Abstract

We consider nondifferentiable minimax fractional programming problems involving 𝐵-(𝑝, 𝑟)-invex functions with respect to 𝜂 and 𝑏. Sufficient optimality conditions and duality results for a class of nondifferentiable minimax fractional programming problems are obtained undr 𝐵-(𝑝, 𝑟)-invexity assumption on objective and constraint functions. Parametric duality, Mond-Weir duality, and Wolfe duality problems may be formulated, and duality results are derived under 𝐵-(𝑝, 𝑟)-invex functions.

1. Introduction

Convexity plays an important role in many aspects of mathematical programming including sufficient optimality conditions and duality theorems. In general, we use the invex function to replace convexity on sufficient optimality conditions and duality theorems (see, e.g., [16]).

Many authors investigated the optimality conditions and duality theorems for minimax (fractional) programming problems. For details, one can consult [114]. In particular, Lai et al. [10] have established the theorems of necessary and sufficient optimality conditions for nondifferentiable minimax fractional problem under the conditions of convexity. In [11], Lai and Lee employed the optimality conditions to construct two parameter-free dual models of nondifferentiable minimax fractional programming problem which involve pseudoconvex and quasiconvex functions, and derived weak and strong duality theorems. In the formulation of the dual models in [11] optimality conditions given in [10] are used. Mishra et al. [4] derived a Kuhn-Tucker-type sufficient optimality condition for an optimal solution to the nondifferentiable minimax fractional programming problem and established weak, strong, and converse duality theorems for the problem and its three different forms of dual problems under generalized univexity. Mishra et al. [5, 13] considered the nondifferentiable minimax fractional programming problem and obtain optimality and duality results under generalized 𝛼-invexity [5] and generalized 𝛼-unvexity [13]. Recently, Antczak [15] defined a new class of functions, named 𝐵-(𝑝,𝑟)-invex, which is an extension of invex function. In [1], parametric and nonparametric sufficient optimality conditions and several parametric and parameter-free duality models for the generalized fractional minimax programs are obtained under 𝐵-(𝑝,𝑟)-invexity assumption on objective and constraint functions.

In this paper, we are inspired to extend the result of Lai et al. [10] to 𝐵-(𝑝,𝑟)-invexity and organize this paper as follows. In Section 2 we introduce some basic results. We establish sufficient optimality conditions for nondifferentiable minimax fractional programming problem under 𝐵-(𝑝,𝑟)-invex with respect to the same function 𝜂 and with respect to, not necessarily, the same function 𝑏 in Section 3. Employing these results, we construct three dual problems in Sections 46. Here we investigate weak, strong, and strict converse duality theorems under the framework of 𝐵-(𝑝,𝑟)-invex with respect to the same function 𝜂 and with respect to, not necessarily, the same function 𝑏.

2. Some Notations and Preliminary Results

Let 𝑛 be the 𝑛-dimensional Euclidean space and 𝑛+ its nonnegative orthant. Throughout the paper, let 𝑋 be a nonempty open set of 𝕟.

The following definition can be found in [15].

Definition 2.1 (see [15]). Let 𝑝 and 𝑟 be any real numbers. The differentiable function 𝑓𝑋 is said to be (strictly) 𝐵-(𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑢𝑋 on a nonempty set 𝑋𝑛 if, there exist a function 𝜂𝑋×𝑋𝑛 and a function 𝑏𝑋×𝑋+{0} such that, for all 𝑥𝑋, the inequalities 1𝑟𝑒𝑏(𝑥,𝑢)𝑟(𝑓(𝑥)𝑓(𝑢))11𝑝𝑒𝑓(𝑢)𝑝𝜂(𝑥,𝑢)1𝟏(>if𝑥𝑢)for𝑝0,𝑟0,𝑓(𝑢)𝜂(𝑥,𝑢)(>if𝑥𝑢)for𝑝=0,𝑟0,𝑏(𝑥,𝑢)(𝑓(𝑥)𝑓(𝑢))𝑝𝑒𝑓(𝑢)𝑝𝜂(𝑥,𝑢)(𝟏(>if𝑥𝑢)for𝑝0,𝑟=0,𝑓(𝑢)𝜂(𝑥,𝑢)>if𝑥𝑢)for𝑝=0,𝑟=0(2.1) hold.

𝑓 is said to be 𝐵-(𝑝,𝑟)-invex (strictly 𝐵-(𝑝,𝑟)-invex) with respect to 𝜂 and 𝑏 on 𝑋 if it is 𝐵-(𝑝,𝑟)-invex with respect to the same 𝜂 and 𝑏 at each 𝑢𝑋.

It should be pointed out that exponentials appearing on the right-hand sides of the above inequalities are understood to be taken componentwise and 𝟏=(1,1,,1)𝑛.

We consider the following nondifferentiable minimax fractional programming problem: minimize𝐹(𝑥)=sup𝑦𝑌𝑥𝑓(𝑥,𝑦)+𝐵𝑥1/2𝑥(𝑥,𝑦)𝐷𝑥1/2(subjectto𝑔(𝑥)0,P) where 𝑌 is a compact subset of 𝑚, 𝑓(,)𝑛×𝑚, (,)𝑛×𝑚, and 𝑔()𝑛𝑝 are 𝐶1-functions, 𝐵 and 𝐷 are 𝑛×𝑛 positive semidefinite matrices, 𝑓(𝑥,𝑦)+(𝑥𝐵𝑥)1/20, and (𝑥,𝑦)(𝑥𝐷𝑥)1/2>0 for each (𝑥,𝑦) in 𝑋×𝑌, where 𝑋 is the set of feasible solutions of problem (P); that is, 𝑋={𝑥𝑋𝑔(𝑥)0}. This is a nondifferentiable programming problem if either 𝐵 or 𝐷 is nonzero. If 𝐵 and 𝐷 are null matrices, then problem (P) is a minimax fractional programming problem.

For each (𝑥,𝑦)𝑛×𝑚 define 𝑥𝜙(𝑥,𝑦)=𝑓(𝑥,𝑦)+𝐵𝑥1/2𝑥(𝑥,𝑦)𝐷𝑥1/2.(2.2) We let𝐽={1,2,,𝑝},𝐽(𝑥)=𝑗𝐽𝑔𝑗,(𝑥)=0𝑌(𝑥)=𝑦𝑌𝜙(𝑥,𝑦)=sup𝑧𝑌,𝜙(𝑥,𝑧)𝐾(𝑥)=(𝑠,𝑡,𝑦)×𝑠+×𝑚𝑠𝑡1𝑠𝑛+1,𝑡=1,𝑡2,,𝑡𝑠𝑠+with𝑠𝑖=1𝑡𝑖𝑦=1,𝑦=1,𝑦2,,𝑦𝑠with𝑦𝑖.𝑌(𝑥),𝑖=1,2,,𝑠(2.3)

Because 𝑓 and are contionuous differentiable and 𝑌 is compact subset of 𝑚, we see that for each 𝑥0𝑋, 𝑌(𝑥0), and for any 𝑦𝑖𝑌(𝑥0), we have a postive constant 𝑘0𝑥=𝜙0,𝑦𝑖=𝑓𝑥0,𝑦𝑖+𝑥0𝐵𝑥01/2𝑥0,𝑦𝑖𝑥0𝐷𝑥01/2.(2.4)

We will use the generalized Schwarz inequality 𝑥𝑥𝐵𝑣𝐵𝑥1/2𝑣𝐵𝑣1/2,for𝑥,𝑣𝑛;(2.5) the equality holds when 𝐵𝑥=𝜆𝐵𝑣, for some 𝜆0.

