Determining the Geometrical Sizes of Plates with Internal Hinges by Using Additional Conditions

Table 6

With precision, using the bisection method, obtained solutions and size values of corresponding to both Cases 1 and 2 ( is the number of iterations).

Cases
1			2	0.34592					2	0.34592
			2.5	0.29672					2.3	0.31587
			3	0.25203					2.6	0.28742
			3.5	0.21192					2.9	0.26060
	1	0.31523	3.34239	0.22406					3.2	0.23543
	2	0.04077	3.32843	0.22516					3.5	0.21192
	3	0.54886	3.33473	0.22467		1		0.53769	3.33869	0.22435
	4	0.21550	3.34074	0.22419		2		0.01649	3.33641	0.22453
	5	0.77388	3.33608	0.224559
2			2	0.52485					2	0.52486
			2.5	0.44800					2.3	0.47790
			3	0.37827					2.6	0.43347
			3.5	0.31582					2.9	0.39164
	1	0.32042	3.33979	0.33504					3.2	0.35242
	2	0.04127	3.32577	0.33675					3.5	0.31582
	3	0.53826	3.33224	0.33596		1		0.54680	3.33596	0.33551
	4	0.16465	3.33854	0.33519		2		0.01649	3.3340	0.33578
		5	0.83065	3.33331	0.335829