Abstract

We investigate the asymptotic behavior of solutions for the heat equation in the weighted space 𝑌𝜎0(𝑁){𝜑𝐶(𝑁)lim|𝑥|(1+|𝑥|2)𝜎/2𝜑(𝑥)=0}. Exactly, we find that the unbounded function space 𝑌𝜎0(𝑁) with 0<𝜎<𝑁 can provide a setting where complexity occurs in the asymptotic behavior of solutions for the heat equation.

1. Introduction

In this paper, we consider the asymptotic behavior of solutions to the Cauchy problem of the heat equation 𝜕𝑢𝜕𝑡Δ𝑢=0,(𝑥,𝑡)𝑁×(0,),𝑢(𝑥,0)=𝑢0(𝑥),𝑥𝑁,(1.1) where 𝑁1 and the initial value 𝑢0𝑌𝜎0(𝑁).

Whether complexity occurs in the asymptotic behavior of solutions for some evolution equations or not mainly depends on the work spaces that one selects [19]. In the space 𝐿𝑝(𝑁) with 1𝑝<, the problem (1.1) under consideration is well posed and the asymptotic behavior of the solutions is rather simple, reflecting the simple structure of the heat equation. Considering, for instance, the problem (1.1) with the initial value 𝑢0𝐿1(𝑁), it is well-known that the solutions 𝑢(𝑥,𝑡) converge as 𝑡 toward a multiple of the fundamental solution, the one which has the same integral, 𝑢(𝑥,𝑡)=𝑆(𝑡)𝑢0(𝑥)=𝐺(𝑡)𝑢0(𝑥)𝑀𝐺(𝑥,𝑡),(1.2) where 𝐺(𝑥,𝑡)=(4𝜋𝑡)𝑁/2exp(|𝑥|2/4𝑡) and 𝑀=𝑁𝑢0(𝑥)d𝑥, see [10, 11].

It was first found in 2002 [12] by Vázquez and Zuazua that the bounded function space 𝐿(𝑁) provides a setting where complicated asymptotic behavior of solutions may take place for the heat equation. In fact, they proved that, for any bounded sequence {𝑔𝑗,𝑗=1,2,} in 𝐿(𝑁), there exists an initial value 𝑢0𝐿(𝑁) and a sequence 𝑡𝑗𝑘 as 𝑘 such that 𝑢𝑡𝑗1/2𝑘𝑥,𝑡𝑗𝑘𝑡=𝑆𝑗𝑘𝑢0𝑡𝑗𝑘𝑥𝑆(1)𝑔𝑗(𝑥)(1.3) uniformly on any compact subset of 𝑁 as 𝑘. Subsequently, Cazenave et al. showed that, in the bounded continuous function space 𝐶0(𝑁), the solutions of the heat equation may present more complex asymptotic behavior [1315]. Meanwhile, considerable attention has also been paid to study the complicated asymptotic behavior of solutions for the porous medium equation and other evolution equations in some bounded function spaces such as 𝐶0(𝑁) and 𝐿(𝑁) (see, e.g., [3, 7, 9, 12, 16] and the references therein).

In this paper we find that, even in the unbounded function space 𝑌𝜎0(𝑁) with 0<𝜎<𝑁, the complicated asymptotic behavior of solutions for the heat equation can also occur. For this purpose, we need to establish the 𝐿𝑝𝜎𝐿𝜎 smoothing effect and other estimates for the solutions of the problem (1.1) when the initial value 𝑢0𝐿𝑝𝜎(𝑁){𝜑(1+||2)𝜎/2𝜑()𝐿𝑝(𝑁)} with 1<𝑝 or 𝑢0𝑌𝜎0(𝑁).

The rest of this paper is organized as follows. In the next section, we give some definitions and some estimates of the solutions to the problem (1.1). Section 3 is devoted to study the complicated asymptotic behavior of the solutions.

