Abstract

The Sumudu transform of certain elementary matrix functions is obtained. These transforms are then used to solve the differential equation of a general linear conservative vibration system, a vibrating system with a special type of viscous damping.

1. Introduction

The importance of matrices and matrix problems in engineering has been clearly demonstrated during the last years [1, 2]. It has been shown that the solution of systems of ordinary and partial differential equations that arise in physics and engineering can be most efficiently formulated in the language of matrices. Boundary value problems become matrix problems after first passing through a reformulation in terms of integral equations. One of the most common problems encountered by the mathematical technologist is the solution of sets of ordinary linear differential equations with constant coefficients. It was found in [3] that the response of a linear dynamical system may be efficiently determined by formulating its response in terms of the matrix exponential function.

In the literature, there are several integral transforms and widely used in physics, astronomy as well as in engineering. In [4], Watugala introduced a new transform and named as Sumudu transform which is defined over the set of the functions𝐴=𝑓(𝑡)𝑀,𝜏1,𝜏2||||>0,𝑓(𝑡)<𝑀𝑒𝑡/𝜏𝑖,if𝑡(1)𝑖×[0,)(1.1) by the following formula: []𝐺(𝑢)=𝑆𝑓(𝑡);𝑢=0𝑓(𝑢𝑡)𝑒𝑡𝑑𝑡,𝑢𝜏1,𝜏2(1.2) and applied this new transform to the solution of ordinary differential equations and control engineering problems, see [46]. In [7], some fundamental properties of the Sumudu transform were established.

In [8], the Sumudu transform was extended to the distributions (generalized functions) and some of their properties were also studied in [9, 10]. Recently, Kılıçman et al. applied this transform to solve the system of differential equations, see [11]. The inversion of the transformed coefficients is obtained by using Trzaska’s method [12] and the Heaviside expansion technique.

In the present paper, the intimate connection between the Sumudu transform theory and certain matrix functions that arise in the solution of systems of ordinary differential equations is demonstrated. The techniques are developed and then applied to problems in dynamics and electrical transmission lines.

Note that the Sumudu and Laplace transforms have the following relationship that interchanges the image of sin(𝑥+𝑡) and cos(𝑥+𝑡). It turns out that 𝑆2[]sin(𝑥+𝑡)=2[]=cos(𝑥+𝑡)𝑢+𝑣(1+𝑢)2(1+𝑣)2,𝑆2[]cos(𝑥+𝑡)=2[]=1sin(𝑥+𝑡)(1+𝑢)2(1+𝑣)2.(1.3)

Further, an interesting fact about the Sumudu transform is that the original function and its Sumudu transform have the same Taylor coefficients except for the factor 𝑛!. Thus, if size 𝑓(𝑡)=𝑛=0𝑎𝑛𝑡𝑛, then 𝐹(𝑢)=𝑛=0𝑛!𝑎𝑛𝑡𝑛; see [13]. Furthermore, Laplace and Sumudu transforms of the Dirac delta function and the Heaviside function satisfy𝑆2[]𝐻(𝑥,𝑡)=2[]𝑆𝛿(𝑥,𝑡)=1,2[]𝛿(𝑥,𝑡)=2[]=1𝐻(𝑥,𝑡),𝑢𝑣(1.4) for details, see [8, 14], where the authors generalize the concept of the Sumudu transform to distributions. Since the Sumudu transform is a convenient tool for solving differential equations in the time domain, without the need for performing an inverse Sumudu transform, see [15]. The applicability of this new interesting transform and efficiency in solving the linear ordinary differential equations with constant and nonconstant coefficients having the convolutions were also studied in [16, 17].

2. Main Results

The following theorem was proved in [5].

Theorem 2.1. Let 𝑓(𝑥) and 𝑔(𝑥) be two functions having Sumudu transforms. Then Sumudu transform of the convolution of the 𝑓(𝑥) and 𝑔(𝑥), (𝑓𝑔)(𝑥)=𝑥0𝑓(𝜁)𝑔(𝑥𝜁)𝑑𝜁,(2.1) is given by 𝑆[](𝑓𝑔)(𝑥);𝑢=𝑢𝐹(𝑢)𝐺(𝑢).(2.2)

Next, it can be extended to the double convolution as follows.

