Abstract

We study a new system of nonlinear set-valued variational inclusions involving a finite family of 𝐻(,)-accretive operators in Banach spaces. By using the resolvent operator technique associated with a finite family of 𝐻(,)-accretive operators, we prove the existence of the solution for the system of nonlinear set-valued variational inclusions. Moreover, we introduce a new iterative scheme and prove a strong convergence theorem for finding solutions for this system.

1. Introduction

Variational inequality theory has become a very effective and powerful tool for studying a wide range of problems arising in pure and applied sciences which include work on differential equations, control problems, mechanics, general equilibrium problems in transportation and economics. In 1994, Hassouni and Moudafi [1] introduced and studied a class of variational inclusions and developed a perturbed algorithm for finding approximate solutions of the variational inclusions. In 1996, Adly [2] obtained some important extensions and generalizations of the results in [1] for nonlinear variational inclusions. Recently, Ding [3] introduced and studied a class of generalized quasivariational inclusions and Kazmi [4] introduced and studied another class of quasivariational inclusions in the same year. In [5, 6], Ansari et al. introduced the system of vector equilibrium problems and they proved the existence of solutions for such problems (see also in [79]). In 2004, Verma [10] studied nonlinear variational inclusion problems based on the generalized resolvent operator technique involving 𝐴-monotone mapping. For existence result and approximating solution of the system of set-valued variational inclusions and the class of nonlinear relaxed cocoercive variational inclusions, we refer the reader to Yan et al. [11], Plubtieng and Sriprad [12], Verma [13] and Cho et al. [14].

Very recently, Verma [15] introduced and studied approximation solvability of a general class of nonlinear variational inclusion problems based on (𝐴,𝜂)-resolvent operator technique in a Hilbert space. On the other hand, Zou and Huang [16] studied the Lipschitz continuity of resolvent operator for the 𝐻(,)-accretive operator in Banach spaces. Moreover, they also applied these new concepts to solve a variational-like inclusion problem. One year later, Zou and Huang [17] introduced and studied a new class of system of variational inclusions involving 𝐻(,)-accretive operator in Banach spaces. By using the resolvent operator technique associated with 𝐻(,)-accretive operator, they proved the existence of the solution for the system of inclusions. Moreover, they also develop a step-controlled iterative algorithm to approach the unique solution.

In this paper, we introduce a new system of nonlinear set-valued variational inclusions involving a finite family of 𝐻(,)-accretive operators in Banach spaces. By using the resolvent operators technique associated with a finite family of 𝐻(,)-accretive operator, we prove the existence of the solution for the system of nonlinear set-valued variational inclusions. Moreover, we introduce a new iterative scheme and prove a strong convergence theorem for finding solutions of this system.

2. Preliminaries

Let 𝑋 be a real Banach space with dual space 𝑋,, the dual pair between 𝑋 and 𝑋 and 2𝑋 and 𝐶(𝑋) denote the family of all the nonempty subsets of 𝑋 and the family of all closed subsets of 𝑋, respectively. The generalized duality mapping 𝐽𝑞𝑋2𝑋 is defined by𝐽𝑞(𝑋)=𝑓𝑋𝑥,𝑓=𝑥𝑞,𝑓=𝑥𝑞1,𝑥𝑋,(2.1) where 𝑞>1 is a constant. It is known that, in general, 𝐽𝑞(𝑥)=𝑥𝑞1𝐽2(𝑥) for all 𝑥0 and 𝐽𝑞 is single-valued if 𝑋 is strictly convex. In the sequel, we always assume that 𝑋 is a real Banach space such that 𝐽𝑞 is single-valued.

The modulus of smoothness of 𝑋 is the function 𝜌𝑋[0,)[0,) defined by𝜌𝑋(𝑡)=sup𝑥+𝑦+𝑥𝑦21𝑥1,𝑦𝑡.(2.2) A Banach space 𝑋 is called uniformly smooth iflim𝑡0𝜌𝑋(𝑡)𝑡=0.(2.3)𝑋 is called 𝑞-uniformly smooth if there exists a constant 𝑐>0 such that𝜌𝑋(𝑡)𝑐𝑡𝑞,𝑞>1.(2.4)

Note that 𝐽𝑞 is single valued if 𝑋 is uniformly smooth. In the study of characteristic inequalities in 𝑞-uniformly smooth Banach spaces, Xu [18] proved the following result.

Definition 2.1. Let 𝐻,𝜂𝑋×𝑋𝑋 be two single-valued mappings and 𝐴,𝐵𝑋𝑋 two single-valued mappings.(i)𝐴 is said to be accretive if𝐴𝑥𝐴𝑦,𝐽𝑞(𝑥𝑦)0,𝑥,𝑦𝑋,(2.5)(ii)𝐴 is said to be strictly accretive if 𝐴 is accretive and 𝐴𝑥𝐴𝑦,𝐽𝑞(𝑥𝑦)=0,𝑥,𝑦𝑋,(2.6) if and only if 𝑥=𝑦;(iii)𝐻(𝐴,) is said to be 𝛼-strongly accretive with respect to 𝐴 if there exists a constant 𝛼>0 such that𝐻(𝐴𝑥,𝑢)𝐻(𝐴𝑦,𝑢),𝐽𝑞(𝑥𝑦)𝛼𝑥𝑦𝑞,𝑥,𝑦,𝑢𝑋;(2.7)(iv)𝐻(,𝐵) is said to be 𝛽-relaxed accretive with respect to 𝐵 if there exists a constant 𝛽>0 such that𝐻(𝑢,𝐵𝑥)𝐻(𝑢,𝐵𝑦),𝐽𝑞(𝑥𝑦)𝛽𝑥𝑦𝑞,𝑥,𝑦,𝑢𝑋;(2.8)(v)𝐻(,) is said to be 𝛾-Lipschitz continuous with respect to 𝐴 if there exists a constant 𝛾>0 such that𝐻(𝐴𝑥,𝑢)𝐻(𝐴𝑦,𝑢)𝛾𝑥𝑦𝑞,𝑥,𝑦,𝑢𝑋;(2.9)(vi)𝐴 is said to be 𝜃-Lipschitz continuous if there exists a constant 𝜃>0 such that𝐴𝑥𝐴𝑦𝜃𝑥𝑦𝑞,𝑥,𝑦𝑋;(2.10)(vii)𝜂(,) is said to be strongly accretive with respect to 𝐻(𝐴,𝐵) if there exists a constant 𝜌>0 such that𝜂(𝑥,𝑢)𝜂(𝑦,𝑢),𝐽𝑞(𝐻(𝐴𝑥,𝐵𝑥)𝐻(𝐴𝑦,𝐵𝑦))𝜌𝑥𝑦𝑞,𝑥,𝑦,𝑢𝑋.(2.11)

