Abstract

We establish new oscillation criteria for second-order delay differential equations with mixed nonlinearities of the form (𝑝(𝑡)𝑥(𝑡))+𝑛𝑖=1𝑝𝑖(𝑡)𝑥(𝑡𝜏𝑖)+𝑛𝑖=1𝑞𝑖(𝑡)|𝑥(𝑡𝜏𝑖)|𝛼𝑖sgn𝑥(𝑡𝜏𝑖)=𝑒(𝑡),𝑡0, where 𝑝(𝑡), 𝑝𝑖(𝑡), 𝑞𝑖(𝑡), and 𝑒(𝑡) are continuous functions defined on [0,), and 𝑝(𝑡)>0, 𝑝(𝑡)0, and 𝛼1>>𝛼𝑚>1>𝛼𝑚+1>>𝛼𝑛>0. No restriction is imposed on the potentials 𝑝𝑖(𝑡), 𝑞𝑖(𝑡), and 𝑒(𝑡) to be nonnegative. These oscillation criteria extend and improve the results given in the recent papers. An interesting example illustrating the sharpness of our results is also provided.

1. Introduction

We consider the second-order delay differential equations containing mixed nonlinearities of the form 𝑝(𝑡)𝑥(𝑡)+𝑛𝑖=1𝑝𝑖(𝑡)𝑥𝑡𝜏𝑖+𝑛𝑖=1𝑞𝑖||(𝑡)𝑥(𝑡𝜏𝑖)||𝛼𝑖sgn𝑥𝑡𝜏𝑖=𝑒(𝑡),𝑡0.(1.1)

In what follows we assume that 𝜏𝑖0, 𝑝𝐶1[0,), 𝑝(𝑡)>0,𝑝(𝑡)0,𝑝𝑖,𝑞𝑖,𝑒𝐶[0,), 𝛼1>>𝛼𝑚>1>𝛼𝑚+1>>𝛼𝑛>0(𝑛>𝑚1), and 01𝑝(𝑡)𝑑𝑡=.(1.2)

As usual, a solution 𝑥(𝑡) of (1.1) is called oscillatory if it is defined on some ray [𝑇,) with 𝑇0 and has arbitrary large zeros, otherwise, it is called nonoscillatory. Equation (1.1) is called oscillatory if all of its extendible solutions are oscillatory.

Recently, Mustafa [1] has studied the oscillatory solutions of certain forced Emden-Fowler like equations 𝑥||||(𝑡)+𝑎(𝑡)𝑥(𝑡)𝜆sgn𝑥(𝑡)=𝑒(𝑡),𝑡𝑡01.(1.3) Sun and Wong [2], as well as Sun and Meng [3] have established oscillation criteria for the second-order equation 𝑝(𝑡)𝑥(𝑡)+𝑞(𝑡)𝑥(𝑡)+𝑛𝑖=1𝑞𝑖||||(𝑡)𝑥(𝑡)𝛼𝑖sgn𝑥(𝑡)=𝑒(𝑡),𝑡0.(1.4) Later in [4], Li and Chen have extended (1.4) to the delay differential equation 𝑝(𝑡)𝑥(𝑡)+𝑞(𝑡)𝑥(𝑡𝜏)+𝑛𝑖=1𝑞𝑖||||(𝑡)𝑥(𝑡𝜏)𝛼𝑖sgn𝑥(𝑡𝜏)=𝑒(𝑡),𝑡0.(1.5) As it is indicated in [2, 3], further research on the oscillation of equations of mixed type is necessary as such equations arise in mathematical modeling, for example, in the growth of bacteria population with competitive species. In this paper, we will continue in the direction to study the oscillatory properties of (1.1). We will employ the method in study of Kong in [5] and the arithmetic-geometric mean inequality (see [6]) to establish the interval oscillation criteria for the unforced (1.1) and forced (1.1), which extend and improve the known results. Our results are generalizations of the main results in [3, 4]. We also give an example to illustrate the sharpness of our main results.

2. Main Results

We need the following lemma proved in [2, 3] for our subsequent discussion.

