|†Assuming use of wood as biomass for pulp and cellulose mills.|
§Assuming use of pulpwood as biomass for energy; these data do not include energy in nonpulp products (bark and limbs), which might be used when energy is the principal output.
UEV for evapotranspiration = 3.10E4 sej J−1 , evapotranspiration = (7,796 mm ha−1) * (1.00E4 L mm−1 ha) * (1 kg L−1) * (4.94E3 J kg−1).
Topsoil loss based on the organic matter content = (5.4E4 kcal kg−1 OM) * (1,28% OM)* (4.17E3 J Kcal−1) * (2.4E5 sej J−1 ) = 7.18E11 sej kg−1.
Diesel UEV and emergy content  = (1.32E8 J galão−1) * (1 gallon 3.8 L−1) * (1.1E5 sej J−1) = 3.85E7 sej L−1.
(4) UEV for machinery depreciation = (6.7E9 sej g−1),  after , Per kg = (6.7E9 sej g−1) * (1,000 g kg−1) = 6.70E12 sej kg−1.
(5) UEV for labor 4.5E6 sej J−1, by , energy of human labor = (231.8 h) * (2500 kcal dia−1) * (day 8 h−1) * (4,186 J kcal−1) = 3.03E8 J.
(6) UEVs: K2O = 2.92E9 sej g−1 K  * 83%K K2O−1, P2O5 = 2.99E10 sej g−1 P  * 43,7% P , N = 7,7E9 sej g−1 N , 06-30-10 has 6% N, 30% P2O5 and 10% K2O; and 14-00-15 has 14% N and 15% K2O.
(7) Based on the UEV of pesticides 2.49E10 sej g−1 * 1000 g kg−1 .
(8) UEV: K2O = 2.92E9 sej g−1 K  * 1,000 g kg−1, KCl * 63% K2O KCl−1 * 83% K-K2O−1.
(9) UEV of a seedling is 1.6E11 sej, from .
(10) Water potential chemical energy (4,94E3 J kg−1) multiply by irrigation UEV (4,28E5 sej J−1,  = 1.26E9 sej kg−1 or 1.26E9 sej L−1 H2O.
(11) Lime UEV (1.68E10 sej g−1) .
(12) Yield = (41.5 m3 ha−1 ano−1) * (7 years) = 290.5 m3 ha−1.
(13) Wood energy content = (290.5 m3 ha−1) * (495 kg m−3) * (1.5E7 J kg−1) = 2.16E12 J ha−1, energy content  from .
* considered the purchased loss of diesel oil as 783.50 L ha−1 because it was accounted for to support two trucks for repair and fuel used together for two harvester and forwarders.