Abstract

The traveling wave solution of a hyperbolic model for chemotaxis in one space dimension is studied in this paper. By using some transformations of dependent variables and independent variables, we apply the tanh method and improved tanh method to the model, from which some traveling wave solutions in explicit form are presented.

1. Introduction

Chemotaxis is a widespread phenomenon in biological systems describing the response of individuals to an external chemical together with its gradient. It has attracted significant interest due to its critical role in a wide range of biological phenomena. Chemotaxis was studied mathematically beginning with the early papers of Patlak [1] and Keller and Segel [2, 3]. Since then the mathematical literature on the modeling of chemotaxis has grown rapidly. The parabolic Keller-Segel model of chemotaxis [2] has proved a cornerstone for much of this work. For a review of the recent literature, see Hillen and Painter [4]. However, the parabolic Keller-Segel model allows arbitrarily large speed of the population, it is physically unrealistic for small time. Motivated by the fact, Hillen and Stevens [5] proposed a hyperbolic model for chemotaxis in 1-D, which deal with finite speed. The model is𝑢+𝑡+𝛾(𝑆,𝑆𝑡,𝑆𝑥)𝑢+𝑥=𝜇+𝑆,𝑆𝑡,𝑆𝑥𝑢++𝜇𝑆,𝑆𝑡,𝑆𝑥𝑢,𝑢𝑡𝛾(𝑆,𝑆𝑡,𝑆𝑥)𝑢𝑥=𝜇+𝑆,𝑆𝑡,𝑆𝑥𝑢+𝜇𝑆,𝑆𝑡,𝑆𝑥𝑢,𝜏𝑆𝑡=𝐷0𝑆𝑥𝑥+𝑓𝑆,𝑢++𝑢,𝜏0,(1.1) where 𝑢±(𝑥,𝑡) denotes the particle densities of right (+)/left (−) moving particles, 𝛾(𝑆,𝑆𝑡,𝑆𝑥) denotes the particle speed, and 𝜇±(𝑆,𝑆𝑡,𝑆𝑥) are turning rates (rates of change of direction from + to − and vice versa).𝑆(𝑥,𝑡) denotes the concentration of the chemical external signal. The production and degradation of the external chemical signal is modeled by the reaction term 𝑓.

For the special case with 𝐷=0, constant speed 𝛾 and 𝜇± depending only on 𝑆 and 𝑆𝑥,𝑢+𝑡+𝛾𝑢+𝑥=𝜇+𝑆,𝑆𝑥𝑢++𝜇𝑆,𝑆𝑥𝑢,𝑢𝑡𝛾𝑢𝑥=𝜇+𝑆,𝑆𝑥𝑢+𝜇𝑆,𝑆𝑥𝑢,𝑆𝑡=𝑓𝑆,𝑢++𝑢.(1.2) Segel in [9] first used it to analyze a very specific scenario. Later Rivero et al. [6] and Ford et al. [7, 8] used it to describe experimental data. In the works [59], the issues of local and global in time existence of solutions were considered theoretically and numerically. Hillen and Levine [10] studied finite time blowup of the system (1.2) with𝑢𝑓=𝑆++𝑢,(1.3) and three specific forms of turning rates, one of which is𝜇±𝑆,𝑆𝑥=𝛾2𝐷1𝛼𝛾𝑆𝑆𝑥.(1.4)

Keller and Segel in 1971 [11] considered an experimental setup that results in visible bands of bacteria traveling up a capillary tube filled with a mixture of oxygen and nutrient rich substrate. It raised the question of existence of a traveling wave solution to the Keller-Segel model of chemotaxis. Liu in 2008 [12] constructed some explicit solutions of the system (1.2) with the choice of 𝑓 and 𝜇± as in (1.3) and (1.4).

In this paper, we try to find some exact traveling wave solutions of the system𝑢+𝑡+𝛾𝑢+𝑥=𝜇+𝑆,𝑆𝑥𝑢++𝜇𝑆,𝑆𝑥𝑢,𝑢𝑡𝛾𝑢𝑥=𝜇+𝑆,𝑆𝑥𝑢+𝜇𝑆,𝑆𝑥𝑢,𝑆𝑡=𝐷0𝑆𝑥𝑥+𝑓𝑆,𝑢++𝑢,(1.5) where 𝐷00,𝛾>0 are constants, 𝑓(𝑆,𝑢++𝑢) and 𝜇±(𝑆,𝑆𝑥) are defined above (1.3) and (1.4). It is clear that system (1.5) is a special case of the system (1.1) and a more generalized case of (1.2).

