Abstract

Using two successive reductions: B-equivalence of the system on a variable time scale to a system on a time scale and a reduction to an impulsive differential equation and by Leggett-Williams fixed point theorem, we investigate the existence of three positive periodic solutions to the nonlinear neutral functional differential equation on variable time scales with a transition condition between two consecutive parts of the scale (𝑑/𝑑𝑡)(𝑥(𝑡)+𝑐(𝑡)𝑥(𝑡𝛼))=𝑎(𝑡)𝑔(𝑥(𝑡))𝑥(𝑡)𝑛𝑗=1𝜆𝑗𝑓𝑗(𝑡,𝑥(𝑡𝑣𝑗(𝑡))), (𝑡,𝑥)𝕋0(𝑥),Δ𝑡|(𝑡,𝑥)𝒮2𝑖=Π1𝑖(𝑡,𝑥)𝑡, Δ𝑥|(𝑡,𝑥)𝒮2𝑖=Π2𝑖(𝑡,𝑥)𝑥, where Π1𝑖(𝑡,𝑥)=𝑡2𝑖+1+𝜏2𝑖+1(Π2𝑖(𝑡,𝑥)) and Π2𝑖(𝑡,𝑥)=𝐵𝑖𝑥+𝐽𝑖(𝑥)+𝑥,𝑖=1,2,.𝜆𝑗(𝑗=1,2,,𝑛) are parameters, 𝕋0(𝑥) is a variable time scale with (𝜔,𝑝)-property, 𝑐(𝑡),𝑎(𝑡), 𝑣𝑗(𝑡), and 𝑓𝑗(𝑡,𝑥)(𝑗=1,2,,𝑛) are 𝜔-periodic functions of 𝑡, 𝐵𝑖+𝑝=𝐵𝑖,𝐽𝑖+𝑝(𝑥)=𝐽𝑖(𝑥) uniformly with respect to 𝑖.

1. Introduction

In the last several decades, the theory of dynamic equations on time scales (DETS) has been developed very intensively. For the full description of the equations we refer to the nicely written books [1, 2] and papers [3, 4]. The equations have a very special transition condition for adjoint elements of time scales. To enlarge the field of applications of the DETS, Akhmet and Turan proposed to generalize the transition operator [5], correspondingly to investigate differential equations on variable time scales with transition condition (DETC). In [6], Akhmet and Turan proposed some basic theory of dynamic equations on variable time scales; the method of investigation is by means of two successive reductions: 𝐵-equivalence of the system [79] on a variable time scale to a system on a time scale and a reduction to an impulsive differential equation [5, 7]. Consequently, these results are very effective to develop methods of investigation of mechanical models with impacts.

Also, neutral differential equations arise in many areas of applied mathematics, and for this reason these equations have received much attention in the last few decades; they are not only an extension of functional differential equations but also provide good models in many fields including biology, mechanics, and economics. In particular, qualitative analysis such as periodicity and stability of solutions of neutral functional differential equations has been studied extensively by many authors. We refer to [1019] for some recent work on the subject of periodicity and stability of neutral equations. In [20], the authors discussed a class of neutral functional differential equations with impulses and parameters on nonvariable time scales𝑥(𝑡)+𝑐(𝑡)𝑥𝑡𝑟1Δ=𝑎(𝑡)𝑔(𝑥(𝑡))𝑥(𝑡)𝑛𝑖=1𝜆𝑖𝑓𝑖𝑡,𝑥𝑡𝜏𝑖,(𝑡)𝑡𝑡𝑗𝑥𝑡,𝑡𝕋,𝑗=1,2,,𝑞,𝑗𝑡𝑥+𝑗=𝐼𝑗𝑥𝑡𝑗,𝑡=𝑡𝑗,𝑗=1,2,,𝑞,(1.1) where 𝜆𝑖, 𝑖=1,2,,𝑛 are parameters, 𝕋 is an 𝜔-periodic nonvariable time scale, 𝑎𝐶(𝕋,+),𝑐𝐶(𝕋,[0,1)) and both of them are 𝜔-periodic functions, 𝜏𝑖𝐶(𝕋,),𝑖=1,2,,𝑛 are 𝜔-periodic functions, 𝑓𝑖𝐶(𝕋×+,+),𝑖=1,2,,𝑛 are nondecreasing with respect to their second arguments and 𝜔-periodic with respect to their first arguments, respectively; 𝑔𝐶(,+) and there exist two positive constants 𝑙,𝐿 such that 0<𝑙𝑔(𝑥)𝐿< for all 𝑥>0,𝐼𝑗𝐶(,+)(𝑗=1,2,,𝑞) and is bounded, 𝑟1 is a constant.

To the best of authors’ knowledge, there has been no paper published on the existence of solutions to neutral functional differential equations on variable time scales. Our main purpose of this paper is by using theory of dynamic equations on variable time scales to investigate the existence of three positive periodic solutions to the nonlinear neutral functional differential equations on variable time scales with a transition condition between two consecutive parts of the scaledd𝑡(𝑥(𝑡)+𝑐(𝑡)𝑥(𝑡𝛼))=𝑎(𝑡)𝑔(𝑥(𝑡))𝑥(𝑡)𝑛𝑗=1𝜆𝑗𝑓𝑗𝑡,𝑥𝑡𝑣𝑗(𝑡),(𝑡,𝑥)𝕋0(𝑥),Δ𝑡|(𝑡,𝑥)𝒮2𝑖=Π1𝑖(𝑡,𝑥)𝑡,Δ𝑥(𝑡,𝑥)𝒮2𝑖=Π2𝑖(𝑡,𝑥)𝑥,(1.2) where Π1𝑖(𝑡,𝑥)=𝑡2𝑖+1+𝜏2𝑖+1(Π2𝑖(𝑡,𝑥)) and Π2𝑖(𝑡,𝑥)=𝐵𝑖𝑥+𝐽𝑖(𝑥)+𝑥,𝑖=1,2,𝜆𝑗(𝑗=1,2,,𝑛) are parameters, 𝕋0(𝑥) is a variable time scale with (𝜔,𝑝)-property, 𝑐(𝑡),𝑎(𝑡), 𝑣𝑗(𝑡), and 𝑓𝑗(𝑡,𝑥)(𝑗=1,2,,𝑛) are 𝜔-periodic functions of 𝑡, 𝐵𝑖+𝑝=𝐵𝑖,𝐽𝑖+𝑝(𝑥)=𝐽𝑖(𝑥) uniformly with respect to 𝑖.

For convenience, we introduce the notation𝑎=max[]𝑡0,𝜔𝑎(𝑡),𝑎=mint[]0,𝜔𝑎(𝑡),𝑐=min[]𝑡0,𝜔𝑐(𝑡),𝑐=max[]𝑡0,𝜔𝑐(𝑡),𝑟0=exp0𝜔.𝑎(𝑠)d𝑠(1.3)

Throughout this paper, we assume the following.(H1) 𝕋0(𝑥) is a variable time scale with (𝜔,𝑝)-property, 𝑐𝐶(,[0,1)),𝑎𝐶(,+),𝑣𝑗𝐶(,), and 𝑓𝑗(𝑡,𝑥)𝐶(𝕋0(𝑥),+),(𝑗=1,2,,𝑛) are 𝜔-periodic functions of 𝑡, 𝐽𝑖𝐶(,),𝐵𝑖+𝑝=𝐵𝑖,𝐽𝑖+𝑝(𝑥)=𝐽𝑖(𝑥) uniformly with respect to 𝑖,𝐽𝑖(0)=0,𝐵𝑖0 for each 𝑖.(H2) 𝑓𝑗(𝑡,𝑥)𝐶(𝕋0(𝑥),+) is nondecreasing with respect to 𝑥 and 𝑓𝑗(𝑡,0)=0 for each 𝑗{1,2,,𝑛}.(H3)𝑔𝐶(,+) and there exist two positive constants 𝑙, 𝐿 such that 0<𝑙𝑔(𝑥)𝐿< for all 𝑥>0.(H4)There exists a number 𝛿>0 such that (𝑐+𝑐)/2𝛿<1,0((2𝛿𝑐)(1𝑐2))/(1(2𝛿𝑐)2)<𝑟𝐿0(1𝑟𝑙0)/(1𝑟𝐿0).

2. Preliminaries

Let 𝐸 be a real Banach space and 𝑃 be a cone in 𝐸. A map 𝜌 is said to be a nonnegative continuous concave functional on 𝑃 if 𝜌𝑃[0,) is continuous and []𝜌(𝑡𝑥+(1𝑡)𝑦)𝑡𝜌(𝑥)+(1𝑡)𝜌(𝑦)𝑥,𝑦𝑃and𝑡0,1.(2.1)

For numbers 𝛽1,𝛽4 such that 0<𝛽1<𝛽4 and 𝜌 is a nonnegative continuous concave function on 𝑃, we define the following sets: 𝑃𝛽1={𝑥𝑃𝑥<𝛽1},𝑃𝛽1={𝑥𝑃𝑥𝛽1},𝑃(𝜌,𝛽1,𝛽4)={𝑥𝑃𝛽1𝜌(𝑥),𝑥𝛽4}.

Now, we state the following Leggett-Williams fixed-point theorem, which is critical to the proof of our main results.

Lemma 2.1 (see [21]). Let 𝑇𝑃𝛽4𝑃𝛽4 be completely continuous and 𝜌 nonnegative continuous concave functional on 𝑃 such that 𝜌(𝑢)𝑢 for all 𝑢𝑃𝛽4. Suppose that there exist positive constants 𝛽1,𝛽2,𝛽3,𝛽4 with 0<𝛽1<𝛽2<𝛽3𝛽4 such that(1){𝑢𝑃(𝜌,𝛽2,𝛽3)𝜌(𝑥)>𝛽2}𝜙 and 𝜌(𝑇𝑢)>𝛽2 for 𝑢𝑃(𝜌,𝛽2,𝛽3);(2)𝑇𝑢<𝛽1 for 𝑢𝑃𝛽1;(3)𝜌(𝑇𝑢)>𝛽2 for 𝑢𝑃(𝜌,𝛽2,𝛽4) with 𝑇𝑢>𝛽3.