Definition 2.2. Let 𝜂𝑋×𝑋𝑋 be single-valued mapping. Let 𝑀𝑋2𝑋 be a set-valued mapping.(i)𝜂 is said to be 𝒯-Lipschitz continuous if there exists a constant 𝒯>0 such that𝜂(𝑥,𝑦)𝒯𝑥𝑦,𝑥,𝑦𝑋;(2.12)(ii) 𝑀 is said to be accretive if𝑢𝑣,𝐽𝑞(𝑥𝑦)0,𝑥,𝑦𝑋,𝑢𝑀(𝑥),𝑣𝑀(𝑦);(2.13)(iii) 𝑀 is said to be 𝜂-accretive if𝑢𝑣,𝐽𝑞(𝜂(𝑥,𝑦))0,𝑥,𝑦𝑋,𝑢𝑀(𝑥),𝑣𝑀(𝑦);(2.14)(iv)𝑀 is said to be strictly 𝜂-accretive if 𝑀 is 𝜂-accretive and equality holds if and only if 𝑥=𝑦;(v) 𝑀 is said to be 𝛾-strongly 𝜂-accretive if there exists a positive constant 𝛾>0 such that𝑢𝑣,𝐽𝑞(𝜂(𝑥,𝑦))𝛾𝑥𝑦𝑞,𝑥,𝑦𝑋,𝑢𝑀(𝑥),𝑣𝑀(𝑦);(2.15)(vi) 𝑀 is said to be 𝛼-relaxed 𝜂-accretive if there exists a positive constant 𝛼>0 such that𝑢𝑣,𝐽𝑞(𝜂(𝑥,𝑦))𝛼𝑥𝑦𝑞,𝑥,𝑦𝑋,𝑢𝑀(𝑥),𝑣𝑀(𝑦).(2.16)

Definition 2.3. Let 𝐴,𝐵𝑋𝑋, 𝐻𝑋×𝑋𝑋 be three single-valued mappings. Let 𝑀𝑋2𝑋 be a set-valued mapping. 𝑀 is said to be 𝐻(,)-accretive with respect to 𝐴 and 𝐵 (or simply 𝐻(,)-accretive in the sequel), if 𝑀 is accretive and (𝐻(𝐴,𝐵)+𝜆𝑀)(𝑋)=𝑋 for every 𝜆>0.

Lemma 2.4. Let 𝑋 be a real uniformly smooth Banach space. Then 𝑋 is 𝑞-uniformly smooth if and only if there exists a constant 𝑐𝑞>0 such that for all 𝑥,𝑦𝑋𝑥+𝑦𝑞𝑥𝑞+𝑞𝑦,𝐽𝑞(𝑥)+𝑐𝑞𝑦𝑞.(2.17)

Lemma 2.5 (see[16]). Let 𝐻(𝐴,𝐵) be 𝛼-strongly accretive with respect to 𝐴, 𝛽-relaxed accretive with respect to 𝐵, and 𝛼>𝛽. Let 𝑀 be an 𝐻(,)-accretive operator with respect to 𝐴 and 𝐵. Then, the operator 𝐻((𝐴,𝐵)+𝜆𝑀)1 is single valued. Based on Lemma 2.4, one can define the resolvent operator 𝑅𝐻(,)𝑀,𝜆 as follows.

Definition 2.6. Let 𝐻,𝐴,𝐵,𝑀 be defined as in Definition 2.3. Let 𝐻(𝐴,𝐵) be 𝛼-strongly accretive with respect to 𝐴, 𝛽-relaxed accretive with respect to 𝐵, and 𝛼>𝛽. Let 𝑀 be an 𝐻(,)-accretive operator with respect to 𝐴 and 𝐵. The resolvent operator 𝑅𝐻(,)𝑀,𝜆𝑋𝑋 is defined by 𝑅𝐻(,)𝑀,𝜆(𝑧)=(𝐻(𝐴,𝐵)+𝜆𝑀)1(𝑧),𝑧𝑋,(2.18) where 𝜆>0 is a constant.