Lemma 2.1. For any given 𝑛-tuple {𝛼1,𝛼2,,𝛼𝑛} satisfying 𝛼1>𝛼2>>𝛼𝑚>1>𝛼𝑚+1>>𝛼𝑛>0, there corresponds an n-tuple {𝜂1,𝜂2,,𝜂𝑛} such that 𝑛𝑖=1𝛼𝑖𝜂𝑖=1,(a) which also satisfies either 𝑛𝑖=1𝜂𝑖<1,0<𝜂𝑖<1,(b) or 𝑛𝑖=1𝜂𝑖=1,0<𝜂𝑖<1.(c)

For a given set of exponents {𝛼𝑖} satisfying 𝛼1>𝛼2>>𝛼𝑚>1>𝛼𝑚+1>>𝛼𝑛>0, Lemma 2.1 ensures the existence of an 𝑛-tuple {𝜂1,𝜂2,,𝜂𝑛} such that either (a) and (b) hold or (a) and (c) hold. When 𝑛=2 and 𝛼1>1>𝛼2>0, in the first case, we have 𝜂1=1𝛼21𝜂0𝛼1𝛼2,𝜂2=𝛼11𝜂01𝛼1𝛼2,(2.1) where 𝜂0 can be any positive number satisfying 0<𝜂0<(𝛼11)/𝛼1. This will ensure that 0<𝜂1, 𝜂2<1, and conditions (a) and (b) are satisfied. In the second case, we simply solve (a) and (c) and obtain 𝜂1=1𝛼2𝛼1𝛼2,𝜂2=𝛼11𝛼1𝛼2.(2.2)

Following Philos [7], we say that a continuous function 𝐻(𝑡,𝑠) belongs to a function class 𝒟𝑎,𝑏, denoted by 𝐻𝒟𝑎,𝑏, if 𝐻(𝑏,𝑠)>0,𝐻(𝑠,𝑎)>0 for 𝑏>𝑠>𝑎, and 𝐻(𝑡,𝑠) has continuous partial derivatives 𝜕𝐻(𝑡,𝑠)/𝜕𝑡 and 𝜕𝐻(𝑡,𝑠)/𝜕𝑠 in [𝑎,𝑏]×[𝑎,𝑏]. Set 1(𝑡,𝑠)=𝜕𝐻(𝑡,𝑠)/𝜕𝑡2𝐻(𝑡,𝑠),2(𝑡,𝑠)=𝜕𝐻(𝑡,𝑠)/𝜕𝑠2.𝐻(𝑡,𝑠)(2.3)

Based on Lemma 2.1, we have the following interval criterion for oscillation of (1.1).

Theorem 2.2. If, for any 𝑇0, there exist 𝑎1, 𝑏1, 𝑐1, 𝑎2,𝑏2 and 𝑐2 such that 𝑇𝑎1<𝑐1<𝑏1𝑎2<𝑐2<𝑏2,𝑝𝑖𝑎(𝑡)0,𝑡1𝜏𝑖,𝑏1𝑎2𝜏𝑖,𝑏2𝑞,𝑖=1,2,,𝑛,𝑖(𝑎𝑡)0,𝑡1𝜏𝑖,𝑏1𝑎2𝜏𝑖,𝑏2𝑒𝑎,𝑖=1,2,,𝑛,(𝑡)0,𝑡1𝜏𝑖,𝑏1𝑎,𝑒(𝑡)0,𝑡2𝜏𝑖,𝑏2,(2.4) and there exist 𝐻𝑗𝒟𝑎𝑗,𝑏𝑗 such that 1𝐻𝑗𝑐𝑗,𝑎𝑗𝑐𝑗𝑎𝑗𝑄𝑗(𝑠)𝐻𝑗𝑠,𝑎𝑗𝑝(𝑠)2𝑗1𝑠,𝑎𝑗+1𝑑𝑠𝐻𝑗𝑏𝑗,𝑐𝑗𝑏𝑗𝑐𝑗𝑄𝑗(𝑠)𝐻𝑗𝑏𝑗,𝑠𝑝(𝑠)2𝑗2𝑏𝑗,𝑠𝑑𝑠>0,(2.5) for 𝑗=1,2, where 𝑗1, 𝑗2 are defined as in (2.3), 𝜂1,𝜂2,,𝜂𝑛 are positive constants satisfying (a) and (b) in Lemma 2.1, 𝜂0=1𝑛𝑖=1𝜂𝑖, and 𝑄𝑗(𝑡)=𝑛𝑖=1𝑝𝑖(𝑡)𝑡𝑎𝑗𝑡𝑎𝑗+𝜏𝑖+𝜂01||||𝑒(𝑡)𝜂0𝑛𝑖=1𝜂𝑖1𝑞𝑖(𝑡)𝜂𝑖𝑡𝑎𝑗𝑡𝑎𝑗+𝜏𝑖𝛼𝑖𝜂𝑖,(2.6) then (1.1) is oscillatory.