2. Main Estimates

In this section, we investigate some properties of solutions for the problem (1.1) when the initial value 𝑢0 belongs to some weighted spaces. For these purposes, we first introduce the mild solutions 𝑢(𝑥,𝑡) of the problem (1.1) which are defined as 𝑢(𝑥,𝑡)=𝑆(𝑡)𝑢0(𝑥)=(4𝜋𝑡)𝑁/2𝑁||||exp𝑥𝑦2𝑢4𝑡0(𝑦)d𝑦.(2.1) Letting 𝜎0 and 1𝑝, we define two weighted spaces 𝑌𝜎0(𝑁) and 𝐿𝑝𝜎(𝑁) as follows: 𝑌𝜎0𝑁𝜑(𝑥)𝐶𝑁lim|𝑥|𝜑(𝑥)1+|𝑥|2𝜎/2,𝐿=0𝑝𝜎𝑁𝜑𝜑()1+||2𝜎/2𝐿𝑝𝑁.(2.2) Endowed with the obvious norms, 𝜑𝑌𝜎0(𝑁)=𝜑()1+||2𝜎/2𝐿(𝑁),𝜑𝐿𝑝𝜎(𝑁)=𝜑()1+||2𝜎/2𝐿𝑝(𝑁),(2.3) the spaces 𝑌𝜎0(𝑁) and 𝐿𝑝𝜎(𝑁) are both Banach spaces. Notice that if 𝜎=0, then 𝑌00𝑁=𝐶0𝑁,𝐿0𝑁=𝐿𝑁,𝐿𝑝0𝑁=𝐿𝑝𝑁.(2.4) Next we give the definition of the 𝜔-limit set 𝜔𝜎𝜇,𝛽(𝑢0) which is our main study object in this paper.

Definition 2.1. Let 𝜎0, 𝜇,  𝛽>0, and suppose that 𝑢0𝑌𝜎0(𝑁). The 𝜔-limit set 𝜔𝜎𝜇,𝛽(𝑢0) is given by 𝜔𝜎𝜇,𝛽𝑢0𝑓𝑌𝜎0𝑁;𝑡𝑛s.t.𝐷𝜇,𝛽𝑡𝑛𝑆𝑡𝑛𝑢0𝑛𝑓in𝑌𝜎0𝑁.(2.5)
Here 𝐷𝜆𝜇,𝛽𝜑(𝑥)𝜆𝜇𝜑(𝜆2𝛽𝑥) for 𝜑𝐿1loc(𝑁) and 𝜆>0.
In the rest of this section, we will consider the properties of the solutions for the problem (1.1) when the initial value 𝑢0𝐿𝑝𝜎(𝑁) or 𝑢0𝑌𝜎0(𝑁).
The following theorem can be seen as some extension of the maximum principle for the problem (1.1).

Theorem 2.2. Let 0𝜎<. Suppose that 𝑢0𝐿𝜎𝑁(2.6) and that 𝑢(𝑥,𝑡)=𝑆(𝑡)𝑢0(𝑥) are the mild solutions of the problem (1.1). Then 𝑢(𝑡)=𝑆(𝑡)𝑢0𝐿𝜎𝑁for𝑡>0.(2.7) Moreover, if 𝑡>1, then 𝑆(𝑡)𝑢0𝐿𝜎(𝑁)𝐶𝑡𝜎𝑢0𝐿𝜎(𝑁),(2.8) or if 0<𝑡1, then 𝑆(𝑡)𝑢0𝐿𝜎(𝑁)𝑢𝐶0𝐿𝜎(𝑁).(2.9)

Remark 2.3. Let 𝜎=0. From Theorem 2.2, we can obtain the well-known result (maximum principle) that if 𝑢0𝐿0(𝑁)=𝐿(𝑁), then 𝑆(𝑡)𝑢0𝐿(𝑁)𝑢𝐶0𝐿(𝑁).(2.10)