Theorem 2.2. Let 𝑓(𝑡,𝑥) and 𝑔(𝑡,𝑥) have double Sumudu transform. Then, double Sumudu transform of the double convolution of 𝑓 and 𝑔, (𝑓𝑔)(𝑡,𝑥)=𝑡0𝑥0𝑓(𝜁,𝜂)𝑔(𝑡𝜁,𝑥𝜂)𝑑𝜁𝑑𝜂,(2.3) exists and is given by 𝑆2[](𝑓𝑔)(𝑡,𝑥);𝑣,𝑢=𝑢𝑣𝐹(𝑣,𝑢)𝐺(𝑣,𝑢).(2.4)

Proof. By using the definition of double Sumudu transform and double convolution, we have 𝑆2[]=1(𝑓𝑔)(𝑡,𝑥);𝑣,𝑢𝑢𝑣0𝑒((𝑡/𝑣)+(𝑥/𝑢))=1(𝑓𝑔)(𝑡,𝑥)𝑑𝑡𝑑𝑥𝑢𝑣0𝑒((𝑡/𝑣)+(𝑥/𝑢))𝑡0𝑥0𝑓(𝜁,𝜂)𝑔(𝑡𝜁,𝑥𝜂)𝑑𝜁𝑑𝜂𝑑𝑡𝑑𝑥.(2.5) Let 𝛼=𝑡𝜁 and 𝛽=𝑥𝜂, and using the valid extension of upper bound of integrals to 𝑡 and 𝑥, we have 𝑆2[]=1(𝑓𝑔)(𝑡,𝑥);𝑣,𝑢𝑢𝑣0𝑒((𝜁/𝑣)(𝜂/𝑢))𝑑𝜁𝑑𝜂𝜁𝜂𝑒((𝛼/𝑣)(𝛽/𝑢))𝑔(𝛼,𝛽)𝑑𝛼𝑑𝛽.(2.6) Since both functions 𝑓(𝑡,𝑥) and 𝑔(𝑡,𝑥) are zero, for 𝑡<0, and 𝑥<0, it follows with respect to lower limit of integrations that 𝑆2[]=1(𝑓𝑔)(𝑡,𝑥);𝑣,𝑢𝑢𝑣0𝑒((𝜁/𝑣)(𝜂/𝑢))𝑑𝜁𝑑𝜂0𝑒((𝛼/𝑣)(𝛽/𝑢))𝑔(𝛼,𝛽)𝑑𝛼𝑑𝛽.(2.7) Then, it is easy to see that 𝑆2[](𝑓𝑔)(𝑡,𝑥);𝑣,𝑢=𝑢𝑣𝐹(𝑣,𝑢)𝐺(𝑣,𝑢).(2.8) See the further details in [14].

Mathematical models of many physical biological and economic processes are involved with system of linear constant coefficient of ordinary differential 𝑑𝑓𝑑𝑥=𝐴𝑓,𝑓(0)=𝐼.(2.9) Equation (2.9) was studied in [18] by using by Laplace transform where 𝑓 and 𝐴 are square matrices of the 𝑛th order, and the elements of 𝐴 are known constants, and also in control theory 𝐴 is known as the state of companion matrix. The initial condition satisfied by the matrix 𝑓(𝑥) is 𝑓(0)=𝐼, where 𝐼 is the 𝑛th order unit matrix. It is well known that (2.9) as the solution with the given initial condition is 𝑓(𝑥)=𝑘=0(𝐴𝑥)𝑘𝑘!=𝑒𝐴𝑥,(2.10) where 𝑒𝐴𝑥 is the matrix exponential function. To obtain the solution of (2.9) by Sumudu transform, we use the following definition:𝑆𝑓(𝑥)=0𝑒𝑥/𝑢𝑓(𝑥)𝑑𝑥=𝐹(𝑢),Re𝑢>0(2.11) and Sumudu transform of derivatives 𝑆𝑑𝑓=1𝑑𝑥𝑢1𝐹(𝑢)𝑢1𝑓(0)=𝑢1𝐹(𝑢)𝑢𝐼.(2.12) Then Sumudu transform of (2.9) is, therefore, given by []𝐼𝑢𝐴𝐹(𝑢)=𝐼.(2.13) Hence 𝐼𝐹(𝑢)=[].𝐼𝑢𝐴(2.14) In the next, we give some applications.