Hence if 𝑣𝐵𝑣1, we have 𝑥𝑥𝐵𝑣𝐵𝑥1/2.(2.6)

In [10] Lai et al. derived the following necessary conditions for optimality (P).

Theorem 2.2 ((necessary conditions) see, [10]). Let 𝑥0 be a (𝑃)-optimal solution and satisfying 𝑥0𝐵𝑥0>0, 𝑥0𝐷𝑥0>0, and 𝑔𝑗(𝑥0),𝑗𝐽(𝑥0) is linearly independent. Then there exist (𝑠,𝑡,𝑦)𝐾(𝑥0), 𝑘0+, 𝑤,𝑣𝑛, and 𝜇𝑝+ such that 𝑠𝑖=1𝑡𝑖𝑥𝑓0,𝑦𝑖+𝐵𝑤𝑘0𝑥0,𝑦𝑖𝐷𝑣+𝑝𝑗=1𝜇𝑗𝑔𝑗𝑥0𝑓𝑥=0,(2.7)0,𝑦𝑖+𝑥0𝐵𝑥01/2𝑘0𝑥0,𝑦𝑖𝑥0𝐷𝑥01/2=0,𝑖=1,2,,𝑠,(2.8)𝑝𝑗=1𝜇𝑗𝑔𝑗𝑥0𝑡=0,(2.9)𝑖0,𝑠𝑖=1𝑡𝑖𝑤=1,(2.10)𝐵𝑤1,𝑣𝑥𝐷𝑣1,0𝑥𝐵𝑤=0𝐵𝑥01/2,𝑥0𝑥𝐷𝑣=0𝐵𝑥01/2.(2.11)

It should be noted that both the matrices 𝐵 and 𝐷 are positive definite at the solution 𝑥0 in the above theorem. If one of 𝑥0𝐵𝑥0 and 𝑥0𝐷𝑥0 is zero, or both 𝐵 and 𝐷 are singular at 𝑥0, then, for (𝑠,𝑡,𝑦)𝐾(𝑥0), we define a set 𝑍𝑦(𝑥0) by 𝑍𝑦𝑥0=𝑧𝑛𝑧𝑔𝑗𝑥0𝑥0,𝑗𝐽0.,withanyoneofthenextconditions(i)-(iii)holds(2.12)

Here conditions (i)–(iii) are given as follows:(i)if 𝑥0𝐵𝑥0>0 and 𝑥0𝐷𝑥0=0, then 𝑧𝑠𝑖=1𝑡𝑖𝑥𝑓0,𝑦𝑖+𝐵𝑥0𝑥0𝐵𝑥01/2𝑘0𝑥0,𝑦𝑖+𝑧𝑘20𝐷𝑧1/2<0,(2.13)(ii)if 𝑥0𝐵𝑥0=0 and 𝑥0𝐷𝑥0>0, then 𝑧𝑠𝑖=1𝑡𝑖𝑥𝑓0,𝑦𝑖𝑘0𝑥0,𝑦𝑖𝐷𝑥0𝑥0𝐷𝑥01/2+𝑧𝐵𝑧1/2<0,(2.14)(iii)if 𝑥0𝐵𝑥0=0 and 𝑥0𝐷𝑥0=0, then 𝑧𝑠𝑖=1𝑡𝑖𝑥𝑓0,𝑦𝑖𝑘0𝑥0,𝑦𝑖+𝑧𝑘0𝐷𝑧1/2+𝑧𝐵𝑧1/2<0.(2.15)

If we take condition 𝑍𝑦(𝑥0)= in Theorem 2.2, then the result of Theorem 2.2 still holds.

3. Optimality Conditions

In this section we derive sufficient conditions for optimality of (P) under the assumpition of a particular form of generalized 𝐵-(𝑝,𝑟)-invexity. All theorems in this work will be proved only in the case when 𝑝0, 𝑟0 (other cases can be dealt with by similarity since the only difference is arised from the form of the inequality defining the class of the 𝐵-(𝑝,𝑟)-invex functions with respect to 𝜂 and 𝑏 for given 𝑝 and 𝑟). The proofs of the other cases are easier than this one.

We would establish the sufficient conditions under the 𝐵-(𝑝,𝑟)-invex function.

Theorem 3.1 (sufficient optimality conditions). Let 𝑥0𝑋 be a feasible solution of (P). There exist a positive interger 𝑠, 1𝑠𝑛+1, 𝑡𝑠, 𝑦𝑖𝑌(𝑥0)(𝑖=1,2,,𝑠), 𝑘0+, (𝑤,𝑣)𝑛×𝑛, and 𝜇𝑝+ to satisfy relations (2.7)~(2.11). Furthermore suppose that any one of conditions (a) and (b) holds: (a)Υ()=𝑠𝑖=1𝑡𝑖((𝑓(,𝑦𝑖)+()𝐵𝑤)𝑘0((,𝑦𝑖)()𝐷𝑣)) is 𝐵-(𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑥0, and 𝑝𝑗=1𝜇𝑗𝑔𝑗() is 𝐵-(𝑝,𝑟)-invex with respect to the same function 𝜂 and another function 𝑏1 at 𝑥0 on 𝑋, not necessarily, equal to 𝑏, (b)Υ1()=𝑠𝑖=1𝑡𝑖((𝑓(,𝑦𝑖)+()𝐵𝑤)𝑘0((,𝑦𝑖)()𝐷𝑣))+𝑝𝑗=1𝜇𝑗𝑔𝑗() is 𝐵-(𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑥0 on 𝑋,then 𝑥0 is an optimal solution of (P).

