On Spectral Homotopy Analysis Method for Solving Linear Volterra and Fredholm Integrodifferential Equations

Table 1

Numerical result of Example 5.1 against the HAM and the SHAM solutions whit ℎ=−0.85.

𝑥	SHAM			HAM			Numerical
	2nd order	4th order	5th order	2nd order	5th order	11th order
−0.8	−0.360376	−0.360001	−0.36000000	−0.370525	−0.360086	−0.36000000	−0.36000000
−0.6	−0.640699	−0.640003	−0.64000000	−0.658320	−0.640123	−0.64000000	−0.64000000
−0.4	−0.840976	−0.840005	−0.84000000	−0.860438	−0.840105	−0.84000000	−0.84000000
−0.2	−0.961198	−0.960005	−0.96000000	−0.979684	−0.960078	−0.96000000	−0.96000000
0.0	−1.001354	−1.000005	−1.00000000	−1.018938	−1.000066	−1.00000000	−1.00000000
0.2	−0.961421	−0.960005	−0.96000000	−0.978828	−0.960067	−0.96000000	−0.96000000
0.4	−0.841370	−0.840005	−0.84000000	−0.857858	−0.840073	−0.84000000	−0.84000000
0.6	−0.641159	−0.640004	−0.64000000	−0.654041	−0.64048	−0.64000000	−0.64000000
0.8	−0.360727	−0.360002	−0.36000000	−0.367054	−0.360011	−0.36000000	−0.36000000