2.1. Resolvent of 𝐴

The matrix 𝐹(𝑢)=[𝐼𝑢𝐴] is the characteristic matrix of 𝐴. The matrix 𝑄(𝑢)=(𝐼𝑢𝐴)1 is called the resolvent of 𝐴. If 𝜆 is the eigenvalue of 𝐴 with maximum modulus, then we have the geometric progression expansion, 𝑄(𝑢)=(𝐼𝑢𝐴)1=𝑘=0(𝐴𝑢)𝑘=𝐹(𝑢),(2.15) provided that, |𝑢|>|𝜆|. Sumudu transform variable 𝑢 may be taken large enough so that |𝑢|>|𝜆| is satisfied in the infinite geometric series in (2.15). The inverse Sumudu transform of (2.15) may now be taken in order to obtain𝑆1[]𝐹(𝑢)=𝑆1(𝐼𝑢𝐴)1=𝑆1𝑘=0(𝐴𝑢)𝑘=𝑓(𝑥),(2.16) and, therefore, (2.16) can be written in the form of𝑆1[]𝐹(𝑢)=𝑓(𝑥)=𝑘=0(𝐴𝑥)𝑘𝑘!=𝑒𝐴𝑥.(2.17) Thus we have, useful result,𝑆1(𝐼𝑢𝐴)1=𝑒𝐴𝑥(2.18) as a well-known scalar inverse Sumudu transform, 𝑆1(1𝑎𝑢)1=𝑒𝑎𝑥.(2.19) The partial fractional exponential of the resolvent, if 𝐺(𝐴) is a rational function of 𝐴, then𝐺𝜆(𝐴)=𝐺1𝐿1𝜆+𝐺2𝐿2𝜆++𝐺𝑛𝐿𝑛,(2.20) where 𝑛 eigenvalues of 𝐴,𝜆𝑘,𝑘=1,2,3,,𝑛 and𝐿𝑘=𝐵𝜆𝑘Φ𝜆𝑘,(2.21) in (2.21), 𝐵(𝜆) and Φ(𝜆) are defined by𝐵(𝜆)=adj(𝐼𝜆𝐴),Φ(𝜆)=det(𝐼𝜆𝐴),Φ𝜆𝑘=𝑑Φ𝑑𝜆𝜆=𝜆𝑘.(2.22) The matrices 𝐿𝑘,𝑘=1,2,3,,𝑛 are called Sylvester matrices of 𝐴. It is also well known that the Sylvester matrices have the following properties:𝐿1+𝐿2++𝐿𝑛𝐿=𝐼,𝑠𝐿𝑡=0if𝑠𝑡,orthogonal.(2.23) In order to obtain the partial fraction of resolvent 𝑄(𝑢)=(𝐼𝑢𝐴)1, we let 𝐺(𝐴)=(𝐼𝑢𝐴)1 in (2.20); we obtain𝑄(𝑢)=(𝐼𝑢𝐴)1=𝐿11𝜆1𝑢+𝐿21𝜆2𝑢𝐿++𝑛1𝜆𝑛𝑢.(2.24) Now by taking the inverse Sumudu transform of (2.24), we have𝑆1[𝑄](𝑢)=𝐿1𝑒𝜆1𝑥+𝐿2𝑒𝜆2𝑥++𝐿𝑛𝑒𝜆𝑛𝑥=𝑒𝐴𝑥.(2.25) In the next example, we apply inverse Sumudu transform as follows: let1𝐹(𝑢)=𝐼𝐴2𝑢2,(2.26) where 𝐴𝑛th is order square matrix as defined above, 𝑢 is the Sumudu transform variable, and 𝐼 is the 𝑛th order unit matrix; by using partial fractional form and inverse Sumudu transform, we have 𝑆1[]𝐹(𝑢)=𝑆112(𝐼𝐴𝑢)+𝑆11=12(𝐼+𝐴𝑢)2𝑒𝐴𝑥+𝑒𝐴𝑥=cosh(𝐴𝑥).(2.27) Another example, consider the case in which 𝐹(𝑢) is given by𝐹(𝑢)=1+𝑘𝑢(𝐼+𝑘𝑢)2𝐴2𝑢2,(2.28) where 𝑢 is the Sumudu transform variable, 𝐼 is the 𝑛th order unit matrix, 𝑘 is scalar, and 𝐴𝑛th is order square matrix, by using partial fractional form, we have1𝐹(𝑢)=21+1(𝐼(𝐴𝑘)𝑢)(I+(𝐴+𝑘)𝑢).(2.29) The inverse Sumudu transform of (2.29) is𝑆1[]𝐹(𝑢)=𝑆1121+1(𝐼(𝐴𝑘)𝑢)(𝐼+(𝐴+𝑘)𝑢)=𝑒𝑘𝑥cosh(𝐴𝑥),(2.30) where cosh(𝐴𝑥) is the matrix hyperbolic cos function of 𝐴.