Then 𝑇 has at least three fixed points 𝑢1,𝑢2,𝑢3 satisfying𝑢1𝑃𝛽1,𝑢2𝑢𝑃𝜌,𝛽2,𝛽4𝜌(𝑢)>𝛽2,𝑢3𝑃𝛽4𝑃𝜌,𝛽2,𝛽4𝑃𝛽1.(2.2)

Let 𝕋 be a periodic time scale, and let 𝐸={𝑥𝐶(𝕋,)𝑥(𝑡)=𝑥(𝑡+𝜔)} be a Banach space with the norm 𝑥=sup𝑡[0,𝜔]𝕋{|𝑥(𝑡)|𝑥𝐸}, and let Φ𝐸𝐸 be defined by(Φ𝑥)(𝑡)=𝑥(𝑡)+𝑐(𝑡)𝑥(𝑡𝜏).(2.3)

Lemma 2.2 (see [20]). If 0𝑐(𝑡)<1 and 𝐸 is a Banach space, then Φ has a bounded inverse Φ1 on 𝐸, and for all 𝑥𝐸, Φ1𝑥(𝑡)=𝑗00𝑖𝑗1(1)𝑘𝑐(𝑡𝑖𝜏)𝑥(𝑡𝑗𝜏)(2.4) and Φ1𝑥𝑥/(1𝑐).

Definition 2.3 (see [6]). A nonempty closed set 𝕋0(𝑥) in ×𝑛 is said to be a variable time scale if for any 𝑥0𝑛 the projection of 𝕋0(𝑥0) on time axis, that is, the set {𝑡(𝑡,𝑥0)𝕋0(𝑥0)} is a time scale in Hilger sense.
Fix a sequence {𝑡𝑖} such that 𝑡𝑖<𝑡𝑖+1 for all 𝑖, and |𝑡𝑖| as |𝑖|. Denote 𝛿𝑖=𝑡2𝑖1𝑡2𝑖, 𝜅𝑖=𝑡2𝑖𝑡2𝑖1 and take a sequence of functions {𝜏𝑖(𝑥)}𝐶(𝑛,). Assume that(C1) for some positive numbers 𝜃,𝜃,𝜃𝑡𝑖+1𝑡𝑖𝜃;(C2)there exists 𝑙0, 0<2𝑙0<𝜃 such that 𝜏𝑖(𝑥)𝑙0 for all 𝑥𝑛,𝑖.
Denote 𝑙𝑖=inf𝑥𝑛𝑡𝑖+𝜏𝑖(𝑥),𝑟𝑖=sup𝑥𝑛𝑡𝑖+𝜏𝑖.(𝑥)(2.5)
We set 𝑖=(𝑡,𝑥)×𝑛𝑡2𝑖+𝜏2𝑖(𝑥)<𝑡<𝑡2𝑖+1+𝜏2𝑖+1,𝒮(𝑥)𝑖=(𝑡,𝑥)×𝑛𝑡=𝑡𝑖+𝜏𝑖(,𝒟𝑥)𝑖=(𝑡,𝑥)×𝑛𝑡2𝑖1+𝜏2𝑖1(𝑥)𝑡𝑡2𝑖+𝜏2𝑖.(𝑥)(2.6)
Following [6], we denote 𝕋0(𝑥)=𝑖=𝒟𝑖 and 𝕋𝑐=𝑖=[𝑡2𝑖1,𝑡2𝑖].

A transition operator Π𝑖𝒮2𝑖𝒮2𝑖+1, for all 𝑖, such that Π𝑖(𝑡,𝑦)=(Π1𝑖(𝑡,𝑦),Π2𝑖(𝑡,𝑦)) where Π1𝑖𝒮2𝑖 and Π2𝑖𝒮2𝑖𝑛, andΠ1𝑖(𝑡,𝑦)=𝑡2𝑖+1+𝜏2𝑖+1Π2𝑖(𝑡,𝑦),Π2𝑖(𝑡,𝑦)=𝐼𝑖(𝑦)+𝑦,(2.7) where 𝐼𝑖𝑛𝑛 is a function. One can easily see that Π1𝑖(𝑡,𝑦) is the time coordinate of (𝑡+,𝑦+)=Π𝑖(𝑡,𝑦), the image of (𝑡,𝑦)𝒮2𝑖 under the operator Π𝑖, and Π2𝑖(𝑡,𝑦) is the space coordinate of the image.

Let 𝑡=𝛼𝑖 and 𝑡=𝛽𝑖 be the moments that the graph of 𝑦=𝜑(𝑡) intersects the surface 𝒮2𝑖1 and 𝒮2𝑖, respectively, where the surfaces are defined previously. Then, we set the nonvariable time scale𝕋𝜑𝑐=𝑖=𝛼𝑖,𝛽𝑖,(2.8) which is the domain of 𝜑, and define the Δ-derivative as in the introduction. That is, for 𝑡=𝛽𝑖, we have𝜑Δ𝛽𝑖=𝜑𝛼𝑖+1𝛽𝜑𝑖𝛼𝑖+1𝛽𝑖,𝜑Δ(𝑡)=lim𝑠𝑡𝜑(𝑠)𝜑(𝑡),𝑠𝑡(2.9) for any other 𝑡𝕋𝜑𝑐, whenever the limit exists.

Consider the system on variable time scales:𝑦=𝐴(𝑡)𝑦+𝑓(𝑡,𝑦),(𝑡,𝑦)𝕋0(𝑦),Δ𝑡|(𝑡,𝑦)𝒮2𝑖=Π1𝑖(𝑡,𝑦)𝑡,Δ𝑦|(𝑡,𝑦)𝒮2𝑖=Π2𝑖(𝑡,𝑦)𝑦,(2.10) where 𝐴(𝑡)𝑛×𝑛 is an 𝑛×𝑛 continuous real-valued matrix function, 𝐵𝑖 is an 𝑛×𝑛 matrix, functions 𝑓(𝑡,𝑦)𝕋0(𝑦)𝑛 and 𝐽𝑖(𝑦)𝑛𝑛 are continuous, Π1𝑖(𝑡,𝑦)=𝑡2𝑖+1+𝜏2𝑖+1(Π2𝑖(𝑡,𝑦)), and Π2𝑖(𝑡,𝑦)=𝐵𝑖𝑦+𝐽𝑖(𝑦)+𝑦.

For any 𝛼,𝛽 we define the oriented interval [𝛼,𝛽] as=[][]𝛼,𝛽𝛼,𝛽,if𝛼𝛽,𝛽,𝛼,otherwise.(2.11)

Consider the nonvariable time scale𝕋0𝑐=𝑖=𝑙2𝑖1,𝑟2𝑖,(2.12) where 𝑙𝑖,𝑟𝑖,𝑖 are defined by (2.5) for the variable time scale 𝕋0(𝑦), and take a continuation 𝑓𝕋0𝑐×𝑛𝑛 of 𝑓𝕋0(𝑦)𝑛 which is Lipschitzian with the same Lipschitz constant 𝑙; furthermore, if 𝑓 is a monotone function, a continuation 𝑓 can also have the same monotony with 𝑓. Set 𝕋𝑐=𝑖=[𝑡2𝑖1,𝑡2𝑖].(C3)𝜏𝑖(𝑥)𝜏𝑖(𝑦)+𝐽𝑖(𝑥)𝐽𝑖(𝑦)+𝑓(𝑡,𝑥)𝑓(𝑡,𝑦)𝑙𝑥𝑦 for arbitrary 𝑥,𝑦𝑛, where 𝑙 is a Lipschitz constant.

By (C3), in [6], one can see the following important lemma.

Lemma 2.4 (see [6]). Assume (C3) is satisfied. Then there are mappings 𝑊𝑖(𝑧)𝑛𝑛,𝑖, such that, corresponding to each solution 𝑦(𝑡) of (2.10), there is a solution 𝑧(𝑡) of the system 𝑧=𝐴(𝑡)𝑧+𝑓(𝑡,𝑧),𝑡𝑡2𝑖,𝑧𝑡2𝑖+1=𝐵𝑖𝑧𝑡2𝑖+𝑊𝑖𝑧𝑡2𝑖𝑡+𝑧2𝑖,(2.13) such that 𝑦(𝑡)=𝑧(𝑡) for all 𝑡𝕋𝑐 except possibly on [𝑡2𝑖1,𝛼𝑖] and [𝛽𝑖,𝑡2𝑖], where 𝛼𝑖 and 𝛽𝑖 are the moments that 𝑦(𝑡) meets the surfaces 𝒮2𝑖1 and 𝒮2𝑖, respectively.
Furthermore, the functions 𝑊𝑖 satisfy the inequality 𝑊𝑖(𝑧)𝑊𝑖(𝑦)𝑘(𝑙)𝑙𝑧𝑦,(2.14) uniformly with respect to 𝑖 for all 𝑧,𝑦𝑛 such that 𝑧 and 𝑦; here 𝑘(𝑙0)=𝑘(𝑙0,) is a bounded function. Under the sense of Lemma 2.4, we say that systems (2.10) and (2.13) are 𝐵-equivalent.