Lemma 2.7 (see [16]). Let 𝐻,𝐴,𝐵,𝑀 be defined as in Definition 2.3. Let 𝐻(𝐴,𝐵) be 𝛼-strongly accretive with respect to 𝐴, 𝛽-relaxed accretive with respect to 𝐵, and 𝛼>𝛽. Suppose that 𝑀𝑋2𝑋 is an 𝐻(,)-accretive operator. Then resolvent operator 𝑅𝐻(,)𝑀,𝜆 defined by (2.18) is 1/(𝛼𝛽) Lipschitz continuous. That is, 𝑅𝐻(,)𝑀,𝜆(𝑥)𝑅𝐻(,)𝑀,𝜆(𝑦)1𝛼𝛽𝑥𝑦,𝑥,𝑦𝑋.(2.19)

We define a Hausdorff pseudometric 𝐷2𝑋×2𝑋[0,+] by𝐷(𝑈,𝑉)=maxsup𝑢𝑈inf𝑣𝑉𝑢𝑣,sup𝑢𝑉inf𝑣𝑈𝑢𝑣(2.20) for any given 𝑈,𝑉2𝑋. Note that if the domain of 𝐷 is restricted to closed bounded subsets, then 𝐷 is the Hausdorff metric.

Lemma 2.8 (see [19]). Let {𝑐𝑛} and {𝑘𝑛} be two real sequences of nonnegative numbers that satisfy the following conditions:(i)0<𝑘𝑛<1 for 𝑛=0,1,2,, and limsup𝑛𝑘𝑛<1;(ii)𝑐𝑛+1𝑘𝑛𝑐𝑛 for 𝑛=0,1,2,.Then, 𝑐𝑛 converges to 0 as 𝑛.

3. Main Result

Let 𝑋 be 𝑞-uniformly smooth real Banach space and 𝐶(𝑋) a nonempty closed convex set. Let 𝑆𝑖,𝐻𝑖𝑋×𝑋𝑋, 𝐴𝑖,𝐵𝑖𝑋𝑋 be single-valued operators, for all 𝑖=1,2,,𝑁. For any fix 𝑖{1,2,,𝑁}, we let 𝑀𝑖𝑋2𝑋, 𝐻𝑖(𝐴𝑖,𝐵𝑖)-accretive set-valued operator and 𝑈𝑖𝑋2𝑋 a set-valued mapping which nonempty values. The system of nonlinear set-valued variational inclusions is to find 𝑎1,,𝑎𝑁𝑋, 𝑢1𝑈1(𝑎𝑁),,𝑢𝑁𝑈𝑁(𝑎1) such that0𝑆𝑖𝑎𝑖,𝑢𝑖+𝑀𝑖𝑎𝑖,𝑖=1,2,,𝑁.(3.1)

If 𝑁=2, then system of nonlinear set-valued variational inclusions (3.1) becomes following system of variational inclusions: finding 𝑎1,𝑎2𝑋, 𝑢1𝑈1(𝑎2) and 𝑢2𝑈2(𝑎1) such that0𝑆1𝑎1,𝑢1+𝑀1𝑎1,0𝑆2𝑎2,𝑢2+𝑀2𝑎2.(3.2)

If 𝑁=1, then system of nonlinear set-valued variational inclusions (3.1) becomes the following class of nonlinear set-valued variational inclusions see [15]: finding 𝑎𝑋, 𝑢𝑈(𝑎) such that0𝑆(𝑎,𝑢)+𝑀(𝑎).(3.3)

For solving the system of nonlinear set-valued variational inclusions involving a finite family of 𝐻(,)-accretive operators in Banach spaces, let us give the following assumptions.

For any 𝑖{1,2,,𝑁}, we suppose that(A1)𝐻(𝐴𝑖,𝐵𝑖) is 𝛼𝑖-strongly accretive with respect to 𝐴𝑖, 𝛽𝑖-relaxed accretive with respect to 𝐵𝑖 and 𝛼𝑖>𝛽𝑖,(A2)𝑀𝑖𝑋2𝑋 is an 𝐻𝑖(,)-accretive single-valued mapping,(A3)𝑈𝑖𝑋𝐶(𝑋) is a contraction set-valued mapping with 0𝐿𝑖<1 and nonempty values,(A4)𝐻𝑖(𝐴𝑖,𝐵𝑖) is 𝑟𝑖-Lipschitz continuous with respect to 𝐴𝑖 and 𝑡𝑖-Lipschitz continuous with respect to 𝐵𝑖,(A5)𝑆𝑖𝑋×𝑋𝑋 is 𝑙𝑖-Lipschitz continuous with respect to its first argument and 𝑚𝑖-Lipschitz continuous with respect to its second argument,(A6)𝑆𝑖(,𝑢) is 𝑠𝑖-strongly accretive with respect to 𝐻𝑖(𝐴𝑖,𝐵𝑖).

Theorem 3.1. For given 𝑎1,,𝑎𝑁𝑋, 𝑢1𝑈1(𝑎𝑁),,𝑢𝑁𝑈𝑁(𝑎1), it is a solution of problem (3.1) if and only if 𝑎𝑖=𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑎𝑖,𝐵𝑖𝑎𝑖𝜆𝑖𝑆𝑖𝑎𝑖,𝑢𝑖,(3.4) where 𝜆𝑖>0 are constants.

Proof. We note from the Definition 2.6 that 𝑎1,,𝑎𝑁𝑋, 𝑢1𝑈1(𝑎𝑁),,𝑢𝑁𝑈𝑁(𝑎1) is a solution of (3.1) if and only if, for each 𝑖{1,2,,𝑁}, we have 𝑎𝑖=𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑎𝑖,𝐵𝑖𝑎𝑖𝜆𝑖𝑆𝑖𝑎𝑖,𝑢𝑖𝑎𝑖=𝐻𝑖𝐴𝑖,𝐵𝑖+𝜆𝑖𝑀𝑖1𝐻𝑖𝐴𝑖𝑎𝑖,𝐵𝑖𝑎𝑖𝜆𝑖𝑆𝑖𝑎𝑖,𝑢𝑖𝐻𝑖𝐴𝑖𝑎𝑖,𝐵𝑖𝑎𝑖𝜆𝑖𝑆i𝑎𝑖,𝑢𝑖𝐻𝑖𝐴𝑖,𝐵𝑖+𝜆𝑖𝑀𝑖𝑎𝑖𝜆𝑖𝑆𝑖𝑎𝑖,𝑢𝑖𝜆𝑖𝑀𝑖𝑎𝑖0𝑆𝑖𝑎𝑖,𝑢𝑖+𝑀𝑖𝑎𝑖.(3.5)