Proof. To prove this theorem, we need the fact that if 𝜑(𝑥)=𝑀1+|𝑥|2𝜎/2forsome𝑀>0,(2.11) then there exists a constant 𝐶 such that 𝑆(𝑡)𝜑(𝑥)𝐶1+𝑡+|𝑥|2𝜎/2,(2.12) which proof can be found in [17]; we give the proof here for completeness. Consider the following problem: 𝜕𝑣𝜕𝑡Δ𝑣=0,in𝑁×(0,),𝑣(𝑥,0)=𝑣0(𝑥)=𝑀|𝑥|𝜎,in𝑁.(2.13) For 𝜆>0, from (2.1), we can get that 𝐷𝜆𝜎/2,1/2𝑆(𝜆𝑡)𝑣0(𝑥)=𝜆𝜎/2𝑆(𝜆𝑡)𝑣0𝜆1/2𝑥𝐷=𝑆(𝑡)𝜆𝜎/2,1/2𝑣0(𝑥)=𝑆(𝑡)𝑣0(𝑥).(2.14) By the existence and the regularity theories of the solutions, we can obtain that, for 𝑡>0, 0<𝑆(𝑡)𝑣0𝐶(0,)×𝑁,(2.15) see [10, 18]. Now taking 𝑡=1, 𝜆=𝑠 and 𝑔(𝑥)=𝑆(1)𝑣0(𝑥) in the expression (2.14), we have 𝑆(𝑠)𝑣0(𝑥)=𝑠𝜎/2𝑔𝑠1/2𝑥.(2.16) The fact that 𝑆(𝑠)𝑣0(𝑥)𝐶([0,)×𝑁(0,0)) clearly implies that, for |𝑥|=1, 𝑠𝜎/2𝑔𝑠1/2𝑥=𝑆(𝑠)𝑣0(𝑥)𝑣0(𝑥)=𝑀|𝑥|𝜎=𝑀(2.17) as 𝑠0. Let 𝑦=𝑠1/2𝑥.(2.18) So, ||𝑦||as𝑠0.(2.19) Therefore, ||𝑦||𝜎𝑔(𝑦)𝑀0(2.20) as |𝑦|. So, there exists constant 0<𝐶< such that 0𝑔(𝑥)𝐶1+|𝑥|2𝜎/2.(2.21) By (2.16), we thus have 𝑆(𝑠)𝑣0(𝑥)𝐶𝑠+|𝑥|2𝜎/2.(2.22) Notice that 0𝜑(𝑥)𝐶1+𝑣0(𝑥).(2.23) Therefore, by comparison principle and (2.22), we can get that, for all 𝑡0, there exists constant 𝐶>0 such that 0𝑆(𝑡)𝜑(𝑥)𝐶1+𝑡+|𝑥|2𝜎/2.(2.24) So we complete the proof of (2.12). For any 𝑡>0, from (2.1) and (2.12), we thus obtain that ||𝑢||=||𝑆(𝑥,𝑡)(𝑡)𝑢0||=||||(𝑥)(4𝜋𝑡)𝑁/2𝑁exp(|𝑥𝑦|2/4𝑡)𝑢0||||=||||((𝑦)d𝑦4𝜋𝑡)𝑁/2𝑁exp(|𝑥𝑦|2/4𝑡)||𝑦||1+2𝜎/2𝑢0(||𝑦||𝑦)1+2𝜎/2||||𝑢d𝑦0𝑌𝜎(𝑁)(4𝜋𝑡)𝑁/2𝑁exp(|𝑥𝑦|2/4𝑡)||𝑦||1+2𝜎/2d𝑦𝐶1+𝑡+|𝑥|2𝜎/2𝑢0𝑌𝜎(𝑁).(2.25) Therefore, if 𝑡>1, then ||||𝑢(𝑥,𝑡)𝐶1+|𝑥|2𝜎/2𝑡𝜎𝑢0𝑌𝜎(𝑁).(2.26) This clearly illustrates (2.8). If 0<𝑡1, then ||||𝑢(𝑥,𝑡)𝐶1+|𝑥|2𝜎/2𝑢0𝑌𝜎(𝑁).(2.27) From this, we can get (2.9). So we complete the proof of this theorem.