Proof. Fix 𝑖. Let 𝑧(𝑡) be the solution of (2.10) such that 𝑧(𝑡2𝑖)=𝑧, and assume that 𝛼i and 𝛽𝑖 are solutions of 𝛼=𝑡2𝑖1+𝜏2𝑖1(𝑧(𝛼)) and 𝛽=𝑡2𝑖+𝜏2𝑖(𝑧(𝛽)), respectively. Let 𝑧1(𝑡) be the solution of the system 𝑧=𝐴(𝑡)𝑧+𝑓(𝑡,𝑧)(2.15) with the initial condition 𝑧1(𝛼𝑖+1)=Π2𝑖(𝛽𝑖,𝑧(𝛽𝑖)).
We first note that 𝑧1(𝛼𝑖+1)=(𝐼+𝐵𝑖)𝑧(𝛽𝑖)+𝐽𝑖(𝑧(𝛽𝑖)). Moreover, for 𝑡𝑡[2𝑖,𝛽𝑖],𝑡𝑧(𝑡)=𝑧2𝑖+𝑡𝑡2𝑖𝐴(𝑠)𝑧(𝑠)+𝑓(𝑠,𝑧(𝑠))d𝑠,(2.16) and for 𝛼𝑡[𝑖+1,𝑡2𝑖+1], 𝑧1(𝑡)=𝑧1𝛼𝑖+1+𝑡𝛼𝑖+1𝐴(𝑠)𝑧1(𝑠)+𝑓𝑠,𝑧1(=𝑠)d𝑠𝐼+𝐵𝑖𝑧𝛽𝑖+𝐽𝑖𝑧𝛽𝑖+𝑡𝛼𝑖+1𝐴(𝑠)𝑧1𝑓(𝑠)+𝑠,𝑧1=(𝑠)d𝑠𝐼+𝐵𝑖𝑧𝑡2𝑖+𝛽𝑖𝑡2𝑖𝐴(𝑠)𝑧(𝑠)+𝑓(𝑠,𝑧(𝑠))d𝑠+𝐽𝑖𝑧𝛽𝑖+𝑡𝛼𝑖+1𝐴(𝑠)𝑧1𝑓(𝑠)+𝑠,𝑧1(𝑠)d𝑠.(2.17) Thus, we have 𝑊𝑖(𝑧)=𝐼+𝐵𝑖𝛽𝑖𝑡2𝑖𝐴(𝑠)𝑧(𝑠)+𝑓(𝑠,𝑧(𝑠))d𝑠+𝐽𝑖𝑧𝛽𝑖+𝑡2𝑖+1𝛼𝑖+1𝐴(𝑠)𝑧1𝑓(𝑠)+𝑠,𝑧1(𝑠)d𝑠.(2.18)
Substituting (2.18) in (2.13), we see that 𝑊𝑖(𝑧) satisfies the first conclusion of the lemma.
Next, we prove (2.14). Let 𝑧(𝑡2𝑖). By employ integrals (2.16) and (2.17), we find that the solutions 𝑧(𝑡) and 𝑧1(𝑡) determined above satisfy the inequalities 𝑧(𝑡)𝐻 and 𝑧1(𝑡)𝐻 on [𝛽𝑖,𝑡2𝑖] and[𝛼𝑖+1,𝑡2𝑖+1], where 𝐻=𝑀(1+𝑙)+(1+𝑁+𝑙)(+𝑀𝑙)𝑒𝑁𝑙+𝑙2𝑒𝑁𝑙+𝑙2.(2.19) Let 𝑦(𝑡) be the solution of (2.10) such that 𝑦(𝑡2𝑖)=𝑦, and assume that𝛼𝑖 and𝛽𝑖 are solutions of𝛼=𝑡2𝑖1+𝜏2𝑖1(𝑦(𝛼)) and𝛽=𝑡2𝑖+𝜏2𝑖(𝑦(𝛽)), respectively. Let 𝑦1(𝑡) be the solution of (2.15) with initial condition 𝑦1(𝛼𝑖+1)=Π2𝑖(𝛽𝑖,𝑦(𝛽𝑖)). Without loss of any generality, we assume that𝛽𝑖𝛽𝑖 and 𝛼𝑖+1𝛼𝑖+1. Application of the Gronwall-Bellman lemma shows that, for 𝛽𝑡[𝑖,𝑡2𝑖], 𝑧(𝑡)𝑦(𝑡)𝑒(𝑁+𝑙)𝑙𝑧𝑦.(2.20) The equation 𝑦𝛽𝑖𝛽=𝑦𝑖+𝛽𝑖𝛽𝑖𝐴(𝑠)𝑦(𝑠)+𝑓(𝑠,𝑦(𝑠))d𝑠(2.21) gives us 𝑦𝛽𝑖𝛽𝑦𝑖(𝑁𝐻+𝑙𝐻+𝑀)𝛽𝑖𝛽𝑖.(2.22) Thus, we obtain 𝑧𝛽𝑖𝑦𝛽𝑖𝑒(𝑁+𝑙)𝑙𝑧𝑦+(𝑁𝐻+𝑙𝐻+𝑀)𝛽𝑖𝛽𝑖.(2.23) Now condition (C3) together with (2.23) leads to 𝛽𝑖𝛽𝑖𝑙𝑒(𝑁+𝑙)𝑙1𝑙(𝑁𝐻+𝑙𝐻+𝑀)𝑧𝑦.(2.24) Hence (2.23) becomes 𝑧𝛽𝑖𝑦𝛽𝑖𝑒(𝑁+𝑙)𝑙1𝑙(𝑁𝐻+𝑙𝐻+𝑀)𝑧𝑦.(2.25) On the other hand, 𝑦1𝛼𝑖+1=𝑦1𝛼𝑖+1+𝛼𝑖+1𝛼𝑖+1𝐴(𝑠)𝑦1𝑓(𝑠)+𝑠,𝑦1(𝑠)d𝑠(2.26) gives us 𝑦1𝛼𝑖+1𝑦1𝛼𝑖+1𝛼(𝑁𝐻+𝑙𝐻+𝑀)𝑖+1𝛼𝑖+1.(2.27) Using the transition operators and (2.25) we get 𝑧1𝛼𝑖+1𝑦1𝛼𝑖+1(1+𝑁+𝑙)𝑒(𝑁+𝑙)𝑙1𝑙(𝑁𝐻+𝑙𝐻+𝑀)𝑧𝑦.(2.28) Condition (C3) and (2.28) imply that 𝛼𝑖+1𝛼𝑖+1𝑙(1+𝑁+𝑙)𝑒(𝑁+𝑙)𝑙1𝑙(𝑁𝐻+𝑙𝐻+𝑀)𝑧𝑦.(2.29) From (2.27)–(2.29) we obtain 𝑧1𝛼𝑖+1𝑦1𝛼𝑖+1𝐻1𝑒(𝑁+𝑙)𝑙𝑧𝑦,(2.30) where 𝐻1=(1+𝑁+𝑙)[1+𝑙(𝑁𝐻+𝑙𝐻+𝑀)]/[1𝑙(𝑁𝐻+𝑙𝐻+𝑀)]. Solutions 𝑧1(𝑡) and 𝑦1(𝑡) on [𝛼𝑖+1,𝑡2𝑖+1] satisfy the inequality 𝑧1(𝑡)𝑦1(𝑡)𝐻1𝑒2(𝑁+𝑙)𝑙𝑧𝑦.(2.31) Now subtracting the expression 𝑊𝑖(𝑦)=𝐼+𝐵𝑖𝛽𝑖𝑡2𝑖𝐴(𝑠)𝑦(𝑠)+𝑓(𝑠,𝑦(𝑠))d𝑠+𝐽𝑖𝑦𝛽𝑖+𝑡2𝑖+1𝛼𝑖+1𝐴(𝑠)𝑦1𝑓(𝑠)+𝑠,𝑦1(𝑠)d𝑠(2.32) from (2.18) and using (2.20), (2.24), (2.29), and (2.31), we conclude that (2.14) holds. The proof is complete.

A special transformation called 𝜓-substitution [5], which is change of the independent variable and defined for 𝑡𝑖=(𝑡2𝑖1,𝑡2𝑖] as 𝜓(𝑡)=𝑡0<𝑡2𝑘<𝑡𝛿𝑘,𝑡0,𝑡+𝑡𝑡2𝑘<0𝛿𝑘,𝑡<0,(2.33) where 𝛿𝑘=𝑡2𝑘+1𝑡2𝑘. Setting 𝑠𝑖=𝜓(𝑡2𝑖), we see that this transformation has an inverse given by𝜓1(𝑠)=𝑠+0<𝑠𝑘<𝑠𝛿𝑘,𝑠0,𝑠𝑠𝑠𝑘<0𝛿𝑘,𝑠<0.(2.34)

Lemma 2.5 (see [5, 6]). 𝜓(𝑡)=1 if 𝑡𝑖=(𝑡2𝑖1,𝑡2𝑖].

Proof. Assume that 𝑡0. Then, 𝜓(𝑡)=lim0𝜓(𝑡+)𝜓(𝑡)=lim01𝑡+0<𝑡2𝑘<𝑡+𝛿𝑘𝑡0<𝑡2𝑘<𝑡𝛿𝑘=1.(2.35) The assertion for 𝑡<0 can be proved in the same way. The proof is complete.

Definition 2.6 (see [5]). The time scale 𝕋0 is said to have an 𝜔-property if there exists a number 𝜔+ such that 𝑡+𝜔𝕋0 whenever 𝑡𝕋0.

Definition 2.7 (see [5]). A sequence {𝑎𝑖} is said to satisfy an (𝜔,𝑝)-property if there exist numbers 𝜔+ and 𝑝 such that 𝑎𝑖+𝑝=𝑎𝑖+𝜔 for all 𝑖.