Proof. Suppose that 𝑥0 is not an optimal solution of (P). Then there exists a (𝑃)-feasible solution 𝑥1 such that sup𝑦𝑌𝑓𝑥1+𝑥,𝑦1𝐵𝑥11/2𝑥1𝑥,𝑦1𝐷𝑥11/2<sup𝑦𝑌𝑓𝑥0+𝑥,𝑦0𝐵𝑥01/2𝑥0𝑥,𝑦0𝐷𝑥01/2.(3.1) We note that sup𝑦𝑌𝑓𝑥0+𝑥,𝑦0𝐵𝑥01/2𝑥0𝑥,𝑦0𝐷𝑥01/2=𝑓𝑥0,𝑦𝑖+𝑥0𝐵𝑥01/2𝑥0,𝑦𝑖𝑥0𝐷𝑥01/2=𝑘0,(3.2) for 𝑦𝑖𝑌(𝑥0), 𝑖=1,2,,𝑠, and 𝑓𝑥1,𝑦𝑖+𝑥1𝐵𝑥11/2𝑥1,𝑦𝑖𝑥1𝐷𝑥11/2sup𝑦𝑌𝑓𝑥1+𝑥,𝑦1𝐵𝑥11/2𝑥1𝑥,𝑦1𝐷𝑥11/2.(3.3) Then, we obtain 𝑓𝑥1,𝑦𝑖+𝑥1𝐵𝑥11/2𝑥1,𝑦𝑖𝑥1𝐷𝑥11/2<𝑘0,for𝑖=1,2,,𝑠.(3.4) It follows that 𝑓𝑥1,𝑦𝑖+𝑥1𝐵𝑥11/2𝑘0𝑥1,𝑦𝑖𝑥1𝐷𝑥11/2<0,for𝑖=1,2,,𝑠.(3.5) From relations (2.6), (2.11), (2.8), (2.10), and (3.5), we have Υ𝑥1=𝑠𝑖=1𝑡𝑖𝑓𝑥1,𝑦𝑖+𝑥1𝐵𝑤𝑘0𝑥1,𝑦𝑖𝑥1𝐷𝑣𝑠𝑖=1𝑡𝑖𝑓𝑥1,𝑦𝑖+𝑥1𝐵𝑥11/2𝑘0𝑥1,𝑦𝑖𝑥1𝐷𝑥11/2=<0𝑠𝑖=1𝑡𝑖𝑓𝑥0,𝑦𝑖+𝑥0𝐵𝑥01/2𝑘0𝑥0,𝑦𝑖𝑥0𝐷𝑥01/2=𝑠𝑖=1𝑡𝑖𝑓𝑥0,𝑦𝑖+𝑥0𝐵𝑤𝑘0𝑥0,𝑦𝑖𝑥0𝑥𝐷𝑣=Υ0.(3.6) That is, Υ𝑥1𝑥<Υ0.(3.7) From relations (P) and (2.9), we obtain 𝑝𝑗=1𝜇𝑗𝑔𝑗𝑥10=𝑝𝑗=1𝜇𝑗𝑔𝑗𝑥0.(3.8) If hypothesis (a) holds, from the 𝐵-(𝑝,𝑟)-invexity with respect to 𝜂 and 𝑏1 at 𝑥0 of 𝑝𝑗=1𝜇𝑗𝑔𝑗(), we have 1𝑟𝑏1𝑥1,𝑥0𝑒𝑟(𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑥1)𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑥0))11𝑝𝑝𝑗=1𝜇𝑗𝑔𝑗𝑥0𝑒𝑝𝜂(𝑥1,𝑥0).𝟏(3.9) From the inequalities (3.8) and (3.9), we get 1𝑝𝑝𝑗=1𝜇𝑗𝑔𝑗𝑥0𝑒𝑝𝜂(𝑥1,𝑥0)𝟏0.(3.10) Now, multiplying equality (2.7) by (1/𝑝)(𝑒𝑝𝜂(𝑥1,𝑥0)𝟏), we know 1𝑝𝑒𝑝𝜂(𝑥1,𝑥0)𝟏𝑠𝑖=1𝑡𝑖𝑥𝑓0,𝑦𝑖+𝐵𝑤𝑘0𝑥0,𝑦𝑖𝐷𝑣+𝑝𝑗=1𝜇𝑗𝑔j𝑥0=0.(3.11) From relations (3.10) and (3.11), we have 1𝑝𝑒𝑝𝜂(𝑥1,𝑥0)𝟏𝑠𝑖=1𝑡𝑖𝑥𝑓0,𝑦𝑖+𝐵𝑤𝑘0𝑥0,𝑦𝑖𝐷𝑣0.(3.12) From the 𝐵-(𝑝,𝑟)-invexity with respect to the same function 𝜂 and the function 𝑏 at 𝑥0 of Υ(), 1𝑟𝑒𝑏(𝑥,𝑢)𝑟(Υ(𝑥1)Υ(𝑥0))11𝑝𝑥Υ0𝑒𝑝𝜂(𝑥1,𝑥0).𝟏(3.13) From inequality (3.12) and the above inequality, we obtain Υ𝑥1𝑥Υ0,(3.14) which contradicts (3.7), and proves that 𝑥0 is an optimal solution to (P).
If hypothesis (b) holds, from the 𝐵-(𝑝,𝑟)-invexity with respect to 𝜂 and 𝑏 at 𝑥0 of Υ1(), then 1𝑟𝑒𝑏(𝑥,𝑢)𝑟(Υ1(𝑥1)Υ1(𝑥0))11𝑝Υ1𝑥0𝑒𝑝𝜂(𝑥1,𝑥0)𝟏.(3.15) The above inequality along with (2.7) yields Υ1𝑥1Υ1𝑥0,(3.16) which contradicts (3.7). Hence, the proof is completed.

4. Parametric Dual-Type Model

We use the optimality conditions of the preceding section and show that the following formation is a dual (D) to the minimax problem (P):max(𝑠,𝑡,𝑦)𝐾(𝑧)sup(𝑧,𝜇,𝑘,𝑤,𝑣)𝐻1(𝑠,𝑡,𝑦)(𝑘,D) where 𝐻1(𝑠,𝑡,𝑦) denotes the set of (𝑧,𝜇,𝑘,𝑤,𝑣)𝑛×𝑝+×+×𝑛×𝑛 satisfying 𝑠𝑖=1𝑡𝑖𝑓𝑧,𝑦𝑖+𝐵𝑤𝑘𝑧,𝑦𝑖𝐷𝑣+𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧)=0,(4.1)𝑠𝑖=1𝑡𝑖𝑓𝑧,y𝑖+𝑧𝐵𝑤𝑘𝑧,𝑦𝑖𝑧𝐷𝑣0,(4.2)𝑝𝑗=1𝜇𝑗𝑔𝑗𝑤(𝑧)0,(4.3)𝐵𝑤1,𝑣𝐷𝑣1,(𝑠,𝑡,𝑦)𝐾(𝑧).(4.4) If for a triplet (𝑠,𝑡,𝑦)𝐾(𝑧) the set 𝐻1(𝑠,𝑡,𝑦) is empty, then we define the supremum over it to be .

Let Γ denote the set of all feasible points of (D). Moreover, we denote 𝑝𝑟𝑋Γ={𝑧𝑋(𝑧,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣,𝑘)Γ}.

We can derive the following weak duality theorem between (P) and (D).