Algorithm 3.2. For given 𝑎10,,𝑎𝑁0𝑋, 𝑢10𝑈1(𝑎𝑁0),,𝑢𝑁0𝑈𝑁(𝑎10), we let 𝑎𝑖1=𝜎0𝑎𝑖0+1𝜎0𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑎𝑖0,𝐵𝑖𝑎𝑖0𝜆𝑖𝑆𝑖𝑎𝑖0,𝑢𝑖0,(3.6) for all 𝑖=1,2,,𝑁, where 0<𝜎01. By Nadler theorem [20], there exists 𝑢11𝑈1(𝑎𝑁1),,𝑢𝑁1𝑈𝑁(𝑎11) such that 𝑢𝑖1𝑢𝑖0(1+1)𝐷𝑈𝑖𝑎𝑁(𝑖1)1,𝑈𝑖𝑎𝑁(𝑖1)0,𝑖=1,2,,𝑁,(3.7) where 𝐷(,) is the Hausdorff pseudo metric on 2𝑋. Continuing the above process inductively, we can obtain the sequences {𝑎𝑖𝑛} and {𝑢𝑖𝑛} such that 𝑎𝑖𝑛+1=𝜎𝑛𝑎𝑖𝑛+1𝜎𝑛𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑎i𝑛,𝐵𝑖𝑎𝑖𝑛𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛,(3.8) for all 𝑛=1,2,3,,𝑖=1,2,,𝑁, where 0<𝜎𝑛1 with limsup𝑛𝜎𝑛<1. Therefore, by Nadler theorem [20], there exists 𝑢1𝑛+1𝑈1(𝑎𝑁𝑛+1),,𝑢𝑁𝑛+1𝑈𝑁(𝑎1𝑛+1) such that 𝑢𝑖𝑛+1𝑢𝑖𝑛1+(1+𝑛)1𝐷𝑈𝑖𝑎𝑁(𝑖1)𝑛+1,𝑈𝑖𝑎𝑁(𝑖1)𝑛,𝑛=1,2,3,,𝑖=1,2,,𝑁.(3.9)
The idea of the proof of the next theorem is contained in the paper of Verma [15] and Zou and Huang [17].

Theorem 3.3. Let 𝑋 be q-uniformly smooth real Banach space. Let 𝐴𝑖,𝐵𝑖𝑋𝑋 be single-valued operators, 𝐻𝑖𝑋×𝑋𝑋 a single-valued operator satisfy (A1) and 𝑀𝑖, 𝑈𝑖, 𝐻𝑖(𝐴𝑖,𝐵𝑖), 𝑆𝑖, 𝑆𝑖(,𝑢) satisfy conditions (A2)–(A6), respectively. If there exists a constant 𝑐𝑞,𝑖 such that 𝑞𝑟𝑖+𝑡𝑖𝑞𝑞𝜆𝑖𝑠𝑖+𝑐𝑞,𝑖𝜆𝑞𝑖𝑙𝑞𝑖𝛼𝑖𝛽𝑖+𝜆𝑖𝑚𝑖𝛼𝑖𝛽𝑖<1(3.10) for all 𝑖=1,2,,𝑁, then problem (3.1) has a solution 𝑎1,,𝑎𝑁, 𝑢1𝑈1(𝑎𝑁),,𝑢𝑁𝑈𝑁(𝑎1).

