Abstract
We introduce and analyze a relaxed extragradient-like viscosity iterative algorithm for finding a solution of a generalized mixed equilibrium problem with constraints of several problems: a finite family of variational inequalities for inverse strongly monotone mappings, a finite family of variational inclusions for maximal monotone and inverse strongly monotone mappings, and a fixed point problem of infinitely many nonexpansive mappings in a real Hilbert space. Under some suitable conditions, we derive the strong convergence of the sequence generated by the proposed algorithm to a common solution of these problems which also solves a variational inequality problem.
1. Introduction
Let be a real Hilbert space with inner product and norm , a nonempty closed convex subset of , and the metric projection of onto . Let be a nonlinear mapping on . We denote by the set of fixed points of and by the set of all real numbers. A mapping is called strongly positive on if there exists a constant such that A mapping is called -Lipschitz continuous if there exists a constant such that In particular, if , then is called a nonexpansive mapping; if , then is called a contraction.
Let be a nonlinear mapping on . We consider the following variational inequality problem (VIP) [1]: find a point such that The solution set of VIP (3) is denoted by .
In 1976, Korpelevič [2] proposed an iterative algorithm for solving the VIP (3) in Euclidean space : with a given number, which is known as the extragradient method. The literature on the VIP is vast and Korpelevich’s extragradient method has received great attention given by many authors. See, for example, [3–10] and references therein.
Let be a real-valued function, a nonlinear mapping, and a bifunction. In 2008, Peng and Yao [11] introduced the following generalized mixed equilibrium problem (GMEP): finding such that We denote the set of solutions of (5) by .
Throughout this paper, it is assumed as in [11] that is a bifunction satisfying conditions (H1)–(H4) and is a lower semicontinuous and convex function with restriction (H5), where(H1) for all ,(H2) is monotone, that is, for any ,(H3) is upper hemicontinuous, that is, for each , (H4) is convex and lower semicontinuous for each ,(H5)for each and , there exists a bounded subset and such that, for any , given a positive number . Let be the solution set of the auxiliary mixed equilibrium problem; that is, for each , In particular, whenever , is rewritten as .
Let be an infinite family of nonexpansive mappings on and a sequence of nonnegative numbers in . For any , define a mapping on as follows: Such a mapping is called the -mapping generated by and .
In 2010, for the case where , Yao et al. [12] proposed the following hybrid iterative algorithm: where is a contraction, is differentiable and strongly convex, , , and , are given, for finding a common element of the set and the fixed point set of an infinite family of nonexpansive mappings on . They proved the strong convergence of the sequence generated by the hybrid iterative algorithm (10) to a point under some appropriate conditions. This point also solves the following optimization problem: where is the potential function of .
On the other hand, let be a single-valued mapping of into and a set-valued mapping with . Consider the following variational inclusion: find a point such that We denote by the solution set of the variational inclusion (11). In particular, if , then . If , then problem (11) becomes the inclusion problem introduced by Rockafellar [13]. Let a set-valued mapping be maximal monotone. We define the resolvent operator associated with and as follows: where is a positive number.
In 1998, Huang [14] studied problem (11) in the case where is maximal monotone and is strongly monotone and Lipschitz continuous with . Subsequently, Zeng et al. [15] further studied problem (11) in the case which is more general than Huang’s one [14].
Inspired by the above facts, we introduce and analyze an iterative algorithm by relaxed extragradient-like viscosity method for finding a solution of a generalized mixed equilibrium problem with constraints of several problems: a finite family of variational inequalities for inverse strongly monotone mappings, a finite family of variational inclusions for maximal monotone and inverse strongly monotone mappings, and a fixed point problem of infinitely many nonexpansive mappings in a real Hilbert space. Under some suitable conditions, we derive the strong convergence of the sequence generated by the proposed algorithm to a common solution of these problems. Such solution also solves a variational inequality problem. Several special cases are also discussed. The results presented in this paper are the supplement, extension, improvement, and generalization of the previously known results in this area.
2. Preliminaries
Throughout this paper, we assume that is a real Hilbert space whose inner product and norm are denoted by and , respectively. Let be a nonempty closed convex subset of . We write to indicate that the sequence converges weakly to and to indicate that the sequence converges strongly to . Moreover, we use to denote the weak -limit set of the sequence ; that is,
Definition 1. A mapping is called(i)monotone if
(ii)-strongly monotone if there exists a constant such that
(iii)-inverse strongly monotone if there exists a constant such that
It is easy to see that the projection is -ism. Inverse strongly monotone (also referred to as cocoercive) operators have been applied widely in solving practical problems in various fields.
Definition 2. A differentiable function is called(i)convex, if
where is the Frechet derivative of at ;(ii)strongly convex, if there exists a constant such that
It is easy to see that if is a differentiable strongly convex function with constant then is strongly monotone with constant .
The metric (or nearest point) projection from onto is the mapping which assigns to each point the unique point satisfying the property
Some important properties of projections are gathered in the following proposition.
Proposition 3. For given and ,(i);(ii);(iii), for all . (This implies that is nonexpansive and monotone.)
By using the technique of [16], we can readily obtain the following elementary result.
Proposition 4 (see [17, Lemma 1 and Proposition 1]). Let be a nonempty closed convex subset of a real Hilbert space and let be a lower semicontinuous and convex function. Let be a bifunction satisfying the conditions (H1)–(H4). Assume that(i) is strongly convex with constant and the function is weakly upper semicontinuous for each ;(ii)for each and , there exists a bounded subset and such that, for any , Then the following hold:(a)for each ,(b) is single valued,(c) is nonexpansive if is Lipschitz continuous with constant and where for ,(d)for all and (e),(f) is closed and convex.In particular, whenever is a bifunction satisfying the conditions (H1)–(H4) and , for all , then that is, for any , ( is firmly nonexpansive) and In this case, is rewritten as . If, in addition, , then is rewritten as .