The system (1.5) can be transformed into an equivalent system for the total particle density, 𝑢=𝑢++𝑢, and particle flux, 𝑣=𝑢+𝑢. The resulting system for (𝑢,𝑣) is (3.1) below. Using tanh method and improved tanh method, we search for traveling wave solutions of the system (3.1). When 𝐷00, three different kinds of traveling wave solutions are found. To the best of our knowledge, those traveling wave solutions are new and have not appeared in literature. When 𝐷0=0, the solutions obtained here are different from those known ones in [12].

2. The Two Methods

The tanh method and improved tanh method are powerful techniques to search for traveling wave solutions arising from one dimensional nonlinear wave and evolution equations. Let us first review the main features of two methods. They will be used in this paper. For more details, see [1317] and reference therein.

For both methods, we first use the wave variable 𝜉=𝑘(𝑥𝑝𝑡)+𝜉0 to carry a PDE in two independent variables𝐻𝑢,𝑢𝑡,𝑢𝑥,𝑢𝑥𝑥,=0(2.1) into an ODE𝑄𝑢,𝑢,𝑢,=0,(2.2) where 𝑘 and 𝑝 are the wave number and the wave speed, respectively.

2.1. The tanh Method

In the standard tanh method, the tanh is used as a new variable and the solution of (2.2) is expressed as a finite series of tanh𝑢(𝜉)=𝑀𝑖=0𝑎𝑖𝑇𝑖,𝑇=tanh𝜉,(2.3) where 𝑀 is a positive integer that will be determined. Substituting (2.3) into the reduced ODE (2.2) results in an algebraic equation in powers of 𝑇. To determine the parameter 𝑀, we usually balance the linear terms of highest order in the resulting equation with the highest order nonlinear terms. With 𝑀 determined, we collect all coefficients of powers of 𝑇 in the resulting equation where these coefficients have to vanish. This will give a system of algebraic equations involving the parameters 𝑘,𝑝, and 𝑎𝑖. Having determined these parameters, we obtain an analytic solution 𝑢(𝑥,𝑡) in a closed form.

The tanh method is a computerizable method, in which generating an algebraic system and solving it are two key procedures and laborious to do by hand. But they can be implemented on a computer with the help of computer algebra software such as Mathematica.

2.2. The Improved tanh Method

The crucial point of the improved tanh method is to replace the tanh𝜉 in (2.3) by the solution of Riccati equation𝐹=𝐴+𝐵𝐹+𝐶𝐹2,𝐶0,(2.4) where =𝑑/𝑑𝜉, and 𝐴, 𝐵, 𝐶 are some constants.

Supposing that 𝐹 is a solution of (2.4), it is easy to verify(1)if 𝐵24𝐴𝐶>0, (2.4) possesses a solution 𝐵𝐹(𝜉)=2𝐶𝐵24𝐴𝐶2𝐶tanh𝐵24𝐴𝐶2𝜉;(2.5)(2)if 𝐵24𝐴𝐶=0, (2.4) possesses a solution 𝐵𝐹(𝜉)=12𝐶;𝐶𝜉(2.6)(3)if 𝐵24𝐴𝐶<0, (2.4) possesses a solution 𝐵𝐹(𝜉)=+2𝐶4𝐴𝐶𝐵22𝐶tan4𝐴𝐶𝐵22𝜉.(2.7)

Based on (2.5), the solution of (2.2) can be expressed as in (2.3), and based on (2.6) and (2.7), the solution of (2.2) can be expressed as𝑢(𝜉)=𝑀𝑖=0𝑎𝑖1𝜉𝑖,(2.8)𝑢(𝜉)=𝑀𝑖=0𝑎𝑖tan𝑖𝜉,(2.9) where parameters 𝑀,𝑘,𝑝, and 𝑎𝑖 are to be determined.

