Predicting the Ultimate Bearing Capacity of Bolts with an Optimized Function Model

Table 2

Model parameters for example 1.

Bolt	AH	CH	IE	IEPF
A1	a = −5.45	a = −5.77	a = 0.07	a = −16.79
A2	b = 5.70	b = 11.39	k = −0.63	b = 0.09
	a = 22.45	c = −0.02	a = 2.1 × 10^−3	c = −1.96
	b = 4.21	a = 7.51	k = −0.99	k = −302.10
		b = −0.85		a = 0.13
		c = −1.46		b = 5.48
				c = 0.89
				k = −0.98