2.2. State-Space Equation

Every linear time-invariant lumped system can be described by a set of equations in the following form:𝑓(𝑡)=𝐴𝑓(𝑡)+𝐵𝑣(𝑡),𝑔(𝑡)=𝐶𝑓(𝑡)+𝐷𝑣(𝑡).(2.31) Then for a system with 𝑝 inputs, 𝑞 outputs, and 𝑛 state variables, 𝐴,𝐵,𝐶, and 𝐷 are, respectively, 𝑛×𝑛,𝑛×𝑝,𝑞×𝑛 and 𝑞×𝑝 constant matrices. Applying Sumudu transform to (2.31) yields1𝑢1𝐹(𝑢)𝑢𝑓(0)=𝐴𝐹(𝑢)+𝐵𝑉(𝑢),𝐺(𝑢)=𝐶𝐹(𝑢)+𝐷𝑉(𝑢),(2.32) where 𝑆𝑓(𝑡)=0𝑒𝑡/𝑢𝑓(𝑥)𝑑𝑥=𝐹(𝑢),Re𝑢>0,𝑆𝑣(𝑡)=0𝑒𝑡/𝑢𝑣(𝑡)𝑑𝑥=𝑉(𝑢),𝑆𝑔(𝑡)=0𝑒𝑡/𝑢𝑔(𝑡)𝑑𝑥=𝐺(𝑢).(2.33) Hence𝐹(𝑢)=𝑓(0)+(𝐼𝐴𝑢)𝐵𝑢𝑉(𝑢).(𝐼𝐴𝑢)(2.34) Thus𝐺(𝑢)=𝐶𝑓(0)+(𝐼𝐴𝑢)𝐶𝐵𝑢𝑉(𝑢)(𝐼𝐴𝑢)+𝐷𝑉(𝑢).(2.35) On using inverse Sumudu transform for (2.34) and (2.35) and the above theorem, we obtain 𝑓(𝑡) and 𝑔(𝑡) as follows: 𝑓(𝑡)=𝑓(0)𝑒𝐴𝑡+𝐵𝑡0𝑒(𝑡𝜁)𝑣(𝜁)𝑑𝜁,𝑔(𝑡)=𝐶𝑓(0)𝑒𝐴𝑡+𝐵𝐶𝑡0𝑒(𝑡𝜁)𝑣(𝜁)𝑑𝜁+𝐷𝑣(𝑡).(2.36) Now let us apply Sumudu transform to matrix differential equation as follows consider Vibrations of linear conservative system𝑀𝑓+𝜇𝑓=𝑔(𝑥),(2.37) where 𝑀 is a symmetric matrix of order 𝑛 called the inertia matrix; 𝑓 is an 𝑛th order matrix whose elements are the 𝑛 generalized coordinates of the system; 𝜇 is an 𝑛th order symmetric matrix called the stiffness matrix; 𝑔(𝑥) is an 𝑛th order column matrix of the 𝑛 generalized forces acting on the system. If we multiply (2.37) by 𝑀1, the inverse of the inertia matrix 𝑀, then we have𝑓+𝑀1𝜇𝑓=𝑀1𝑔(𝑥).(2.38) Let the following notation be introduced:𝑀1𝜇=𝑉=𝐴2,𝑀1𝑔(𝑥)=(𝑥),(2.39) with above notation (2.39) written in the form of𝑓+𝐴2𝑓=(𝑥).(2.40) Let Sumudu transform of𝑆[]𝑓𝑓(𝑥)=𝐹(𝑢),𝑆=𝐹(𝑥)(𝑢)𝑢2𝑓(0)𝑢2𝑓(0)𝑢[],𝑆(𝑥)=𝐻(𝑢).(2.41) The matrix 𝑓(0) is an 𝑛th order column matrix whose elements are the initial values of the generalized coordinate; 𝑓(0) is an 𝑛th order column matrix whose elements are the initial values of the generalized velocities of the system. The Sumudu transform of (2.40) is given by𝐹(𝑢)𝑢2+𝐴2𝐹(𝑢)=𝐻(𝑢)+𝑓(0)𝑢2+𝑓(0)𝑢.(2.42) Equation (2.42) can be written in the form of1𝐹(𝑢)=𝐼+𝐴2𝑢2𝑢2𝐻(𝑢)+𝑓(0)+𝑢𝑓(0).(2.43) By using inverse Sumudu transform and convolution for (2.43), we have 1𝑓(𝑥)=𝑓(0)cos(𝐴𝑥)+𝐴𝑓(10)sin(𝐴𝑥)+𝐴𝑡0[]sin𝐴(𝑥𝑡)(𝑡)𝑑𝑡.(2.44)