3. Traveling Wave Solutions

A transformation of the dependent variables is necessary, before the just-described methods can be applied to the hyperbolic model (1.5). As in [10], we rewrite system (1.5) as a system for 𝑢=𝑢++𝑢 and 𝑣=𝑢+𝑢:𝑢𝑡+𝛾𝑣𝑥𝑣=0,𝑡+𝛾𝑢𝑥=𝛾𝐷1𝛼𝑆𝑥𝑆𝛾𝑢2𝐷1𝑆𝑣,𝑡=𝐷0𝑆𝑥𝑥+𝑆𝑢.(3.1) Eliminating 𝑣 in system (3.1), it is clear that (3.1) is of the form1𝛾𝑢𝑡𝑡+𝛾𝑢𝑥𝑥=𝛼𝛾𝐷1𝑢𝑆𝑥𝑆𝑥+𝛾𝐷1𝑢𝑡,𝑆𝑡=𝐷0𝑆𝑥𝑥+𝑆𝑢.(3.2) Taking into account the transformation𝑢=𝑢(𝜉),𝑆=𝑒𝜑(𝜉),𝜉=𝑘(𝑥𝑝𝑡)+𝜉0,(3.3) where 𝑘>0,𝑝>0, and 𝜉0 is an arbitrary constant, the (3.2) can be put into the format𝑘𝑝𝛾2𝛾𝑢=𝛼𝛾𝑘𝐷1𝑢𝜑+𝑢𝜑𝛾𝑝𝐷1𝑢,(3.4)𝑘𝑝𝜑=𝐷0𝑘2𝜑2+𝜑+𝑢,(3.5) where 𝑝2𝛾2.

3.1. Using tanh Method

Let𝑢(𝜉)=𝑀𝑖=0𝑎𝑖tanh𝑖𝜉.(3.6) It is noted that ||||tanh𝑥𝑑𝑥=lncosh𝑥+𝐶,tanh2𝑥𝑑𝑥=𝑥tanh𝑥+𝐶,tanh𝑘𝑥𝑑𝑥=tanh𝑘1𝑥+𝑘1tanh𝑘2𝑥𝑑𝑥,(3.7) as a result, we guess the 𝜑 has the form𝜑(𝜉)=𝑏2𝜉+𝑏1||||+lncosh𝜉𝑀2𝑖=0𝑏𝑖tanh𝑖𝜉.(3.8)

