Abstract

We study the existence of multiple solutions for a fourth-order nonlinear boundary value problem. We give some new criteria for guaranteeing that the fourth-order elastic beam equation with a perturbed term has at least three solutions. The proof is based on some three critical points theorems of B. Ricceri. Furthermore, numerical simulations are also presented.

1. Introduction

In this paper, we consider the following elastic beam equation with nonlinear boundary conditions: where , are two positive parameters, , are two -Carathéodory’s functions, and is real function. This kind of problem arises in the study of deflections of elastic beams on nonlinear elastic foundations. The problem has the following physical description: a thin flexible elastic beam of length is clamped at its left end and resting on an elastic device at its right end , which is given by . Then, the problem models the static equilibrium of the beam under a load, along its length, characterized by and . The derivation of the model can be found in [1, 2].

In recent years, fourth-order boundary value problems modeling bending equilibria of elastic beams have been extensively studied by many researchers. We refer the reader to [18]. Some of them are concerned with nonlinear equations with null boundary conditions; see [36]. Others are concerned with nonlinear equations with nonzero or nonlinear boundary conditions, which can model beams resting on elastic bearings located in their extremities; see, for instance, [1, 2, 7, 8] and the references therein.

Let us briefly comment the known results related to problem (1). In [2], Ma studied the existence of positive solutions for problem (1) with and using mountain pass theorem. Later, Yang et al. [8] considered the existence of two solutions for problem (1) with , which are generated by the function . Very recently, Li and Sun [9] obtained the existence of infinitely many solutions for problem (1) with and by using the fountain theorem.

Motivated by the above works, in the present paper, we establish some existence results of three solutions for problem (1) under rather different assumptions on functions , , and . We require that satisfies the asymptotically linear or sublinear conditions at infinity on . The proof is based on some three critical points theorems due to Ricceri. It is worth noting that these critical points theorems have been extensively applied in the study of the existence of solutions for nonlinear differential equations; see [1013].

The remainder of this paper is organized as follows. In Section 2, some preliminary results are presented. In Section 3, we give the proofs of our main results. In addition, some numerical simulations are presented at the end of the paper.

2. Variational Setting and Preliminaries

If is a real Banach space, denote by the class of all functionals possessing the following property: if is a sequence in converging weakly to and , then has a subsequence converging strongly to .

For example, if is uniformly convex and is a continuous, strictly increasing function, then, by a classical result, the functional belongs to the class .

Theorem 1 (see [14]). Let be a separable and reflexive real Banach space; let be a coercive, sequentially weakly lower semicontinuous   functional, belonging to , bounded on each bounded subset of and whose derivative admits a continuous inverse on ; a functional with compact derivative. Assume that has a strict local minimum with . Finally, setting assume that .
Then, for each compact interval (with the conventions , there exists with the following property: for every and every functional with compact derivative, there exists such that, for each , has at least three solutions in whose norms are less than .

The following two results of Ricceri guarantee the existence of three solutions for a given equation.

Theorem 2 (see [15]). Let be a reflexive real Banach space; an interval; let be a sequentially weakly lower semicontinuous functional, bounded on each bounded subset of , whose derivative admits a continuous inverse on ; a functional with compact derivative. Assume that for all , and that there exists such that Then, there exist a nonempty open set and a positive number with the following property: for every and every functional with compact derivative, there exists such that, for each , has at least three solutions in whose norms are less than .

Proposition 3 (see [16]). Let be a nonempty set and , two real functions on . Assume that there are and , such that Then, for each satisfying one has

Now, we begin describing the variational formulation of problem (1), which is based on the function space where is the Sobolev space of all functions such that and its distributional derivative are absolutely continuous and belongs to . Then, is a Hilbert space equipped with the inner product and norm where denotes the standard -norm. In addition, is compactly embedded in the spaces and , and, therefore, there exist immersion constants ,   , such that

We recall that is an -Carathéodory function if(a)the mapping is measurable for every ;(b)the mapping is continuous for almost every ;(c)for every there exists a function such that for almost every .

Definition 4. One says that a function is a weak solution of problem (1) if holds for any .

In order to study problem (1), we will use the functionals , , and defined by putting respectively, for every , where, By the continuity of   , we get that functional is a continuous Gâteaux differential functional whose Gâteaux derivative is the functional , given by for any , . Since , are two -Carathéodory functions, it implies that and are well defined and continuously Gâteaux differentiable in . More precisely, their Gâteaux derivatives are respectively, for every , .