2.3. Free Oscillations of the System

If (𝑥)=0, we have the free oscillations of the conservative system. Since 𝑀1𝜇=𝑉=𝐴2, then (2.43) can be written as𝐹(𝑢)=𝐼+𝑉𝑢21𝑓(0)+𝑢𝑓.(0)(2.45) Representation of 𝐹(𝑢) may be obtained by substituting𝐹(𝑉)=𝐼+𝑉𝑢21.(2.46) For 𝐹(𝑉) Sylvester’s theorem (2.20), we have𝑄(𝑢)=𝐼+𝜆𝑢21=𝐿11+𝜆1𝑢2+𝐿21+𝜆2𝑢2𝐿++𝑛1+𝜆𝑛𝑢2𝑓(0)+𝑢𝑓(0),(2.47) where 𝐿𝑘 is the 𝑘th Sylvester’s matrix of 𝑉 and 𝜆𝑘 is the eigenvalue of 𝑉. If we let 𝜆𝑘=𝑣2𝑘,𝑘=1,2,3,,𝑛.(2.48) Then (2.47) took the form𝐿𝑄(𝑢)=11+𝑣21𝑢2+𝐿21+𝑣22𝑢2𝐿++𝑛1+𝑣2𝑛𝑢2𝑓(0)+𝑢𝑓(0).(2.49) If we take the inverse Sumudu transform of each term of (2.49), we obtain 𝑓𝐿(𝑥)=1𝑣cos1𝑥+𝐿2𝑣cos2𝑥++𝐿𝑛𝑣cos𝑛𝑥𝑓+𝐿(0)1𝑣sin1𝑥𝑣1+𝐿2𝑣sin2𝑥𝑣2𝐿++𝑛𝑣sin𝑛𝑥𝑣𝑛𝑓(0)=cos(𝐴𝑥)𝑓(0)+𝐴1sin(𝐴𝑥)𝑓(0),𝐴2=𝑉.(2.50)

2.4. Linear Vibrations with Symmetric Damping

The solution of problems involving vibrations of linear systems with viscous damping entails some difficulty because of the presence of complex eigenvalues in the computations. In this part, the vibrations of damped linear systems that exhibit symmetry are considered. The matrix differential equation of motion equation (2.37) takes the form𝑀𝑓+2𝐶𝑓+𝐾𝑓=𝑔(𝑥).(2.51) The matrix 2𝐶 is the damping matrix of the system. Let us consider the free oscillations for which 𝑔(𝑥)=0. If we follows the same procedure as used above, we may obtain Sumudu transform of (2.51) at 𝑔(𝑥)=0 as follows:𝑀𝑢2+2𝐶𝑢+𝐾𝐹(𝑢)=𝑀𝑓(0)𝑢2+𝑓(0)𝑢+2𝐶𝑓(0)𝑢,(2.52) where, as above, Sumudu transforms of 𝑓(𝑥)=𝐹(𝑢) and 𝑓(0) and 𝑓(0) are the initial displacement and initial velocity vector of the system; let us consider the following cases to the matrix 𝐶. (I) If 𝐶=𝛼𝑀, in this case the matrix 𝐶 is proportional to the inertia matrix 𝑀, where 𝛼 is scalar constant having the proper dimensions. And multipling the resulting by 𝑀1, (2.51) becomes𝐼+2𝛼𝐼𝑢+𝑉𝑢2𝐹(𝑢)=𝑓(0)+𝑓(0)𝑢+2𝛼𝑓(0)𝑢,𝑉=𝑀1𝐾.(2.53) Now let us define the following identity:𝐼+2𝛼𝐼+𝑉𝑢2𝐹(𝑢)=𝑓(0)+𝑓(0)𝑢+2𝛼𝐼𝑢𝑓(0),𝑉=𝐴2+𝛼2𝐼.(2.54) By using (2.53) and (2.54), we have(𝐹(𝑢)=1+𝛼𝑢)𝑓(0)(𝐼+𝛼𝑢)2+𝐴2𝑢2+𝑢𝑓(0)+𝛼𝑓(0)(𝐼+𝛼𝑢)2+𝐴2𝑢2.(2.55) On using inverse Sumudu transform for (2.55), we obtain 𝑓(𝑥)=𝑒𝛼𝑥1cos(𝐴𝑥)𝑓(0)+𝐴𝑒𝛼𝑥𝑓sin(𝐴𝑥).(0)+𝛼𝑓(0)(2.56)