Theorem 2.4 (𝐿𝑝𝜎𝐿𝜎 smoothing effect). Let 1<𝑝< and 0𝜎<. Suppose 𝑢0𝐿𝑝𝜎(𝑁) and that 𝑢(𝑥,𝑡)=𝑆(𝑡)𝑢0(𝑥) are the solutions of the problem (1.1). Then 𝑢(𝑡)=𝑆(𝑡)𝑢0𝐿𝜎𝑁for𝑡>0.(2.28) Moreover, if 𝑡>1, then 𝑆(𝑡)𝑢0𝐿𝜎(𝑁)𝐶𝑡𝜎𝑁/2𝑝𝑢0𝐿𝑝𝜎(𝑁),(2.29) or if 0<𝑡1, then 𝑆(𝑡)𝑢0𝐿𝜎(𝑁)𝐶𝑡𝑁/2𝑝𝑢0𝐿𝑝𝜎(𝑁).(2.30)

Remark 2.5. If 𝜎=0, then Theorem 2.4 captures the result 𝐿𝑝𝐿 smoothing effect for the heat equation.

Proof. For any 𝑡>0, from (2.1) and Theorem 2.2, we thus obtain that ||𝑢||=||𝑆(𝑥,𝑡)(𝑡)𝑢0||=||||(𝑥)(4𝜋𝑡)𝑁/2𝑁exp(|𝑥𝑦|2/4𝑡)𝑢0||||=||||((𝑦)d𝑦4𝜋𝑡)𝑁/2𝑁exp(|𝑥𝑦|2/4𝑡)||𝑦||1+2𝜎/2𝑢0(||𝑦||𝑦)1+2𝜎/2||||d𝑦(4𝜋𝑡)𝑁/2𝑁exp(|𝑥𝑦|2/4𝑡)||𝑦||1+2𝑝𝜎/2d𝑦1/𝑝×(4𝜋𝑡)𝑁/2𝑁exp(|𝑥𝑦|2/4𝑡)||𝑦||1+2𝑝𝜎/2𝑢𝑝0(𝑦)d𝑦1/𝑝𝐶1+𝑡+|𝑥|2𝜎/2𝑡𝑁/2𝑝𝑢0𝐿𝑝𝜎(𝑁).(2.31) Here 1/𝑝+1/𝑝=1. From this, we can get that, if 𝑡1, then 𝑢(𝑡)𝐿𝜎(𝑁)𝐶𝑡𝜎/2𝑁/2𝑝𝑢0𝐿𝑝𝜎(𝑁),(2.32) or if 0<𝑡<1, then 𝑢(𝑡)𝐿𝜎(𝑁)𝐶𝑡𝑁/2𝑝𝑢0𝐿𝑝𝜎(𝑁).(2.33)
So we complete the proof of this theorem.

In the following theorem, we consider the property of the solutions 𝑢(𝑥,𝑡) of (1.1) with the initial data 𝑢0𝑌𝜎0(𝑁).

Theorem 2.6. Let 0𝜎<. If 𝑢0𝑌𝜎0(𝑁), then 𝑆(𝑡)𝑢0𝑌𝜎0𝑁for𝑡0.(2.34)