Definition 2.8 (see [6]). The variable time scale 𝕋0(𝑦) is said to satisfy an (𝜔,𝑝)-property if (𝑡±𝜔,𝑦) is in 𝕋0(𝑦) whenever (𝑡,𝑦) is. In this case, there exists 𝑝 such that the sequences {𝑡2𝑖1} and {𝑡2𝑖} satisfy the (𝜔,𝑝)-property and 𝜏𝑖+𝑝(𝑦)=𝜏𝑖(𝑦) for all 𝑖.
Suppose now that (2.10) is 𝜔-periodic; that is, 𝕋0(𝑦) satisfies the (𝜔,𝑝)-property, 𝐴(𝑡) and 𝑓(𝑡,𝑦) are 𝜔-periodic functions of 𝑡, and 𝐵𝑖+𝑝=𝐵𝑖,𝐽𝑖+𝑝(𝑦)=𝐽𝑖(𝑦) uniformly with respect to 𝑖.

Lemma 2.9 (see [6]). If (2.10) is 𝜔-periodic, then the sequence 𝑊𝑖(𝑧) is 𝑝-periodic uniformly with respect to 𝑧𝑛.

Proof. Since the variable time scale 𝕋0(𝑦) satisfies an (𝜔,𝑝)-property, by (2.18), one can easily see that 𝑊𝑖(𝑧) is 𝑝-periodic uniformly with respect to 𝑧𝑛. The proof is complete.

Lemma 2.10 (see [5]). If 𝕋0 has an 𝜔-property, then the sequence {𝑠𝑖},𝑠𝑖=𝜓(𝑡2𝑖), is (𝜔,𝑝0)-periodic with 𝜔=𝜔0<𝑡2𝑘<𝜔𝛿𝑘=𝜓(𝜔).(2.36)

Proof. In order to prove this lemma, we only need to verify that 𝑠𝑖+𝑝0=𝑠𝑖+𝜔 for all 𝑖. Assume that 𝑖0,𝑖=𝑛𝑝0+𝑗 for some 𝑛,0𝑗<𝑝0 and 0<𝑡0<<𝑡2(𝑝01)<𝜔. Then 𝑠𝑖+𝑝0𝑡=𝜓2(𝑖+𝑝0)=𝑡2(𝑖+𝑝0)0<𝑡2𝑘<𝑡0)2(𝑖+𝑝𝛿𝑘=𝑡2𝑖+𝜔0<𝑡2𝑘<𝑡2i𝛿𝑘𝑡2𝑖𝑡2𝑘<𝑡0)2(𝑖+𝑝𝛿𝑘𝑡=𝜓2𝑖+𝜔𝑖+𝑝01𝑘=𝑖𝛿𝑘=𝑠𝑖+𝜔𝑗+𝑝01𝑘=𝑗𝛿𝑘+𝑛𝑝0=𝑠𝑖+𝜔𝑗+𝑝01𝑘=𝑗𝛿𝑘=𝑠𝑖+𝜔𝑝01𝑘=0𝛿𝑘=𝑠𝑖+𝜔0<𝑡2𝑘<𝜔𝛿𝑘=𝑠𝑖+𝜔,(2.37) where we have used the fact that 𝑗+𝑝01𝑘=𝑗𝛿𝑘=𝑝01𝑘=𝑗𝛿𝑘+𝑗+𝑝01𝑘=𝑝0𝛿𝑘=𝑝01𝑘=𝑗𝛿𝑘+𝑗1𝑘=0𝛿𝑘+𝑝0=𝑝01𝑘=𝑗𝛿𝑘+𝑗1𝑘=0𝛿𝑘=𝑝01𝑘=0𝛿𝑘.(2.38) All other cases can be verified similarly. The proof is complete.

Lemma 2.11 (see [5, 6]). If 𝕋0(𝑦) satisfies an (𝜔,𝑝)-property, then 𝜓(𝑡+𝜔)=𝜓(𝑡)+𝜓(𝜔).Proof. Assume that 𝑡0. By Lemma 2.10, we have 𝜓(𝑡+𝜔)=𝑡+𝜔0<𝑡2𝑘<𝑡+𝜔𝛿𝑘=𝑡+𝜔0<𝑡2𝑘<𝜔𝛿𝑘𝜔𝑡2𝑘<𝑡+𝜔𝛿𝑘=𝑡𝜔𝑡2𝑘<𝑡+𝜔𝛿𝑘+𝜓(𝜔)=𝜓(𝑡)+𝜓(𝜔).(2.39) The assertion for 𝑡<0 can be proved in the same way. The proof is complete.

Lemma 2.12 (see [5, 6]). A function 𝜙(𝑡) is an 𝜔-periodic function on 𝕋𝑐, if and only if 𝜙(𝜓1(𝑠)) is an 𝜔-periodic function on , where 𝜔=𝜓(𝜔).

Proof. By Lemma 2.11, 𝑠+𝜔=𝜓(𝑡+𝜔). Then the equality 𝜙𝜓1𝜓𝑠+𝜔=𝜙(𝑡+𝜔)=𝜙(𝑡)=𝜙1(𝑠)(2.40) completes the proof.

For any fixed 𝑥0, we set 𝕋𝑥𝑃𝐶0=𝑡𝑥𝐶2𝑖1+𝜏2𝑖1𝑥0,𝑡2𝑖+𝜏2𝑖𝑥0,Π2𝑖(𝑡,𝑥)=𝐵𝑖𝑥+𝐽𝑖(𝑥)+𝑥,𝑖=1,2,(2.41) and consider the Banach space 𝕋𝑥𝐸=𝑥𝑥𝑃𝐶0𝑥(𝑡)=𝑥(𝑡+𝜔).(2.42) Let Φ𝐸𝐸 be defined by(Φ𝑥)(𝑡)=𝑥(𝑡)+𝑐(𝑡)𝑥(𝑡𝛼)=𝑦(𝑡).(2.43)

Using the inverse transformation of Φ, we can obtainΠ1𝑖𝑡,Φ1𝑦=𝑡2𝑖+1+𝜏2𝑖+1Π2𝑖𝑡,Φ1𝑦,Π2𝑖𝑡,Φ1𝑦=𝐵𝑖Φ1𝑦+𝐽𝑖Φ1𝑦+Φ1𝑦.(2.44) From the second equation, it is easy to getΦΠ2𝑖𝑡,Φ1𝑦=Φ𝐵𝑖Φ1𝑦+Φ𝐽𝑖Φ1Π𝑦+𝑦=2𝑖(𝑡,𝑦),(2.45) that is, Π2𝑖(𝑡,Φ1𝑦)=Φ1(Π2𝑖(𝑡,𝑦)). HenceΠ1𝑖𝑡,Φ1𝑦=𝑡2𝑖+1+𝜏2𝑖+1Φ1Π2𝑖(𝑡,𝑦)=𝑡2𝑖+1+𝜏2𝑖+1Φ1Π2𝑖(𝑡,𝑦)=𝑡2𝑖+1+̃𝜏2𝑖+1Π2𝑖Π(𝑡,𝑦)=1𝑖(𝑡,𝑦).(2.46)

Therefore, we can obtain the other variable time scale plane 𝑇0(𝑦) by the inverse transformation of Φ and𝑖=(𝑡,𝑦)×𝑡2𝑖+̃𝜏2𝑖(𝑦)<𝑡<𝑡2𝑖+1+̃𝜏2𝑖+1,𝒮(𝑦)𝑖=(𝑡,𝑦)×𝑡=𝑡𝑖+̃𝜏𝑖,𝒟(𝑦)𝑖=(𝑡,𝑦)×𝑡2𝑖1+̃𝜏2𝑖1(𝑦)𝑡𝑡2𝑖+̃𝜏2𝑖.(𝑦)(2.47)

Hence, (1.2) can be changed into the following form:𝑦Φ=𝑎(𝑡)𝑔1𝑦(𝑡)𝑦(𝑡)𝑎(𝑡)𝐻(𝑦(𝑡))𝑛𝑗=1𝜆𝑗𝑓𝑗Φ𝑡,1𝑦𝑡𝑣𝑗(𝑡),(𝑡,𝑦)𝕋0(𝑦),Δ𝑡|(𝑡,𝑦)𝒮2𝑖=Π1𝑖(𝑡,𝑦)𝑡,Δ𝑦|(𝑡,𝑦)𝒮2𝑖=Π2𝑖(𝑡,𝑦)𝑦,(2.48) where 𝐻(𝑦(𝑡))=𝑐(𝑡)𝑔((Φ1𝑦)(𝑡))(Φ1𝑦)(𝑡𝛼).

Define a cone in 𝐸 by𝑃0={𝑦(𝑡)𝐸𝑦(𝑡)𝑘𝑦},(2.49) where 𝑘(((2𝛿𝑐)(1𝑐2))/(1(2𝛿𝑐)2),𝑟𝐿0(1𝑟𝑙0)/(1𝑟𝐿0)].

Lemma 2.13 (see [20]). Suppose that conditions (H1)–(H4) hold and 0𝑐(𝑡)<1 and 𝑦𝑃0, then Φ𝛼𝑦1𝑦1(𝑡)1𝑐𝑦,(2.50)𝑙𝑐𝐿𝛼𝑦𝐻(𝑦(𝑡))𝑐1𝑐𝑦,(2.51) where 𝛼=(𝑘/(1𝑐2))(2𝛿𝑐)/(1(2𝛿𝑐)2).

(H5)𝜏𝑖(𝑥)𝜏𝑖(𝑦)+𝐽𝑖(𝑥)𝐽𝑖(𝑦)+𝑛𝑗=1𝑓𝑗(𝑡,𝑥)𝑓𝑗(𝑡,𝑦)𝑙0𝑥𝑦 for arbitrary 𝑥,𝑦𝑛, where 𝑙0 is a Lipschitz constant.