(II) If 𝐶=𝛽𝐾, the matrix 𝐶 is proportional to the stiffness matrix 𝐾 of the system so that, 𝐶=𝛽𝐾 where 𝛽 is a scalar constant of proper dimensions. By substituting 𝐶 in (2.52) and multiplying the results by 𝑀1, we obtain𝐼+2𝑢𝛽𝑉+𝑢2𝐴2+𝛽2𝑉2𝐹(𝑢)=𝑓(0)+𝑓(0)𝑢+2𝛽𝑉𝑢𝑓(0),𝑉=𝑀1𝐾,𝐴2+𝛽2𝑉2=𝑉.(2.57) By simplifying (2.57),(𝐹(𝑢)=𝐼+𝛽𝑉𝑢)𝑓(0)(𝐼+𝛽𝑉𝑢)2+𝐴2𝑢2+𝑢𝛽𝑉𝑓(0)+𝑓(0)(𝐼+𝛽𝑉𝑢)2+𝐴2𝑢2.(2.58) On using the inverse Sumudu transform for (2.58), we obtain 𝑓(𝑥)=𝑒𝛼𝑉𝑥cos(𝐴𝑥)𝑓(0)+𝑒𝛼𝑉𝑥sin(𝐴𝑥)𝛽𝑉𝑓(0)+𝑓(0).(2.59)