Proof. Let 𝑥(𝑡) be a nonoscillatory solution of (1.1). Without loss of generality, we may assume that 𝑥(𝑡)>0 for all 𝑡𝑡1𝜏0, where 𝑡1 depends on the solution 𝑥(𝑡) and 𝜏=max{𝜏𝑖}, 𝑖=1,,𝑛. When 𝑥(𝑡) is eventually negative, the proof follows the same argument by using the interval [𝑎2,𝑏2] instead of [𝑎1,𝑏1]. Choose 𝑎1,𝑏1𝑡1 such that 𝑝𝑖(𝑡),𝑞𝑖(𝑡)0, 𝑒(𝑡)0 for 𝑡[𝑎1𝜏𝑖,𝑏1], and 𝑖=1,2,,𝑛.
From (1.1), we have that 𝑥(𝑡)0 for 𝑡[𝑎1𝜏𝑖,𝑏1]. If not, there exists 𝑡2[𝑎1𝜏𝑖,𝑏1] such that 𝑥(𝑡2)<0. Because 𝑝(𝑡)𝑥(𝑡)0,(2.7) we have 𝑝(𝑡)𝑥(𝑡)𝑝(𝑡2)𝑥(𝑡2). Integrating from 𝑡2 to 𝑡, we obtain 𝑡𝑥(𝑡)𝑥2𝑡+𝑝2𝑥𝑡2𝜏𝑡21𝑝(𝑠)𝑑𝑠.(2.8) Noting the assumption (1.2), we have 𝑥(𝑡)0 for sufficient large 𝑡. This is a contradiction with 𝑥(𝑡)>0. From (2.7) and the conditions 𝑝(𝑡)>0, 𝑝(𝑡)0, we obtain 𝑥(𝑡)0 for 𝑡[𝑎1𝜏𝑖,𝑏1].
Employing the convexity of 𝑥(𝑡), we obtain 𝑥𝑡𝜏𝑖𝑥(𝑡)𝑡𝑎1𝑡𝑎1+𝜏𝑖𝑎,𝑡1,𝑏1.(2.9)
Define 𝑝𝜔(𝑡)=(𝑡)𝑥(𝑡).𝑥(𝑡)(2.10)