Proof. For 𝜎=0, the above theorem is a well-known result. So, in the rest of this proof, we assume that 0<𝜎<. From (2.1), we have 1+|𝑥|2𝜎/2||||=𝑢(𝑥,𝑡)1+|𝑥|2𝜎/2||||(4𝜋𝑡)𝑁/2𝑁exp(|𝑥𝑦|2/4𝑡)𝑢0||||=(𝑦)d𝑦1+|𝑥|2𝜎/2||||(4𝜋𝑡)𝑁/2|𝑦|𝑀exp(|𝑥𝑦|2/4𝑡)𝑢0||||+(𝑦)d𝑦1+|𝑥|2𝜎/2||||(4𝜋𝑡)𝑁/2|𝑦|𝑀exp(|𝑥𝑦|2/4𝑡)𝑢0||||(𝑦)d𝑦=I1(𝑥)+I2(𝑥).(2.35) For any 𝜀>0, from 𝑢0𝑌𝜎0(𝑁), we obtain that there exists an 𝑀>0 such that if |𝑦|>𝑀, then ||||𝑢0||𝑦||(𝑦)1+2𝜎/2||||<𝜀.(2.36) So, from (2.12), we have I2(𝑥)=1+|𝑥|2𝜎/2||||(4𝜋𝑡)𝑁/2|𝑦|>𝑀exp(|𝑥𝑦|2/4𝑡)𝑢0||𝑦||(𝑦)1+2𝜎/2||𝑦||1+2𝜎/2||||d𝑦1+|𝑥|2𝜎/2sup||𝑦||>𝑀||||𝑢0(||𝑦||𝑦)1+2𝜎/2||||(4𝜋𝑡)𝑁/2|𝑦|>𝑀exp(|𝑥𝑦|2/4𝑡)||𝑦||1+2𝜎/2d𝑦𝐶1+|𝑥|2𝜎/21+𝑡+|𝑥|2𝜎/2𝜀.(2.37) So, if 𝑡>1, then I2(𝑥)𝐶1+|𝑥|2𝜎/21+𝑡+|𝑥|2𝜎/2𝜀𝐶𝑡𝜎/2𝜀,(2.38) or if 0𝑡1, then I2(𝑥)𝐶1+|𝑥|2𝜎/21+𝑡+|𝑥|2𝜎/2𝜀𝐶𝜀.(2.39) Notice also that 𝑢0𝑌𝜎0𝑁𝐶𝑁.(2.40) So, there exists a constant 𝐶 such that sup||𝑦||𝑀||𝑢0||(𝑦)𝐶.(2.41) This means that I1(𝑥)=1+|𝑥|2𝜎/2||||(4𝜋𝑡)𝑁/2|𝑦|𝑀exp(|𝑥𝑦|2/4𝑡)𝑢0||||(𝑦)d𝑦𝐶1+|𝑥|2𝜎/2.(2.42) So, there exists an 𝑀1>0 such that if |𝑥|>𝑀1, then I1(𝑥)<𝜀.(2.43) Combining this with (2.35), (2.38), and (2.39), we can obtain that, for 𝑡0, 𝑢(𝑡)=𝑆(𝑡)𝑢0𝑌𝜎0𝑁.(2.44) So we complete the proof of this theorem.

3. Complicated Asymptotic Behavior

In this section, we investigate the asymptotic behavior of solutions for the problem (1.1) and give the fact that the weighted space 𝑌𝜎0(𝑁) with 0𝜎<𝑁 can provide a setting where complexity occurs in the asymptotic behavior of solutions.

Theorem 3.1. Let 𝜇>0, 𝜎0, 𝑝>1, and 𝛽>1/2. If 𝑁𝜇+2𝛽𝜎<𝑝,𝑓𝑌𝜎0𝑁𝐿𝑝𝜎𝑁,(3.1) then there exists an initial value 𝑢0𝑌𝜎0(𝑁) and a sequence 𝑡𝑛 as 𝑛 such that 𝐷𝜇,𝛽𝑡𝑛𝑆𝑡𝑛𝑢0𝑛𝑓in𝑌𝜎0𝑁.(3.2) That is, 𝑓𝜔𝜎𝜇,𝛽(𝑢0).

