Abstract

For 𝑝[0,1], the generalized Seiffert mean of two positive numbers 𝑎 and 𝑏 is defined by 𝑆𝑝(𝑎,𝑏)=𝑝(𝑎𝑏)/arctan[2𝑝(𝑎𝑏)/(𝑎+𝑏)],0<𝑝1,𝑎𝑏;(𝑎+𝑏)/2,𝑝=0,𝑎𝑏;𝑎,𝑎=𝑏. In this paper, we find the greatest value 𝛼 and least value 𝛽 such that the double inequality 𝑆𝛼(𝑎,𝑏)<𝑇(𝑎,𝑏)<𝑆𝛽(𝑎,𝑏) holds for all 𝑎,𝑏>0 with 𝑎𝑏, and give new bounds for the complete elliptic integrals of the second kind. Here, 𝑇(𝑎,𝑏)=(2/𝜋)0𝜋/2𝑎2cos2𝜃+𝑏2sin2𝜃𝑑𝜃 denotes the Toader mean of two positive numbers 𝑎 and 𝑏.

1. Introduction

For 𝑝[0,1], the generalized Seiffert mean of two positive numbers 𝑎 and 𝑏 is defined by 𝑆𝑝(𝑎,𝑏)=𝑝(𝑎𝑏)[]arctan2𝑝(𝑎𝑏)/(𝑎+𝑏),0<𝑝1,𝑎𝑏,𝑎+𝑏2,𝑝=0,𝑎𝑏,𝑎,𝑎=𝑏.(1.1)

It is well known that 𝑆𝑝(𝑎,𝑏) is continuous and strictly increasing with respect to 𝑝[0,1] for fixed 𝑎,𝑏>0 with 𝑎𝑏. In particular, if 𝑝=1/2, then the generalized Seiffert mean reduces to the Seiffert mean 𝑆(𝑎,𝑏)=𝑎𝑏2arctan((𝑎𝑏)/(𝑎+𝑏)),𝑎𝑏,𝑎,𝑎=𝑏.(1.2)

Recently, the Seiffert mean and its generalization have been the subject of intensive research, many remarkable inequalities for these means can be found in the literature [15].

In [6], Toader introduced the Toader mean 𝑇(𝑎,𝑏) of two positive numbers 𝑎 and 𝑏 as follows: 2𝑇(𝑎,𝑏)=𝜋0𝜋/2𝑎2cos2𝜃+𝑏2sin2=𝜃𝑑𝜃,2𝑎1(𝑏/𝑎)2𝜋,𝑎>𝑏,2𝑏1(𝑎/𝑏)2𝜋,𝑎<𝑏,𝑎,𝑎=𝑏,(1.3) where (𝑟)=0𝜋/2(1𝑟2sin2𝑡)1/2𝑑𝑡, 𝑟[0,1) is the complete elliptic integral of the second kind.

Vuorinen [7] conjectured that 𝑀3/2(𝑎,𝑏)<𝑇(𝑎,𝑏)(1.4) for all 𝑎,𝑏>0 with 𝑎𝑏, where 𝑀𝑝𝑎(𝑎,𝑏)=𝑝+𝑏𝑝21/𝑝,𝑝0,𝑎𝑏,𝑝=0(1.5) is the power mean of order 𝑝 of two positive numbers 𝑎 and 𝑏. This conjecture was proved by Barnard et al. [8].

In [9], Alzer and Qiu presented a best possible upper power mean bound for the Toader mean as follows:𝑇(𝑎,𝑏)<𝑀log2/log(𝜋/2)(𝑎,𝑏)(1.6) for all 𝑎,𝑏>0 with 𝑎𝑏.

The main purpose of this paper is to find the greatest value 𝛼 and least value 𝛽 such that the double inequality 𝑆𝛼(𝑎,𝑏)<𝑇(𝑎,𝑏)<𝑆𝛽(𝑎,𝑏) holds for all 𝑎,𝑏>0 with 𝑎𝑏 and give new bounds for the complete elliptic integrals of the second kind.

2. Lemmas

In order to establish our main result, we need several formulas and lemmas, which we present in this section.