2.5. Oscillations of the Foucault Pendulum

The use of Sumudu transforms of functions of matrices is demonstrated. As a concrete example, the motion of Foucault’s pendulum is considered. The equations of motion for small oscillations of the Foucault pendulum are given by the following system:̈𝑥2𝜂̇𝑦+𝜌2𝑥=0,̈𝑦+2𝜂̇𝑥+𝜌2𝑦=0,(2.60) where the following notations are used: 𝑥 is the deflection of the pendulum toward the south, 𝑦 is the deflection of the pendulum toward the east, 𝜂=𝜔sin𝜃, 𝜔 is the angular velocity of the earth, and 𝜃 is the angle of latitude. Equation (2.60) can be written in the matrix form as follows:𝐼̈̇𝑓+2𝜂𝐽𝑓+𝐼𝜌2𝑓=0,(2.61) where 𝑖 is second order unit matrix and the coordinate vector has the form𝑥𝑦𝑓=,𝐽=0110,(2.62) where 𝐽 is matrix 2×2, where 𝐽2=𝐼. Now by taking Sumudu transform for (2.61), and after arrangement, we have𝐼+2𝜂𝐽𝑢+𝐼𝜌2𝑢2𝐹(𝑢)=(𝐼+2𝜂𝐽𝑢)𝑓(0)+𝐼𝑢𝑓(0),(2.63) where 𝑓(0) and 𝑓(0) represent the initial coordinate and initial velocity vector, respectively; in order to use inverse Sumudu transform, we need the following identity: 𝐼+2𝜂𝐽𝑢+𝐼𝜌2𝑢2=(𝐼+𝜂𝐽𝑢)2+𝐴2𝑢2=𝐼+2𝜂𝐽𝑢+(𝜂𝐽𝑢)2+𝐴2𝑢2,(2.64) where (𝜂𝐽𝑢)2+𝐴2𝑢2=𝐴2𝜂2𝐼𝑢2=𝐼𝜌2𝑢2.(2.65) Therefore, we obtain 𝐴2𝑢2=𝜂2+𝜌2𝐼𝑢2=𝐼𝐵2𝑢2.(2.66) On using the above identity (2.63), it becomes(𝐹(𝑢)=𝐼+𝜂𝐽𝑢)𝑓(0)(𝐼+𝜂𝐽𝑢)2+𝐼𝐵2𝑢2+𝜂𝐽𝑓(0)+𝐼𝑓𝑢(0)(𝐼+𝜂𝐽𝑢)2+𝐼𝐵2𝑢2.(2.67) By taking inverse Sumudu transform for (2.67), we obtain 𝑓(𝑡)=𝑒𝜂𝐽𝑡𝑒cos(𝐼𝐵𝑡)𝑓(0)+𝜂𝐽𝑡𝐵sin(𝐼𝐵𝑡)𝜂𝐽𝑓(0)+𝐼𝑓.(0)(2.68) Thus consider the following system:𝑎11𝑦1+𝑏11𝑦1+𝑎12𝑦2+𝑏12𝑦2=𝑓1𝑎(𝑡),21𝑦1+𝑏21𝑦1+𝑎22𝑦2+𝑏22𝑦2=𝑓2(𝑡).(2.69) We presume the existence of the limits of the excitations as 𝑡+0, 𝑓1(0+) and 𝑓2(0+) deferring further specifications concerning these functions. Let the system be anomalous; that is,||||||𝑎𝐴=11𝑎12𝑎21𝑎22||||||.(2.70) Initial values 𝑦01 and 𝑦02 of 𝑦1 and 𝑦2 are given as limits as 𝑡+0:𝑦10+=𝑦01,𝑦20+=𝑦02.(2.71) Because of (2.70), we can eliminate 𝑦1 and 𝑦2 from (2.69). Since (2.69) represents a system of differential equations, at least one of the coefficients𝑎𝑖𝑘 must have a nonzero value; without loss of generality, let 𝑎110. To accomplish the attempted elimination, multiply the first equation by 𝑎21 and the second equation by 𝑎11, and then subtract the first from the second. With||||||𝑎𝐵=11𝑏11𝑎21𝑏21||||||||||||𝑎,𝐶=11𝑏12𝑎21𝑏22||||||,(2.72) thus we can write the result compactly𝐵𝑦1(𝑡)+𝐶𝑦2(𝑡)=𝑎21𝑓1(𝑡)+𝑎11𝑓2(𝑡).(2.73) The compatibility condition is obtained from (2.73), by the limiting process 𝑡+0𝐵𝑦01+𝐶𝑦02=𝑎21𝑓10++𝑎11𝑓20+.