Substituting 𝑢(𝜉) and 𝜑(𝜉) into (3.4)-(3.5), we obtain 𝑀=2, and the solutions of system (3.4)-(3.5) is of the form𝑢=𝑎0+𝑎1tanh𝜉+𝑎2tanh2𝜉,𝜑=𝑏2𝜉+𝑏1||||.lncosh𝜉(3.9) With the help of the symbolic software Mathematica, substituting (3.9) into (3.4) and (3.5)and setting the coefficients of tanh𝑖𝜉 to be zero, we obtain2𝑘𝐷1𝛾2𝑝2𝑎2𝛼𝛾2𝑘𝑎1𝑏2+𝑎0𝑏1+𝛾2𝑝𝑎1=0,𝑘𝐷1𝛾2𝑝2𝑎1𝛼𝛾2𝑘𝑎2𝑏2+𝑎1𝑏1+𝛾2𝑝𝑎2=0,3𝑘2𝐷1𝛾2𝑝2+𝛼𝛾2𝑏1𝑎2=0,𝑘𝑝𝑏2+𝐷0𝑘2𝑏22+𝑏1+𝑎0=0,𝑘𝑝𝑏1+2𝐷0𝑘2𝑏2𝑏1+𝑎1𝐷=0,0𝑘2𝑏21𝑏1+𝑎2=0.(3.10) If 𝐷00 and 𝑝 satisfies𝛾Δ=2𝑝22𝐷214𝐷20+4𝛼𝐷0+5𝛼2𝛾+22𝑝2𝐷1𝛼3𝛾2𝛼2𝛾4𝐷0𝛼+𝐷0>0,(3.11) solving the algebraic equations (3.10) with the aid of Mathematica, we arrive at𝛾𝑘=2𝑝Δ2𝐷0𝐷1||4𝐷1𝛾2𝑝2+𝛼𝛾2𝛾2𝑝2||,𝑏1=2𝐷1𝛾2𝑝2𝛼𝛾2,𝑏2=1𝛼𝑘𝐷02𝑝𝐷0𝐷1𝛾2𝑝2+𝑝𝐷0𝛼𝛾2𝑝𝐷1𝛼𝛾2𝑝24𝐷1𝛾2𝑝2+𝛼𝛾2,𝑎0=2𝑘2𝐷0𝐷1𝛾2𝑝2𝛼𝛾2𝑝𝑝𝛼𝛾2𝐷0𝑝𝛼𝐷1𝛾2𝑝2+2𝑝𝐷0𝐷1𝛾2𝑝2𝛼𝐷0𝛼𝛾2+4𝐷1𝛾2𝑝2𝐷0𝑝𝛼𝛾2𝐷0𝑝𝛼𝐷1(𝛾2𝑝2)+2𝑝𝐷0𝐷1(𝛾2𝑝2)2𝛼2𝐷20𝛼𝛾2+4𝐷1(𝛾2𝑝2)2,𝑎1=2𝑘𝐷1𝛾2𝑝2×𝑝𝛼2𝛾2+2𝑝𝛼𝛾2𝐷0+2𝑝𝛼𝐷1𝛾2𝑝2+4𝑝𝐷0𝐷1𝛾2𝑝2𝛼2𝛾2𝛼𝛾2+4𝐷1𝛾2𝑝2,𝑎2=2𝑘2𝐷0𝐷1𝛾2𝑝2𝛼𝛾2+2𝐷1𝛾2𝑝2𝛼𝛾22,(3.12) which leads to the solutions of system (3.1)𝑢(𝑥,𝑡)=𝑎0+𝑎1tanh𝑘(𝑥𝑝𝑡)+𝜉0+𝑎2tanh2𝑘(𝑥𝑝𝑡)+𝜉0,||𝑆(𝑥,𝑡)=cosh𝑘(𝑥𝑝𝑡)+𝜉0||𝑏1𝑏exp2𝑘(𝑥𝑝𝑡)+𝜉0,𝑝𝑣(𝑥,𝑡)=𝛾𝑢(𝑥,𝑡).(3.13) If 𝐷0=0, we found 𝑎2=0, and 𝑏1𝐷=1𝛾2𝑝2𝛼𝛾2,𝑏2=𝑝,𝑎2𝛼𝑘0𝑝=22𝛼,𝑎1=𝑘𝑝𝐷1𝛾2𝑝2𝛼𝛾2.(3.14) Consequently, we obtain the following solutions of system (3.1)𝑢𝑝(𝑥,𝑡)=2+𝐷2𝑎1𝛾𝑘𝑝2𝑝2𝛼𝛾2𝑘tanh(𝑥𝑝𝑡)+𝜉0,𝑆(𝑥,𝑡)=cosh𝑘(𝑥𝑝𝑡)+𝜉0𝐷1(𝛾2𝑝2)/𝛼𝛾2𝑝exp2𝑎𝑘𝑘(𝑥𝑝𝑡)+𝜉0,𝑝𝑣(𝑥,𝑡)=3+𝐷2𝑎𝛾1𝑘𝑝2𝛾2𝑝2𝛼𝛾3tanh𝑘(𝑥𝑝𝑡)+𝜉0,(3.15) which is different from the solutions obtained in [12].