The following formulas were presented in [10, Appendix E, pages 474-475]: Let 𝑟[0,1), then 𝒦(𝑟)=0𝜋/21𝑟2sin2𝑡1/2𝜋𝑑𝑡,𝒦(0)=2,𝒦(1)=+,(𝑟)=0𝜋/21𝑟2sin2𝑡1/2𝑑𝑡,(0)=𝜋/2,(1)=1,𝑑𝒦(𝑟)=𝑑𝑟(𝑟)1𝑟2𝒦(𝑟)𝑟1𝑟2,𝑑(𝑟)=𝑑𝑟(𝑟)𝒦(𝑟)𝑟,𝑑(𝑟)1𝑟2𝒦(𝑟)𝑑[]𝑑𝑟=𝑟𝒦(𝑟),𝒦(𝑟)(𝑟)=𝑑𝑟𝑟(𝑟)1𝑟2,2𝑟=1+𝑟2(𝑟)1𝑟2𝒦(𝑟).1+𝑟(2.1)

Lemma 2.1 (see [10, Theorem 1.25]). For <𝑎<𝑏<, let 𝑓(𝑥),𝑔(𝑥)[𝑎,𝑏] be continuous on [𝑎,𝑏] and be differentiable on (𝑎,𝑏), let 𝑔(𝑥)0 for all 𝑥(𝑎,𝑏). If 𝑓(𝑥)/𝑔(𝑥) is increasing (decreasing) on (𝑎,𝑏), then so are 𝑓(𝑥)𝑓(𝑎),𝑔(𝑥)𝑔(𝑎)𝑓(𝑥)𝑓(𝑏)𝑔(𝑥)𝑔(𝑏).(2.2) If 𝑓(𝑥)/𝑔(𝑥) is strictly monotone, then the monotonicity in the conclusion is also strict.

Lemma 2.2. (1)  [(𝑟)(1𝑟2)𝒦(𝑟)]/𝑟2 is strictly increasing from (0,1) onto (𝜋/4,1);
(2)    {[(𝑟)(1𝑟2)𝒦(𝑟)]/𝑟2𝜋/4}/𝑟2 is strictly increasing from (0,1) onto (𝜋/32,1𝜋/4);
(3)    [𝒦(𝑟)(𝑟)]/𝑟2 is strictly increasing from (0,1) onto (𝜋/4,+);
(4)    2(𝑟)(1𝑟2)𝒦(𝑟) is strictly increasing from (0,1) onto (𝜋/2,2);
(5)    𝐹(𝑟)=[(2𝑟2)𝒦(𝑟)2(𝑟)]/𝑟4 is strictly increasing from (0,1) onto (𝜋/16,+);
(6)    𝐺(𝑟)=[4𝜋𝜋𝑟28(𝑟)]/𝑟4 is strictly increasing from (0,1) onto (3𝜋/16,3𝜋8).

Proof. Parts (1)–(4) can be found in [10, Theorem 3.21(1), Theorem  3.31(6), and Exercise 3.43(11) and (13)].
For part (5), clearly 𝐹(1)=+. Let 𝐹1(𝑟)=(2𝑟2)𝒦(𝑟)2(𝑟) and 𝐹2(𝑟)=𝑟4, then 𝐹(𝑟)=𝐹1(𝑟)/𝐹2(𝑟), 𝐹1(0)=𝐹2(0)=0 and 𝐹1(𝑟)𝐹2=(𝑟)(𝑟)1𝑟2𝒦4𝑟21𝑟2.(2.3)
It follows from (2.3) and part (1) together with Lemma 2.1 that 𝐹(𝑟) is strictly increasing in (0,1) and 𝐹(0+)=𝜋/16.
For part (6), clearly 𝐺(1)=3𝜋8. Let 𝐺1(𝑟)=4𝜋𝜋𝑟28(𝑟) and 𝐺2(𝑟)=𝑟4, then 𝐺(𝑟)=𝐺1(𝑟)/𝐺2(𝑟), 𝐺1(0)=𝐺2(0)=0, and 𝐺1(𝑟)2𝐺2=(𝑟)2𝑟2𝒦(𝑟)2(𝑟)𝑟4+(𝑟)1𝑟2𝒦(𝑟)/𝑟2𝜋/4𝑟2.(2.4)
From (2.4), parts (2) and (5) together with Lemma 2.1, we know that 𝐺(𝑟) is strictly increasing in (0,1), and 𝑓(0+)=3𝜋/16.

