Research Article | Open Access

Yong-Hong Fan, Lin-Lin Wang, "Sufficient and Necessary Conditions for the Permanence of a Discrete Model with Beddington-DeAngelis Functional Response", *Abstract and Applied Analysis*, vol. 2014, Article ID 740895, 9 pages, 2014. https://doi.org/10.1155/2014/740895

# Sufficient and Necessary Conditions for the Permanence of a Discrete Model with Beddington-DeAngelis Functional Response

**Academic Editor:**Chun-Lei Tang

#### Abstract

We give a sufficient and necessary condition for the permanence of a discrete model with Beddington-DeAngelis functional response with the form = / where , and are periodic sequences with the common period is nonnegative; , and are positive. It is because of the difference between the comparison theorem for discrete system and its corresponding continuous system that an additional condition should be considered. In addition, through some analysis on the limit case of this system, we find that the sequence has great influence on the permanence.

#### 1. Introduction

Many mathematical models have been established to describe the relationships between the species and the outer environment or among the different species in biomathematics. The dynamics of the growth of a population can be described if the functional behavior of the rate of growth is known. Of course, it is this functional behavior which is usually measured in the laboratory or in the field. Among the relationships between the species living in the same outer environment, the predator-prey theory plays an important and fundamental role. The dynamic relationship between predators and their prey has long been and will continue to be one of the dominant themes in both ecology and mathematical ecology due to its universal existence and importance. These problems may appear to be simple mathematically at first sight; they are, in fact, very challenging and complicated. Though most predator-prey theories are based on continuous models governed by differential equations, the discrete time models are more appropriate than the continuous ones when the size of the population is rarely small or the population has nonoverlapping generations. On the other hand, the concept of permanence has played an important role in mathematical ecology. Biologically, when a system of interacting species is persistent in a suitable sense, it means that all the species survive in the long term. For investigations on permanence of discrete predator-prey models, one can refer to [1â€“3] and references cited therein.

In 2006, Cui and Takeuchi studied the permanence, extinction, and periodic solutions for a predator-prey model with Beddington-DeAngelis functional response (see [4]); they gave a sufficient and necessary condition to guarantee the predator and prey to be permanent. As we all know, the continuous dynamic system and its corresponding discrete dynamic system, in some extent, have some similar properties, but also they have many differences. In this paper, we want to study the permanence for the following discrete predator-prey model with Beddington-DeAngelis functional response: where , and are periodic sequences with the common period is nonnegative; , and are positive. The reason and significance for the analysis on the properties of these biological models could be found in [5, 6]. The system (1) can be seen as the discrete form of the continuous situation which has been investigated in [4]. And the discretization method could be found in [7].

As usual, we define the average value of periodic sequences with period as and we denote where .

In order to describe our main results, we need some lemmas below.

Lemma 1. *If for all and , then has at least one nonnegative periodic solution . Moreover, if , then for all and if , then . Moreover, if , then the zero solution is globally asymptotically stable for any positive initial condition.*

*Proof. *The existence conclusion could be found in [8]. Now we only prove the globally asymptotical stability. That is, we consider the case . Notice that
which implies that
Therefore
where represents the integer part of ; thus if , then . If , by (4), we have
which implies that all the subsequences of are monotonically decreasing. Notice that they all have a lower bounded zero; thus, there exists some nonnegative constant such that . We claim that all . If all , then ; for sufficiently large, we have . While (7) implies that
this contradiction shows that there exists at least one such that
and then (4) implies that all . The proof is complete.

*Remark 2. *This lemma is different from the continuous one; here the condition can not support the globally asymptotical stability of (from the work of May [9] and Zhang and Zhou [10]). In addition, we can find that the continuous form of this lemma plays an important role in the proof of the permanence in [4].

Lemma 3. *Assume that and are all -periodic sequences and is positive; if and the following inequality
**
holds, then any solution for the periodic equation with positive initial condition has the property
**
where is defined as that in Lemma 1.*

*Proof. *By Lemma 1, we know that exists, and it is positive; for any positive solution of the equation
denote
and then satisfies
Define , and then
Notice that
and here we use the inequality ; thus for any positive solution of (12), we have
and by (10), we know that
In particular, . Then equality (15) implies that ; that is, is nonincreasing; thus it converges, by (14), . The proof is complete.

*Remark 4. *In [11], Professor Zhou considered the existence and stability of the periodic solution of the equation . Here and are all positive -periodic sequences; under the condition
the conclusion of Lemma 3 is satisfied. By Lemma 3, the condition (19) can be replaced by
Notice that if , then the condition (19) can be simplified as
In fact, in this case, by the work of Zhang and Zhou [10], the condition (21) could be generalized to
It is worthy to say that, when , the conclusion of Lemma 3 is false. This is quite different from the corresponding continuous case. In particular, if , then (10) could be replaced by (22).

For the permanence of (1), we have the following.

Theorem 5. *Assume that and are all -periodic sequences and is positive; if
**
and hold true, then the system (1) is permanent and has at least one positive periodic solution provided that
**
where is the unique periodic solution of given by Lemma 1.*

Theorem 6. *Suppose that
**
and (23) hold; if (1) is permanent, then (24) is true.*

By Theorems 5 and 6, we can easily obtain the following.