Proof. For any 𝑖{1,2,,𝑁} and 𝜆𝑖>0, we define 𝐹𝑖𝑋×𝑋𝑋 by 𝐹𝑖(𝑢,𝑣)=𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖(𝑢),𝐵𝑖(𝑢)𝜆𝑖𝑆𝑖(𝑢,𝑣),(3.11) for all 𝑢,𝑣𝑋. Let 𝐽𝑖(𝑥,𝑦)=𝐻𝑖(𝐴𝑖(𝑥),𝐵𝑖(𝑦)). For any (𝑢1,𝑣1),(𝑢2,𝑣2)𝑋×𝑋, we note by (3.11) and Lemma 2.7 that 𝐹𝑖𝑢1,𝑣1𝐹𝑖𝑢2,𝑣2=𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑢1,𝐵𝑖𝑢1𝜆𝑖𝑆𝑖𝑢1,𝑣1𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑢2,𝐵𝑖𝑢2𝜆𝑖𝑆𝑖𝑢2,𝑣2=𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐽𝑖𝑢1,𝑢1𝜆𝑖𝑆𝑖𝑢1,𝑣1𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐽𝑖𝑢2,𝑢2𝜆𝑖𝑆𝑖𝑢2,𝑣21𝛼𝑖𝛽𝑖𝐽𝑖𝑢1,𝑢1𝜆𝑖𝑆𝑖𝑢1,𝑣1𝐽𝑖𝑢2,𝑢2𝜆𝑖𝑆𝑖𝑢2,𝑣2=1𝛼𝑖𝛽𝑖𝐽𝑖𝑢1,𝑢1𝐽𝑖𝑢2,𝑢2𝜆𝑖𝑆𝑖𝑢1,𝑣1𝑆𝑖𝑢2,𝑣21𝛼𝑖𝛽𝑖𝐽𝑖𝑢1,𝑢1𝐽𝑖𝑢2,𝑢2𝜆𝑖𝑆𝑖𝑢1,𝑣1𝑆𝑖𝑢2,𝑣1+𝜆𝑖𝛼𝑖𝛽𝑖𝑆𝑖𝑢2,𝑣1𝑆𝑖𝑢2,𝑣2.(3.12) By Lemma 2.4, we have 𝐽𝑖𝑢1,𝑢1𝐽𝑖𝑢2,𝑢2𝜆𝑖𝑆𝑖𝑢1,𝑣1𝑆𝑖𝑢2,𝑣1𝑞𝐽𝑖𝑢1,𝑢1𝐽𝑖𝑢2,𝑢2𝑞𝑞𝜆𝑖𝑆𝑖𝑢1,𝑣1𝑆𝑖𝑢2,𝑣1,𝐽𝑞𝐽𝑖𝑢1,𝑢1𝐽𝑖𝑢2,𝑢2+𝑐𝑞,𝑖𝜆𝑞𝑖𝑆𝑖𝑢1,𝑣1𝑆𝑖𝑢2,𝑣1𝑞.(3.13) Moreover, by (A4), we obtain 𝐽𝑖𝑢1,𝑢1𝐽𝑖𝑢2,𝑢2𝐽𝑖𝑢1,𝑢1𝐽𝑖𝑢2,𝑢1+𝐽𝑖𝑢2,𝑢1𝐽𝑖𝑢2,𝑢2𝑟𝑖𝑢1𝑢2+𝑡𝑖𝑢1𝑢2𝑟𝑖+𝑡𝑖𝑢1𝑢2.(3.14) From (A6), we have 𝑞𝜆𝑖𝑆𝑖𝑢1,𝑣1𝑆𝑖𝑢2,𝑣1,𝐽𝑞𝐽𝑖𝑢1,𝑢1𝐽𝑖𝑢2,𝑢2𝑞𝜆𝑖𝑠𝑖𝑢1𝑢2𝑞.(3.15) Moreover, from (A5), we obtain 𝑆𝑖𝑢1,𝑣1𝑆𝑖𝑢2,𝑣1𝑙𝑖𝑢1𝑢2,(3.16)𝑆𝑖𝑢2,𝑣1𝑆𝑖𝑢2,𝑣2𝑚𝑖𝑣1𝑣2.(3.17) From (3.13)–(3.16), we have 𝐽𝑖𝑢1,𝑢1𝐽𝑖(𝑢2,𝑢2)𝜆𝑖𝑆𝑖𝑢1,𝑣1𝑆𝑖𝑢2,𝑣1𝑞𝑞𝑟𝑖+𝑡𝑖𝑞𝑞𝜆𝑖𝑠𝑖+𝑐𝑞,𝑖𝜆𝑞𝑖𝑙𝑞𝑖𝑢1𝑢2.(3.18) It follows from (3.12), (3.17), and (3.18) that 𝐹𝑖𝑢1,𝑣1𝐹𝑖𝑢2,𝑣2𝑞𝑟𝑖+𝑡𝑖𝑞𝑞𝜆𝑖𝑠𝑖+𝑐𝑞,𝑖𝜆𝑞𝑖𝑙𝑞𝑖𝛼𝑖𝛽𝑖𝑢1𝑢2+𝜆𝑖𝑚𝑖𝛼𝑖𝛽𝑖𝑣1𝑣2.(3.19) Put 𝜃𝑖1=𝑞𝑟𝑖+𝑡𝑖𝑞𝑞𝜆𝑖𝑠𝑖+𝑐𝑞,𝑖𝜆𝑞𝑖𝑙𝑞𝑖𝛼𝑖𝛽𝑖,𝜃𝑖2=𝜆𝑖𝑚𝑖𝛼𝑖𝛽𝑖.(3.20) Define on 𝑋××𝑋𝑁times by (𝑥1,,𝑥𝑁)=𝑥1+𝑥𝑁 for all (𝑥1,,𝑥𝑁)𝑋××𝑋𝑁times. It is easy to see that (𝑋××𝑋𝑁times,) is a Banach space. For any given 𝑥1,,𝑥𝑁𝑋, we choose a finite sequence 𝑤1𝑈1(𝑥𝑁),,𝑤𝑁𝑈𝑁(𝑥1). Define 𝑄𝑋××𝑋𝑁times𝑋××𝑋𝑁times by 𝑄(𝑥1,,𝑥𝑁)=(𝐹1(𝑥1,𝑤1),,𝐹𝑁(𝑥𝑁,𝑤𝑁)). Set 𝑘=max{(𝜃11+𝜃𝑁2𝐿𝑁),,(𝜃12𝐿1+𝜃𝑁1)}, where 𝐿1,,𝐿𝑁 are contraction constants of 𝑈1,,𝑈𝑁, respectively. We note that 𝜃𝑖1+𝜃𝑖2𝐿𝑖<𝜃𝑖1+𝜃𝑖2<1, for all 𝑖=1,2,,𝑁, and so 𝑘<1. Let 𝑥1,,𝑥𝑁𝑋, 𝑤1𝑈1(𝑥𝑁),,𝑤𝑁𝑈𝑁(𝑥1) and 𝑦1,,𝑦𝑁𝑋, 𝑧1𝑈1(𝑦𝑁),,𝑧𝑁𝑈𝑁(𝑦1). By (A3), we get 𝑄𝑥1,,𝑥𝑁𝑄𝑦1,,𝑦𝑁=𝐹1𝑥1,𝑤1,,𝐹𝑁𝑥𝑁,𝑤𝑁𝐹1𝑦1,𝑧1,,𝐹𝑁𝑦𝑁,𝑧𝑁=𝐹1𝑥1,𝑤1𝐹1𝑦1,𝑧1++𝐹𝑁𝑥𝑁,𝑤𝑁𝐹𝑁𝑦𝑁,𝑧𝑁𝜃11𝑥1𝑦1+𝜃12𝑤1𝑧1++𝜃𝑁1𝑥𝑁𝑦𝑁+𝜃𝑁2𝑤𝑁𝑧𝑁𝜃11𝑥1𝑦1+𝜃12𝐿1𝑥𝑁𝑦𝑁++𝜃𝑁1𝑥𝑁𝑦𝑁+𝜃𝑁2𝐿𝑁𝑥1𝑦1=𝜃11+𝜃𝑁2𝐿𝑁𝑥1𝑦1++𝜃𝑁1+𝜃12𝐿1𝑥𝑁𝑦𝑁𝑘𝑥1𝑦1++𝑘𝑥𝑁𝑦𝑁=𝑘𝑥1𝑦1++𝑥𝑁𝑦𝑁=𝑘𝑥1,,𝑥𝑁𝑦1,,𝑦𝑁,(3.21) and so 𝑄 is a contraction on 𝑋××𝑋𝑁times. Hence there exists 𝑎1,,𝑎𝑁𝑋,𝑢1𝑈1(𝑎𝑁),,𝑢𝑁𝑈𝑁(𝑎1) such that 𝑎1=𝐹1(𝑎1,𝑢1),,𝑎𝑁=𝐹𝑁(𝑎𝑁,𝑢𝑁). From Theorem 3.1, 𝑎1,,𝑎𝑁𝑋, 𝑢1𝑈1(𝑎𝑁),,𝑢𝑁𝑈𝑁(𝑎1) is the solution of the problem (3.1).