Lemma 2.3. (1)𝑔(𝑟)=arctan(3𝑟/2)3𝜋𝑟/{4[2(𝑟)(1𝑟2)𝒦(𝑟)]} is strictly increasing from (0,1) onto (0,arctan(3/2)3𝜋/8).
(2)𝑓(𝑟)=arctan𝑟𝜋𝑟/{2[2(𝑟)(1𝑟2)𝒦(𝑟)]}<0 for 𝑟(0,1).

Proof. For part (1), clearly 𝑔(0+)=0 and 𝑔(1)=arctan(3/2)3𝜋/8=0.0335>0. Simple computation leads to 𝑔2(𝑟)=34+3𝑟23𝜋(𝑟)42(𝑟)1𝑟2𝒦(𝑟)2=3𝑟4(𝑟)44+3𝑟22(𝑟)1𝑟2𝒦(𝑟)2𝑔1(𝑟),(2.5) where 𝑔1(𝑟)={8[2(𝑟)(1𝑟2)𝒦(𝑟)]2𝜋(4+3𝑟2)(𝑟)}/[𝑟4(𝑟)].
Making use of Lemma 2.2 (1), (2), and (6), we get 𝑔18(𝑟)=(𝑟)(𝑟)1𝑟2𝒦(𝑟)𝑟22+16(𝑟)1𝑟2𝒦(𝑟)/𝑟2𝜋/4𝑟24𝜋𝜋𝑟28(𝑟)𝑟4>16𝜋𝜋42𝜋+1632(3𝜋8)=83𝜋2>0.(2.6)
Therefore, part (1) follows from (2.5) and (2.6) together with the limiting values of 𝑔(𝑟) at 𝑟=0 and 𝑟=1.
For part (2), simple computations yield that lim𝑟0+𝑓(𝑟)=lim𝑟1𝑓(𝑟)=0,(2.7)𝑓𝑓(𝑟)=1(𝑟)21+𝑟22(𝑟)1𝑟2𝒦(𝑟)2,(2.8) where 𝑓1(𝑟)=2[2(𝑟)(1𝑟2)𝒦(𝑟)]2𝜋(1+𝑟2)(𝑟). Note that lim𝑟0+𝑓1(𝑟)=0,(2.9)lim𝑟1𝑓1𝑓(𝑟)=82𝜋>0,(2.10)14(𝑟)=2(𝑟)1𝑟2𝒦(𝑟)(𝑟)1𝑟2𝒦(𝑟)𝑟2𝜋𝑟(𝑟)𝜋1+𝑟2(𝑟)𝒦(𝑟)𝑟=𝑟𝑓2(𝑟),(2.11) where 𝑓2(𝑟)=4[2(𝑟)(1𝑟2)𝒦(𝑟)][(𝑟)(1𝑟2)𝒦(𝑟)]/𝑟22𝜋(𝑟)+𝜋(1+𝑟2)[𝒦(𝑟)(𝑟)]/𝑟2.
From Lemma 2.2(1), (3), and (4) together with the monotonicity of (𝑟) we know that 𝑓2(𝑟) is strictly increasing in (0,1). Moreover, lim𝑟0+𝑓2𝜋(𝑟)=24,(2.12)lim𝑟1𝑓2(𝑟)=+.(2.13)
Equations (2.11)–(2.13) and the monotonicity of 𝑓2(𝑟) lead to the conclusion that there exists 𝑟0(0,1) such that 𝑓1(𝑟) is strictly decreasing in (0,𝑟0) and strictly increasing in (𝑟0,1).
It follows from (2.8)–(2.10) and the piecewise monotonicity of 𝑓1(𝑟) that there exists 𝑟1(0,1) such that 𝑓(𝑟) is strictly decreasing in (0,𝑟1) and strictly increasing in (𝑟1,1).
Therefore, part (2) follows from (2.7) and the piecewise monotonicity of 𝑓(𝑟).

3. Main Result

Theorem 3.1. Inequality 𝑆3/4(𝑎,𝑏)<𝑇(𝑎,𝑏)<𝑆1/2(𝑎,𝑏) holds for all 𝑎,𝑏>0 with 𝑎𝑏, and 𝑆3/4(𝑎,𝑏) and 𝑆1/2(𝑎,𝑏) are the best possible lower and upper generalized Seiffert mean bounds for the Toader mean 𝑇(𝑎,𝑏), respectively.