3.2. Using Improved tanh Method

Case 1. We seek solutions in the form of (2.8) 𝑢(𝜉)=𝑀𝑖=0𝑎𝑖/𝜉𝑖. Motivated by the expression of (3.5), we turn to the assumption 𝜑(𝜉)=𝑏2𝜉+𝑏1ln|𝜉|+𝑀2𝑗=0𝑏𝑗/𝜉𝑗 and also imply that 𝑀=2. Therefore, we have 𝑢(𝜉)=𝑎0+𝑎11𝜉+𝑎21𝜉2,𝜑(𝜉)=𝑏2𝜉+𝑏1||𝜉||.ln(3.16)
By substituting (3.16) into (3.4) and (3.5), and setting the coefficients of 1/𝜉𝑗(𝑗=0,1,2) to be zero, we set 𝑎𝛼𝛾𝑘1𝑏2+𝑎0𝑏1𝛾𝑝𝑎1=0,2𝑘𝐷1𝛾2𝑝2𝑎1+2𝛼𝛾2𝑘𝑎1𝑏1+𝑎2𝑏22𝛾2𝑝𝑎2=0,6𝑘𝐷1𝛾2𝑝2𝑎2+3𝛼𝛾2𝑘𝑎2𝑏1=0,𝑘𝑝𝑏2+𝐷0𝑘2𝑏22+𝑎0=0,𝑘𝑝𝑏1+2𝐷0𝑘2𝑏2𝑏1+𝑎1𝐷=0,0𝑘2𝑏21𝑏1+𝑎2=0.(3.17) If 𝐷00 and 𝛼Δ=1+3±𝛼2𝐷0+𝛼𝐷20+𝛼𝐷0+𝛼25𝛼2𝐷1+4𝐷20𝐷1+4𝛼𝐷0𝐷1>0,(3.18) solving algebraic equations (3.17) gives 𝑏1=2𝐷1𝛾2𝑝2𝛼𝛾2,𝑏2=1𝛼𝑘𝐷02𝑝𝐷0𝐷1𝛾2𝑝2+𝑝𝐷0𝛼𝛾2𝑝𝐷1𝛼𝛾2𝑝24𝐷1𝛾2𝑝2+𝛼𝛾2,𝑎0𝑝=22𝐷0𝐷1𝐷1𝛼𝛾2𝑝2+𝛼𝛾2𝐷0𝛼2𝐷04𝐷1(𝛾2𝑝2)+𝛼𝛾22×3𝛼𝐷1+2𝐷0𝐷1𝛾2𝑝2+𝛼2𝛾2+𝛼𝛾2𝐷0,𝑎1=2𝑘𝑝𝐷1𝛾2𝑝2𝛼2𝛾2𝛼𝛾2+4𝐷1𝛾2𝑝2×𝛼2𝛾2+2𝛼𝛾2𝐷0+2𝛼𝐷1𝛾2𝑝2+4𝐷0𝐷1𝛾2𝑝2,𝑎2=2𝑘2𝐷0𝐷1𝛾2𝑝2𝛼𝛾22𝛼𝛾2+2𝐷1𝛾2𝑝2,𝑝=𝛾Δ,(3.19) where Δ is specified by (3.18).
This in turn gives the solutions of system (3.1) 𝑢(𝑥,𝑡)=𝑎0+𝑎1𝑘(𝑥𝑝𝑡)+𝜉0+𝑎2𝑘(𝑥𝑝𝑡)+𝜉02,||𝑆(𝑥,𝑡)=𝑘(𝑥𝑝𝑡)+𝜉0||𝑏1𝑏exp2𝑘(𝑥𝑝𝑡)+𝜉0,𝑝𝑣(𝑥,𝑡)=𝛾𝑎0+𝑎1𝑘(𝑥𝑝𝑡)+𝜉0+𝑎2𝑘(𝑥𝑝𝑡)+𝜉02,(3.20) where 𝑘 is an arbitrary constant and 𝑎𝑖(𝑖=0,1,2), 𝑏𝑗(𝑗=1,2),𝑝 are given in (3.19).