Recall the arithmetic-geometric mean inequality 𝑛𝑖=0𝜂𝑖𝑢𝑖𝑛𝑖=0𝑢𝜂𝑖𝑖,𝑢𝑖0,(2.11) where 𝜂0=1𝑛𝑖=1𝜂𝑖 and 𝜂𝑖>0, 𝑖=1,2,,𝑛, are chosen according to the given 𝛼1,𝛼2,,𝛼𝑛 as in Lemma 2.1 satisfying (a) and (b). Let 𝑢0(𝑡)=𝜂01||||𝑒(𝑡),𝑢𝑖(𝑡)=𝜂𝑖1𝑞𝑖𝑥(𝑡)𝑡𝜏𝑖𝛼𝑖.(2.12) We have 𝜔(𝑡)=(𝑝(𝑡)𝑥(𝑡))+𝜔𝑥(𝑡)2(𝑡)=𝑝(𝑡)𝑛𝑖=1𝑝𝑖(𝑡)𝑥𝑡𝜏𝑖+𝑛𝑖=1𝑞𝑖𝑥(𝑡)𝑡𝜏𝑖𝛼𝑖𝑒(𝑡)+𝜔𝑥(𝑡)2(𝑡)𝑝(𝑡)𝑛𝑖=1𝑝𝑖(𝑡)𝑡𝑎1𝑡𝑎1+𝜏𝑖+𝜂01||||𝑒(𝑡)𝜂0𝑛𝑖=1𝜂𝑖1𝑞𝑖(𝑡)𝜂𝑖𝑥𝛼𝑖𝜂𝑖𝑡𝜏𝑖+𝜔𝑥(𝑡)2(𝑡)=𝑝(𝑡)𝑛𝑖=1𝑝𝑖(𝑡)𝑡𝑎1𝑡𝑎1+𝜏𝑖+𝜂01||||𝑒(𝑡)𝜂0𝑛𝑖=1𝜂𝑖1𝑞𝑖(𝑡)𝜂𝑖𝑥𝛼𝑖𝜂𝑖𝑡𝜏𝑖𝑛𝑖=1𝑥𝛼𝑖𝜂𝑖+𝜔(𝑡)2(𝑡)𝑝(𝑡)𝑛𝑖=1𝑝𝑖(𝑡)𝑡𝑎1𝑡𝑎1+𝜏𝑖+𝜂01||||𝑒(𝑡)𝜂0𝑛𝑖=1𝜂𝑖1𝑞𝑖(𝑡)𝜂𝑖𝑡𝑎1𝑡𝑎1+𝜏𝑖𝛼𝑖𝜂𝑖+𝜔2(𝑡)𝑝(𝑡)=𝑄1(𝜔𝑡)+2(𝑡).𝑝(𝑡)(2.13)
Multiplying both sides of (2.13) by 𝐻1(𝑏1,𝑡)𝒟𝑎1,𝑏1 and integrating by parts, we find that 𝑐𝜔1𝐻1𝑏1,𝑐1𝑏1𝑐1𝑄1(𝑠)𝐻1𝑏1,𝑠𝑝(𝑠)212𝑏1,𝑠𝑑𝑠.(2.14) That is, 𝑐𝜔11𝐻1𝑏1,𝑐1𝑏1𝑐1𝑄1(𝑠)𝐻1𝑏1,𝑠𝑝(𝑠)212𝑏1,𝑠𝑑𝑠.(2.15)
On the other hand, multiplying both sides of (2.13) by 𝐻1(𝑡,𝑎1)𝒟𝑎1,𝑏1 and integrating by parts, we can easily obtain 𝜔𝑐11𝐻1𝑐1,𝑎1𝑐1𝑎1𝑄1(𝑠)𝐻1𝑠,𝑎1𝑝(𝑠)211𝑠,𝑎1𝑑𝑠.(2.16)
Equations (2.15) and (2.16) yield 1𝐻1𝑐1,𝑎1𝑐1𝑎1𝑄1(𝑠)𝐻1𝑠,𝑎1𝑝(𝑠)211𝑠,𝑎1+1𝑑𝑠𝐻1𝑏1,𝑐1𝑏1𝑐1𝑄1(𝑠)𝐻1𝑏1,𝑠𝑝(𝑠)212𝑏1,𝑠𝑑𝑠0,(2.17) which contradicts (2.5) for 𝑗=1. The proof of Theorem 2.2 is complete.