Theorem 4.1 (weak duality). Let 𝑥 and (𝑧,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣,𝑘) be (𝑃)-feasible and (𝐷)-feasible, respectively. Suppose that any one of the following conditions (𝑎) and (𝑏) holds: (a)Υ2()=𝑠𝑖=1𝑡𝑖((𝑓(,𝑦𝑖)+()𝐵𝑤)𝑘((,𝑦𝑖)()𝐷𝑣)) is 𝐵-(𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑧 and 𝑝𝑗=1𝜇𝑗𝑔𝑗() is 𝐵-(𝑝,𝑟)-invex with respect to the same function 𝜂 and another function 𝑏2 at 𝑧 on 𝑋𝑝𝑟𝑋Γ, not necessarily, equal to 𝑏, (b)Υ3()=𝑠𝑖=1𝑡𝑖((𝑓(,𝑦𝑖)+()𝐵𝑤)𝑘((,𝑦𝑖)()𝐷𝑣))+𝑝𝑗=1𝜇𝑗𝑔𝑗() is (𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑧 on 𝑋𝑝𝑟𝑋Γ. Then sup𝑦𝑌𝑥𝑓(𝑥,𝑦)+𝐵𝑥1/2𝑥(𝑥,𝑦)𝐷𝑥1/2𝑘.(4.5)

Proof. Suppose on the contrary that sup𝑦𝑌𝑥𝑓(𝑥,𝑦)+𝐵𝑥1/2𝑥(𝑥,𝑦)𝐷𝑥1/2<𝑘.(4.6) Then, we have an inequality 𝑥𝑓(𝑥,𝑦)+𝐵𝑥1/2𝑥𝑘(𝑥,𝑦)𝐷𝑥1/2<0𝑦𝑌.(4.7) It follows that for 𝑡𝑖0, 𝑖=1,2,,𝑠 with 𝑠𝑖=1𝑡𝑖=1, we have 𝑡𝑖𝑓𝑥,𝑦𝑖+𝑥𝐵𝑥1/2𝑘𝑥,𝑦𝑖𝑥𝐷𝑥1/20,(4.8) with at least one strict inequality because 𝑡=(𝑡1,𝑡2,,𝑡𝑠)0. From relations (2.6), (4.4), (4.8), and (4.2), we obtain Υ2(𝑥)=𝑠𝑖=1𝑡𝑖𝑓𝑥,𝑦𝑖+𝑥𝐵𝑤𝑘𝑥,𝑦𝑖𝑥𝐷𝑣𝑠𝑖=1𝑡𝑖𝑓𝑥,𝑦𝑖+𝑥𝐵𝑥1/2𝑘𝑥,𝑦𝑖𝑥𝐷𝑥1/2<0𝑠𝑖=1𝑡𝑖𝑓𝑧,𝑦𝑖+𝑧𝐵𝑤𝑘𝑧,𝑦𝑖𝑧𝐷𝑣=Υ2(𝑧).(4.9) That is, Υ2(𝑥)<Υ2(𝑧).(4.10) From relations (P) and (4.3), we have 𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑥)0𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧),(4.11) If hypothesis (a) holds, from 𝐵-(𝑝,𝑟)-invexity with respect to 𝜂 and 𝑏 at 𝑧 of Υ2(), we get 1𝑟e𝑏(𝑥,𝑧)𝑟(Υ2(𝑥)Υ2(𝑧))11𝑝Υ2𝑒(𝑧)𝑝𝜂(𝑥,𝑧).𝟏(4.12) From the above inequality together with relation (4.10), we have 1𝑝Υ2𝑒(𝑧)𝑝𝜂(𝑥,𝑧)𝟏<0.(4.13) Multiplying (4.1) by (1/𝑝)(𝑒𝑝𝜂(𝑥,𝑧)𝟏), we obtain 1𝑝𝑒𝑝𝜂(𝑥,𝑧)𝟏𝑠𝑖=1𝑡𝑖𝑓𝑧,𝑦𝑖+𝐵𝑤𝑘𝑧,𝑦𝑖𝐷𝑣+𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧)=0.(4.14) From the above equality and inequality (4.13), we get 1𝑝𝑒𝑝𝜂(𝑥,𝑧)𝟏𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧)>0.(4.15) Using the 𝐵-(𝑝,𝑟)-invexity of 𝑝𝑗=1𝜇𝑗𝑔𝑗() with respect to the same function 𝜂 and the function 𝑏2 at 𝑧 and inequality (4.15), we get 𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑥)>𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧).(4.16) which contradicts (4.11) and proves that sup𝑦𝑌((𝑓(𝑥,𝑦)+(𝑥𝐵𝑥)1/2)/((𝑥,𝑦)(𝑥𝐷x)1/2))𝑘.
If hypothesis (b) holds, from the 𝐵-(𝑝,𝑟)-invexity with respect to 𝜂 and 𝑏 at 𝑧 of Υ3(), then 1𝑟𝑒𝑏(𝑥,𝑧)𝑟(Υ3(𝑥)Υ3(𝑧))11𝑝Υ3𝑒(𝑧)𝑝𝜂(𝑥,𝑧).𝟏(4.17) By the above inequality and equality (4.1), we have Υ3(𝑥)Υ3(𝑧).(4.18) From relations (4.10) and (4.11), we obtain Υ3(𝑥)<Υ3(𝑧),(4.19) which contradicts inequality (4.18). Thus, the proof is complete.

Theorem 4.2 (strong duality). Let 𝑥 be an optimal solution of (P), and let 𝑥 satisfy a constraint qualification for (P). Then there exist (𝑠,𝑡,𝑦)𝐾(𝑥) and (𝑥,𝜇,𝑘,𝑤,𝑣)𝐻1(𝑠,𝑡,𝑦) such that (𝑥,𝜇,𝑠,𝑡,𝑦,𝑘,𝑤,𝑣) is a feasible solution of (D). If in addition the hypothesis of Theorem 4.1 holds, then (𝑥,𝜇,𝑠,𝑡,𝑦,𝑘,𝑤,𝑣) is an optimal solution of (D) and the two problems (P) and (D) have the same optimal value.

Proof. By Theorem 2.2, there exist (𝑠,𝑡,𝑦)𝐾(𝑥) and (𝑥,𝜇,𝑘,𝑤,𝑣)𝐻1(𝑠,𝑡,𝑦) such that (𝑥,𝜇,𝑠,𝑡,𝑦,𝑘,𝑤,𝑣) is feasible for (D), and 𝑘=𝑓𝑥,𝑦𝑖+𝑥𝐵𝑥1/2𝑥,𝑦𝑖𝑥𝐷𝑥1/2.(4.20) The optimality of this feasible solution for (D) follows from Theorem 4.1.

Theorem 4.3 (strict converse duality). Let 𝑥 and (𝑧,𝜇,𝑠,𝑡,𝑦,𝑘,𝑤𝑣) be optimal solutions of (P) and (D), respectively, and assume that the hypothesis of Theorem 4.2 is fulfilled. Suppose that any one of the following conditions (a) and (b) holds: (a)Υ4()=𝑠𝑖=1𝑡𝑖{𝑓(,𝑦𝑖)+()𝐵𝑤𝑘((,𝑦𝑖)()𝐷𝑣)} is strictly 𝐵-(𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑧 and 𝑝𝑗=1𝜇𝑗𝑔𝑗() is (𝑝,𝑟)-invex with respect to the same function 𝜂 and another function 𝑏4 at 𝑧 on 𝑋𝑝𝑟𝑋Γ, not necessarily, equal to 𝑏, (b)Υ5()=𝑠𝑖=1𝑡𝑖{𝑓(,𝑦𝑖)+()𝐵𝑤𝑘((,𝑦𝑖)()𝐷𝑣)}+𝑝𝑗=1𝜇𝑗𝑔𝑗() is strictly (𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑧 on 𝑋𝑝𝑟𝑋Γ.Then 𝑥=𝑧, that is, 𝑧 solves (P) and sup𝑦𝑌((𝑓(𝑧,𝑦)+((𝑧)𝐵𝑧)1/2)/((𝑧,𝑦)((𝑧)𝐷𝑧)1/2))=𝑘.