In view of (H5) by Lemma 2.4, it is easy to get the following lemma.

Lemma 2.14. Assume that (H5) is satisfied. Then there are mappings 𝑊𝑖(𝑧),𝑖 such that, corresponding to each solution 𝑦(𝑡) of (2.48), there is a solution 𝑧(𝑡) of the system 𝑧Φ=𝑎(𝑡)𝑔1𝑧(𝑡)𝑧(𝑡)𝑎(𝑡)𝐻(𝑧(𝑡))𝑛𝑗=1𝜆𝑗𝑓𝑗Φ𝑡,1𝑧𝑡𝑣𝑗(𝑡),𝑡𝑡2𝑖,𝑧𝑡2𝑖+1=Φ𝐵𝑖Φ1𝑧𝑡2𝑖+Φ𝑊𝑖Φ1𝑧𝑡2𝑖𝑡+𝑧2𝑖,𝑡=𝑡2𝑖(2.52) such that 𝑦(𝑡)=𝑧(𝑡) for all 𝑡𝕋𝑐 except possibly on [𝑡2𝑖1,𝛼𝑖] and [𝛽𝑖,𝑡2𝑖] where 𝛼𝑖 and 𝛽𝑖 are the moments that 𝑦(𝑡) meets the surfaces 𝒮2𝑖1 and 𝒮2𝑖, respectively.
Furthermore, the functions 𝑊𝑖 satisfy the inequality 𝑊𝑖(𝑧)𝑊𝑖𝑙(𝑦)𝑘0𝑙0𝑧𝑦,(2.53) uniformly with respect to 𝑖 for all 𝑧,𝑦𝑛 such that 𝑧 and 𝑦; here 𝑘(𝑙0)=𝑘(𝑙0,) is a bounded function. Under the sense of lemma 2.14, we say that systems (2.48) and (2.52) are 𝐵-equivalent.

Proof. For fixed 𝑖. Let 𝑧(𝑡) be the solution of (2.48) such that 𝑧(𝑡2𝑖)=𝑧, and assume that 𝛼𝑖 and 𝛽𝑖 are solutions of 𝛼=𝑡2𝑖1+̃𝜏2𝑖1(𝑧(𝛼)) and 𝛽=𝑡2𝑖+̃𝜏2𝑖(𝑧(𝛽)), respectively. Let 𝑧1(𝑡) be the solution of the system 𝑧Φ=𝑎(𝑡)𝑔1𝑧(𝑡)z(𝑡)𝑎(𝑡)𝐻(𝑧(𝑡))𝑛𝑗=1𝜆𝑗𝑓𝑗Φ𝑡,1𝑧𝑡𝑣𝑗(𝑡)(2.54) with the initial condition 𝑧1(𝛼𝑖+1Π)=2𝑖(𝛽𝑖,𝑧(𝛽𝑖)).
We first note that 𝑧1(𝛼𝑖+1)=(Φ𝐵𝑖Φ1)(𝑧(𝛽𝑖))+(Φ𝐽𝑖Φ1)(𝑧(𝛽𝑖))+𝑧(𝛽𝑖). Moreover, for 𝑡𝑡[2𝑖,𝛽𝑖], 𝑡𝑧(𝑡)=𝑧2𝑖+𝑡2𝑖Φ𝑎(𝑠)𝑔1𝑧(𝑠)𝑧(𝑠)𝑎(𝑠)𝐻(𝑧(𝑠))𝑛𝑗=1𝜆𝑗𝑓𝑗Φ𝑠,1𝑧𝑠𝑣𝑗(𝑠)d𝑠,(2.55) and for 𝛼𝑡[𝑖+1,𝑡2𝑖+1], 𝑧1(𝑡)=𝑧1𝛼𝑖+1+𝑡𝛼𝑖+1Φ𝑎(𝑠)𝑔1𝑧1𝑧(𝑠)1𝑧(𝑠)𝑎(𝑠)𝐻1(𝑠)𝑛𝑗=1𝜆𝑗𝑓𝑗Φ𝑠,1𝑧1𝑠𝑣𝑗=(𝑠)d𝑠Φ𝐵𝑖Φ1𝑧𝛽𝑖+Φ𝐽𝑖Φ1𝑧𝛽𝑖𝛽+𝑧𝑖+𝑡𝛼𝑖+1Φ𝑎(𝑠)𝑔1𝑧1𝑧(𝑠)1𝑧(𝑠)𝑎(𝑠)𝐻1(𝑠)𝑛𝑗=1𝜆𝑗𝑓𝑗Φ𝑠,1𝑧1𝑠𝑣𝑗=Φ𝐵(𝑠)d𝑠𝑖Φ+𝐼1𝑧𝑡2𝑖+𝛽𝑖𝑡2𝑖Φ𝑎(𝑠)𝑔1𝑧(𝑠)𝑧(𝑠)𝑎(𝑠)𝐻(𝑧(𝑠))𝑛𝑗=1𝜆𝑗𝑓𝑗Φ𝑠,1𝑧𝑠𝑣𝑗(+𝑠)d𝑠Φ𝐽𝑖Φ1𝑧𝛽𝑖+𝑡𝛼𝑖+1Φ𝑎(𝑠)𝑔1𝑧1𝑧(𝑠)1𝑧(𝑠)𝑎(𝑠)𝐻1(𝑠)𝑛𝑗=1𝜆𝑗𝑓𝑗Φ𝑠,1𝑧1𝑠𝑣𝑗(𝑠)d𝑠.(2.56) Thus, we set 𝑊𝑖Φ𝐵(𝑧)=𝑖Φ+𝐼1𝛽𝑖𝑡2𝑖Φ𝑎(𝑠)𝑔1𝑧(𝑠)𝑧(𝑠)𝑎(𝑠)𝐻(𝑧(𝑠))𝑛𝑗=1𝜆𝑗𝑓𝑗Φ𝑠,1𝑧𝑠𝑣𝑗(𝑠)d𝑠+Φ𝐽𝑖Φ1𝑧𝛽𝑖+𝑡2𝑖+1𝛼𝑖+1Φ𝑎(𝑠)𝑔1𝑧1𝑧(𝑠)1𝑧(𝑠)𝑎(𝑠)𝐻1(𝑠)𝑛𝑗=1𝜆𝑗𝑓𝑗Φ𝑠,1𝑧1𝑠𝑣𝑗(𝑠)d𝑠.(2.57) Substituting (2.57) in (2.52), we see that 𝑊𝑖(𝑧) satisfies the first conclusion of the lemma.
The rest of the proof is similar to that of Lemma 2.4, and we can use Gronwall-Bellman lemma to show that 𝑊𝑖(𝑧) satisfies (2.53) and it will be omitted here. This completes the proof.

Next, we will use 𝜓-substitution, reducing (2.52) to an impulsive differential equation. Letting 𝑚(𝑠)=𝑧(𝜓1(𝑠)), we obtain, for 𝑡𝑡2𝑖, Φ1𝑧𝑡𝑣𝑗=Φ(𝑡)1𝑧𝜓1(𝑠)𝑣𝑗𝜓1=Φ(𝑠)1𝑧𝜓1𝜓𝜓1(𝑠)𝑣𝑗𝜓1=Φ(𝑠)1𝑚𝜓𝜓1(𝑠)𝑣𝑗𝜓1(𝑠)=𝜈(𝑠),(2.58) hence 𝑚𝜓=𝑎1𝑔Φ(𝑠)1𝑚𝜓(𝑠)𝑚(𝑠)𝑎1(𝑠)𝐻(𝑚(𝑠))𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1,(𝑠),𝜈(𝑠)(2.59) and for 𝑡=𝑡2𝑖, we get 𝑚𝑠𝑖𝑡=𝑧2𝑖+1=Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖𝑠+𝑚𝑖.(2.60) Thus, the second equation in (2.23) leads to Δ𝑚|𝑠=𝑠𝑖=Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖,(2.61) where Δ𝑚|𝑠=𝑠𝑖=𝑚(𝑠𝑖)𝑚(𝑠𝑖). Hence, 𝑚(𝑠) is a solution of the impulsive differential equation: 𝑚𝜓=𝑎1𝑔Φ(𝑠)1𝑚𝜓(𝑠)𝑚(𝑠)𝑎1(𝑠)𝐻(𝑚(𝑠))𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝑠),𝜈(𝑠),𝑠𝑠𝑖,Δ𝑚𝑠=𝑠𝑖=Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖,𝑠=𝑠𝑖.(2.62)

In the following, we set 𝑃𝐶=𝑚𝑚(𝑠𝑖,𝑠𝑖+1)𝑠𝐶𝑖,𝑠𝑖+1𝑠,,𝑚+𝑖𝑠=𝑚𝑖,𝑖=1,2,(2.63) and consider the Banach space 𝐸=𝑚𝑚𝑃𝐶,𝑚(𝑠)=𝑚𝑠+𝜔(2.64) with the norm 𝑚=sup𝑠[0,𝜔]{|𝑚(𝑠)|𝑚𝐸}, where 𝜔=𝜓(𝜔). Define a cone in𝐸 by 𝑃=𝑚(𝑠)𝐸𝑚(𝑠)𝑘𝑚,(2.65) where 𝑘((2𝛿𝑐)(1𝑐2)/(1(2𝛿𝑐)2),𝑟𝐿0(1𝑟𝑙0)/(1𝑟𝐿0)].