Remark 2.3. When 𝜏1==𝜏𝑛=0, Σ𝑛𝑖=1𝑝𝑖(𝑡)=𝑞(𝑡), the conditions 𝑞(𝑡)0 for 𝑡[𝑎1,𝑏1][𝑎2,𝑏2], 𝑝(𝑡)0 and (1.2) can be removed. Therefore, Theorem 2.2 reduces to Theorem 1 in [3].

Remark 2.4. When 𝜏1==𝜏𝑛=𝜏, Σ𝑛i=1𝑝𝑖(𝑡)=𝑞(𝑡), Theorem 2.2 reduces to Theorem 1 in [4] for which the conditions 𝑞(𝑡)0 for 𝑡[𝑎1𝜏,𝑏1][𝑎2𝜏,𝑏2],𝑝(𝑡)0 and (1.2) are needed. There are some mistakes in the proof of Theorem 1 in [4].

The following theorem gives an oscillation criterion for the unforced (1.1).

Theorem 2.5. If, for any 𝑇0, there exist 𝑎, 𝑏, and 𝑐 such that 𝑇𝑎<𝑐<𝑏, 𝑝𝑖(𝑡)0, and 𝑞𝑖(𝑡)0 for 𝑡[𝑎𝜏𝑖,𝑏],𝑖=1,2,,𝑛, and there exists 𝐻𝒟𝑎,𝑏, such that 1𝐻(𝑐,𝑎)𝑐𝑎𝐻(𝑠,𝑎)𝑄(𝑠)𝑝(𝑠)211(𝑠,𝑎)𝑑𝑠+𝐻(𝑏,𝑐)𝑏𝑐𝐻(𝑏,𝑠)𝑄(𝑠)𝑝(𝑠)22(𝑏,𝑠)𝑑𝑠>0,(2.18) where 𝑄(𝑡)=𝑛𝑖=1𝑝𝑖(𝑡)𝑡𝑎𝑡𝑎+𝜏𝑖+𝑛𝑖=1𝜂𝑖1𝑞𝑖(𝑡)𝜂𝑖𝑡𝑎𝑡𝑎+𝜏𝑖𝛼𝑖𝜂𝑖,(2.19)𝜂1,𝜂2,,𝜂𝑛 are positive constants satisfying (a) and (c) in Lemma 2.1, and 1, 2 are defined as in (2.3), then the unforced (1.1) is oscillatory.