Proof. We shall assume that 𝑥𝑧 and reach a contradiction. From Theorem 4.2, we know that there exist (𝑠,𝑡,𝑦)𝐾(𝑥) and (𝑥,𝜇,𝑘,𝑤,𝑣)𝐻1(𝑠,𝑡,𝑦) such that (𝑥,𝜇,𝑠,𝑡,𝑦,𝑘,𝑤,𝑣) is an optimal solution for (D) with the optimal value sup𝑦𝑌𝑓+𝑥,𝑦𝑥𝐵𝑥1/2𝑥,𝑦𝑥𝐷𝑥1/2=𝑘.(4.21) Now like the proof of Theorem 4.1 by 𝑥 replacing by 𝑥 and (𝑧,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣,𝑘) by (𝑧,𝜇,𝑠,𝑡,𝑦,𝑘,𝑤,𝑣), we obtain sup𝑦𝑌𝑓+𝑥,𝑦𝑥𝐵𝑥1/2𝑥,𝑦𝑥𝐷𝑥1/2>𝑘.(4.22) The above inequality contradicts sup𝑦𝑌𝑓+𝑥,𝑦𝑥𝐵𝑥1/2𝑥,𝑦𝑥𝐷𝑥1/2=𝑘=𝑘.(4.23) Therefore, we conclude that 𝑥=𝑧. Here, the proof of the theorem is complete.

Remark 4.4. In Theorem 4.3, if 𝑝𝑗=1𝜇𝑗𝑔𝑗() is a strictly 𝐵-(𝑝,𝑟)-invex function with respect to 𝜂 and 𝑏4 and Υ4() is a 𝐵-(𝑝,𝑟)-invex function with respect to the same function 𝜂 and the function 𝑏, not necessarily, equal to 𝑏4, then Theorem 4.3 also holds.

5. Mond-Weir Dual-Type Model

In this section, we formulate the Mond-Weir-type dual model to the problem (𝑃) as follows:max(𝑠,𝑡,𝑦)𝐾(𝑧)sup(𝑧,𝜇,𝑤,𝑣)𝐻2(𝑠,𝑡,𝑦)((𝑧),MWD) where 𝐻2(𝑠,𝑡,𝑦) denotes the set of (𝑧,𝜇,𝑤,𝑣)𝑛×𝑝+×𝑛×𝑛 satisfying𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝐷𝑧1/2𝑓𝑧,𝑦𝑖𝑓+𝐵𝑤𝑧,𝑦𝑖+𝑧𝐵𝑧1/2𝑧,𝑦𝑖+𝐷𝑣𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧)=0,(5.1)𝑝𝑗=1𝜇𝑗𝑔𝑗𝑤(𝑧)0,(5.2)𝐵𝑤1,𝑣𝑧𝐷𝑣1,𝑧𝐵𝑤=𝐵𝑧1/2𝑧𝑧𝐷𝑣=𝐵𝑧1/2,(5.3) where (𝑧)=sup𝑦𝑌𝑧𝑓(𝑧,𝑦)+𝐵𝑧1/2𝑧(𝑧,𝑦)𝐷𝑧1/2=sup𝑦𝑌𝜙(𝑧,𝑦).(5.4)

If for a triplet (𝑠,𝑡,𝑦)𝐾(𝑧) the set 𝐻2(𝑠,𝑡,𝑦) is empty, then we define the supremum over it to be .

Let Γ denote the set of all feasible points of (MWD). Moreover, we denote 𝑝𝑟𝑋Γ={𝑧𝑋(𝑧,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣)Γ}.

We establish the weak, strong, and strict converse duality theorems for (MWD) with respect to the primal problem (P).

Theorem 5.1 (weak duality). Let 𝑥 and (𝑧,𝜇,s,𝑡,𝑦,𝑤,𝑣) be (𝑃)-feasible and (𝑀𝑊𝐷)-feasible, respectively. Suppose that any one of the following conditions (a) and (b) holds: (a)Υ6()=𝑠𝑖=1𝑡𝑖{((𝑧,𝑦𝑖)𝑧𝐷𝑣)(𝑓(,𝑦𝑖)+()𝐵𝑤)(𝑓(𝑧,𝑦𝑖)+𝑧𝐵𝑤)((,𝑦𝑖)()𝐷𝑣)} is 𝐵-(𝑝,𝑟)-invex, respect to 𝜂 and 𝑏 at 𝑧 and 𝑝𝑗=1𝜇𝑗𝑔𝑗() is 𝐵-(𝑝,𝑟)-invex with respect to the same function 𝜂 and another function 𝑏6 at 𝑧 on 𝑋Γ, not necessarily, equal to 𝑏, (b)Υ7=𝑠𝑖=1𝑡𝑖{((𝑧,𝑦𝑖)𝑧𝐷𝑣)(𝑓(,𝑦𝑖)+()𝐵𝑤)(𝑓(𝑧,𝑦𝑖)+𝑧𝐵𝑤)((,𝑦𝑖)()𝐷𝑣)}+𝑝𝑗=1𝜇𝑗𝑔𝑗() is 𝐵-(𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑧 on 𝑋Γ. Then sup𝑦𝑌𝑥𝑓(𝑥,𝑦)+𝐵𝑥1/2𝑥(𝑥,𝑦)𝐷𝑥1/2(𝑧).(5.5)

