Abstract

Using elementary methods, the following results are obtained:(I) If p is prime, 0mn, 0<b<apnm, and pab, then (apnbpm)(1)p1(apbnm)(modpn); If r, s are the roots of x2=AxB, where (A,B)=1 and D=A24B>0, if un=rnsnrs, vn=rn+sn, and k0, then (II) vkpnvkpn1(modpn); (III) If p is odd and pD, then ukpn(Dp)ukpn1(modpn); (IV) uk2n(1)Buk2n1(mod2n).