Proof. Let 𝑥(𝑡) be a nonoscillatory solution of (1.1). Without loss of generality, we may assume that 𝑥(𝑡)>0 for all 𝑡𝑡1𝜏0, where 𝑡1 depends on the solution 𝑥(𝑡) and 𝜏=max{𝜏𝑖}, 𝑖=1,,𝑛. Similar to the proof in Theorem 2.2, we can obtain 𝑥𝑡𝜏𝑖𝑥(𝑡)𝑡𝑎𝑡𝑎+𝜏𝑖[].,𝑡𝑎,𝑏(2.20) Define 𝑝𝜔(𝑡)=(𝑡)𝑥(𝑡).𝑥(𝑡)(2.21) Recall the arithmetic-geometric mean inequality 𝑛𝑖=1𝜂𝑖𝑢𝑖𝑛𝑖=1𝑢𝜂𝑖𝑖,𝑢𝑖0,(2.22) where 𝜂𝑖>0, 𝑖=1,2,,𝑛, are chosen according to the given 𝛼1,𝛼2,,𝛼𝑛 as in Lemma 2.1 satisfying (a) and (c). Let 𝑢𝑖=𝜂𝑖1𝑞𝑖𝑥(𝑡)𝑡𝜏𝑖𝛼𝑖.(2.23) We can obtain 𝜔(𝑡)=(𝑝(𝑡)𝑥(𝑡))+𝜔𝑥(𝑡)2(𝑡)=𝑝(𝑡)𝑛𝑖=1𝑝𝑖(𝑡)𝑥𝑡𝜏𝑖+𝑛𝑖=1𝑞𝑖𝑥(𝑡)𝑡𝜏𝑖𝛼𝑖+𝜔𝑥(𝑡)2(𝑡)𝑝(𝑡)𝑛𝑖=1𝑝𝑖(𝑡)𝑡𝑎𝑡𝑎+𝜏𝑖+𝑛𝑖=1𝜂𝑖1𝑞𝑖(𝑡)𝜂𝑖𝑥𝛼𝑖𝜂𝑖𝑡𝜏𝑖+𝜔𝑥(𝑡)2(𝑡)=𝑝(𝑡)𝑛𝑖=1𝑝𝑖(𝑡)𝑡𝑎𝑡𝑎+𝜏𝑖+𝑛𝑖=1𝜂𝑖1𝑞𝑖(𝑡)𝜂𝑖𝑥𝛼𝑖𝜂𝑖𝑡𝜏𝑖𝑛𝑖=1𝑥𝛼𝑖𝜂𝑖+𝜔(𝑡)2(𝑡)𝑝(𝑡)𝑛𝑖=1𝑝𝑖(t)𝑡𝑎𝑡𝑎+𝜏𝑖+𝑛𝑖=1𝜂𝑖1𝑞𝑖(𝑡)𝜂𝑖𝑡𝑎𝑡𝑎+𝜏𝑖𝛼𝑖𝜂𝑖+𝜔2(𝑡)𝜔𝑝(𝑡)=𝑄(𝑡)+2(𝑡).𝑝(𝑡)(2.24)
Multiplying both sides of (2.24) by 𝐻(𝑏,𝑡)𝒟𝑎,𝑏 and integrating by parts, we obtain 𝑏𝑐𝐻(𝑏,𝑡)𝜔(𝑡)𝑑𝑡𝑏𝑐𝐻(𝑏,𝑡)𝑄(𝑡)𝑑𝑡+𝑏𝑐𝜔𝐻(𝑏,𝑡)2(𝑡)𝑝(𝑡)𝑑𝑡,𝐻(𝑏,𝑐)𝜔(𝑐)𝑏𝑐𝐻(𝑏,𝑡)𝑄(𝑡)𝑑𝑡+𝑏𝑐𝜔𝐻(𝑏,𝑡)2(𝑡)𝑝(𝑡)2𝜔(𝑡)2(𝑏,𝑡)=𝐻(𝑏,𝑡)𝑑𝑡𝑏𝑐𝐻(𝑏,𝑡)𝑄(𝑡)𝑝(𝑡)22(𝑏,𝑡)𝑑𝑡+𝑏𝑐𝐻(𝑏,𝑡)𝑝(𝑡)𝜔(𝑡)𝑝(𝑡)2(𝑏,𝑡)2𝑑𝑡𝑏𝑐𝐻(𝑏,𝑡)𝑄(𝑡)𝑝(𝑡)22(𝑏,𝑡)𝑑𝑡.(2.25) It follows that 1𝜔(𝑐)𝐻(𝑏,𝑐)𝑏𝑐𝐻(𝑏,𝑡)𝑄(𝑡)𝑝(𝑡)22(𝑏,𝑡)𝑑𝑡.(2.26) On the other hand, multiplying both sides of (2.24) by 𝐻(𝑡,𝑎)𝒟𝑎,𝑏 and integrating by parts, we have 1𝜔(𝑐)𝐻(𝑐,𝑎)𝑐𝑎𝐻(𝑡,𝑎)𝑄(𝑡)𝑝(𝑡)21(𝑡,𝑎)𝑑𝑡.(2.27) Equations (2.26) and (2.27) yield 1𝐻(𝑐,𝑎)𝑐𝑎𝐻(𝑡,𝑎)𝑄(𝑡)𝑝(𝑡)211(𝑡,𝑎)𝑑𝑡+𝐻(𝑏,𝑐)𝑏𝑐𝐻(𝑏,𝑡)𝑄(𝑡)𝑝(𝑡)22(𝑏,𝑡)𝑑𝑡<0,(2.28) which contradicts (2.24). The proof of Theorem 2.5 is complete.

Remark 2.6. When 𝜏1==𝜏𝑛=0, Σ𝑛𝑖=1𝑝𝑖(𝑡)=𝑞(𝑡), the conditions 𝑞(𝑡)0 for 𝑡[𝑎,𝑏], 𝑝(𝑡)0 and (1.2) can be removed. Therefore, Theorem 2.5 reduces to Theorem 2 in [3].

Remark 2.7. When 𝜏1==𝜏𝑛=𝜏, Σ𝑛𝑖=1𝑝𝑖(𝑡)=𝑞(𝑡), Theorem 2.5 reduces to Theorem 2 in [4] for which the conditions 𝑞(𝑡)0 for 𝑡[𝑎𝜏,𝑏], 𝑝(𝑡)0 and (1.2) are needed.

3. Example

In this section, we provide an example to illustrate our results.

