Abstract

W. Freedman introduced an alternate to the Dunford-Pettis property, called the DP1 property, in 1997. He showed that for 1p<, (α𝒜Xα)p has the DP1 property if and only if each Xα does. This is not the case for (α𝒜Xα). In fact, we show that (α𝒜Xα) has the DP1 property if and only if it has the Dunford-Pettis property. A similar result also holds for vector-valued continuous function spaces.