Let the operator Ψ𝑃𝐸 be defined by (Ψ𝑚)(𝑠)=𝑠+𝜔𝑠𝐺𝑎𝜓(𝑠,𝜃)1𝐻(𝜃)(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖,(2.66) where 𝑒𝐺(𝑠,𝜃)=𝑠𝜃𝑎(𝜓1(𝑟))𝑔((Φ1𝑚)(𝑟))d𝑟1𝑒0𝜔𝑎(𝜓1(𝑟))𝑔((Φ1𝑚)(𝑟))d𝑟,𝜃𝑠,𝑠+𝜔.(2.67) By the assumptions, we have 𝑟𝐿01𝑟𝐿01𝐺(𝑠,𝜃)1𝑟𝑙0.(2.68)

Lemma 2.15. 𝑚 is an 𝜔-periodic solution of (2.62) if and only if 𝑚 is a fixed point of the operator Ψ.

Proof. If 𝑚(𝑠) is an 𝜔-periodic solution of (2.62), for any 𝑠, there exists 𝑖 such that 𝑠𝑖 is the first impulsive point after 𝑠. Hence, for 𝜃[𝑠,𝑠𝑖], we have 𝑚(𝜃)=𝑒𝜃𝑠𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝜃𝑠𝑒𝜃𝑟𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑎𝜓1(𝑟)𝐻(𝑚(𝑟))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝑟),𝜈(𝑟)d𝑟,(2.69) then 𝑚𝑠𝑖=𝑒𝑠𝑖𝑠𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑚(𝑠)𝑠𝑖𝑠𝑒𝑠𝑖r𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑎𝜓1(𝑟)𝐻(𝑚(𝑟))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝑟),𝜈(𝑟)d𝑟.(2.70) Again, for 𝜃(𝑠𝑖,𝑠𝑖+1], then 𝑚(𝑠)=𝑒𝜃𝑠𝑖𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑚𝑠+𝑖𝜃𝑠𝑖𝑒𝜃𝑟𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑎𝜓1(𝑟)𝐻(𝑚(𝑟))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝑟),𝜈(𝑟)d𝑟=𝑒𝜃𝑠𝑖𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖𝑠+𝑚𝑖𝜃𝑠𝑖𝑒𝜃𝑟𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑎𝜓1(𝑟)𝐻(𝑚(𝑟))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝑟),𝜈(𝑟)d𝑟=𝑒𝜃𝑠𝑖𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖𝜃𝑠𝑖𝑒𝜃𝑟𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑎𝜓1(𝑟)𝐻(𝑚(𝑟))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝑟),𝜈(𝑟)d𝑟+𝑒𝜃𝑠𝑖𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑚𝑠𝑖,𝑒𝜃𝑠𝑖𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑚𝑠𝑖=𝑒𝜃𝑠𝑖𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑒𝑠𝑖𝑠𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑚(𝑠)𝑠𝑖𝑠𝑒𝑠𝑖𝑟𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏×𝑎𝜓1(𝑟)𝐻(𝑚(𝑟))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝑟),𝜈(𝑟)d𝑟=𝑒𝜃𝑠𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑚(𝑠)𝑠𝑖𝑠𝑒𝜃𝑟𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑎𝜓1(𝑟)𝐻(𝑚(𝑟))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝑟),𝜈(𝑟)d𝑟.(2.71) So we can obtain 𝑚(𝑠)=𝑒𝜃𝑠𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑚(𝑠)𝜃𝑠𝑒𝜃𝑟𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑎𝜓1(𝑟)𝐻(𝑚(𝑟))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝑟),𝜈(𝑟)d𝑟+𝑒𝜃𝑠𝑖𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖.(2.72) Repeating the above process for 𝜃[𝑠,𝑠+𝜔], we obtain 𝑚(𝑠)=𝑒𝜃𝑠𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑚(𝑠)𝜃𝑠𝑒𝜃𝑟𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏𝑎𝜓1(𝑟)𝐻(𝑚(𝑟))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝑟),𝜈(𝑟)d𝑟𝑖𝑠𝑖[𝑠,𝜃)𝑒𝜃𝑠𝑖𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏Φ1𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖.(2.73) Noticing that 𝑚(𝑠)=𝑚(𝑠+𝜔) and 𝑒𝑠𝑠+𝜔𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏=𝑒0𝜔𝑎(𝜓1(𝜏))𝑔((Φ1𝑚)(𝜏))d𝜏, we find that 𝑚 is a fixed point of Ψ.
Let 𝑚 be a fixed point of Ψ. If 𝑠𝑠𝑖,𝑖, we have 𝑚𝑎𝜓(𝑠)=𝐺𝑠,𝑠+𝜔1𝐻𝑚+𝑠+𝜔𝑠+𝜔𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1𝑎𝜓𝑠+𝜔,𝜈𝑠+𝜔𝐺(𝑠,𝑠)1(𝑠)𝐻(𝑚(𝑠))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1𝜓(𝑠),𝜈(𝑠)+𝑎1𝑔Φ(𝑠)1𝑚𝑚(𝑠)(𝑠).(2.74) By Lemmas 2.11 and 2.12, we have 𝜓(𝑡+𝜔)=𝜓(𝑡)+𝜓(𝜔)=𝜓(𝑡)+𝜔, so it is easy to have 𝑡+𝜔=𝜓1(𝜓(𝑡)+𝜔)=𝜓1(𝑠+𝜔) and 𝜈(𝑠+𝜔)=𝜈(𝑠). Therefore, we can obtain 𝑚𝜓(𝑠)=𝑎1𝑔Φ(𝑠)1𝑚𝑎𝜓(𝑠)𝑚(𝑠)1(𝑠)𝐻(𝑚(𝑠))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1.(𝑠),𝜈(𝑠)(2.75) If 𝑠=𝑠𝑖,𝑖, we can get 𝑚𝑠+𝑖𝑠𝑚𝑖=𝑗𝑠𝑗𝑠+𝑖,𝑠+𝑖+𝜔𝐺𝑠𝑖,𝑠𝑗Φ𝐵𝑖Φ1𝑚𝑠𝑗+Φ𝑊𝑖Φ1𝑚𝑠𝑗𝑗𝑠𝑗𝑠𝑖,𝑠𝑖+𝜔𝐺𝑠𝑖,𝑠𝑗Φ𝐵𝑖Φ1𝑚𝑠𝑗+Φ𝑊𝑖Φ1𝑚𝑠𝑗𝑠=𝐺𝑖,𝑠𝑖+𝜔Φ𝐵𝑖Φ1𝑚𝑠𝑗++𝜔Φ𝑊𝑖Φ1𝑚𝑠𝑗𝑠+𝜔𝐺𝑖,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑗+Φ𝑊𝑖Φ1𝑚𝑠𝑗=Φ𝐵𝑖Φ1𝑚𝑠𝑗+Φ𝑊𝑖Φ1𝑚𝑠𝑗.(2.76) Therefore, 𝑚 is 𝜔-periodic solution of (2.62). The proof is complete.

Lemma 2.16. Assume that (H1)–(H5) hold, then Ψ(𝑃)𝑃, and Ψ𝑃𝑃 is compact and continuous.

