Table 1: Thermodynamic equilibrium reactions in ZnSO4-NaOH-H2O system (298 K).

ReactionsConstant

H2O = H+ + OH1.02 × 10−14(1)
ZnSO4 = Zn2+ + 2.23 × 103(2)
= + H+1.04 × 10−2(3)
H2SO4 = + H+3.46 × 109(4)
NaOH = Na+ + OH8.45 × 106(5)
Na2SO4 = 2Na+ + 4.73 × 10−1(6)
Zn2+ + 2OH = + H+1.73(7)
Zn2+ + 2OH = + 2H+2.90 × 10−13(8)
Zn2+ + OH = ZnOH+1.44 × 106(9)
Zn2+ + 2OH = Zn(OH)2(aq)1.16 × 1013(10)
Zn2+ + 3OH = 2.50 × 1014(11)
Zn2+ + 4OH = 4.61 × 1015(12)