Proof. Suppose that 𝑎>2 is a constant. Then let 𝜆1𝜆=𝑎,𝑗𝑗=max2𝑝/(𝑁𝑝(𝜇+2𝛽𝜎))𝜆(2𝛽𝑁𝑝(𝜇+2𝛽𝜎))/(𝑁𝑝(𝜇+2𝛽𝜎))𝑗1,2𝑗𝜆𝑗11/𝜇for𝑗>1.(3.3) Now we define the initial-value 𝑢0 as 𝑢0(𝑥)=𝑗=1𝜆𝑗𝜇𝑓𝑥𝜆𝑗2𝛽=𝑗=1𝐷𝜆𝜇,𝛽𝑗1𝑓(𝑥).(3.4) Let =max𝑓𝑌𝜎0(𝑁),𝑓𝐿𝑝𝜎(𝑁).(3.5) So, 𝑢0𝑌𝜎0(𝑁)𝑗=1𝜆𝑗𝜇𝑓1𝜆𝑗2𝛽𝑌𝜎0(𝑁)𝑗=12𝑗𝑓(𝑥)𝑌𝜎0(𝑁).(3.6) Here we have used the fact that if 0<𝜆1, then 𝑓(𝜆)𝑌𝜎0(𝑁)=sup𝑥𝑁|||1+𝑥2𝜎/2|||𝑓(𝜆𝑥)=sup𝑥𝑁|||||||||𝑓(𝜆𝑥)1+𝜆𝑥2𝜎/2||||1+𝜆𝑥21+|𝑥|2𝜎/2|||||sup𝑥𝑁||||||||𝑓(𝜆𝑥)1+𝜆𝑥2𝜎/2||||=𝑓𝑌𝜎0(𝑁).(3.7) Therefore, the sequence of (3.4) is convergent in 𝑌𝜎0(𝑁). This means that 𝑢0𝑌𝜎0𝑁.(3.8) As a result of (2.1), we see that, for 0<𝑡<𝑇<,𝐷𝜆𝜇,𝛽𝑛𝑆𝜆2𝑛𝑡𝑢0(𝑥)=𝑆𝑡𝜆𝑛24𝛽𝑢𝑛+𝑣𝑛+𝑤𝑛=𝑆𝑡𝜆𝑛24𝛽𝑢𝑛+𝑆𝑡𝜆𝑛24𝛽𝑣𝑛+𝑆𝑡𝜆𝑛24𝛽𝑤𝑛,(3.9) where 𝑢𝑛(𝑥)=𝑛1𝑗=1𝐷𝜆𝜇,𝛽𝑛𝐷𝜆𝜇,𝛽𝑗1𝑓(𝑥)=𝜆𝜇𝑛𝑛1𝑗=1𝜆𝑗𝜇𝑓𝑥𝜆𝑛2𝛽𝜆𝑗2𝛽,𝑣𝑛(𝑥)=𝐷𝜆𝜇,𝛽𝑛𝐷𝜆𝜇,𝛽𝑛1𝑤𝑓(𝑥)=𝑓(𝑥),𝑛=𝑗=𝑛+1𝐷𝜆𝜇,𝛽𝑛𝐷𝜆𝜇,𝛽𝑗1𝑓(𝑥)=𝜆𝜇𝑛𝑗=𝑛+1𝜆𝑗𝜇𝑓𝑥𝜆𝑛2𝛽𝜆𝑗2𝛽.(3.10) Notice that, if 𝜆1, then 𝑓(𝜆)𝑌𝜎𝑝(𝑁)=𝑁|||1+|𝑥|2𝜎/2|||𝑓(𝜆𝑥)𝑝d𝑥1/𝑝𝑁|||||||||𝑓(𝜆𝑥)1+𝜆𝑥2𝜎/2||||1+𝜆𝑥21+|𝑥|2𝜎/2|||||𝑝d𝑥1/𝑝𝜆𝜎𝑁||||||||𝑓(𝜆𝑥)1+𝜆𝑥2𝜎/2||||𝑝d𝑥1/𝑝=𝜆𝜎𝑁/𝑝𝑓𝑌𝜎𝑝(𝑁),(3.11) we thus obtain that 𝑢𝑛𝑌𝜎𝑝(𝑁)𝑛1𝑗=1𝜆𝑛𝜆𝑗𝜇2𝛽𝑁/𝑝+2𝛽𝜎𝑓𝑌𝜎𝑝(𝑁)𝜆𝑛𝑛𝜆𝑛1𝜇2𝛽𝑁/𝑝+2𝛽𝜎𝑓𝑌𝜎𝑝(𝑁).(3.12) Consequently, for any 𝑡>0, we can select 𝑁 large enough to satisfy that if 𝑛>𝑁, then 0<𝜆𝑛24𝛽𝑡<1.(3.13) Here we have used the hypothesis 𝛽>1/2. So, (2.30), (3.11), and (3.12) indicate 𝑆𝜆𝑛24𝛽𝑡𝑢𝑛(𝑥)𝑌𝜎0(𝑁)𝜆𝐶𝑛24𝛽𝑡𝑁/2𝑝𝑢𝑛(𝑥)𝐿𝑝𝜎(𝑁)𝐶𝜆2𝛽𝑁/𝑝2𝛽𝜎𝜇𝑛1𝑡2𝑁/𝑝(𝑛)𝜆𝑛𝜇𝑁/𝑝+2𝛽𝜎.(3.14) From (3.3), we thus obtain that 𝑆𝜆𝑛24𝛽𝑡𝑢𝑛(𝑥)𝑌𝜎0(𝑁)𝐶𝑡2𝑁/𝑝𝑛10(3.15) as 𝑛. From (3.7) and the definition of 𝑤𝑛(𝑥), we have 𝑤𝑛𝑌𝜎0(𝑁)𝑗=𝑛+1𝜆𝑛𝜆𝑗𝜇𝑓𝜆𝑛𝜆𝑗2𝛽𝑌𝜎0(𝑁)𝑗=𝑛+1𝜆𝑛𝜆𝑗𝜇.(3.16)
