Abstract
By introducing some parameters, we establish generalizations of the Hilbert-type inequality. As applications, the reverse and its equivalent form are considered.
1. Introduction
Considerable attention has been given to Hilbert inequalities and Hilbert-type inequalities by several authors including Gao and Yang [1], Yang [2–4], Jichang and Debnath [5], Pachpatte [6], Zhao [7], Brnetić and Pečarić [8]. In 2007, Li et al. [9] gave a new inequality similar to Hilbert inequality for integrals:
If , then one has
where constant factor 4 is the best possible.
An equivalent inequality is
In this paper, by introducing some parameters we generalize (1.1), (1.2), and we obtain the reverse form for each of them. The equivalent forms are also considered.
2. Main Results
Lemma 2.1. Suppose that , define
weight functions , ,
respectively as
One
has
Proof. Letting ,
we have
By symmetry we have
The lemma is proved.
Lemma 2.2. Let , , and setting
Then for
one gets
Proof. Letting ,
we have
Now, observe that
then
We get
On the other hand,
Hence, (2.5) is valid. The lemma is proved.
Theorem 2.3. Let , , , If , , then one has
where constant factor is the best possible. In particular, for inequality (2.11) reduces to
Proof. Applying Hölder’s inequality and Lemma 2.1, we have
If (2.13)
takes the form of equality, then there exist constants and ,
such that they are not all zero, and
a.e. in .
It follows that there exists a constant , such that
Without lose of generality, suppose ,
then we have
which contradicts the fact that hence (2.13) takes the form of strict
inequality, so we obtain (2.11).
Assume that the
constant factor in (2.11) is not the best possible, then there
exists a positive number (with ) such that (2.11)
is still valid if one replaces by .
In particular, for , setting and as for , , for then we have
By using Lemma 2.2, we find
Therefore, we get
or
For it
follows that This contradicts the fact that Hence, the constant factor in (2.11) is the best
possible. Theorem 2.3 is proved.
Theorem 2.4. Let , , , If , , then one has
where the constant factor is the best possible. In particular, for the inequality reduces to
Proof. Applying reverse Hölder’s inequality and the same arguments as before, we have (2.21).
If the
constant factor in (2.21) is not the best possible, then there
exists a positive number (with ), such that (2.21)
is still valid if one replaces by .
In particular, for , setting and as in Theorem 2.3, we have
By using Lemma 2.2, we find
Therefore, we get
for and it
follows that This contradicts the fact that Hence, the constant factor in (2.21) is the best
possible. Theorem 2.4 is proved.
Theorem 2.5. If , , , , then one has
where the constant factor is the best possible. Inequality (2.26) is
equivalent to (2.11).
Proof. Setting
then by (2.11), we find
Hence, we obtain
Thus, by (2.11), both (2.28) and (2.29) keep the form of strict
inequalities, then we have (2.26).
Applying Hölder’s inequality, we have
Therefore, by (2.26) we have (2.11). It follows that inequality
(2.26) is equivalent to (2.11), and the
constant factors in (2.26) are the
best possible. The theorem is proved.
Theorem 2.6. If , , , , then one has
where the constant factor is the best possible. Inequality (2.31) is equivalent to (2.21).
The proof of Theorem 2.6 is similar to that of Theorem 2.5, so we omit it.
Acknowledgment
The author would like to thank the anonymous referees for their suggestions and corrections.