Research Article

Validity and Reliability of Semiquantitative Food Frequency Questionnaires for Assessing Nutrient Intake among Preschool Children in Northwest China

Table 4

Relative validity of FFQs for preschool children.

Item (units/d)A_FFQ3DRP valueSCCICC%CC%GM%difference
Median(P25–P75)Median(P25–P75)

Energy (kcal)1802.71(1439.81, 2059.31)1522.51(1313.65, 1704.75)0.0650.8140.82570518.4
Carbohydrates (g)231.44(185.06, 273.14)194.05(162.54, 229.23)0.0580.7030.67165919.3
Protein (g)76.40(61.74, 88.86)66.94(56.23, 77.21)0.1260.7450.70566814.1
Fat (g)55.09(40.94, 66.53)44.56(36.97, 57.32)0.0470.5450.707591523.6
Dietary fibre (g)20.52(16.03, 27.03)17.97(13.67, 23.12)0.1090.4410.539571614.2
Cholesterol (mg)378.93(261.09, 482.60)330.45(223.63, 470.06)0.1640.3100.313481714.7
Vitamin A (IU)1057.42(815.14, 1424.37)998.99(713.66, 1263.93)0.3360.3060.30644185.8
Thiamin (mg)0.90(0.76, 1.09)0.80(0.66, 0.93)0.3680.7070.64956912.5
Riboflavin (mg)1.46(1.22, 1.81)1.37(1.09, 1.63)0.4060.6300.39354116.6
Vitamin C (mg)87.26(66.76, 121.74)75.13(48.81, 107.39)0.1320.3210.338451716.1
Vitamin E (mg)15.83(11.57, 19.88)12.73(10.31, 17.46)0.0310.0380.598551524.4
Niacin (mg)18.24(14.09, 21.58)15.90(13.23, 19.34)0.1470.5540.39750914.7
Calcium (mg)670.08(527.28, 834.41)638.63(457.12, 800.97)0.4320.4720.46155144.9
Iron (mg)28.03(21.33, 36.05)23.67(19.19, 33.02)0.0420.5180.454571218.4
Zinc (mg)6.72(5.31, 8.02)5.90(4.88, 7.40)0.1650.4110.350491813.9
Phosphorus (mg)955.28(744.88, 1097.16)887.33(695.83, 1056.06)0.2080.5310.52150147.7
Sodium (mg)649.36(513.53, 809.68)570.61(473.25, 691.78)0.2520.6640.72168513.8
Selenium (mg)23.25(15.81, 29.45)18.55(14.41, 28.86)0.0460.1680.210401925.3
Magnesium (mg)429.47(336.37, 543.28)369.20(298.78, 488.18)0.1820.6120.62764716.3

value of t test between A_FFQ and 3DR. ICC: intraclass correlation coefficient; SCC: Spearman’s correlation coefficient; %CC: the percentage of correctly classified; %GM: the percentage of grossly misclassified; %difference in nutrient intakes between A_ FFQ and 3DR; %difference = (A_FFQ − 3DR/3DR) × 100%.