Applying (2.9) to 𝑆(𝑡𝜆𝑛24𝛽)𝑤𝑛, we thus have 𝑆𝑡𝜆𝑛24𝛽𝑤𝑛𝑌𝜎0(𝑁)𝐶𝜆𝜇𝑛𝑗=𝑛+1𝜆𝑗+1𝜇𝐶𝑗=𝑛+12𝑗0(3.17) as 𝑛. Here we have used (3.3) and the fact that 0<𝜆𝑛22𝛽𝑡<1 for 𝑛>𝑁. At present, we want to verify the claim that, for 0𝑡<, 𝑆𝜆𝑛24𝛽𝑡𝑣𝑛𝑓𝑌𝜎0(𝑁)𝑛0.(3.18) In fact, if 0<𝑡<, then 𝑆𝜆𝑛24𝛽𝑡𝑣𝑛𝑓𝑌𝜎0(𝑁)sup|𝑥|𝑀1+|𝑥|2𝜎/2|||𝑆𝜆𝑛24𝛽𝑡𝑣𝑛|||(𝑥)𝑓(𝑥)+sup|𝑥|>𝑀1+|𝑥|2𝜎/2|||𝑆𝜆𝑛24𝛽𝑡𝑣𝑛(|||𝑥)+sup|𝑥|>𝑀1+|𝑥|2𝜎/2||||.𝑓(𝑥)(3.19) Notice that 𝑣𝑛=𝑓𝑌𝜎0𝑁.(3.20) Therefore, from Theorem 2.6, we have 𝑆𝜆𝑛24𝛽𝑡𝑣𝑛𝑌𝜎0𝑁.(3.21) So, for any 𝜀>0, from (2.35), (2.39), and (2.43), we get that if 𝑛>𝑁, there exists a constant 𝑀 independing on 𝑛 and 𝑡 such that sup|𝑥|>𝑀1+|𝑥|2𝜎/2|||𝑆𝜆𝑛24𝛽𝑡𝑣𝑛|||<𝜀(𝑥)3,sup|𝑥|>𝑀1+|𝑥|2𝜎/2||𝑓||<𝜀(𝑥)3.(3.22) The fact 𝑣𝑛=𝑓𝐶(𝑁) means that 𝑆(𝑡)𝑣𝑛[𝐶0,)×𝑁.(3.23) Therefore, for any 𝜀>0, there exists an 𝑁1>0 such that if 𝑛>𝑁1, then sup|𝑥|𝑀1+|𝑥|2𝜎/2|||𝑆𝜆𝑛24𝛽𝑡𝑣𝑛|||<𝜀(𝑥)𝑓(𝑥)3.(3.24)
So, from (3.19), (3.22), and (3.24), we thus obtain that 𝑆𝜆𝑛24𝛽𝑡𝑣𝑛𝑓𝑌𝜎0(𝑁)0(3.25) as 𝑛. From (3.9), (3.15), (3.17), and (3.18), we obtain that for any fixed 0<𝑡<, 𝐷𝜆𝜇,𝛽𝑛𝑆𝜆2𝑛𝑡𝑢0𝜆=𝑆𝑛22𝛽𝑡𝑢𝑛+𝑣𝑛+𝑤𝑛𝑛𝑓in𝑌𝜎0𝑁.(3.26) Equation (3.2) follows from (3.26) by setting 𝑡=1 and 𝑡𝑛=𝜆2𝑛. The proof of this theorem is complete.