Proof. By the definition of 𝑃, for 𝑚𝑃, we have =(Ψ𝑚)𝑠+𝜔𝑠+2𝜔𝑠+𝐺𝑎𝜓𝜔𝑠+𝜔,𝜃1𝐻(𝜃)(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠+𝜔,𝑠+2𝜔𝐺𝑠+𝜔,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖=𝑠+𝜔𝑠𝐺𝑎𝜓𝑠+𝜔,𝜃+𝜔1𝐻𝑚+𝜃+𝜔𝜃+𝜔𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+𝜃+𝜔,𝜈𝜃+𝜔d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠+𝜔,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖=𝑠+𝜔𝑠𝑎𝜓𝐺(𝑠,𝜃)1(𝜃)𝐻(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖=(Ψ𝑚)(𝑠).(2.77) Thus, (Ψ𝑚)(𝑠+𝜔)=(Ψ𝑚)(𝑠),𝑠. So in view of (2.66), (2.68), for 𝑚𝑃,𝑠[0,𝜔], we have (Ψ𝑚)(𝑠)=𝑠+𝜔𝑠𝐺𝑎𝜓(𝑠,𝜃)1𝐻(𝜃)(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖𝑟𝐿01𝑟𝐿0𝑠+𝜔𝑠𝑎𝜓1𝐻(𝜃)(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖1𝑘1𝑟𝑙0𝑠+𝜔𝑠𝑎𝜓1(𝜃)𝐻(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖𝑘Ψ𝑚.(2.78) Therefore, Ψ𝑚𝑃. Next, we will show that Ψ is continuous and compact. Firstly, we will consider the continuity of Ψ. Let 𝑚𝑛𝑃 and 𝑚𝑛𝑚0 as 𝑛+, then 𝑚𝑃 and |𝑚𝑛(𝑠)𝑚(𝑠)|0 as 𝑛+ for any 𝑠[0,𝜔]. By the continuity of 𝑓𝑗(𝑗=1,2,,𝑛),𝑔,Φ,Φ1,𝑊𝑖(𝑖=1,2,,𝑝), for any 𝑠[0,𝜔] and 𝜀>0, we have ||𝐻𝑚𝑛||(𝑠)𝐻(𝑚(𝑠))1𝑟𝑙03𝜔𝑎𝜀,(2.79) and denote 𝜈𝑛(𝑠)=(Φ1𝑚𝑛)(𝜓(𝜓1(𝑠)𝑣𝑗(𝜓1(𝑠)))), and it is easy to see that 𝑚𝑛𝑚0 as 𝑛+ implies 𝜈𝑛𝜈0 as 𝑛+, thus ||𝑓𝑗𝜓1(𝑠),𝜈𝑛𝑓(𝑠)𝑗𝜓1||(𝑠),𝜈(𝑠)1𝑟𝑙03𝜔𝜆𝑗𝑛||𝜀,𝑗=1,2,,𝑛,Φ𝐵𝑖Φ1𝑚𝑛𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑛𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖||1𝑟𝑙03𝜔𝑝𝜀,(2.80) where 𝑛 is sufficiently large. For 𝑠[0,𝜔], we have Ψ𝑚𝑛Ψ𝑚=sup𝑠0,𝜔|||||||𝑠+𝜔𝑠𝑎𝜓𝐺(𝑠,𝜃)1𝐻𝑚(𝜃)𝑛+(𝜃)𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝜃),𝜈𝑛+(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑛𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑛𝑠𝑖𝑠+𝜔𝑠𝑎𝜓𝐺(𝑠,𝜃)1(𝜃)𝐻(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖|||||||=sup𝑠0,𝜔|||||𝑠+𝜔𝑠𝑎𝜓𝐺(𝑠,𝜃)1𝐻𝑚(𝑠)𝑛+(𝑠)𝐻(𝑚(𝑠))𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝜃),𝜈𝑛𝑓(𝜃)𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑛𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑛𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖|||||𝜔1𝑟𝑙0𝑎1𝑟𝑙03𝜔𝑎𝜀+𝑛𝑗=1𝜆𝑗1𝑟𝑙03𝜔𝜆𝑗𝑛𝜀+𝑝1𝑟𝑙0𝜀3𝜔𝑝=𝜀.(2.81) Therefore, Ψ is continuous on 𝑃.
Next, we prove that Ψ is a compact operator. Let 𝑆𝑃 be an arbitrary bounded set in 𝑃, then there exists a number 𝐿0>0 such that 𝑚<𝐿0 for any 𝑚𝑆. We prove that Ψ𝑆 is compact. In fact, from (H1), one has 𝑊𝑖(0)=0,𝑖=1,2,; by (2.53), it is easy to see that for any 𝑧, one has the following: 𝑊𝑖𝑙(𝑧)𝑘0𝑙0𝑊𝑧+𝑖𝑙(0)=𝑘0𝑙0𝑧,𝑖=1,2,.(2.82) So for any {𝑚𝑛}𝑛𝑆 and 𝑠[0,𝜔], we have Ψ𝑚𝑛=sup𝑠0,𝜔|||||𝑠+𝜔𝑠𝑎𝜓(𝑠,𝜃)1𝐻𝑚(𝜃)𝑛+(𝜃)𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝜃),𝜈𝑛+(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑛𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑛𝑠𝑖|||||||𝜔1𝑟𝑙0𝑎𝐿𝑐1𝑐+𝑛𝑗=1max𝜈𝐿0,𝐿0𝑠0,𝜔𝜆𝑗𝑓𝑗𝜓1(𝑠),𝜈(𝑠)+𝐿0𝑝𝑖=1𝐵𝑖𝑙+𝑘0𝑙0=𝐾,Ψ𝑚𝑛=sup𝑠0,𝜔|||||𝑎𝜓1𝑔Φ(𝑠)1𝑚𝑛𝑚(𝑠)𝑛𝑎𝜓(𝑠)1𝐻𝑚(𝑠)𝑛+(𝑠)𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝑠),𝜈𝑛|||||(𝑠)𝑎𝐿0Ψ𝑚𝑛+𝑎𝐿𝑐1𝑐+𝑛𝑗=1max𝜈𝐿0,𝐿0𝑠0,𝜔𝜆𝑗𝑓𝑗𝜓1(𝑠),𝜈(𝑠)𝑎𝐿0𝐾+𝑎𝐿𝑐1𝑐+𝑛𝑗=1max𝜈𝐿0,𝐿0𝑠0,𝜔𝜆𝑗𝑓𝑗𝜓1(𝑠),𝜈(𝑠)=𝑄,(2.83) where 𝐿0=𝐿0/(1𝑐), which implies that {Ψ𝑚𝑛}𝑛 and {(Ψ𝑚𝑛)}𝑛 are uniformly bounded on[0,𝜔]. Therefore, there exists a subsequence of {Ψ𝑚𝑛}𝑛 which converges uniformly on [0,𝜔]; namely,Ψ𝑆 is compact. The proof is complete.

3. Main Results

Our main results of this paper are as follows.

Theorem 3.1. Assume that (H1)–(H5) hold, 0𝑐(𝑡)<1, for a sufficiently small Lipschitz constant 𝑙0; suppose that the following conditions hold:(H6)𝛼0=(1𝑐)(1𝑟𝑙0)𝜔𝑎𝐿𝑐(1𝑐)𝑝𝑖=1(𝐵𝑖+𝑘(𝑙0)𝑙0)>0. (H7)There exist positive constants 𝛽1,𝛽2, and 𝛽4 with 0<𝛽1<𝛽2<𝛽4 such that sup𝑠[0,𝜔]𝑓𝑗𝜓1(𝑠),𝛽1/1𝑐𝛽1/1𝑐𝛼0<sup𝑠[0,𝜔]𝑓𝑗𝜓1(𝑠),𝛽4/1𝑐𝛽4/1𝑐𝛼0<inf𝑠[0,𝜔]𝑓𝑗𝜓1(𝑠),𝛼𝛽2𝛼𝛽2̃𝛽0,(3.1) where ̃𝛽0=((1𝑟𝐿0)/𝛼𝑟𝐿0)𝜔𝑎𝑙𝑐 and 𝜔=𝜓(𝜔).Then for all 𝑗=1,2,,𝑛,𝜆𝑗(𝜆𝑗1,𝜆𝑗2], (1.2) has at least three positive 𝜔-periodic solutions, where 𝜆𝑗1=𝛼𝛽2̃𝛽0𝜔𝑛inf𝑠[0,𝜔]𝑓𝑗𝑡,𝛼𝛽2,𝜆𝑗2=𝛽4/1𝑐𝛼0𝜔𝑛sup𝑠[0,𝜔]𝑓𝑗𝑡,𝛽4/1𝑐,𝑗=1,2,,𝑛.(3.2)