Consider the following equation: 𝑥(|||𝑥𝜋𝑡)+𝑘sin𝑡𝑡8|||𝛼1𝜋sgn𝑥𝑡8|||𝑥𝜋+𝑙cos𝑡𝑡4|||𝛼2𝜋sgn𝑥𝑡4=𝑚cos2𝑡,𝑡0,(3.1) where 𝑘, 𝑙, 𝑚 are positive constants, 𝛼1>1, and 0<𝛼2<1. Here 𝑝(𝑡)=1,𝑝1(𝑡)=𝑝2(𝑡)=0,𝑞1(𝑡)=𝑘sin𝑡,𝑞2𝜏(𝑡)=𝑙cos𝑡,1=𝜋8,𝜏2=𝜋4,𝑒(𝑡)=𝑚cos2𝑡.(3.2)

According to the direct computation, we have 𝑄𝑗(𝑡)=𝑘0||||cos2𝑡𝜂0(sin𝑡)𝜂1(cos𝑡)𝜂2𝑡𝑎𝑗𝑡𝑎𝑗+𝜏1𝛼1𝜂1𝑡𝑎𝑗𝑡𝑎𝑗+𝜏2𝛼2𝜂2,𝑗=1,2,(3.3) where 𝑘0=(𝜂01/𝑚)𝜂0(𝜂11/𝑘)𝜂1(𝜂21/𝑙)𝜂2,𝜂0 can be any positive number satisfying 0<𝜂0<(𝛼11)/𝛼1, and 𝜂1, 𝜂2 satisfy (2.1). For any 𝑇0, we can choose 𝑎1=2𝑖𝜋,𝑎2=𝑏1𝜋=2𝑖𝜋+4,𝑏2𝜋=2𝑖𝜋+2,𝑐1𝜋=2𝑖𝜋+8,𝑐2=2𝑖𝜋+3𝜋8,(3.4) for 𝑖=0,1,, and 𝐻1(𝑡,𝑠)=𝐻2(𝑡,𝑠)=(𝑡𝑠)2. By simple computation, we obtain 𝑗1(𝑡,𝑠)=𝑗2(𝑡,𝑠)=1, 𝑗=1,2. From Theorem 2.2, we have that (3.1) is oscillatory if 2𝑖𝜋+𝜋/82𝑖𝜋𝑄1(𝑠)(𝑠2𝑖𝜋)2𝑑𝑠+2𝑖𝜋+𝜋/42𝑖𝜋+𝜋/8𝑄1𝜋(𝑠)2𝑖𝜋+4𝑠2𝜋𝑑𝑠>4,2𝑖𝜋+3𝜋/82𝑖𝜋+𝜋/4𝑄2𝜋(𝑠)𝑠2𝑖𝜋42𝑑𝑠+2𝑖𝜋+𝜋/22𝑖𝜋+3𝜋/8𝑄2𝜋(𝑠)2𝑖𝜋+2𝑠2𝜋𝑑𝑠>4.(3.5) If 𝐻1(𝑡,𝑠)=𝐻2(𝑡,𝑠)=sin2(𝑡𝑠), by simple computation, we obtain 𝑗1(𝑡,𝑠)=𝑗2(𝑡,𝑠)=cos(𝑡𝑠) for 𝑗=1,2. From Theorem 2.2, we have that (3.1) is oscillatory if 2𝑖𝜋+𝜋/82𝑖𝜋𝑄1(𝑠)(𝑠2𝑖𝜋)2𝑑𝑠+2𝑖𝜋+𝜋/42𝑖𝜋+𝜋/8𝑄1𝜋(𝑠)2𝑖𝜋+4𝑠2𝜋𝑑𝑠>+1628,2𝑖𝜋+3𝜋/82𝑖𝜋+𝜋/4𝑄2𝜋(𝑠)𝑠2𝑖𝜋42𝑑𝑠+2𝑖𝜋+𝜋/22𝑖𝜋+3𝜋/8𝑄2𝜋(𝑠)2𝑖𝜋+2𝑠2𝜋𝑑𝑠>+1628.(3.6)

Acknowledgments

The authors would like to thank the referees for their valuable comments which have led to an improvement of the presentation of this paper. This project is supported by the National Natural Science Foundation of China (10771118) and STPF of University in Shandong Province of China (J09LA04).