Proof. On the contrary, if possible, suppose that for each 𝑥𝑋, sup𝑦𝑌𝑥𝑓(𝑥,𝑦)+𝐵𝑥1/2𝑥(𝑥,𝑦)𝐷𝑥1/2<𝐹(𝑧).(5.6) From the above inequality and 𝑦𝑖𝑌(𝑧), 𝑖=1,2,,𝑠, we obtain 𝑓𝑥,𝑦𝑖+𝑥𝐵𝑥1/2𝑥,𝑦𝑖𝑥𝐷𝑥1/2𝑓<𝐹(𝑧)=𝑧,𝑦𝑖+𝑧𝐵𝑧1/2𝑧,𝑦𝑖𝑧𝐷𝑧1/2,𝑖=1,2,,𝑠.(5.7) By the above inequality, we know that 𝑓𝑥,𝑦𝑖+𝑥𝐵𝑥1/2𝑧,𝑦𝑖𝑧𝐷𝑧1/2𝑥,𝑦𝑖𝑥𝐷𝑥1/2𝑓𝑧,𝑦𝑖+𝑧𝐵𝑧1/2<0,(5.8) for all 𝑖=1,2,,𝑠 and 𝑦𝑖𝑌(𝑧).
Multiplying the above inequality by 𝑡𝑖𝑠+ with 𝑠𝑖=1𝑡𝑖=1, we have 𝑠𝑖=1𝑡𝑖𝑓𝑥,𝑦𝑖+𝑥𝐵𝑥1/2𝑧,𝑦𝑖𝑧𝐷𝑧1/2𝑥,𝑦𝑖𝑥𝐷𝑥1/2𝑓𝑧,𝑦𝑖+𝑧𝐵𝑧1/2<0.(5.9) From relations (2.6), (5.3), and (5.9), we get Υ6(𝑥)=𝑠𝑖=1𝑡𝑖𝑓𝑥,𝑦𝑖+𝑥𝐵𝑤𝑧,𝑦𝑖𝑧𝐷𝑣𝑥,𝑦𝑖𝑥𝑓𝐷𝑣𝑧,𝑦𝑖+𝑧𝐵𝑤𝑠𝑖=1𝑡𝑖𝑓𝑥,𝑦𝑖+𝑥𝐵𝑥1/2𝑧,𝑦𝑖𝑧𝐷𝑧1/2𝑥,𝑦𝑖𝑥𝐷𝑥1/2𝑓𝑧,𝑦𝑖+𝑧𝐵𝑧1/2<0=Υ6(𝑧).(5.10) By relations (P) and (5.2), we have 𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑥)0𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧).(5.11) Now, if condition (a) holds, from 𝐵-(𝑝,𝑟)-invexity with respect to 𝜂 and 𝑏6 at 𝑧 of 𝑝𝑗=1𝜇𝑗𝑔𝑗(), we get 1𝑟𝑏1𝑥1,𝑥0𝑒𝑟(𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑥)𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧))11𝑝𝑝𝑗=1𝜇𝑗𝑔𝑗𝑒(𝑧)𝑝𝜂(𝑥,𝑧).𝟏(5.12) From the above inequality and inequality (5.11), we obtain 1𝑝𝑝𝑗=1𝜇𝑗𝑔𝑗𝑒(𝑧)𝑝𝜂(𝑥,𝑧)𝟏0.(5.13) Multiplying (5.1) by (1/𝑝)(𝑒𝑝𝜂(𝑥,𝑧)𝟏), we have 1𝑝𝑒𝑝𝜂(𝑥,𝑧)𝟏𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝐷𝑧1/2𝑓𝑧,𝑦𝑖𝑓+𝐵𝑤𝑧,𝑦𝑖+𝑧𝐵𝑧1/2𝑧,𝑦𝑖+𝐷𝑣𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧)=0.(5.14) By the above equality and inequality (5.13), we obtain 1𝑝𝑒𝑝𝜂(𝑥,𝑧)𝟏𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝐷𝑧1/2𝑓𝑧,𝑦𝑖𝑓+𝐵𝑤𝑧,𝑦𝑖+𝑧𝐵𝑧1/2𝑧,𝑦𝑖𝐷𝑣0.(5.15) Using the 𝐵-(𝑝,𝑟)-invexity with respect to the same function 𝜂 and the function 𝑏 at 𝑧 of Υ6() and the above inequality, we have Υ6(𝑥)Υ6(𝑧),(5.16) which contradicts (5.10) and proves that sup𝑦𝑌((𝑓(𝑥,𝑦)+(𝑥𝐵𝑥)1/2)/((𝑥,𝑦)(𝑥𝐷𝑥)1/2))(𝑧).
If hypothesis (b) holds, from the 𝐵-(𝑝,𝑟)-invexity with respect to 𝜂 and 𝑏 at 𝑧 of Υ7() and the equality (5.1), then Υ7(𝑥)Υ7(𝑧).(5.17) From relations (5.10) and (5.11), we have 𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝑓𝐷𝑣𝑥,𝑦𝑖+𝑥𝑓𝐵𝑤𝑧,𝑦𝑖+𝑧𝐵𝑤𝑥,𝑦𝑖𝑥+𝐷𝑣𝑝𝑗=1𝜇𝑗𝑔𝑗<(𝑥)𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝑓𝐷𝑣𝑧,𝑦𝑖+𝑧𝑓𝐵𝑤𝑧,𝑦𝑖+𝑧𝐵𝑤𝑧,𝑦𝑖𝑧+𝐷𝑣𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧),(5.18) which contradicts inequality (5.17). Hence, the proof is complete.

Similar to the proof of Theorem 4.2, we can establish Theorem 5.2.

Theorem 5.2 (strong duality). Let 𝑥 be an optimal solution of (P) and let 𝑥 satisfy a constraint qualification for (P). Then there exist (𝑠,𝑡,𝑦)𝐾(𝑥) and (𝑥,𝜇,𝑤,𝑣)𝐻1(𝑠,𝑡,𝑦) such that (𝑥,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣) is a feasible solution of (MWD). If in addition the hypothesis of Theorem 5.1 holds, then (𝑥,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣) is an optimal solution of (MWD) and the two problems (P) and (MWD) have the same optimal value.

Theorem 5.3 (strict converse duality). Let 𝑥 and (𝑧,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣) be optimal solutions of (P) and (MWD), respectively, and assume that the hypothesis of Theorem 5.2 is fulfilled. Suppose that any one of the following conditions (a) and (b) holds: (a)Υ8()=𝑠𝑖=1𝑡𝑖{((𝑧,𝑦𝑖)(𝑧)𝐷𝑣)(𝑓(,𝑦𝑖)+()𝐵𝑤)(𝑓(𝑧,𝑦𝑖)+(𝑧)𝐵𝑤)((,𝑦𝑖)()𝐷𝑣)} is strictly 𝐵-(𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑧 and 𝑝𝑗=1𝜇𝑗𝑔𝑗() is 𝐵-(𝑝,𝑟)-invex with respect to the same function 𝜂 and another function 𝑏8 at 𝑧 on 𝑋Γ, not necessarily, equal to 𝑏, (b)Υ9()=𝑠𝑖=1𝑡𝑖{((𝑧,𝑦𝑖)(𝑧)𝐷𝑣)(𝑓(,𝑦𝑖)+()𝐵𝑤)(𝑓(𝑧,𝑦𝑖)+(𝑧)𝐵𝑤)((,𝑦𝑖)()𝐷𝑣)}+𝑝𝑗=1𝜇𝑗𝑔𝑗() is strictly 𝐵-(𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑧 on 𝑋Γ.Then 𝑥=𝑧, that is, 𝑧 solves (P) and sup𝑦𝑌((𝑓(𝑧,𝑦)+((𝑧)𝐵𝑧)1/2)/((𝑧,𝑦)((𝑧)𝐷𝑧)1/2))=(𝑧).