(2.74) If not only the determinant 𝐴 but also the determinants 𝐵 and 𝐶 are each zero, then we must conclude that the coefficients of the second equation (2.69) are fixed multiples of the coefficients of the first equation of (2.69). In this case, either the second equation is equivalent to the first if 𝑓2 too is the same fixed multiple of 𝑓1, or else the equations would contradict one another. Hence, 𝐵 and 𝐶 cannot both be zero. Now we apply the Sumudu transformation to the system (2.69); we obtain𝑎11+𝑏11𝑢𝑌1𝑎(𝑢)+12+𝑏12𝑢𝑌2(𝑢)=𝑢𝐹1(𝑢)+𝑎11𝑦01+𝑎11𝑦02,𝑎21+𝑏21𝑢𝑌1𝑎(𝑢)+22+𝑏22𝑢𝑌2(𝑢)=𝑢𝐹2(𝑢)+𝑎21𝑦01+𝑎22𝑦02.(2.75) With (2.70) and (2.72), we introduce short notations for three determinants of the matrix of coefficients of (2.69), here as follows:||||||𝑏𝐷=11𝑎12𝑏21𝑎22||||||||||||𝑏,𝐸=11𝑏12𝑏21𝑏22||||||||||||𝑎,𝐺=12𝑏12𝑎22𝑏22||||||.(2.76) On using the notation of (2.76), we obtainΔ(𝑢)=(𝐶+𝐷)+𝐸𝑢.(2.77) Then (2.77) follows, Δ(𝑢)𝑌1(||||||𝑢)=𝑢𝐹1(𝑢)𝑎12+𝑏12𝑢𝑢𝐹2(𝑢)𝑎22+𝑏22𝑢||||||+||||||𝑎11𝑦01+𝑎12𝑦02𝑎12+𝑏12𝑢𝑎21𝑦01+𝑎22𝑦02𝑎22+𝑏22𝑢||||||.(2.78) Since 𝐴=0, thenΔ(𝑢)𝑌1(𝑢)=𝑢𝐹1𝑎(𝑢)22+𝑏22𝑢𝑢𝐹2𝑎(𝑢)12+𝑏12𝑢+𝐶𝑦01+𝐺𝑦02,Δ(𝑢)𝑌2(𝑢)=𝑢𝐹1𝑎(𝑢)21+𝑏21𝑢+𝑢𝐹2𝑎(𝑢)11+𝑏11𝑢𝐵𝑦01+𝐷𝑦02.(2.79) For brevity, we set 𝐶+𝐷=𝐻.(2.80) We presume here 𝐻0, that is, Δ(𝑢) is a linear function; we divide (2.79) by the coefficient Δ(𝑢); then we have𝑌1(𝑢)=𝑢𝐹1𝑎(𝑢)22+𝑏22𝑢𝐻+𝐸𝑢𝑢𝐹2𝑎(𝑢)12+𝑏12𝑢+𝐻+𝐸𝑢𝐶𝑦01+𝐻+𝐸𝑢𝐺𝑦02𝐻+𝐸𝑢,(2.81)Δ(𝑢)𝑌2(𝑢)=𝑢𝐹1𝑎(𝑢)21+𝑏21𝑢+𝐻+𝐸𝑢𝑢𝐹2𝑎(𝑢)11+𝑏11𝑢𝐻+𝐸𝑢𝐵𝑦01+𝐻+𝐸𝑢𝐷𝑦02.𝐻+𝐸𝑢(2.82) The first term of (2.81) can be modified as follows: 𝑢𝐹1𝑎(𝑢)22+𝑏22𝑢𝐻+𝐸𝑢=𝑢𝐹1𝑏(𝑢)22𝐸+Γ𝑎1+(𝐸/𝐻)𝑢,whereΓ=22𝐻𝑏22𝐸.(2.83) The inverse Sumudu transform of above function is given by 𝑆1𝑢𝐹1𝑏(𝑢)22𝐸+Γ𝑏𝐼+(𝐸/𝐻)𝑢=𝐼22𝐸𝑓1(𝑡)+𝑓1(𝑡)Γ𝑒(𝐸/𝐻)𝑡.(2.84) The rest terms of (2.81) are similarly modified. Then we obtain the solution of (2.81) as 𝑦1𝑏(𝑡)=𝐼22𝐸𝑓1(𝑡)+𝑓1(𝑡)Γ𝑒(𝐸/𝐻)𝑡𝑏𝐼12𝐸𝑓2(𝑡)𝑓2(𝑡)Ψ𝑒(𝐸/𝐻)𝑡+𝐶𝐻𝑦01𝑒(𝐸/𝐻)𝑡+𝐺𝐻𝑦02𝑒(𝐸/𝐻)𝑡,(2.85) where Ψ=(𝑎12/𝐻)(𝑏12/𝐸); similarly one can find the solution of (2.82) 𝑦2𝑏(𝑡)=𝐼21𝐸𝑓1(𝑡)𝑓1(𝑡)Φ𝑒(𝐸/𝐻)𝑡𝑏+𝐼11𝐸𝑓2(𝑡)+𝑓2(𝑡)Ω𝑒(𝐸/𝐻)𝑡𝐵𝐻𝑦01𝑒(𝐸/𝐻)𝑡+𝐷𝐻𝑦02𝑒(𝐸/𝐻)𝑡,(2.86) where Φ=(𝑏21/𝐻)(𝑎21/𝐸) and Ω=(𝑏11/𝐻)(𝑎11/𝐸).

Acknowledgments

The authors express their sincere thanks to the referee(s) for careful reading of the paper and helpful suggestions. The authors also gratefully acknowledge that this research is partially supported by Ministry of Science, Technology and Innovations (MOSTI), Malaysia under the e-Science Grant no. 06-01-04-SF1050.