Corollary 7. *Assume that and are all -periodic sequences and is positive; if (23) and hold true, then system (1) is permanent if and only if (24) holds.*

#### 2. Proof of the Main Results

In this section, we will give the proofs of Theorems 5 and 6. First we give some lemmas.

Lemma 8. *Under the condition (25), there exist two positive constants and such that
**
for any solution of (1) with positive initial conditions.*

*Proof. *Notice that, for any positive initial value, from mathematical induction, we can obtain that . Then we have
Notice that
If we let
then by (27) and (28), we have
If there exists some positive integer such that for , then . If there exists some positive integer such that for , then (30) implies that the sequence converges to zero, which shows that ; thus also hold true. If the sequence oscillates about zero, let be the first element of the th positive semicycle of the sequence ; then from (30), we have
and therefore
and from the above analysis, we can obtain
From the second equation of (1), we have
If does not oscillate about , then from (34) we have
Otherwise, if we let be the first element of the th positive semicycle of the sequence , then from (34), we know that
and by (35) and (36), we have
The proof is complete.

Lemma 9. *Assume that (25) holds true, then there exists a positive constant such that
**
for any solution of (1) with positive initial conditions.*

*Proof . *We prove it by contradiction. If (38) is false, then for every , there exists a solution with initial condition such that
Choose sufficiently small positive constants and such that
From (39), for any given , there exists a positive integer such that
Equation (42) shows that there exists a sufficiently large such that
Then the second equation of (1) now yields
and by (40), we have
This implies that the subsequence of is monotonically decreasing; thus it is convergent; by (45),
Notice that is bounded; thus by (44), using mathematical induction, we can easily obtain
and thus there exists a sufficiently large such that
therefore the first equation of (1) yields
By (41), utilizing Lemma 1, we know that the equation has at least one positive -periodic solution called . It is obvious that is independent of . Let
then
If does not oscillate about zero, then
which implies that when is large enough,

If oscillates about zero, let be the first element of the th negative semicycle of the sequence ; then from (51), we know that
Notice that
and thus when is sufficiently large,
Inequalities (53) and (56) imply that when is sufficiently large, . Since is independent of , then
and this contradicts (42). The proof is complete.

Lemma 10. *Assume that (25), (24), and (23) hold true; then there exists a positive constant such that
**
for any solution of (1) with positive initial values.*

*Proof. *If (58) is not true, then, for any , there exists a positive initial value which may be dependent on such that
where is the solution of (1) with positive initial values .

By (25) and (24), we can choose the constant and sufficiently small such that
From (59), we can choose sufficiently large such that ; then the first equation of (1) implies that
By (61) and Lemmas 1 and 3, the following equation
has a unique positive -periodic solution for any sufficiently small positive number and
We claim that, for any , there exists a sufficiently large such that
In fact, by (62) and (63), if we set
where the sequence is the solution of (63) with initial condition , then
Thus
Denote
and then (68) implies that
Notice that
and by (23), we have
Define a function
Then
From (70), we can obtain . By (73), (74), and (72), we know that
which implies that
Under condition (23), by Lemma 3, we have
and then (64), (77), and (76) imply that (65) holds. Now the second equation of (1) yields
and thus (60) shows that
This contradicts (59). The proof is complete.

Lemma 11. *Assume that (25) holds true; then there is a positive constant such that
**
for any solution of (1) with positive initial conditions.*

*Proof. *If (80) is false, then there exists an initial value such that
for any , where represents the solution of (1) with initial value . Thus, there is a subsequence of such that
On the other hand, by Lemma 9, there exists a constant (which is independent of the initial value ) such that
Notice that, for any , there exists a which satisfies , (82), and (83). Choose sufficiently large such that
Obviously, such exists. Fixing it, and by the first equation of (1), we know
and by mathematical induction, we can easily obtain
and this contradicts (83). The proof is complete.

Lemma 12. *Assume that (25), (24), and (23) hold true, then there exists a positive constant such that
**
for any solution of (1) with positive initial values.*

*Proof. *If (87) is false, then for any , there exist an initial value and a positive integer sequence such that
where represents the solution of (1) with initial value .

From the proof of Lemma 10, we can find that, for any , when is sufficiently large, ,
here is sufficiently large. On the other hand, by Lemma 10, there also exist a constant (which is independent to ) and a subsequence of such that

The rest of the proof is similar to that of Lemma 11; we omit it here.

*Proof of Theorem 5. *By Lemmas 8, 11, and 12, we can easily obtain it.

*Proof of Theorem 6. *Assume that (1) is permanent; then there exist two constants and such that
for simplicity, the inequality holds true only for sufficiently large ; we omit the explanation of the domain for in what follows. Choose sufficiently small such that
Consider the following equation:
by (93) and Lemma 3, (94) has a unique positive solution which is globally asymptotically stable. Obviously,
In addition, . Notice that
Thus
If
then (98) implies that
this is a contradiction.

If