Proof. We suppose on the contrary that if 𝑥𝑧, then sup𝑦𝑌𝑓+𝑥,𝑦𝑥𝐵𝑥1/2𝑥,𝑦𝑥𝐷𝑥1/2𝑧.(5.19) Since 𝑦𝑖𝑌(𝑧), for 𝑖=1,2,,𝑠, 𝑓𝑧,𝑦𝑖+𝑧𝐵𝑧1/2𝑧,𝑦𝑖(𝑧)𝐷𝑧1/2𝑧=,for𝑖=1,2,,𝑠.(5.20) It follows that 𝑓+𝑥,𝑦𝑥𝐵𝑥1/2𝑧,𝑦𝑖𝑧𝐷𝑧1/2𝑥,𝑦𝑥𝐷𝑥1/2𝑓𝑧,𝑦𝑖+𝑧𝐵𝑧1/20,for𝑖=1,2,,𝑠,𝑦𝑌.(5.21) From 𝑦𝑖𝑌(𝑧)𝑌 and 𝑡𝑠+ with 𝑠𝑖=1𝑡𝑖=1, we have 𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝐷𝑧1/2𝑓𝑥,𝑦𝑖+𝑥𝐵𝑥1/2𝑥,𝑦𝑖𝑥𝐷𝑥1/2𝑓𝑧,𝑦𝑖+𝑧𝐵𝑧1/20.(5.22) From relations (2.6), (5.3), and inequality (5.22), we obtain that Υ8𝑥=𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝑓𝐷𝑣𝑥,𝑦𝑖+𝑥𝑓𝑧𝐵𝑤,𝑦𝑖+𝑧𝐵𝑤𝑥,𝑦𝑖𝑥𝐷𝑣𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑥𝐷𝑥1/2𝑓𝑧,𝑦𝑖+𝑧𝐵𝑧1/2𝑥,𝑦𝑖𝑥𝐷𝑥1/2𝑓𝑧,𝑦𝑖+𝑧𝐵𝑧1/20=Υ8𝑧.(5.23) By relations (P) and (5.2), we get 𝑝𝑗=1𝜇𝑗𝑔𝑗𝑥0𝑝𝑗=1𝜇𝑗𝑔𝑗𝑧.(5.24) Now, if condition (a) holds, from 𝐵-(𝑝,𝑟)-invexity with respect to 𝜂 and 𝑏8 at 𝑧 of 𝑝𝑗=1𝜇𝑗𝑔𝑗(), then 1𝑟𝑏1𝑥,𝑧𝑒𝑟(𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑥)𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧))11𝑝𝑝𝑗=1𝜇𝑗𝑔𝑗𝑧𝑒𝑝𝜂(𝑥,𝑧).𝟏(5.25) From the above inequality and inequality (5.24), we know that 1𝑝𝑝𝑗=1𝜇𝑗𝑔𝑗𝑧𝑒𝑝𝜂(𝑥,𝑧)𝟏0.(5.26) Multiplying (MWD) by (1/𝑝)(𝑒𝑝𝜂(𝑥,𝑧)1), we have 1𝑝𝑒𝑝𝜂(𝑥,𝑧)𝟏𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝐷𝑧1/2𝑧𝑓,𝑦𝑖+𝐵𝑤𝑓𝑧,𝑦𝑖+𝑧𝐵𝑧1/2𝑧,𝑦𝑖+𝐷𝑣𝑝𝑗=1𝜇𝑗𝑔𝑗𝑧=0.(5.27) Basing on the above inequality and (5.26), we get the inequality 1𝑝𝑒𝑝𝜂(𝑥,𝑧)𝟏𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝐷𝑧1/2𝑧𝑓,𝑦𝑖+𝐵𝑤𝑓𝑧,𝑦𝑖+𝑧𝐵𝑧1/2𝑧,𝑦𝑖𝐷𝑣0.(5.28) Since Υ8() is strictly 𝐵-(𝑝,𝑟)-invex with respect to the same function 𝜂 and the function 𝑏 at 𝑧 and the above inequality, we obtain Υ8𝑧<Υ8𝑥,(5.29) which contradicts relations (5.23). Hence 𝑥=𝑧 and 𝑧 is an optimal solution of (P).
If hypothesis (b) holds, from the strict 𝐵-(𝑝,𝑟)-invexity with respect to 𝜂 and 𝑏 at 𝑧 of Υ9() and equality (5.1), then Υ9𝑥>Υ9𝑧.(5.30) Relations (5.23) together with (5.24) yield 𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝑓𝐷𝑣𝑥,𝑦𝑖+𝑥𝑓𝑧𝐵𝑤,𝑦𝑖+𝑧𝐵𝑤𝑥,𝑦𝑖𝑥+𝐷𝑣𝑝𝑗=1𝜇𝑗𝑔𝑗𝑥𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝑓𝑧𝐷𝑣,𝑦𝑖+𝑧𝑓𝑧𝐵𝑤,𝑦𝑖+𝑧𝑧𝐵𝑤,𝑦𝑖𝑧+𝐷𝑣𝑝𝑗=1𝜇𝑗𝑔𝑗𝑧,(5.31) which contradicts (5.30). Hence 𝑧=𝑥 is also an optimal solution of (P). The proof is complete.

Remark 5.4. In Theorem 5.3, if 𝑝𝑗=1𝜇𝑗𝑔𝑗() is a strictly 𝐵-(𝑝,𝑟)-invex function with respect to 𝜂 and 𝑏8 and Υ8() is a 𝐵-(𝑝,𝑟)-invex function with respect to the same function 𝜂 and the function 𝑏, not necessarily, equal to 𝑏8, then Theorem 5.3 also holds.

6. Wolfe Dual-Type Model

Based on the result of Theorem 2.2, we can rewrite Theorem 2.2 as follows.

Theorem 6.1 ((necessary conditions) Lai and Lee [11, Theorem 4]). Let 𝑥0 be a (𝑃)-optimal solution, and let 𝑔𝑗(𝑥0), 𝑗𝐽(𝑥0) be linearly independent. Then there exist (𝑠,𝑡,𝑦)𝐾(𝑥0),(𝑤,𝑣)𝑛×𝑛, and 𝜇𝑝+ such that 𝑠𝑖=1𝑡𝑖𝑓𝑥0,𝑦𝑖+𝑥0𝐵𝑤+𝑝𝑗=1𝜇𝑗𝑔𝑗𝑥0𝑠𝑖=1𝑡𝑖𝑥0,𝑦𝑖𝑥0𝐷𝑣=0,𝑝𝑗=1𝜇𝑗𝑔𝑗𝑥0𝑡=0,𝑖0,𝑠𝑖=1𝑡𝑖𝑤=1,𝐵𝑤1,𝑣𝑥𝐷𝑣1,0𝑥𝐵𝑤=0𝐵𝑥01/2,𝑥0𝑥𝐷𝑣=0𝐵𝑥01/2.(6.1)

In this section, we present the Wolfe dual (WD) to the minimax program (P): max(𝑠,𝑡,𝑦)𝐾(𝑧)sup(𝑧,𝜇,𝑤,𝑣)𝐻3(𝑠,𝑡,𝑦)𝒜(𝑧),(WD) where 𝐻3(𝑠,𝑡,𝑦) denotes the set of (𝑧,𝜇,𝑤,𝑣)𝑛×𝑝+×𝑛×𝑛 satisfying 𝑠𝑖=1𝑡𝑖𝑓𝑧,𝑦𝑖+𝑧+𝐵𝑤𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧)𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝑤𝐷𝑣=0,(𝑠,𝑡,𝑦)𝐾,(6.2)𝐵𝑤1,𝑣𝑧𝐷𝑣1,𝑧𝐵𝑤=𝐵𝑧1/2,𝑧𝑧𝐷𝑣=𝐵𝑧1/2,(6.3)𝒜(𝑧)=𝑠𝑖=1𝑡𝑖𝑓𝑧,𝑦𝑖+𝑧+𝐵𝑤𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧)𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧.𝐷𝑣(6.4) If for a triplet (𝑠,𝑡,𝑦)𝐾(𝑧) the set 𝐻3(𝑠,𝑡,𝑦) is empty, then we define the supremum over it to be .