Proof. Firstly, we prove that 𝑆3/4(𝑎,𝑏)<𝑇(𝑎,𝑏)<𝑆1/2(𝑎,𝑏)(3.1) for all 𝑎,𝑏>0 with 𝑎𝑏.
Without loss of generality, we assume that 𝑎>𝑏. Let 𝑡=𝑏/𝑎<1, 𝑟=(1𝑡)/(1+𝑡). Then (1.1) and (1.3) lead to 𝑇(𝑎,𝑏)𝑆3/4(𝑎,𝑏)=2𝑎𝜋1𝑡23𝑎(1𝑡)4arctan3=(1𝑡)/2(1+𝑡)2𝑎𝜋2𝑟1+𝑟3ar2(1+𝑟)arctan𝑟=3/22𝑎𝜋2(𝑟)1𝑟2𝒦(𝑟)1+𝑟3ar2(1+𝑟)arctan𝑟=3/22𝑎2(𝑟)1𝑟2𝒦(𝑟)𝜋(1+𝑟)arctan𝑟3/2𝑔(𝑟),(3.2)𝑇(𝑎,𝑏)𝑆1/2(𝑎,𝑏)=2𝑎𝜋1𝑡2𝑎(1𝑡)=2arctan((1𝑡)/(1+𝑡))2𝑎𝜋2𝑟1+𝑟𝑎𝑟=(1+𝑟)arctan𝑟2𝑎𝜋2(𝑟)1𝑟2𝒦(𝑟)1+𝑟ar=(1+𝑟)arctan𝑟2𝑎2(𝑟)1𝑟2𝒦(𝑟)𝜋(1+𝑟)arctan𝑟𝑓(𝑟),(3.3) where 𝑔(𝑟) and 𝑓(𝑟) are defined as in Lemma 2.3.
Therefore, inequality (3.1) follows from (3.2) and (3.3) together with Lemma 2.3.
Next, we prove that 𝑆3/4(𝑎,𝑏) and 𝑆1/2(𝑎,𝑏) are the best possible lower and upper generalized Seiffert mean bounds for the Toader mean 𝑇(𝑎,𝑏), respectively.
For any 𝜀>0 and 0<𝑥<1, from (1.1) and (1.3) one has lim𝑥0𝑆1/2𝜀=(1,𝑥)𝑇(1,𝑥)12𝜀22arctan(12𝜀)𝜋<122arctan1𝜋𝑆=0,(3.4)3/4+𝜀(1,1𝑥)𝑇(1,1𝑥)=𝐽(𝑥)arctan,3+4𝜀𝑥/2(2𝑥)(3.5) where 𝐽(𝑥)=(3/4+𝜀)𝑥2(2𝑥𝑥2)arctan{[(3+4𝜀)𝑥]/[2(2𝑥)]}/𝜋.
Letting 𝑥0 and making use of Taylor expansion, we get 𝐽(𝑥)=34+𝜀𝑥34𝑥1+𝜀121𝑥+𝑥162𝑥+𝑜2×11+21𝑥+41334+𝜀2𝑥2𝑥+𝑜2=𝜀332+𝜀34𝑥+𝜀3𝑥+𝑜3.(3.6)
Inequality (3.4) and equations (3.5) and (3.6) imply that for any 𝜀>0 there exist 𝛿1=𝛿1(𝜀)>0 and 𝛿2=𝛿2(𝜀)>0, such that 𝑆3/4+𝜀(1,1𝑥)>𝑇(1,1𝑥) for 𝑥(0,𝛿1) and 𝑆1/2𝜀(1,𝑥)<𝑇(1,𝑥) for 𝑥(0,𝛿2).

From Theorem 3.1, we get new bounds for the complete elliptic integrals of the second kind as follows.

Corollary 3.2. The inequality 3𝜋11𝑟28arctan311𝑟2/21+1𝑟2𝜋<𝐸(𝑟)<11𝑟24arctan11𝑟2/1+1𝑟2(3.7) holds for all 𝑟(0,1).

Acknowledgments

This research was supported by the Natural Science Foundation of China under Grant 11071069 and Innovation Team Foundation of the Department of Education of Zhejiang Province under Grant T200924. The authors wish to thank the anonymous referees for their careful reading of the manuscript and their fruitful comments and suggestions.