Lemma 5. Assume that the following condition holds: (H1) are nondecreasing on and , for any .
Then, is sequentially weakly lower semicontinuous, bounded on each bounded subset of , and its derivative admits a continuous inverse.

Proof. Obviously, is weakly lower semicontinuous in . Therefore, it suffices to show that is weakly continuous in . In fact, if and in , converges uniformly to on . Then, there exists such that Therefore, we have where . Thus, is weakly continuous. Therefore, is weakly lower semicontinuous in .
Moreover, let be a bounded subset of ; that is, there exists a constant such that for . Then, Hence, is bounded on each bounded subset of .
Next, we show that admits a continuous inverse. For any , by , we have So, ; that is, is coercive.
For any , by , one has So, is uniformly monotone. By [17, Theorem ], we have that exists and is continuous.

Remark 6. If is replaced by the following condition: are odd and nondecreasing on .
Then, we can obtain the same conclusion.

Lemma 7. and are continuously Gateaux differentiable in and their derivatives are compact.

Proof. It is easy to verify that and are continuously Gâteaux differentiable in . Now, we proof that their derivatives are compact.
For any , , Let as in . Then, in . Since is continuous in , one has as . So as . That is, is strongly continuous on , which implies that is a compact operator by [17, Proposition 26.2]. Moreover, is continuous since it is strongly continuous.
Analogously, we have that is a compact operator for any .

3. Main Results

In this section, we establish the main abstract results of this paper. Put

Theorem 8. Suppose that is an -Carathéodory function and (or ) holds. Moreover, assume that the following conditions hold: there exists a constant such that there exists a function satisfying and
such that Then, for each compact interval , there exists with the following property: for every and for any -Carathéodory function , there exists such that, for each , problem (1) has at least three weak solutions whose norms are less than .

Proof. Obviously, is a separable and uniformly convex Banach space. By Lemmas 5 and 7, we obtain that is a continuous Gâteaux derivative, sequentially weakly lower semicontinuous, bounded on each bounded subset of , and its derivative admits a continuous inverse; , are the Gâteaux derivative functionals whose derivatives are compact. It is clear that (see the beginning of Section 2). Now, we show that . For a sequence , if and , in view of the weak continuity of , one has . Thus, has a subsequence converging strongly to . Therefore, . Moreover, is coercive and has a strict local minimum with .
In view of , there exist , with such that for any and with . Since is a -Carathéodory function, is bounded on and with ; we can choose and in such a way that for all . So, by (12), one has for all . Hence, using and (31), we have Furthermore, using (29) again, for each , we obtain So, we get Combining (32) with (34), one has By , , and (35), we have Then, for each compact interval , there exists with the following property: for every and for any -Carathéodory function , there exists such that, for each , problem (1) has at least three weak solutions whose norms are less than .

Theorem 9. Suppose that is an -Carathéodory function, , and (or holds. Furthermore, assume that the following conditions hold: there exist two functions and satisfying and two positive constants , with such that for all and ; there exist , and a positive constant such that , for all .
Then, there exist a nonempty open set and a positive number with the following property: for every and for any -Carathéodory function , there exists such that, for each , problem (1) has at least three weak solutions whose norms are less than .

Proof. Obviously, . For any and , by and , we have Since , one has for all .
For each and , we have ; that is, Therefore, Define the function From condition , it is easy to verify that and Choose ; then, using (43) and , we have . Furthermore, using , , (35), and (43), we have Therefore, we can fix such that From Proposition 3, we obtain Therefore, using Theorem 2, for each compact interval , there exists with the following property: for every and for any -Carathéodory function , there exists such that, for each , has at least three solutions in . Hence, problem (1) has at least three weak solutions whose norms are less than .

Remark 10. Clearly, Theorem 9 gives the result of at least three solutions for problem (1) with being of sublinear growth.

4. Numerical Solutions

In this section, we consider a numerical algorithm for the problem (1) using the finite differences method. Let be a discretization of the interval with mesh size . Then, putting and and using central differences formula, the first equation of problem (1) becomes . Taking into account the boundary conditions of problem (1), we infer that Then, we can compute by solving the nonlinear system , with Since the system is nonlinear, we use a linearization through an initial approximation and iterative methods for solving it. The quantities are updated after each iteration.

Let and fix . Choose a satisfying all conditions. Using as initial approximation and mesh size , it is easy to obtain the approximate solution with by the Gauss-Seidel method.

Conflict of Interests

The author declares that there is no conflict of interests regarding the publication of this paper.

Acknowledgment

Q. Gao was supported by the Humanities and Social Sciences Foundation of the Ministry of Education in China (Grant no. 13YJAZH112).