Remark 5. Suppose is strongly convex with constant and is Lipschitz continuous with constant . Then is -strongly monotone and -Lipschitz continuous with positive constants . Utilizing Proposition 4 () we obtain that, for all and ,
We need some facts and tools in a real Hilbert space which are listed as lemmas below.
Lemma 6. Let be a real inner product space. Then there holds the following inequality:
Lemma 7. Let be a real Hilbert space. Then the following hold:(a) for all ;(b) for all and with ;(c)if is a sequence in such that , it follows that
We have the following crucial lemmas concerning the -mappings defined by (9).
Lemma 8 (see [18, Lemma 3.2]). Let be a sequence of nonexpansive self-mappings on such that and let be a sequence in for some . Then, for every and the limit exists, where is defined by (9).
Lemma 9 (see [18, Lemma 3.3]). Let be a sequence of nonexpansive self-mappings on such that , and let be a sequence in for some . Then, .
Lemma 10 (see [19, Demiclosedness Principle]). Let be a nonempty closed convex subset of a real Hilbert space . Let be a nonexpansive self-mapping on . Then is demiclosed. That is, whenever is a sequence in weakly converging to some and the sequence strongly converges to some , it follows that . Here is the identity operator of .
Lemma 11. Let be a monotone mapping. In the context of the variational inequality problem the characterization of the projection (see Proposition 3 ()) implies
Lemma 12 (see [20]). Let and be bounded sequences in a real Banach space and a sequence in with . Suppose Then, .
Lemma 13 (see [21]). Assume that is a sequence of nonnegative real numbers such that where is a sequence in and is a real sequence such that(i);(ii) or .Then .
Recall that a set-valued mapping is called monotone if, for all , and imply A set-valued mapping is called maximal monotone if is monotone and for each , where is the identity mapping of . We denote by the graph of . It is known that a monotone mapping is maximal if and only if, for , for every implies . Next we provide an example to illustrate the concept of maximal monotone mapping.
Let be a monotone, -Lipschitz-continuous mapping and let be the normal cone to at ; that is, Define Then, is maximal monotone and if and only if ; see [13].
Assume that is a maximal monotone mapping. Let . In terms of Huang [14], there holds the following property for the resolvent operator .
Lemma 14. is single valued and firmly nonexpansive; that is,
Consequently, is nonexpansive and monotone.
Lemma 15 (see [9]). Let be a maximal monotone mapping with . Then, for any given , is a solution of problem (11) if and only if satisfies
Lemma 16 (see [15]). Let be a maximal monotone mapping with and let be a strongly monotone, continuous, and single-valued mapping. Then, for each , the equation has a unique solution for .
Lemma 17 (see [9]). Let be a maximal monotone mapping with and a monotone, continuous, and single-valued mapping. Then for each . In this case, is maximal monotone.
Lemma 18 (see [22, Lemma 2.8]). Let be a bounded sequence of nonnegative real numbers and a sequence of real numbers such that . Then, .
3. Main Results
We will introduce and analyze an iterative algorithm by relaxed extragradient-like viscosity method for finding a solution of a generalized equilibrium problem with constraints of several problems: a finite family of variational inclusions, a finite family of variational inequalities, and a fixed point problem in a real Hilbert space. Under appropriate conditions imposed on the parameter sequences we will prove strong convergence of the proposed algorithm.
Theorem 19. Let be a nonempty closed convex subset of a real Hilbert space . Let and be two integers. Let be a bifunction from to satisfying (H1)–(H4) and a lower semicontinuous and convex functional. Let be a maximal monotone mapping and let , , and be -inverse strongly monotone, -inverse strongly monotone, and -inverse strongly monotone, respectively, where and . Let be a sequence of nonexpansive mappings on and a sequence in for some . Let be a -strongly positive bounded linear operator with and a -contraction with . Let be the -mapping defined by (9). Assume that . Define − and for each and . Let , and be three sequences in . Assume that(i) is strongly convex with constant and its derivative is Lipschitz continuous with constant such that the function is weakly upper semicontinuous for each ,(ii)for each , there exist a bounded subset and such that, for any , (iii) and ,(iv) and ,(v) + ,(vi) and . Given arbitrarily, the sequence is generated iteratively by where and for each and . If and is firmly nonexpansive, then where is a unique solution in to the VIP
Proof. As , , and , we may assume, without loss of generality, that , and for all . Put
for each and , and , where is the identity mapping on . Moreover, set and .
Since is a -strongly positive bounded linear operator on , we know that
Taking into account that for all , we have
That is, is positive. It follows that
In the meantime, it is not hard to find that and are nonexpansive. As a matter of fact, observe that, for all ,
In addition, note that
That is, is strongly monotone and Lipschitz continuous. So, there exists a unique solution in to the VIP
That is, .
We divide the rest of the proof into several steps.
Step 1. We show that is bounded. Indeed, take arbitrarily. Since , is -inverse strongly monotone, and , we have, for any ,
Since , , and is -inverse strongly monotone, where , , by Proposition 3 we obtain that for each
Since , , and is -inverse strongly monotone, where , , by Lemma 14 we deduce that for each
Hence from (37)–(49), we have
Since is a -contraction with , from (37) and (50) we get
By induction, we get
Therefore, is bounded and so are the sequences , , , , and .
Step 2. We show that and . Indeed, put . Then it follows from conditions (iii) and (iv) that
and hence
Define
Observe that
and hence