Theorem 3.2. Let 𝜇>0, 𝜎0, and 𝛽>1/2. If 0<𝜇+2𝛽𝜎<𝑁,(3.27) then there exists an initial value 𝑢0𝑌𝜎0(𝑁) such that 𝜔𝜎𝜇,𝛽𝑢0=𝑌𝜎0𝑁.(3.28)

Remark 3.3. If 𝜎=0, the above results had been given by Cazenave et al. (see [15, Corollary 6.3]). So our results capture their results. Here we have used some of their ideas.

Proof. By (3.27), there exists a constant 𝑝>1 such that 𝑁𝜇+2𝛽𝜎<𝑝.(3.29) Therefore, there exists a countable dense subset 𝐹 of 𝑌𝜎0(𝑁) such that 𝐹𝑌𝜎0𝑁𝐿𝑝𝜎𝑁.(3.30) So, there exists a sequence {𝜑𝑗}𝑗1𝐹 such that (i)for any 𝜙𝐹, there exists a subsequence {𝜑𝑗𝑘}𝑘1 of the sequence {𝜑𝑗}𝑗1 satisfying 𝜑𝑗𝑘(𝑥)=𝜙𝑘1,(3.31)(ii)there exists a constant 𝐶>0 satisfying 𝜑max𝑗𝑌𝜎0(𝑁),𝜑𝑗𝐿𝑝𝜎(𝑁)𝐶𝑗for𝑗1.(3.32)Now we select a constant 𝑎>2(3.33) and then take 𝜆𝑗=𝑗𝑎if𝑗=1,max4𝑝/(𝑁𝑝(𝜇+2𝛽𝜎))𝜆(2𝛽𝑁𝑝(𝜇+2𝛽𝜎))/(𝑁𝑝(𝜇+2𝛽𝜎))𝑗1,2𝑗𝜆𝑗1𝑗1/𝜇if𝑗>1.(3.34) The initial-value 𝑢0 is given by 𝑢0(𝑥)=𝑗=1𝜆𝑗𝜇𝜑𝑗𝑥𝜆𝑗2𝛽=𝑗=1𝐷𝜆𝜇,𝛽𝑗1𝜑𝑗(𝑥).(3.35)
From (3.7), (3.32), and (3.34), we have 𝑢0𝑌𝜎0(𝑁)𝑗=1𝜆𝑗𝜇𝜑𝑗𝑌𝜎0(𝑁)𝐶𝑗=12𝑗𝐶.(3.36)
This means that the sequence (3.35) is convergent in 𝑌𝜎0(𝑁). So, 𝑢0𝑌𝜎0𝑁.(3.37) Similar to the proof of Theorem 2.2, we can prove that, for any 𝜙𝐹 and 0<𝑡<, there exists a sequence 𝜆𝑗𝑘 as 𝑘 such that 𝐷𝜆𝜇,𝛽𝑗𝑘𝑆𝜆2𝑗𝑘𝑡𝑢0𝜙in𝑌𝜎0𝑁(3.38) as 𝑘. Let 𝑡𝑛𝑘=𝜆𝑛1/2𝑘 and 𝑡=1 in (2.1); we thus have 𝐷𝜇,𝛽𝑡𝑗𝑘𝑆𝑡𝑗𝑘𝑢0𝜙in𝑌𝜎0𝑁.(3.39) Therefore, 𝐹𝜔𝜎𝜇,𝛽𝑢0𝑌𝜎0𝑁.(3.40) Notice that 𝐹 is dense in 𝑌𝜎0(𝑁) and that 𝜔𝜎𝜇,𝛽(𝑢0) is a closed subset of 𝑌𝜎0(𝑁). We thus obtain from (3.40) that 𝜔𝜎𝜇,𝛽𝑢0=𝑌𝜎0𝑁.(3.41) So we complete the proof of this theorem.

Remark 3.4. For any 0𝜎<𝑁, there exist constants 𝜇>0 and 𝛽>1/2 such that 0<𝜇+2𝛽𝜎<𝑁.(3.42)
Therefore, from Theorem 3.2, we can get that the weighted space 𝑌𝜎0(𝑁) provides a setting where complexity occurs in the asymptotic behavior of solutions for the problem (1.1).

Acknowledgment

This work is supported by the National Natural Science Foundation of China, the Specialized Research Fund for the Doctoral Program of Higher Education of China, the Scientific and Technological Projects of Chongqing Municipal Commission of Education.