Let Γ denote the set of all feasible points of (WD). Moreover, we denote 𝑝𝑟𝑋Γ={𝑧𝑋(𝑧,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣)Γ}.

We assume throughout this section that 𝑠𝑖=1𝑡𝑖(𝑓(𝑧,𝑦𝑖)+𝑧𝐵𝑤)+𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧)0 and 𝑠𝑖=1𝑡𝑖((𝑧,𝑦𝑖)𝑧𝐷𝑣)>0.

We establish the weak, strong, and strict converse duality theorems for (𝑊𝐷) with respect to the primal problem (P).

Theorem 6.2 (weak duality). Let 𝑥 and (𝑧,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣) be (𝑃)-feasible and (𝑊𝐷)-feasible, respectively, and assume that Υ10()=𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝐷𝑣𝑠𝑖=1𝑡𝑖𝑓,𝑦𝑖+()+𝐵𝑤𝑝𝑗=1𝜇𝑗𝑔𝑗()𝑠𝑖=1𝑡𝑖𝑓𝑧,𝑦𝑖+𝑧+𝐵𝑤𝑝𝑗=1𝜇𝑗𝑔𝑗(𝑧)𝑠𝑖=1𝑡𝑖,𝑦𝑖()𝐷𝑣(6.5) is 𝐵-(𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑧 on 𝑋𝑝𝑟𝑋Γ; then supy𝑌𝑥𝑓(𝑥,𝑦)+𝐵𝑥1/2𝑥(𝑥,𝑦)𝐷𝑥1/2𝒜(𝑧).(6.6)

Proof. Suppose on the contrary that sup𝑦𝑌𝑥𝑓(𝑥,𝑦)+𝐵𝑥1/2𝑥(𝑥,𝑦)𝐷𝑥1/2<𝐴(𝑧).(6.7) Hence, we have an inequality 𝑥𝑓(x,𝑦)+𝐵𝑥1/2𝑥(𝑥,𝑦)𝐷𝑥1/2<𝐴(𝑧)𝑦𝑌.(6.8) Then, we get 𝑥𝑓(𝑥,𝑦)+𝐵𝑥1/2𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝑥𝐷𝑣(𝑥,𝑦)𝐷𝑥1/2𝑠𝑖=1𝑡𝑖𝑓𝑧,𝑦𝑖+𝑧+𝐵𝑤𝑝𝑖=1𝜇𝑗𝑔𝑗(𝑧)<0,(6.9) for all 𝑦𝑌.
If 𝑦 is replaced by 𝑦𝑖 in the above inequality and is multiplied by 𝑡𝑖, then summing up, we get 𝑠𝑖=1𝑡𝑖𝑓𝑥,𝑦𝑖+𝑥𝐵𝑥1/2𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝐷𝑣𝑠𝑖=1𝑡𝑖𝑥,𝑦𝑖𝑥𝐷𝑥1/2𝑠𝑖=1𝑡𝑖𝑓𝑧,𝑦𝑖+𝑧+𝐵𝑤𝑝𝑖=1𝜇𝑗𝑔𝑗(𝑧)<0.(6.10) By (2.6) and (6.3), we have Υ10(𝑥)𝑠𝑖=1𝑡𝑖𝑓𝑥,𝑦𝑖+𝑥𝐵𝑥1/2+𝑝𝑖=1𝜇𝑗𝑔𝑗(𝑥)𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝐷𝑣𝑠𝑖=1𝑡𝑖𝑥,𝑦𝑖𝑥𝐷𝑥1/2𝑠𝑖=1𝑡𝑖𝑓𝑧,𝑦𝑖+𝑧+𝐵𝑤𝑝𝑖=1𝜇𝑗𝑔𝑗<(𝑧)𝑝𝑖=1𝜇𝑗𝑔𝑗(𝑥)𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧.𝐷𝑣(6.11) Since 𝑠𝑖=1𝑡𝑖((𝑧,𝑦𝑖)𝑧𝐷𝑣)>0 and 𝑝𝑖=1𝜇𝑗𝑔𝑗(𝑥)0, it follows that Υ10(𝑥)<0=Υ10(𝑧).(6.12) Using the 𝐵-(𝑝,𝑟)-invexity with respect to 𝜂 and 𝑏 at 𝑧 of Υ10(), we have the inequality 1𝑝Υ10𝑒(𝑧)𝑝𝜂(𝑥,𝑧)𝟏<0.(6.13) This contradicts the equality of (6.2) ×(1/𝑝)(𝑒𝑝𝜂(𝑥,𝑧)𝟏). Here the proof is complete.

As a consequence of Theorems 6.1 and 6.2, we obtain Theorem 6.3. By a similar way, we can prove the strong duality and strictly converse duality theorems with respect to (P) and (WD) which we state as follows.

Theorem 6.3 (strong duality). Let 𝑥 be an optimal solution of (P) satisfying the hypothesis of Theorem 6.2. Then there exist (𝑠,𝑡,𝑦)𝐾(𝑥) and (𝑥,𝜇,𝑤,𝑣)𝐻3(𝑠,𝑡,𝑦) such that (𝑥,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣) is feasible for (WD). If any of the conditions of Theorem 6.2 hold, then (𝑥,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣) is an optimal solution of (WD) and the two problems (P) and (WD) have the same extremal values.

Theorem 6.4 (strict converse duality). Let 𝑥 and (𝑧,𝜇,𝑠,𝑡,𝑦,𝑤,𝑣) be optimal solutions of (P) and (WD), respectively. Suppose that the assumptions of Theorem 6.3 are fulfilled and Υ11()=𝑠𝑖=1𝑡𝑖𝑧,𝑦𝑖𝑧𝐷𝑣𝑠𝑖=1𝑡𝑖𝑓,𝑦𝑖+()𝐵𝑤+𝑝𝑗=1𝜇𝑗𝑔𝑗()𝑠𝑖=1𝑡𝑖𝑓𝑧,𝑦𝑖+𝑧𝐵𝑤+𝑝𝑗=1𝜇𝑗𝑔𝑗𝑧𝑠𝑖=1𝑡𝑖,𝑦𝑖()𝐷𝑣(6.14) is strictly 𝐵-(𝑝,𝑟)-invex with respect to 𝜂 and 𝑏 at 𝑧 on 𝑋𝑝𝑟𝑋Γ.

Then 𝑥=𝑧, that is, 𝑧 is an optimal solution of (P) and sup𝑦𝑌((𝑓(𝑧,𝑦)+((𝑧)𝐵𝑧)1/2)/((𝑧,𝑦)((𝑧)𝐷𝑧)1/2))=𝒜(𝑧).

Acknowledgment

The author is partly supported by NSC, Taiwan