Proof. First of all, since 0<𝛼<1/(1𝑐) and 0<𝑟0<1, we have 𝛼0>0, so ̃𝛽0=1𝑟𝐿0𝛼𝑟𝐿0𝜔𝑎𝑙𝑐>1𝑟𝐿0𝛼𝑟𝐿0𝜔𝑎𝑙𝑐>1𝑟𝐿0𝛼1𝑐1𝑟𝑙0+1𝑐𝑝𝑖=1𝐵𝑖𝑙+𝑘0𝑙0>1𝑐𝑟𝑙0𝑟𝐿0+1𝑐𝑝𝑖=1𝐵𝑖𝑙+𝑘0𝑙0>0.(3.3) Furthermore, 0<𝜆𝑗1<𝜆𝑗2 in view of (3.1).
Now, define for each 𝜆𝑗(𝜆𝑗1,𝜆𝑗2] and 𝑚𝑃 a mapping Ψ𝑃𝑃 by (Ψ𝑚)(𝑠)=𝑠+𝜔𝑠𝐺𝑎𝜓(𝑠,𝜃)1𝐻(𝜃)(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠iΦ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖,(3.4) and a function 𝜌𝑃[0,) by 𝜌(𝑚)=min𝑠[0,𝜔]𝑚(𝑠).(3.5) For 𝑚𝑃𝛽4, by Lemma 2.13, we have Φ0<1𝑚𝛽(𝑠)<41𝑐.(3.6) It follows from (2.51), (2.68), (3.6), and (H2), for all 𝑗=1,2,,𝑛,𝜆𝑗(𝜆𝑗1,𝜆𝑗2] and 𝑚𝑃𝛽4 that (Ψ𝑚)(𝑠)=𝑠+𝜔𝑠𝐺𝑎𝜓(𝑠,𝜃)1𝐻(𝜃)(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖11𝑟𝑙0𝑠+𝜔𝑠𝑎𝜓1𝐻(𝜃)(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖11𝑟𝑙0𝐿𝑎𝜔𝑐1𝑐𝛽4+𝜔𝑛𝑗=1𝜆𝑗2sup𝑠0,𝜔𝑓𝑗𝜓1(𝛽𝑠),41𝑐+𝛽4𝑝𝑖=1𝑏𝑖𝑙+𝑘0𝑙0=11𝑟𝑙0𝐿𝑎𝜔𝑐1𝑐𝛽4+𝑛𝑗=1𝛽4/1𝑐𝛼0𝜔𝑛sup𝑠[0,𝜔]𝑓𝑗𝜓1(𝑠),𝛽4/1𝑐sup𝑠0,𝜔𝑓𝑗𝜓1𝛽(𝑠),41𝑐+𝛽4𝑝𝑖=1𝐵𝑖𝑙+𝑘0𝑙0𝛽4.(3.7) By Lemma 2.16, we know that Ψ is completely continuous on𝑃𝛽4.
We now assert that the condition (2) of Lemma 2.1 holds. Indeed, if 𝑚𝑃𝛽1, then similar to above argument, by (3.1), we have (Ψ𝑚)(𝑠)=𝑠+𝜔𝑠𝐺𝑎𝜓(𝑠,𝜃)1𝐻(𝜃)(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖11𝑟𝑙0𝑠+𝜔𝑠𝑎𝜓1(𝜃)𝐻(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖11𝑟𝑙0𝑠+𝜔𝑠𝑎𝜓1(𝜃)𝐻(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖11𝑟𝑙0𝐿𝑎𝜔𝑐1𝑐𝛽1+𝜔𝑛𝑗=1𝜆𝑗2sup𝑠0,𝜔𝑓𝑗𝜓1𝛽(𝑠),11𝑐+𝛽1𝑝𝑖=1𝐵𝑖𝑙+𝑘0𝑙0=11𝑟𝑙0𝐿𝑎𝜔𝑐1𝑐𝛽1+𝑛𝑗=1𝛽4/1𝑐𝛼0𝜔𝑛sup𝑠[0,𝜔]𝑓𝑗𝜓1(𝑠),𝛽4/1𝑐sup𝑠0,𝜔𝑓𝑗𝜓1𝛽(𝑠),11𝑐+𝛽1𝑝𝑖=1𝐵𝑖𝑙+𝑘0𝑙0<11𝑟𝑙0𝐿𝑎𝜔𝑐1𝑐𝛽1+𝛽41𝑐𝛼0𝛽1𝛽4+𝛽1𝑝𝑖=1𝐵𝑖𝑙+𝑘0𝑙0=𝛽1.(3.8) Hence, Ψ𝑚<𝛽1 holds.
Choose a positive constant 𝛽3 such that 0<𝛽2<𝑘𝛽3<𝛽3𝛽4. Next, we show that the condition (1) of Lemma 2.1 holds. Obviously, 𝜌 is a concave continuous function on 𝑃 with 𝜌(𝑚)𝑚 for 𝑚𝑃𝛽4. We notice that if 𝑚(𝑠)=(2/5)𝛽2+(3/5)𝛽3 for 𝑠[0,𝜔], then 𝑚{𝑚𝑃(𝜌,𝛽2,𝛽3)𝜌(𝑚)>𝛽2} which implies {𝑚𝑃(𝜌,𝛽2,𝛽3)𝜌(𝑚)>𝛽2}. For 𝑚𝑃(𝜌,𝛽2,𝛽3), we have 𝛽2𝜌(𝑚)=min𝑠[0,𝜔]𝑚(𝑠)𝑚𝛽3,(3.9) which implies, from (2.50), that Φ1𝑚(𝑠)𝛼𝑚𝛼𝛽2.(3.10) And it is also clear that Φ(𝑥) is nondecreasing for 𝑥>0 and 𝐵𝑖,𝑊𝑖𝐶(,+), and we can easily have Φ𝐵𝑖Φ1,Φ𝑊𝑖Φ1𝐶(,+). Hence 𝜌(Ψ𝑚)=min𝑠[0,𝜔](Ψ𝑚)(𝑠)=min𝑠[0,𝜔]𝑠+𝜔𝑠𝑎𝜓𝐺(𝑠,𝜃)1(𝜃)𝐻(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖𝑟𝐿01𝑟𝐿0min𝑠[0,𝜔]𝑠+𝜔𝑠𝑎𝜓1𝐻(𝜃)(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝜃),𝛼𝛽2+d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖>𝑟𝐿01𝑟𝐿0𝜔𝑎𝑙𝑐𝛼𝛽2+𝜔𝑛𝑗=1𝜆𝑗1inf𝑠0,𝜔𝑓𝑗𝜓1(𝑠),𝛼𝛽2+min𝛽2𝑚𝛽3𝑝𝑖=1Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖𝑟𝐿01𝑟𝐿0𝜔𝑎𝑙𝑐𝛼𝛽2+𝜔𝑛𝑗=1𝛼𝛽2̃𝛽0𝜔𝑛inf𝑠[0,𝜔]𝑓𝑗𝜓1(𝑠),𝛼𝛽2inf𝑠0,𝜔𝑓𝑗𝜓1(𝑠),𝛼𝛽2+min𝛽2𝑚𝛽3𝑝𝑖=1Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖>𝛽2(3.11) for all 𝑚𝑃(𝜌,𝛽2,𝛽3).
Finally, we prove that the condition (3) of Lemma 2.1 holds. Let 𝑚𝑃(𝜌,𝛽2,𝛽4) and Ψ𝑚>𝛽3, then 𝜌(Ψ𝑚)>𝛽2. We notice that (3.4) implies that 1Ψ𝑚1𝑟𝑙0𝑠+𝜔𝑠𝑎𝜓1(𝜃)𝐻(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1(𝜃),𝛼𝛽2+d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖.(3.12) Thus 𝜌(Ψ𝑚)=min𝑠[0,𝜔]𝑠+𝜔𝑠𝐺𝑎𝜓(𝑠,𝜃)1𝐻(𝜃)(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔𝐺𝑠,𝑠𝑖Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖𝑟𝐿01𝑟𝐿0min𝑠[0,𝜔]𝑠+𝜔𝑠𝑎𝜓1(𝜃)𝐻(𝑚(𝜃))+𝑛𝑗=1𝜆𝑗𝑓𝑗𝜓1+(𝜃),𝜈(𝜃)d𝜃𝑖𝑠𝑖𝑠,𝑠+𝜔Φ𝐵𝑖Φ1𝑚𝑠𝑖+Φ𝑊𝑖Φ1𝑚𝑠𝑖𝑟𝐿01𝑟𝑙01𝑟𝑙0Ψ𝑚𝑘𝛽3>𝛽2.(3.13) To sum up, all the hypotheses of Lemma 2.1 are satisfied. Hence Ψ has at least three positive fixed points. That is, (1.2) has at least three positive 𝜔-periodic solutions. This completes the proof.

Corollary 3.2. Suppose (H1)–(H6) hold. If lim𝑥sup𝑠[0,𝜔]𝑓𝑗𝜓1(𝑠),𝑥𝑥=0,(3.14)lim𝑥0sup𝑠[0,𝜔]𝑓𝑗𝜓1(𝑠),𝑥𝑥=0,(3.15) where 𝜔=𝜓(𝜔); then (1.2) has at least three positive 𝜔-periodic solutions.

Proof. In view of (3.14), we can choose 𝛽4>𝛽2>0 such that the second inequality in (3.1) holds, and in view of (3.15), we can choose 𝛽1(0,𝛽2) such that the first inequality in (3.1) holds. Therefore, the conclusion of Theorem 3.1 holds. This completes the proof.

4. An Example

Let us consider the variable time scale 𝕋0(𝑥) constructed by 𝑡𝑖=𝑖,𝜏𝑖(𝑥)=(1)𝑖𝑙0sin𝑥, where |𝑥|>1 for all 𝑡𝕋0(𝑥), 0<𝑙0<(1/2) and consider 𝜋-periodic system:1𝑥(𝑡)+9|cos𝑡|𝑥(𝑡𝛼)=1𝜋||||1sin𝑡3+13𝑒𝑥𝑙𝑥(𝑡)03𝑛𝑛𝑗=1𝜆𝑗𝑥1/2𝑥(𝑡)ln𝑡𝑒(1/𝑗)|sin𝑡|,+1(𝑡,𝑥)𝕋0𝑥(𝑥),+2=0.033𝑖𝑥+0.02𝑙0𝑡sin𝑥+𝑥,+=2𝑖+1𝑙0sin𝑥,(4.1) where 𝛼 is a constant, 𝜆𝑗,𝑗=1,2,,𝑛 are nonnegative parameters. In this case, 𝑐(𝑡)=(1/9)|cos𝑡|,𝑎(𝑡)=1/𝜋,𝑔(𝑥(𝑡))=(1/3)+(1/3)𝑒𝑥,𝐵𝑖=0.03(2/3)𝑖,𝐽𝑖(𝑥)=0.02𝑙0sin𝑥,𝑣𝑗𝑒(𝑡)=(1/𝑗)|sin𝑡| and 𝑓𝑗(𝑡,𝑥(𝑡𝑣𝑗(𝑡)))=(𝑙0/3𝑛)𝑥1/2(𝑡)ln(𝑥(𝑡𝑣𝑗(𝑡))+1),𝑗=1,2,,𝑛,𝑖. Obviously, (H1)–(H3) are satisfied, and it is easy to see that (3.14) and (3.15) hold.

By the formula of 𝜓-substitution and 𝛿𝑘=1, one can find𝜔=𝜓(𝜔)=𝜔0<2𝑘<𝜔𝛿𝑘=𝜋1.(4.2)

Clearly, 𝐿=(2/3),𝑙=(1/3),0𝑐(𝑡)(1/9)<1,𝑟0=𝑒(𝜋1)(1/𝜋)0.5058 and 𝑐=1/9,𝑐=0, so we can find 𝛿=(𝑐+𝑐)/2=1/18, and it is easy to check that ((2𝛿𝑐)(1𝑐2))/(1(2𝛿𝑐)2)=9/800.1125<(𝑟𝐿0(1𝑟𝑙0))/(1𝑟𝐿0)=0.3532. Thus, (H4) holds. Furthermore, we also have𝜕𝑓𝑗=𝑙𝜕𝑥03𝑛ln(𝑥+1)2𝑥1/2+𝑥1/2𝑙𝑥+103𝑛ln(𝑥+1)1/2𝑥1/2+𝑥1/2𝑙𝑥+103𝑛(𝑥+1)1/2𝑥1/2+𝑥1/2=𝑙𝑥+1013𝑛1+𝑥1/2+𝑥1/2<𝑙𝑥+10(𝑙3𝑛2+1)=0𝑛.(4.3) Hence, for any 𝑥1,𝑥2, one can get𝑛𝑗=1||𝑓𝑗𝑡,𝑥1𝑓𝑗𝑡,𝑥2||||||𝜕𝑓𝑗||||||𝑥𝜕𝑥1𝑥2||𝑙<𝑛0𝑛||𝑥1𝑥2||=𝑙0||𝑥1𝑥2||.(4.4) So (H5) is satisfied. For a sufficiently small 𝑙0, one can also have𝛼0=1𝑐1𝑟𝑙0𝜔𝑎𝐿𝑐1𝑐𝑝𝑖=1𝐵𝑖𝑙+𝑘0𝑙08=0.07689𝑝𝑖=1𝑘𝑙0𝑙0,(4.5) since 𝑘(𝑙0) is a bounded function; for a sufficiently small 𝑙0, one can have 𝛼0>0 such that (H6) holds. Therefore, according to Corollary 3.2, (4.1) has at least three positive 𝜋-periodic solutions.

Acknowledgment

This work is supported by the National Natural Sciences Foundation of China under Grant no. 10971183.