all
.
From the above two equalities, we get
(2.95)for all
.
Since
,
we have
(2.96)for all
.
Hence
is additive, that is,
(2.97)for all
.
Replace
by
in (2.92) to obtain
(2.98)for all
.
Since
is additive, we have
(2.99)for all
.
From this and (2.98), we get
(2.100)for all
.
From this and
,
we have
(2.101)for all
.
Since
and
are additive,
is additive.
From (2.74), (2.91), and the definitions of
,
we have
(2.102)for all
.
The rest of inequalities in (2.60) can be shown by the similar method.
Theorem 2.6.
Let
be a function such that
(b')
holds for all
.
If the odd functions
satisfy inequalities (2.59) for all
,
then there exist exactly three additive functions
satisfying the inequalities (2.60) for all
,
where
(2.103)
Moreover, the functions
are given by
(2.104)
for all
.
Proof.
The proof is similar to that of Theorem 2.5.
Applying Theorems 2.5 and 2.6, we get the following corollary in the
sense of Rassias inequality.
Corollary 2.7.2.7.
Let
.
If the odd functions
,
,
satisfy
(2.105)
for all
.
Then there exist exactly three
additive functions
satisfying
(2.106)
for all
.
Moreover, the functions
are given by
(2.107)
for all
.
Proof.
Apply Theorem 2.5 for
and Theorem 2.6 for
.
We establish the following theorem for the general
case from Theorems 2.2 and 2.5.
Theorem 2.8.
Let
be a function that satisfies conditions
(a) and (b). Suppose that the functions
,
, satisfy the inequality
(2.108)
for all
.
Then there exist exactly one quadratic function
and exactly three additive functions
satisfying
(2.109)
for all
,
where
(2.110)
for all
.
Moreover, the function
is given by
(2.111)
for
and the functions
are given by
(2.112)
for all,
.
Proof.
From (2.108), we obtain
(2.113)for all
.
From (2.108) and this inequality, one gets
(2.114)for all
,
where
,
for all
,
.
Since
is an even function,
is an odd function, and
,
we can apply Theorems 2.2 and 2.5 to get the desired result.
We establish the following theorem for the general
case from Theorems 2.2 and 2.6.
Theorem 2.9.
Let
be a function that satisfies conditions
(a) and (b'). If the functions
satisfy inequalities (2.108) for all
,
then there exist exactly one quadratic function
and exactly three additive functions
satisfying the inequalities in Theorem 2.8 for
all
,
where
are as in Theorem 2.8 and
(2.115)
for all
.
Moreover, the function
is given by (2.111) and the functions
are given by
(2.116)
(2.117)
for all
.
We establish the following theorem for the general
case from Theorems 2.3 and 2.6.
Theorem 2.10.
Let
be a function that satisfies conditions
(a') and (b'). If the functions
satisfy inequalities (2.108) for all
,
then there exist exactly one quadratic function
and exactly three additive functions
satisfying the inequalities in Theorem 2.8 for
all
,
where
are as in Theorem 2.9 and
(2.118)
for all
.
Moreover, the function
is given by
(2.119)
for
and the functions
are given by (2.116) for all
.
Corollary 2.11.3.
Let
and
.
Suppose that the functions
,
,
satisfy
(2.120)
for all
.
Then there exist exactly one
quadratic function
and three additive functions
satisfying
(2.121)
for all
.
Moreover, the function
is given by (2.111) for
and (2.119) for
and the functions
are given by (2.112) for
and (2.116) for
.
Corollary 2.12.4.
Let
be a fixed real number. Suppose that the
functions
,
,
satisfy
(2.122)
for all
.
Then there exist exactly one
quadratic function
and three additive functions
satisfying
(2.123)
for all
.
Moreover, the function
is given by (2.111) for
and the functions
are given by (2.112) for all
.
Now we obtain the general solution of (1.6) from Corollary 2.12.
Corollary 2.13.5.
Suppose that the functions
,
,
satisfy
(2.124)
for all
.
Then there exist exactly one
quadratic function
and three additive functions
satisfying
(2.125)
for all
.
Moreover, the function
is given by
(2.126)
for
and the functions
are given by
(2.127)
for all
.
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