Theorem 3.4. Let 𝑋 be 𝑞-uniformly smooth real Banach space. For 𝑖=1,2,,𝑁. Let 𝐴𝑖,𝐵𝑖𝑋𝑋 be single-valued operators, 𝐻𝑖𝑋×𝑋𝑋 single-valued operator satisfy (A1) and suppose that 𝑀𝑖, 𝑈𝑖, 𝐻𝑖(𝐴𝑖,𝐵𝑖), 𝑆𝑖, 𝑆𝑖(,𝑢) satisfy conditions (A2)–(A6), respectively. Then, for any 𝑖{1,2,,𝑁}, the sequences {𝑎𝑖𝑛}𝑛=1 and {𝑢𝑖𝑛}𝑛=1 generated by Algorithm 3.2 converge strongly to 𝑎𝑖, 𝑢𝑖𝑈𝑖(𝑎𝑁(𝑖1)), respectively.

Proof. By Theorem 3.3, the problem (3.1) has a solution 𝑎1,,𝑎𝑁𝑋, 𝑢1𝑈1(𝑎𝑁),,𝑢𝑁𝑈𝑁(𝑎1). From Theorem 3.1, we note that 𝑎𝑖=𝜎𝑛𝑎𝑖+1𝜎𝑛𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑎𝑖,𝐵𝑖𝑎𝑖𝜆𝑖𝑆𝑖𝑎𝑖,𝑢𝑖,(3.22) for all 𝑖=1,2,,𝑁. Hence, by (3.8) and (3.22), we have 𝑎𝑖𝑛+1𝑎𝑖𝑛=𝜎𝑛𝑎𝑖𝑛+1𝜎𝑛𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑎𝑖𝑛,𝐵𝑖𝑎𝑖𝑛𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝜎𝑛𝑎𝑖𝑛1+1𝜎𝑛𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑎𝑖𝑛1,𝐵𝑖𝑎𝑖𝑛1𝜆𝑖𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛1𝜎𝑛𝑎𝑖𝑛𝑎𝑖𝑛1+1𝜎𝑛𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑎𝑖𝑛,𝐵𝑖𝑎𝑖𝑛𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑎𝑖𝑛1,𝐵𝑖𝑎𝑖𝑛1𝜆𝑖𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛1=𝜎𝑛𝑎𝑖𝑛𝑎𝑖𝑛1+1𝜎𝑛𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐽𝑖𝑎𝑖𝑛,𝑎𝑖𝑛𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐽𝑖𝑎𝑖𝑛1,𝑎𝑖𝑛1𝜆𝑖𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛1𝜎𝑛𝑎𝑖𝑛𝑎𝑖𝑛1+1𝜎𝑛1𝛼𝑖𝛽𝑖𝐽𝑖𝑎𝑖𝑛,𝑎𝑖𝑛𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝐽𝑖𝑎𝑖𝑛1,𝑎𝑖𝑛1𝜆𝑖𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛1=𝜎𝑛𝑎𝑖𝑛𝑎𝑖𝑛1+1𝜎𝑛1𝛼𝑖𝛽𝑖𝐽𝑖𝑎𝑖𝑛,𝑎𝑖𝑛𝐽𝑖𝑎𝑖𝑛1,𝑎𝑖𝑛1𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛1𝜎𝑛𝑎𝑖𝑛𝑎𝑖𝑛1+1𝜎𝑛1𝛼𝑖𝛽𝑖𝐽𝑖𝑎𝑖𝑛,𝑎𝑖𝑛𝐽𝑖𝑎𝑖𝑛1,𝑎𝑖𝑛1𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛+1𝜎𝑛1𝛼𝑖𝛽𝑖𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛1.(3.23) By Lemma 2.4, we obtain 𝐽𝑖𝑎𝑖𝑛,𝑎𝑖𝑛𝐽𝑖𝑎𝑖𝑛1,𝑎𝑖𝑛1𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛𝑞𝐽𝑖𝑎𝑖𝑛,𝑎𝑖𝑛𝐽𝑖𝑎𝑖𝑛1,𝑎𝑖𝑛1𝑞𝑞𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛,𝐽𝑞,𝑖𝐽𝑖𝑎𝑖𝑛,𝑎𝑖𝑛𝐽𝑖𝑎𝑖𝑛1,𝑎𝑖𝑛1+𝑐𝑞,𝑖𝜆𝑞𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛𝑞.(3.24) From (A4), we note that 𝐽𝑖𝑎𝑖𝑛,𝑎𝑖𝑛𝐽𝑖𝑎𝑖𝑛1,𝑎𝑖𝑛1=𝐻𝑖𝐴𝑖𝑎𝑖𝑛,𝐵𝑖𝑎𝑖𝑛𝐻𝑖𝐴𝑖𝑎𝑖𝑛1,𝐵𝑖𝑎𝑖𝑛1𝐻𝑖𝐴𝑖𝑎𝑖𝑛,𝐵𝑖𝑎𝑖𝑛𝐻𝑖𝐴𝑖𝑎𝑖𝑛1,𝐵𝑖𝑎𝑖𝑛+𝐻𝑖𝐴𝑖𝑎𝑖𝑛1,𝐵𝑖𝑎𝑖𝑛𝐻𝑖𝐴𝑖𝑎𝑖𝑛1,𝐵𝑖𝑎𝑖𝑛1𝑟i+𝑡𝑖𝑎𝑖𝑛𝑎𝑖𝑛1.(3.25) From (3.24) and (A6), it follows that 𝑞𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛,𝐽𝑞,1𝐽𝑖𝑎𝑖𝑛,𝑎𝑖𝑛𝐽𝑖𝑎𝑖𝑛1,𝑎𝑖𝑛1𝑞𝜆𝑖𝑠𝑖𝑎𝑖𝑛𝑎𝑖𝑛1𝑞.(3.26) By (3.23), (3.24), and (A5), we have 𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛1𝑚𝑖𝑢𝑖𝑛𝑢𝑖𝑛1𝑚𝑖𝑑𝑖1+𝑛1𝑎𝑖𝑛𝑎𝑖𝑛1,(3.27)𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛𝑙𝑖𝑎𝑖𝑛𝑎𝑖𝑛1.(3.28) From (3.23)–(3.28), we obtain 𝐽𝑖𝑎i𝑛,𝑎𝑖𝑛𝐽𝑖𝑎𝑖𝑛1,𝑎𝑖𝑛1𝜆𝑖𝑆𝑖𝑎𝑖𝑛,𝑢𝑖𝑛𝑆𝑖𝑎𝑖𝑛1,𝑢𝑖𝑛𝑞𝑞𝑟𝑖+𝑡𝑖𝑞𝑞𝜆𝑖𝑠𝑖+𝑐𝑞,𝑖𝜆𝑞𝑖𝑙𝑞𝑖𝛼𝑖𝛽𝑖𝑎𝑖𝑛𝑎𝑖𝑛1+𝜆𝑖𝑚𝑖𝛼𝑖𝛽𝑖𝑑𝑖1+𝑛1𝑎𝑖𝑛𝑎𝑖𝑛1.(3.29) Hence, by (3.23), (3.28) and (3.29), we have 𝑎𝑖𝑛+1𝑎𝑖𝑛𝜎𝑛𝑎𝑖𝑛𝑎𝑖𝑛1+1𝜎𝑛𝑞𝑟𝑖+𝑡𝑖𝑞𝑞𝜆𝑖𝑠𝑖+𝑐𝑞,𝑖𝜆𝑞𝑖𝑙𝑞𝑖𝛼𝑖𝛽𝑖𝑎𝑖𝑛𝑎𝑖𝑛1+1𝜎𝑛𝜆𝑖𝑚𝑖𝛼𝑖𝛽𝑖𝑑𝑖1+𝑛1𝑎𝑖𝑛𝑎𝑖𝑛1.(3.30) Put 𝑘=max{𝜋1,𝜋𝑁}, where 𝜋𝑖=𝑞𝑟𝑖+𝑡𝑖𝑞𝑞𝜆𝑖𝑠𝑖+𝑐𝑞,𝑖𝜆𝑞𝑖𝑙𝑞𝑖𝛼𝑖𝛽𝑖+𝜆𝑖𝑚𝑖𝑑𝑖1+𝑛1𝛼𝑖𝛽𝑖.(3.31) It follows from (3.30) that 𝑎1𝑛+1𝑎1𝑛++𝑎𝑁𝑛+1𝑎𝑁𝑛𝜎𝑛𝑎1𝑛𝑎1𝑛1+1𝜎𝑛𝑘𝑎1𝑛𝑎1𝑛1++𝜎𝑛𝑎𝑁𝑛𝑎𝑁𝑛1+1𝜎𝑛𝑘𝑎𝑁𝑛𝑎𝑁𝑛1.(3.32) Set 𝑐𝑛=𝑎1𝑛𝑎1𝑛1++𝑎𝑁𝑛𝑎𝑁𝑛1 and 𝑘𝑛=𝑘+(1𝑘)𝜎𝑛. From (3.32), we obtain 𝑐𝑛+1𝑘𝑛𝑐𝑛,𝑛=0,1,2,.(3.33) Since limsup𝑛𝜎𝑛<1, we have limsup𝑛𝑘𝑛<1. Thus, it follows from Lemma 2.8 that 𝑐𝑛+10 and hence lim𝑛𝑎𝑖𝑛+1𝑎𝑖𝑛=0. Therefore, {𝑎𝑖𝑛} is a Cauchy sequence and hence there exists 𝑎𝑖𝑋 such that 𝑎𝑖𝑛𝑎𝑖 as 𝑛, for all 𝑖=1,2,,𝑁. Next, we will show that 𝑢1𝑛𝑢1𝑈1(𝑎𝑁) as 𝑛. Hence, it follows from (3.9) that {𝑢1𝑛} is also a Cauchy sequence. Thus there exists 𝑢1𝑋 such that 𝑢1𝑛𝑢1 as 𝑛. Consider 𝑑𝑢1,𝑈1𝑎𝑁=inf𝑢1𝑞𝑞𝑈1𝑎𝑁𝑢1𝑢1𝑛+𝑑𝑢1𝑛,𝑈1𝑎𝑁𝑢1𝑢1𝑛+𝐷𝑈1𝑎𝑁𝑛,𝑈1𝑎𝑁𝑢1𝑢1𝑛+𝑑1𝑎𝑁𝑛𝑎𝑁0(3.34) as 𝑛. Since 𝑈1(𝑎𝑁) is a closed set and 𝑑(𝑢1,𝑈1(𝑎𝑁))=0, we have 𝑢1𝑈1(𝑎𝑁). By continuing the above process, there exist 𝑢2𝑈2(𝑎𝑁1),,𝑢𝑁𝑈𝑁(𝑎1) such that 𝑢2𝑛𝑢2,,𝑢𝑁𝑛𝑢𝑁 as 𝑛. Hence, by (3.8), we obtain 𝑎𝑖=𝑅𝐻𝑖(,)𝑀𝑖,𝜆𝑖𝐻𝑖𝐴𝑖𝑎𝑖,𝐵𝑖𝑎𝑖𝜆𝑖𝑆𝑖𝑎𝑖,𝑢𝑖.(3.35) Therefore, it follows from Theorem 3.1 that 𝑎1,,𝑎𝑁 is a solution of problem (3.1).
Setting 𝑁=2 in Theorem 3.3, we have the following result.