Case 2. We seek solutions in the form of (2.9). Let 𝑢(𝜉)=𝑀𝑖=0𝑎𝑖tan𝑖𝜉 and 𝜑(𝜉)=𝑏2𝜉+𝑏1ln|cos𝜉|+𝑀2𝑗=0𝑏𝑗tan𝑗𝜉. Substituting 𝑢(𝜉),𝜑(𝜉) into (3.4) and (3.5), balancing the linear terms of highest order with the highest order nonlinear terms, directly results in 𝑀=2 and 𝑢=𝑎0+𝑎1tan𝜉+𝑎2tan2𝜉,𝜑=𝑏2𝜉+𝑏1||||.lncos𝜉(3.21) To progress further substituting (3.21) into (3.4) and (3.5) and setting the coefficients of tan𝑖𝜉(𝑖=0,1,2) in the resulting equations to be zero, we obtain a set of algebraic equations 2𝑘𝐷1𝛾2𝑝2𝑎2𝛼𝛾2𝑘𝑎1𝑏2𝑎0𝑏1+𝛾2𝑝𝑎1=0,𝑘𝐷1𝛾2𝑝2𝑎1𝛼𝛾2𝑘𝑎1𝑏1+𝑎2𝑏2+𝛾2𝑝𝑎2=0,6𝑎2𝑘𝐷1𝛾2𝑝2+3𝛼𝛾2𝑘𝑎2𝑏1=0,𝑘𝑝𝑏2𝐷0𝑘2𝑏22𝑏1=𝑎0,𝑘𝑝𝑏1+2𝐷0𝑘2𝑏1𝑏2=𝑎1,𝐷0𝑘2𝑏21𝑏1=𝑎2.(3.22) If 𝐷00 and 𝑝 satisfies Δ=𝑝45𝐷21𝛼2+4𝐷0𝐷21𝛼+4𝐷20𝐷21+𝑝2𝛾22𝐷1𝛼3+10𝛼2𝐷21+8𝛼𝐷0𝐷21+8𝐷20𝐷21+𝛾4𝛼3𝐷0+𝛼2𝐷202𝛼3𝐷15𝛼2𝐷214𝛼𝐷0𝐷214𝐷20𝐷21>0,(3.23) we know 𝑏1=2𝐷1𝛾2𝑝2𝛼𝛾2,𝑏(3.24)2=𝑝𝛼𝑘𝐷02𝐷0𝐷1𝛾2𝑝2+𝛼𝛾2𝐷0𝐷1𝛼𝛾2𝑝24𝐷1𝛾2𝑝2+𝛼𝛾2,𝑎(3.25)0𝑝=2𝛼𝐷02𝐷0𝐷1𝛾2𝑝2+𝛼𝛾2𝐷0𝛼𝐷1𝛾2𝑝24𝐷1𝛾2𝑝2+𝛼𝛾2𝑝2𝛼2𝐷02𝐷0𝐷1(𝛾2𝑝2)+𝛼𝛾2𝐷0𝛼𝐷1(𝛾2𝑝2)4𝐷1(𝛾2𝑝2)+𝛼𝛾222𝑘2𝐷0𝐷1𝛾2𝑝2𝛼𝛾2,𝑎(3.26)1=2𝑘𝑝𝐷1𝛾2𝑝2𝛼+2𝐷0𝛼𝛾2+2𝐷1𝛾2𝑝2𝛼2𝛾2𝛼𝛾2+4𝐷1𝛾2𝑝2,𝑎(3.27)2=2𝑘2𝐷0𝐷1𝛾2𝑝2𝛼𝛾2+2𝐷1𝛾2𝑝2𝛼𝛾22,(3.28)𝑘=𝑝𝛾22Δ𝐷20𝐷21𝛾2𝑝224𝐷1𝛾2𝑝2+𝛼𝛾22,(3.29) where Δ is given by (3.23). To this end, we therefore derive the solutions of system (3.1) as follows: 𝑢(𝑥,𝑡)=𝑎0+𝑎1tan𝑘(𝑥𝑝𝑡)+𝜉0+𝑎2tan2𝑘(𝑥𝑝𝑡)+𝜉0,||𝑆(𝑥,𝑡)=cos𝑘(𝑥𝑝𝑡)+𝜉0||𝑏1𝑒𝑏2(𝑘(𝑥𝑝𝑡)+𝜉0),𝑎𝑣(𝑥,𝑡)=0+𝑎1tan𝑘(𝑥𝑝𝑡)+𝜉0+𝑎2tan2𝑘(𝑥𝑝𝑡)+𝜉0𝑝𝛾,(3.30) where 𝑏𝑗(𝑗=1,2) and 𝑎𝑖(𝑖=0,1,2) and 𝑘 are given by (3.24)–(3.29), respectively.

4. Conclusion

In the present paper, we have considered the exact traveling wave solutions of a one-space dimensional hyperbolic model for chemotaxis (1.5). Using a transformation of dependent variables and eliminating the dependent variable 𝑣 in the resultant system (3.1), the system (1.5) is reduced to a couple system of two equations (3.2). Applying the transformation (3.3) to unite the independent variables 𝑥 and 𝑡, the (3.2) is convert to a coupled ordinary differential system. Then, the tanh method and improved tanh method are used, with the help of symbolic software MATHMATICA, to search for exact traveling wave solutions of system (3.1). Finally, three kinds of traveling wave solutions including soliton, rational, and triangular solutions are found, all of which are different from those known ones in the literature.

Acknowledgments

This work was supported by the National Natural Science Foundation of China (Grant no. 11001050). The authors gratefully acknowledge valuable discussions with Professor J. B. Chen. Also, the authors thank the three anonymous editors whose suggestions helped improve the paper.