Corollary 3.5. Let 𝑋 be 𝑞-uniformly smooth real Banach spaces. Let 𝐴𝑖,𝐵𝑖𝑋𝑋 be singled valued operators, 𝐻𝑖𝑋×𝑋𝑋 a single-valued operator such that 𝐻(𝐴𝑖,𝐵𝑖) is 𝛼𝑖-strongly accretive with respect to 𝐴𝑖, 𝛽𝑖-relaxed accretive with respect to 𝐵𝑖 and 𝛼𝑖>𝛽𝑖 and suppose that 𝑀𝑖𝑋2𝑋 is an 𝐻𝑖(,)-accretive set-valued mapping and 𝑈𝑖𝑋𝐶(𝑋) contraction set-valued mapping with 0𝐿𝑖<1 and nonempty values, for all 𝑖=1,2. Assume that 𝐻𝑖(𝐴𝑖,𝐵𝑖) is 𝑟𝑖-Lipschitz continuous with respect to 𝐴𝑖 and 𝑡𝑖-Lipschitz continuous with respect to 𝐵𝑖, 𝑆𝑖𝑋×𝑋𝑋 is 𝑙𝑖-Lipschitz continuous with respect to its first argument and 𝑚𝑖-Lipschitz continuous with respect to its second argument, 𝑆1(,𝑦) is 𝑠1-strongly accretive with respect to 𝐻1(𝐴1,𝐵1), and S2(𝑥,) is 𝑠2-strongly accretive with respect to 𝐻2(𝐴2,𝐵2), for all 𝑖=1,2. If 𝑞𝑟𝑖+𝑡𝑖𝑞𝑞𝜆𝑖𝑠𝑖+𝑐𝑞,𝑖𝜆𝑞𝑖𝑙𝑞𝑖𝛼𝑖𝛽𝑖+𝜆𝑖𝑚𝑖𝛼𝑖𝛽𝑖<1,(3.36) for all 𝑖{1,2}, then problem (3.2) has a solution 𝑎1,𝑎2𝑋, 𝑢1𝑈1(𝑎2),𝑢2𝑈2(𝑎1).

Setting 𝑁=1 in Theorem 3.3, we have the following result.

Corollary 3.6. Let 𝑋 be 𝑞-uniformly smooth real Banach spaces. Let 𝐴,𝐵𝑋𝑋 be two singled valued operators, 𝐻𝑋×𝑋𝑋 a single-valued operator such that 𝐻(𝐴,𝐵) is 𝛼-strongly accretive with respect to 𝐴, 𝛽-relaxed accretive with respect to 𝐵, and 𝛼>𝛽 and suppose that 𝑀𝑋2𝑋 is an 𝐻(,)-accretive set-valued mapping, 𝑈𝑋𝐶(𝑋) is contraction set-valued mapping with 0𝐿<1 and nonempty values. Assume that 𝐻(𝐴,𝐵) is 𝑟-Lipschitz continuous with respect to 𝐴 and 𝑡-Lipschitz continuous with respect to 𝐵, 𝑆𝑋×𝑋𝑋 is 𝑙-Lipschitz continuous with respect to its first argument and 𝑚-Lipschitz continuous with respect to its second argument, 𝑆(,𝑦) is 𝑠-strongly accretive with respect to 𝐻(𝐴,𝐵). If 𝑞(𝑟+𝑡)𝑞𝑞𝜆𝑠+𝑐𝑞,𝜆𝑞𝑙𝑞𝛼𝛽+𝜆𝑚𝛼𝛽<1,(3.37) then problem (3.3) has a solution 𝑎𝑋 and 𝑢𝑈(𝑎).

Acknowledgments

The first author would like to thank the Office of the Higher Education Commission, Thailand, financial support under Grant CHE-Ph.D-THA-SUP/191/2551, Thailand. Moreover, the second author would like to thank the Thailand Research Fund for financial support under Grant BRG5280016.